table with different partitions in athena aws
Is it possible to create a table with different types of partitions in athena?
for example having a partition per year month day and another partition only by id
CREATE EXTERNAL TABLE IF NOT EXISTS table_example(
name string,
adress
PARTITIONED BY (year string, month string, day string) ----> partition 1
PARTITIONED BY (id int) -----------> partition 2
ROW FORMAT SERDE 'org.openx.data.jsonserde.JsonSerDe'
WITH SERDEPROPERTIES ('ignore.malformed.json' = 'true')
LOCATION 's3://example/folder/';
is something similar to this possible?
thanks
amazon-s3 hive partition amazon-athena prestodb
edited Nov 12 '18 at 20:13
Piotr Findeisen
5,03111538
asked Nov 12 '18 at 18:19
Bar
223
add a comment |
Is it possible to create a table with different types of partitions in athena?
for example having a partition per year month day and another partition only by id
CREATE EXTERNAL TABLE IF NOT EXISTS table_example(
name string,
adress
PARTITIONED BY (year string, month string, day string) ----> partition 1
PARTITIONED BY (id int) -----------> partition 2
ROW FORMAT SERDE 'org.openx.data.jsonserde.JsonSerDe'
WITH SERDEPROPERTIES ('ignore.malformed.json' = 'true')
LOCATION 's3://example/folder/';
is something similar to this possible?
thanks
amazon-s3 hive partition amazon-athena prestodb
edited Nov 12 '18 at 20:13
Piotr Findeisen
5,03111538
asked Nov 12 '18 at 18:19
Bar
223
add a comment |
Is it possible to create a table with different types of partitions in athena?
for example having a partition per year month day and another partition only by id
CREATE EXTERNAL TABLE IF NOT EXISTS table_example(
name string,
adress
PARTITIONED BY (year string, month string, day string) ----> partition 1
PARTITIONED BY (id int) -----------> partition 2
ROW FORMAT SERDE 'org.openx.data.jsonserde.JsonSerDe'
WITH SERDEPROPERTIES ('ignore.malformed.json' = 'true')
LOCATION 's3://example/folder/';
is something similar to this possible?
thanks
amazon-s3 hive partition amazon-athena prestodb
edited Nov 12 '18 at 20:13
Piotr Findeisen
5,03111538
asked Nov 12 '18 at 18:19
Bar
223
Is it possible to create a table with different types of partitions in athena?
for example having a partition per year month day and another partition only by id
CREATE EXTERNAL TABLE IF NOT EXISTS table_example(
name string,
adress
PARTITIONED BY (year string, month string, day string) ----> partition 1
PARTITIONED BY (id int) -----------> partition 2
ROW FORMAT SERDE 'org.openx.data.jsonserde.JsonSerDe'
WITH SERDEPROPERTIES ('ignore.malformed.json' = 'true')
LOCATION 's3://example/folder/';
is something similar to this possible?
thanks
amazon-s3 hive partition amazon-athena prestodb
amazon-s3 hive partition amazon-athena prestodb
edited Nov 12 '18 at 20:13
Piotr Findeisen
5,03111538
asked Nov 12 '18 at 18:19
Bar
223
edited Nov 12 '18 at 20:13
Piotr Findeisen
5,03111538
asked Nov 12 '18 at 18:19
Bar
223
edited Nov 12 '18 at 20:13
Piotr Findeisen
5,03111538
edited Nov 12 '18 at 20:13
Piotr Findeisen
5,03111538
edited Nov 12 '18 at 20:13
Piotr Findeisen
5,03111538
5,03111538
asked Nov 12 '18 at 18:19
Bar
223
asked Nov 12 '18 at 18:19
Bar
223
asked Nov 12 '18 at 18:19
Bar
223
223
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
No, it is not possible.
Partitioning is not "indexing". It's layout of the data on the file system (or file-system-like storage, here: s3).
What you're after would be two independent copies of the data. For this, you can simply create two tables, one with partitioning by year/month/day and second with partitioning by id.
However, assuming that id is an identifier in your table, you really do not want to partition by id. You might be interested in exploring bucketing by id, though.
answered Nov 12 '18 at 20:16
Piotr Findeisen
5,03111538
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
No, it is not possible.
Partitioning is not "indexing". It's layout of the data on the file system (or file-system-like storage, here: s3).
What you're after would be two independent copies of the data. For this, you can simply create two tables, one with partitioning by year/month/day and second with partitioning by id.
However, assuming that id is an identifier in your table, you really do not want to partition by id. You might be interested in exploring bucketing by id, though.
answered Nov 12 '18 at 20:16
Piotr Findeisen
5,03111538
add a comment |
No, it is not possible.
Partitioning is not "indexing". It's layout of the data on the file system (or file-system-like storage, here: s3).
What you're after would be two independent copies of the data. For this, you can simply create two tables, one with partitioning by year/month/day and second with partitioning by id.
However, assuming that id is an identifier in your table, you really do not want to partition by id. You might be interested in exploring bucketing by id, though.
answered Nov 12 '18 at 20:16
Piotr Findeisen
5,03111538
add a comment |
No, it is not possible.
Partitioning is not "indexing". It's layout of the data on the file system (or file-system-like storage, here: s3).
What you're after would be two independent copies of the data. For this, you can simply create two tables, one with partitioning by year/month/day and second with partitioning by id.
However, assuming that id is an identifier in your table, you really do not want to partition by id. You might be interested in exploring bucketing by id, though.
answered Nov 12 '18 at 20:16
Piotr Findeisen
5,03111538
No, it is not possible.
Partitioning is not "indexing". It's layout of the data on the file system (or file-system-like storage, here: s3).
What you're after would be two independent copies of the data. For this, you can simply create two tables, one with partitioning by year/month/day and second with partitioning by id.
However, assuming that id is an identifier in your table, you really do not want to partition by id. You might be interested in exploring bucketing by id, though.
answered Nov 12 '18 at 20:16
Piotr Findeisen
5,03111538
answered Nov 12 '18 at 20:16
Piotr Findeisen
5,03111538
answered Nov 12 '18 at 20:16
Piotr Findeisen
5,03111538
answered Nov 12 '18 at 20:16
Piotr Findeisen
5,03111538
5,03111538
add a comment |
add a comment |
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