Python error [WinError 123] (File name, directory name or volume label syntax incorrect) when using __file_

Python error [WinError 123] (File name, directory name or volume label syntax incorrect) when using file

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I've been writing a program which writes to text files in the directory it's placed in. So, to find the path to the directory it is placed in, I used this statement:

currentpath = os.path.dirname(__file__)

But whenever I call the program outside of Idle it gives the error:

OSError: [WinError 123] The filename, directory name or volume label syntax is incorrect

I have no idea why this is happening, and even less why it happens outside of Idle and not inside.

So please can someone help because I have little hope of solving this on my own.

Oh, and PS. The name of the file is "File sprayer.py" and the directory name is "File sprayer test". I'm not sure if that helps.

asked Nov 11 at 11:25

EMarshall

135

What do you mean by "outside of Idle"?
– leeym
Nov 11 at 11:48

I mean when I run from the command line or from double-clicking in Windows Explorer rather than using the Run>Run Module feature of Idle.
– EMarshall
Nov 11 at 17:31

add a comment |

up vote
2
down vote

favorite

I've been writing a program which writes to text files in the directory it's placed in. So, to find the path to the directory it is placed in, I used this statement:

currentpath = os.path.dirname(__file__)

But whenever I call the program outside of Idle it gives the error:

OSError: [WinError 123] The filename, directory name or volume label syntax is incorrect

I have no idea why this is happening, and even less why it happens outside of Idle and not inside.

So please can someone help because I have little hope of solving this on my own.

Oh, and PS. The name of the file is "File sprayer.py" and the directory name is "File sprayer test". I'm not sure if that helps.

asked Nov 11 at 11:25

EMarshall

135

What do you mean by "outside of Idle"?
– leeym
Nov 11 at 11:48

I mean when I run from the command line or from double-clicking in Windows Explorer rather than using the Run>Run Module feature of Idle.
– EMarshall
Nov 11 at 17:31

add a comment |

up vote
2
down vote

favorite

I've been writing a program which writes to text files in the directory it's placed in. So, to find the path to the directory it is placed in, I used this statement:

currentpath = os.path.dirname(__file__)

But whenever I call the program outside of Idle it gives the error:

OSError: [WinError 123] The filename, directory name or volume label syntax is incorrect

I have no idea why this is happening, and even less why it happens outside of Idle and not inside.

So please can someone help because I have little hope of solving this on my own.

Oh, and PS. The name of the file is "File sprayer.py" and the directory name is "File sprayer test". I'm not sure if that helps.

asked Nov 11 at 11:25

EMarshall

135

I've been writing a program which writes to text files in the directory it's placed in. So, to find the path to the directory it is placed in, I used this statement:

currentpath = os.path.dirname(__file__)

But whenever I call the program outside of Idle it gives the error:

OSError: [WinError 123] The filename, directory name or volume label syntax is incorrect

I have no idea why this is happening, and even less why it happens outside of Idle and not inside.

So please can someone help because I have little hope of solving this on my own.

Oh, and PS. The name of the file is "File sprayer.py" and the directory name is "File sprayer test". I'm not sure if that helps.

python

asked Nov 11 at 11:25

EMarshall

135

asked Nov 11 at 11:25

EMarshall

135

asked Nov 11 at 11:25

EMarshall

135

asked Nov 11 at 11:25

EMarshall

135

asked Nov 11 at 11:25

EMarshall

135

What do you mean by "outside of Idle"?
– leeym
Nov 11 at 11:48

I mean when I run from the command line or from double-clicking in Windows Explorer rather than using the Run>Run Module feature of Idle.
– EMarshall
Nov 11 at 17:31

add a comment |

What do you mean by "outside of Idle"?
– leeym
Nov 11 at 11:48

I mean when I run from the command line or from double-clicking in Windows Explorer rather than using the Run>Run Module feature of Idle.
– EMarshall
Nov 11 at 17:31

What do you mean by "outside of Idle"?
– leeym
Nov 11 at 11:48

I mean when I run from the command line or from double-clicking in Windows Explorer rather than using the Run>Run Module feature of Idle.
– EMarshall
Nov 11 at 17:31

add a comment |

1 Answer
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0
down vote

accepted

Perhaps try this?

currentpath = os.path.dirname(os.path.abspath(__file__))

answered Nov 11 at 11:50

leeym

3121213

Thank you so much, you're a life saver
– EMarshall
Nov 11 at 17:34

add a comment |

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1 Answer
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active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
0
down vote

accepted

Perhaps try this?

currentpath = os.path.dirname(os.path.abspath(__file__))

answered Nov 11 at 11:50

leeym

3121213

Thank you so much, you're a life saver
– EMarshall
Nov 11 at 17:34

add a comment |

up vote
0
down vote

accepted

Perhaps try this?

currentpath = os.path.dirname(os.path.abspath(__file__))

answered Nov 11 at 11:50

leeym

3121213

Thank you so much, you're a life saver
– EMarshall
Nov 11 at 17:34

add a comment |

up vote
0
down vote

accepted

Perhaps try this?

currentpath = os.path.dirname(os.path.abspath(__file__))

answered Nov 11 at 11:50

leeym

3121213

Perhaps try this?

currentpath = os.path.dirname(os.path.abspath(__file__))

answered Nov 11 at 11:50

leeym

3121213

answered Nov 11 at 11:50

leeym

3121213

answered Nov 11 at 11:50

leeym

3121213

answered Nov 11 at 11:50

leeym

3121213

Thank you so much, you're a life saver
– EMarshall
Nov 11 at 17:34

add a comment |

Thank you so much, you're a life saver
– EMarshall
Nov 11 at 17:34

Thank you so much, you're a life saver
– EMarshall
Nov 11 at 17:34

add a comment |

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