Interpolate variable in command substitution in Makefile
I am trying to do variable interpolation inside a command substitution in a Makefile.
I have this code:
setup:
mkdir -p data_all ;
for i in $(shell jq -r 'keys | @tsv' assets.json) ; do
git_url=$(shell jq -r ".$$i" assets.json) ;
git clone $$git_url data_all/$$i ;
done
The code is failing, however, because $$i
does not expand in the "shell" line that sets git_url.
How do I interpolate the variable $i in the "shell" line that sets git_url?
makefile
add a comment |
I am trying to do variable interpolation inside a command substitution in a Makefile.
I have this code:
setup:
mkdir -p data_all ;
for i in $(shell jq -r 'keys | @tsv' assets.json) ; do
git_url=$(shell jq -r ".$$i" assets.json) ;
git clone $$git_url data_all/$$i ;
done
The code is failing, however, because $$i
does not expand in the "shell" line that sets git_url.
How do I interpolate the variable $i in the "shell" line that sets git_url?
makefile
add a comment |
I am trying to do variable interpolation inside a command substitution in a Makefile.
I have this code:
setup:
mkdir -p data_all ;
for i in $(shell jq -r 'keys | @tsv' assets.json) ; do
git_url=$(shell jq -r ".$$i" assets.json) ;
git clone $$git_url data_all/$$i ;
done
The code is failing, however, because $$i
does not expand in the "shell" line that sets git_url.
How do I interpolate the variable $i in the "shell" line that sets git_url?
makefile
I am trying to do variable interpolation inside a command substitution in a Makefile.
I have this code:
setup:
mkdir -p data_all ;
for i in $(shell jq -r 'keys | @tsv' assets.json) ; do
git_url=$(shell jq -r ".$$i" assets.json) ;
git clone $$git_url data_all/$$i ;
done
The code is failing, however, because $$i
does not expand in the "shell" line that sets git_url.
How do I interpolate the variable $i in the "shell" line that sets git_url?
makefile
makefile
asked Nov 13 '18 at 0:26
Alex HarveyAlex Harvey
3,9121823
3,9121823
add a comment |
add a comment |
1 Answer
1
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oldest
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You mixed up make functions ($(shell ...)
) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:
mkdir -p data_all ;
for i in $( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$( jq -r ".$i" assets.json ) ;
git clone $git_url data_all/$i ;
done
And then escaping the unwanted $
expansion by make:
mkdir -p data_all ;
for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$$( jq -r ".$$i" assets.json ) ;
git clone $$git_url data_all/$$i ;
done
Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
– Alex Harvey
Nov 13 '18 at 6:42
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You mixed up make functions ($(shell ...)
) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:
mkdir -p data_all ;
for i in $( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$( jq -r ".$i" assets.json ) ;
git clone $git_url data_all/$i ;
done
And then escaping the unwanted $
expansion by make:
mkdir -p data_all ;
for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$$( jq -r ".$$i" assets.json ) ;
git clone $$git_url data_all/$$i ;
done
Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
– Alex Harvey
Nov 13 '18 at 6:42
add a comment |
You mixed up make functions ($(shell ...)
) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:
mkdir -p data_all ;
for i in $( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$( jq -r ".$i" assets.json ) ;
git clone $git_url data_all/$i ;
done
And then escaping the unwanted $
expansion by make:
mkdir -p data_all ;
for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$$( jq -r ".$$i" assets.json ) ;
git clone $$git_url data_all/$$i ;
done
Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
– Alex Harvey
Nov 13 '18 at 6:42
add a comment |
You mixed up make functions ($(shell ...)
) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:
mkdir -p data_all ;
for i in $( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$( jq -r ".$i" assets.json ) ;
git clone $git_url data_all/$i ;
done
And then escaping the unwanted $
expansion by make:
mkdir -p data_all ;
for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$$( jq -r ".$$i" assets.json ) ;
git clone $$git_url data_all/$$i ;
done
You mixed up make functions ($(shell ...)
) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:
mkdir -p data_all ;
for i in $( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$( jq -r ".$i" assets.json ) ;
git clone $git_url data_all/$i ;
done
And then escaping the unwanted $
expansion by make:
mkdir -p data_all ;
for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
git_url=$$( jq -r ".$$i" assets.json ) ;
git clone $$git_url data_all/$$i ;
done
answered Nov 13 '18 at 6:32
Renaud PacaletRenaud Pacalet
9,10321729
9,10321729
Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
– Alex Harvey
Nov 13 '18 at 6:42
add a comment |
Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
– Alex Harvey
Nov 13 '18 at 6:42
Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
– Alex Harvey
Nov 13 '18 at 6:42
Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
– Alex Harvey
Nov 13 '18 at 6:42
add a comment |
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