Query name and city using u-sql











up vote
0
down vote

favorite
1












I need to filter name and city from below nested json.



[
{
"Employee": [
{
"name": "John",
"Gender": "Male"
}
],
"Info": {
"location": {
"city": "Kuvala",
"continent": "Asia",
"country": "Singapore"
}
}
},
{
"Employee": [
{
"name": "Mike",
"Gender": "Male"
}
],
"Info": {
"location": {
"city": "Dhabi",
"continent": "Asia",
"country": "Dubai"
}
}
}
]



My code




CREATE ASSEMBLY IF NOT EXISTS [Newtonsoft.Json] FROM @"/Assemblies/Newtonsoft.Json.dll";
CREATE ASSEMBLY IF NOT EXISTS [Microsoft.Analytics.Samples.Formats] FROM @"/Assemblies/Microsoft.Analytics.Samples.Formats.dll";

REFERENCE ASSEMBLY [Newtonsoft.Json];
REFERENCE ASSEMBLY [Microsoft.Analytics.Samples.Formats];

USING Microsoft.Analytics.Samples.Formats.Json;

DECLARE @InputFile string = @"/Source/example.blob";
DECLARE @output string = @"/Output/output.csv";

@json =
EXTRACT Employee String,
Info String
FROM @InputFile
USING new Microsoft.Analytics.Samples.Formats.Json.JsonExtractor("*");

@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee) AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;

@result =
SELECT EmployeeData["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;

OUTPUT @result
TO @output
USING Outputters.Csv(outputHeader : true, quoting : true);



I ma getting error saying cannot convert from 'Microsoft.Analytics.Types.Sql.SqlArray' to 'string' please help.



Please help me to get Name, City from this.
This should outputs:
John Vulala
Mike Dhabi











share|improve this question
























  • Hi, we require some effort from your side. What is your U-sql script so far? There are numerous examples on the internet if you haven't any clue at all. Start with those first.
    – Peter Bons
    Nov 11 at 11:59












  • Hi @PeterBons , I have updated with my code. I am new and not getting proper documentation from beginner to expert level. Please help me this time.
    – David
    Nov 11 at 13:33










  • Please help..,,
    – David
    Nov 11 at 20:07















up vote
0
down vote

favorite
1












I need to filter name and city from below nested json.



[
{
"Employee": [
{
"name": "John",
"Gender": "Male"
}
],
"Info": {
"location": {
"city": "Kuvala",
"continent": "Asia",
"country": "Singapore"
}
}
},
{
"Employee": [
{
"name": "Mike",
"Gender": "Male"
}
],
"Info": {
"location": {
"city": "Dhabi",
"continent": "Asia",
"country": "Dubai"
}
}
}
]



My code




CREATE ASSEMBLY IF NOT EXISTS [Newtonsoft.Json] FROM @"/Assemblies/Newtonsoft.Json.dll";
CREATE ASSEMBLY IF NOT EXISTS [Microsoft.Analytics.Samples.Formats] FROM @"/Assemblies/Microsoft.Analytics.Samples.Formats.dll";

REFERENCE ASSEMBLY [Newtonsoft.Json];
REFERENCE ASSEMBLY [Microsoft.Analytics.Samples.Formats];

USING Microsoft.Analytics.Samples.Formats.Json;

DECLARE @InputFile string = @"/Source/example.blob";
DECLARE @output string = @"/Output/output.csv";

@json =
EXTRACT Employee String,
Info String
FROM @InputFile
USING new Microsoft.Analytics.Samples.Formats.Json.JsonExtractor("*");

@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee) AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;

@result =
SELECT EmployeeData["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;

OUTPUT @result
TO @output
USING Outputters.Csv(outputHeader : true, quoting : true);



I ma getting error saying cannot convert from 'Microsoft.Analytics.Types.Sql.SqlArray' to 'string' please help.



Please help me to get Name, City from this.
This should outputs:
John Vulala
Mike Dhabi











share|improve this question
























  • Hi, we require some effort from your side. What is your U-sql script so far? There are numerous examples on the internet if you haven't any clue at all. Start with those first.
    – Peter Bons
    Nov 11 at 11:59












  • Hi @PeterBons , I have updated with my code. I am new and not getting proper documentation from beginner to expert level. Please help me this time.
    – David
    Nov 11 at 13:33










  • Please help..,,
    – David
    Nov 11 at 20:07













up vote
0
down vote

favorite
1









up vote
0
down vote

favorite
1






1





I need to filter name and city from below nested json.



