Iterate through JSON array: Get name of the parameter
I'm iterating through my JSON response. I've got HTML elements with id's as the parameter names.
For example, my JSON response contains a "costcenter":"1234", and there's a <span> element with the id costcenter.
Now, instead of writing a statement for every id, I thought I could iterate through the JSON array, and automatically read its name.
This is what I got
$(".dataset").click(function() {
changeid = this.id;
$.ajax({
url: "source",
dataType: "json",
contentType: "application/json; charset=utf-8",
data: {
id: changeid
},
success: function(data) {
// How to get the name of the parameter, and then read it's value?
}
})
})
The JSON looks like that, it's just one dimension and 1 result set only:
{"changeid":"1","costcenter":"478","manager":"John Smith"}
jquery json loops
edited Nov 12 at 5:48
Cœur
17.4k9102143
asked Jun 27 '12 at 18:22
Ahatius
2,203104067
add a comment |
I'm iterating through my JSON response. I've got HTML elements with id's as the parameter names.
For example, my JSON response contains a "costcenter":"1234", and there's a <span> element with the id costcenter.
Now, instead of writing a statement for every id, I thought I could iterate through the JSON array, and automatically read its name.
This is what I got
$(".dataset").click(function() {
changeid = this.id;
$.ajax({
url: "source",
dataType: "json",
contentType: "application/json; charset=utf-8",
data: {
id: changeid
},
success: function(data) {
// How to get the name of the parameter, and then read it's value?
}
})
})
The JSON looks like that, it's just one dimension and 1 result set only:
{"changeid":"1","costcenter":"478","manager":"John Smith"}
jquery json loops
edited Nov 12 at 5:48
Cœur
17.4k9102143
asked Jun 27 '12 at 18:22
Ahatius
2,203104067
your code isn't inspecting each .dataset element
– cristi _b
Jun 27 '12 at 18:24
@cristi_b Why do you think?
– Ahatius
Jun 27 '12 at 18:27
add a comment |
I'm iterating through my JSON response. I've got HTML elements with id's as the parameter names.
For example, my JSON response contains a "costcenter":"1234", and there's a <span> element with the id costcenter.
Now, instead of writing a statement for every id, I thought I could iterate through the JSON array, and automatically read its name.
This is what I got
$(".dataset").click(function() {
changeid = this.id;
$.ajax({
url: "source",
dataType: "json",
contentType: "application/json; charset=utf-8",
data: {
id: changeid
},
success: function(data) {
// How to get the name of the parameter, and then read it's value?
}
})
})
The JSON looks like that, it's just one dimension and 1 result set only:
{"changeid":"1","costcenter":"478","manager":"John Smith"}
jquery json loops
edited Nov 12 at 5:48
Cœur
17.4k9102143
asked Jun 27 '12 at 18:22
Ahatius
2,203104067
I'm iterating through my JSON response. I've got HTML elements with id's as the parameter names.
For example, my JSON response contains a "costcenter":"1234", and there's a <span> element with the id costcenter.
Now, instead of writing a statement for every id, I thought I could iterate through the JSON array, and automatically read its name.
This is what I got
$(".dataset").click(function() {
changeid = this.id;
$.ajax({
url: "source",
dataType: "json",
contentType: "application/json; charset=utf-8",
data: {
id: changeid
},
success: function(data) {
// How to get the name of the parameter, and then read it's value?
}
})
})
The JSON looks like that, it's just one dimension and 1 result set only:
{"changeid":"1","costcenter":"478","manager":"John Smith"}
jquery json loops
jquery json loops
edited Nov 12 at 5:48
Cœur
17.4k9102143
asked Jun 27 '12 at 18:22
Ahatius
2,203104067
edited Nov 12 at 5:48
Cœur
17.4k9102143
asked Jun 27 '12 at 18:22
Ahatius
2,203104067
edited Nov 12 at 5:48
Cœur
17.4k9102143
edited Nov 12 at 5:48
Cœur
17.4k9102143
edited Nov 12 at 5:48
Cœur
17.4k9102143
17.4k9102143
asked Jun 27 '12 at 18:22
Ahatius
2,203104067
asked Jun 27 '12 at 18:22
Ahatius
2,203104067
asked Jun 27 '12 at 18:22
Ahatius
2,203104067
2,203104067
your code isn't inspecting each .dataset element
– cristi _b
Jun 27 '12 at 18:24
@cristi_b Why do you think?
– Ahatius
Jun 27 '12 at 18:27
add a comment |
your code isn't inspecting each .dataset element
– cristi _b
Jun 27 '12 at 18:24
@cristi_b Why do you think?
– Ahatius
Jun 27 '12 at 18:27
your code isn't inspecting each .dataset element
– cristi _b
Jun 27 '12 at 18:24
your code isn't inspecting each .dataset element
– cristi _b
Jun 27 '12 at 18:24
@cristi_b Why do you think?
– Ahatius
Jun 27 '12 at 18:27
@cristi_b Why do you think?
– Ahatius
Jun 27 '12 at 18:27
add a comment |
1 Answer
1
active
oldest
votes
If I understand your question you want something like that in your success function :
for (var key in data) {
$('#'+key).html(data[key]);
}
answered Jun 27 '12 at 18:24
Denys Séguret
273k52576593
Yes, you got it right. Works like a charme!
– Ahatius
Jun 27 '12 at 18:27
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If I understand your question you want something like that in your success function :
for (var key in data) {
$('#'+key).html(data[key]);
}
answered Jun 27 '12 at 18:24
Denys Séguret
273k52576593
Yes, you got it right. Works like a charme!
– Ahatius
Jun 27 '12 at 18:27
add a comment |
If I understand your question you want something like that in your success function :
for (var key in data) {
$('#'+key).html(data[key]);
}
answered Jun 27 '12 at 18:24
Denys Séguret
273k52576593
Yes, you got it right. Works like a charme!
– Ahatius
Jun 27 '12 at 18:27
add a comment |
If I understand your question you want something like that in your success function :
for (var key in data) {
$('#'+key).html(data[key]);
}
answered Jun 27 '12 at 18:24
Denys Séguret
273k52576593
If I understand your question you want something like that in your success function :
for (var key in data) {
$('#'+key).html(data[key]);
}
answered Jun 27 '12 at 18:24
Denys Séguret
273k52576593
answered Jun 27 '12 at 18:24
Denys Séguret
273k52576593
answered Jun 27 '12 at 18:24
Denys Séguret
273k52576593
answered Jun 27 '12 at 18:24
Denys Séguret
273k52576593
273k52576593
Yes, you got it right. Works like a charme!
– Ahatius
Jun 27 '12 at 18:27
add a comment |
Yes, you got it right. Works like a charme!
– Ahatius
Jun 27 '12 at 18:27
Yes, you got it right. Works like a charme!
– Ahatius
Jun 27 '12 at 18:27
Yes, you got it right. Works like a charme!
– Ahatius
Jun 27 '12 at 18:27
add a comment |
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your code isn't inspecting each .dataset element
– cristi _b
Jun 27 '12 at 18:24
@cristi_b Why do you think?
– Ahatius
Jun 27 '12 at 18:27