[
{
"Employee": [
{
"name": "John",
"Gender": "Male"
}
],
"Info": {
"location": {
"city": "Kuvala",
"continent": "Asia",
"country": "Singapore"
}
}
},
{
"Employee": [
{
"name": "Mike",
"Gender": "Male"
}
],
"Info": {
"location": {
"city": "Dhabi",
"continent": "Asia",
"country": "Dubai"
}
}
}
]



My code




CREATE ASSEMBLY IF NOT EXISTS [Newtonsoft.Json] FROM @"/Assemblies/Newtonsoft.Json.dll";
CREATE ASSEMBLY IF NOT EXISTS [Microsoft.Analytics.Samples.Formats] FROM @"/Assemblies/Microsoft.Analytics.Samples.Formats.dll";

REFERENCE ASSEMBLY [Newtonsoft.Json];
REFERENCE ASSEMBLY [Microsoft.Analytics.Samples.Formats];

USING Microsoft.Analytics.Samples.Formats.Json;

DECLARE @InputFile string = @"/Source/example.blob";
DECLARE @output string = @"/Output/output.csv";

@json =
EXTRACT Employee String,
Info String
FROM @InputFile
USING new Microsoft.Analytics.Samples.Formats.Json.JsonExtractor("*");

@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee) AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;

@result =
SELECT EmployeeData["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;

OUTPUT @result
TO @output
USING Outputters.Csv(outputHeader : true, quoting : true);



I ma getting error saying cannot convert from 'Microsoft.Analytics.Types.Sql.SqlArray' to 'string' please help.



Please help me to get Name, City from this.
This should outputs:
John Vulala
Mike Dhabi











share|improve this question















I need to filter name and city from below nested json.



[
{
"Employee": [
{
"name": "John",
"Gender": "Male"
}
],
"Info": {
"location": {
"city": "Kuvala",
"continent": "Asia",
"country": "Singapore"
}
}
},
{
"Employee": [
{
"name": "Mike",
"Gender": "Male"
}
],
"Info": {
"location": {
"city": "Dhabi",
"continent": "Asia",
"country": "Dubai"
}
}
}
]



My code




CREATE ASSEMBLY IF NOT EXISTS [Newtonsoft.Json] FROM @"/Assemblies/Newtonsoft.Json.dll";
CREATE ASSEMBLY IF NOT EXISTS [Microsoft.Analytics.Samples.Formats] FROM @"/Assemblies/Microsoft.Analytics.Samples.Formats.dll";

REFERENCE ASSEMBLY [Newtonsoft.Json];
REFERENCE ASSEMBLY [Microsoft.Analytics.Samples.Formats];

USING Microsoft.Analytics.Samples.Formats.Json;

DECLARE @InputFile string = @"/Source/example.blob";
DECLARE @output string = @"/Output/output.csv";

@json =
EXTRACT Employee String,
Info String
FROM @InputFile
USING new Microsoft.Analytics.Samples.Formats.Json.JsonExtractor("*");

@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee) AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;

@result =
SELECT EmployeeData["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;

OUTPUT @result
TO @output
USING Outputters.Csv(outputHeader : true, quoting : true);



I ma getting error saying cannot convert from 'Microsoft.Analytics.Types.Sql.SqlArray' to 'string' please help.



Please help me to get Name, City from this.
This should outputs:
John Vulala
Mike Dhabi








azure azure-sql-database azure-data-lake u-sql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 11 at 13:40

























asked Nov 11 at 11:24









David

32




32












  • Hi, we require some effort from your side. What is your U-sql script so far? There are numerous examples on the internet if you haven't any clue at all. Start with those first.
    – Peter Bons
    Nov 11 at 11:59












  • Hi @PeterBons , I have updated with my code. I am new and not getting proper documentation from beginner to expert level. Please help me this time.
    – David
    Nov 11 at 13:33










  • Please help..,,
    – David
    Nov 11 at 20:07


















  • Hi, we require some effort from your side. What is your U-sql script so far? There are numerous examples on the internet if you haven't any clue at all. Start with those first.
    – Peter Bons
    Nov 11 at 11:59












  • Hi @PeterBons , I have updated with my code. I am new and not getting proper documentation from beginner to expert level. Please help me this time.
    – David
    Nov 11 at 13:33










  • Please help..,,
    – David
    Nov 11 at 20:07
















Hi, we require some effort from your side. What is your U-sql script so far? There are numerous examples on the internet if you haven't any clue at all. Start with those first.
– Peter Bons
Nov 11 at 11:59






Hi, we require some effort from your side. What is your U-sql script so far? There are numerous examples on the internet if you haven't any clue at all. Start with those first.
– Peter Bons
Nov 11 at 11:59














Hi @PeterBons , I have updated with my code. I am new and not getting proper documentation from beginner to expert level. Please help me this time.
– David
Nov 11 at 13:33




Hi @PeterBons , I have updated with my code. I am new and not getting proper documentation from beginner to expert level. Please help me this time.
– David
Nov 11 at 13:33












Please help..,,
– David
Nov 11 at 20:07




Please help..,,
– David
Nov 11 at 20:07












1 Answer
1






active

oldest

votes

















up vote
0
down vote













I think you are getting this error because the contents of the Employee elements is defined as an array:



"Employee": [
{
"name": "Mike",
"Gender": "Male"
}
]


Try changing the Employee elements to something like this:



"Employee": {
"name": "Mike",
"Gender": "Male"
}


Update



It seems you might need to perform JsonTuple on the array item, so this might work:



@result =
SELECT JsonFunctions.JsonTuple(EmployeeData[0])["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


One thing to note, if the Employee array might hold more than one item, you'll probably need to use Cross Apply Explode.



Update 2



Unfortunately, this is the last thing I can think of. try replacing:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee) AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;

@result =
SELECT EmployeeData["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


With this:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee).Values AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;
@result =
SELECT JsonFunctions.JsonTuple(employee)["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple
CROSS APPLY
EXPLODE(EmployeeData) AS employees(employee) ;


Hope it helps!






share|improve this answer























  • I can not change it, the data i am getting is from third party.
    – David
    Nov 12 at 8:23










  • copiler error for EmployeeData[0]["name"]: cannot convert from 'int' to 'string'
    – David
    Nov 12 at 10:33










  • i tried another way and got copiler error for EmployeeData["0"]["name"]: cannot convert from 'string' to 'int'
    – David
    Nov 12 at 10:34












  • See updated answer
    – Itay Podhajcer
    Nov 12 at 11:39










  • Still same exception : cannot convert from 'int' to 'string'
    – David
    Nov 12 at 13:28











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1 Answer
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1 Answer
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active

oldest

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active

oldest

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active

oldest

votes








up vote
0
down vote













I think you are getting this error because the contents of the Employee elements is defined as an array:



"Employee": [
{
"name": "Mike",
"Gender": "Male"
}
]


Try changing the Employee elements to something like this:



"Employee": {
"name": "Mike",
"Gender": "Male"
}


Update



It seems you might need to perform JsonTuple on the array item, so this might work:



@result =
SELECT JsonFunctions.JsonTuple(EmployeeData[0])["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


One thing to note, if the Employee array might hold more than one item, you'll probably need to use Cross Apply Explode.



Update 2



Unfortunately, this is the last thing I can think of. try replacing:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee) AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;

@result =
SELECT EmployeeData["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


With this:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee).Values AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;
@result =
SELECT JsonFunctions.JsonTuple(employee)["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple
CROSS APPLY
EXPLODE(EmployeeData) AS employees(employee) ;


Hope it helps!






share|improve this answer























  • I can not change it, the data i am getting is from third party.
    – David
    Nov 12 at 8:23










  • copiler error for EmployeeData[0]["name"]: cannot convert from 'int' to 'string'
    – David
    Nov 12 at 10:33










  • i tried another way and got copiler error for EmployeeData["0"]["name"]: cannot convert from 'string' to 'int'
    – David
    Nov 12 at 10:34












  • See updated answer
    – Itay Podhajcer
    Nov 12 at 11:39










  • Still same exception : cannot convert from 'int' to 'string'
    – David
    Nov 12 at 13:28















up vote
0
down vote













I think you are getting this error because the contents of the Employee elements is defined as an array:



"Employee": [
{
"name": "Mike",
"Gender": "Male"
}
]


Try changing the Employee elements to something like this:



"Employee": {
"name": "Mike",
"Gender": "Male"
}


Update



It seems you might need to perform JsonTuple on the array item, so this might work:



@result =
SELECT JsonFunctions.JsonTuple(EmployeeData[0])["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


One thing to note, if the Employee array might hold more than one item, you'll probably need to use Cross Apply Explode.



Update 2



Unfortunately, this is the last thing I can think of. try replacing:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee) AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;

@result =
SELECT EmployeeData["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


With this:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee).Values AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;
@result =
SELECT JsonFunctions.JsonTuple(employee)["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple
CROSS APPLY
EXPLODE(EmployeeData) AS employees(employee) ;


Hope it helps!






share|improve this answer























  • I can not change it, the data i am getting is from third party.
    – David
    Nov 12 at 8:23










  • copiler error for EmployeeData[0]["name"]: cannot convert from 'int' to 'string'
    – David
    Nov 12 at 10:33










  • i tried another way and got copiler error for EmployeeData["0"]["name"]: cannot convert from 'string' to 'int'
    – David
    Nov 12 at 10:34












  • See updated answer
    – Itay Podhajcer
    Nov 12 at 11:39










  • Still same exception : cannot convert from 'int' to 'string'
    – David
    Nov 12 at 13:28













up vote
0
down vote










up vote
0
down vote









I think you are getting this error because the contents of the Employee elements is defined as an array:



"Employee": [
{
"name": "Mike",
"Gender": "Male"
}
]


Try changing the Employee elements to something like this:



"Employee": {
"name": "Mike",
"Gender": "Male"
}


Update



It seems you might need to perform JsonTuple on the array item, so this might work:



@result =
SELECT JsonFunctions.JsonTuple(EmployeeData[0])["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


One thing to note, if the Employee array might hold more than one item, you'll probably need to use Cross Apply Explode.



Update 2



Unfortunately, this is the last thing I can think of. try replacing:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee) AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;

@result =
SELECT EmployeeData["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


With this:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee).Values AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;
@result =
SELECT JsonFunctions.JsonTuple(employee)["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple
CROSS APPLY
EXPLODE(EmployeeData) AS employees(employee) ;


Hope it helps!






share|improve this answer














I think you are getting this error because the contents of the Employee elements is defined as an array:



"Employee": [
{
"name": "Mike",
"Gender": "Male"
}
]


Try changing the Employee elements to something like this:



"Employee": {
"name": "Mike",
"Gender": "Male"
}


Update



It seems you might need to perform JsonTuple on the array item, so this might work:



@result =
SELECT JsonFunctions.JsonTuple(EmployeeData[0])["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


One thing to note, if the Employee array might hold more than one item, you'll probably need to use Cross Apply Explode.



Update 2



Unfortunately, this is the last thing I can think of. try replacing:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee) AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;

@result =
SELECT EmployeeData["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple;


With this:



@CreateJSONTuple =
SELECT JsonFunctions.JsonTuple(Employee).Values AS EmployeeData,
JsonFunctions.JsonTuple(Info) AS InfoData
FROM @json;
@result =
SELECT JsonFunctions.JsonTuple(employee)["name"] AS Name,
JsonFunctions.JsonTuple(InfoData, "location") AS LocationData
FROM @CreateJSONTuple
CROSS APPLY
EXPLODE(EmployeeData) AS employees(employee) ;


Hope it helps!







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 12 at 13:47

























answered Nov 12 at 7:08









Itay Podhajcer

1,117312




1,117312












  • I can not change it, the data i am getting is from third party.
    – David
    Nov 12 at 8:23










  • copiler error for EmployeeData[0]["name"]: cannot convert from 'int' to 'string'
    – David
    Nov 12 at 10:33










  • i tried another way and got copiler error for EmployeeData["0"]["name"]: cannot convert from 'string' to 'int'
    – David
    Nov 12 at 10:34












  • See updated answer
    – Itay Podhajcer
    Nov 12 at 11:39










  • Still same exception : cannot convert from 'int' to 'string'
    – David
    Nov 12 at 13:28


















  • I can not change it, the data i am getting is from third party.
    – David
    Nov 12 at 8:23










  • copiler error for EmployeeData[0]["name"]: cannot convert from 'int' to 'string'
    – David
    Nov 12 at 10:33










  • i tried another way and got copiler error for EmployeeData["0"]["name"]: cannot convert from 'string' to 'int'
    – David
    Nov 12 at 10:34












  • See updated answer
    – Itay Podhajcer
    Nov 12 at 11:39










  • Still same exception : cannot convert from 'int' to 'string'
    – David
    Nov 12 at 13:28
















I can not change it, the data i am getting is from third party.
– David
Nov 12 at 8:23




I can not change it, the data i am getting is from third party.
– David
Nov 12 at 8:23












copiler error for EmployeeData[0]["name"]: cannot convert from 'int' to 'string'
– David
Nov 12 at 10:33




copiler error for EmployeeData[0]["name"]: cannot convert from 'int' to 'string'
– David
Nov 12 at 10:33












i tried another way and got copiler error for EmployeeData["0"]["name"]: cannot convert from 'string' to 'int'
– David
Nov 12 at 10:34






i tried another way and got copiler error for EmployeeData["0"]["name"]: cannot convert from 'string' to 'int'
– David
Nov 12 at 10:34














See updated answer
– Itay Podhajcer
Nov 12 at 11:39




See updated answer
– Itay Podhajcer
Nov 12 at 11:39












Still same exception : cannot convert from 'int' to 'string'
– David
Nov 12 at 13:28




Still same exception : cannot convert from 'int' to 'string'
– David
Nov 12 at 13:28


















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