Dynamic groupingBy keyselector in Kotlin











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I would like to pass a dynamic keySelector to my groupingBy function. Is this possible?



   private fun hasNumberOfIdenticalValues(hand: ArrayList<Card>, values: ArrayList<String>, limit: Int) : Boolean {
var numberOfOccurrences : Map<String, Int> = hashMapOf()

for(value in values) {
numberOfOccurrences = hand.groupingBy{it.suit}.eachCount()
}

return true
}









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    up vote
    0
    down vote

    favorite












    I would like to pass a dynamic keySelector to my groupingBy function. Is this possible?



       private fun hasNumberOfIdenticalValues(hand: ArrayList<Card>, values: ArrayList<String>, limit: Int) : Boolean {
    var numberOfOccurrences : Map<String, Int> = hashMapOf()

    for(value in values) {
    numberOfOccurrences = hand.groupingBy{it.suit}.eachCount()
    }

    return true
    }









    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I would like to pass a dynamic keySelector to my groupingBy function. Is this possible?



         private fun hasNumberOfIdenticalValues(hand: ArrayList<Card>, values: ArrayList<String>, limit: Int) : Boolean {
      var numberOfOccurrences : Map<String, Int> = hashMapOf()

      for(value in values) {
      numberOfOccurrences = hand.groupingBy{it.suit}.eachCount()
      }

      return true
      }









      share|improve this question













      I would like to pass a dynamic keySelector to my groupingBy function. Is this possible?



         private fun hasNumberOfIdenticalValues(hand: ArrayList<Card>, values: ArrayList<String>, limit: Int) : Boolean {
      var numberOfOccurrences : Map<String, Int> = hashMapOf()

      for(value in values) {
      numberOfOccurrences = hand.groupingBy{it.suit}.eachCount()
      }

      return true
      }






      java kotlin






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      asked Nov 10 at 19:28









      Paul Mcloughlin

      1,2782917




      1,2782917
























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          You can, you just need to return the string that will classify the interation. For instance, to separete the cards by color of the suit:



          fun Card.color(): String {     
          return if(listof("diamonds","hearts").contains(this.suit))
          "red"
          else
          "black"
          }

          for(value in values) {
          numberOfOccurrences = hand.groupingBy{it.color()}.eachCount()
          }





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            up vote
            0
            down vote













            You can, you just need to return the string that will classify the interation. For instance, to separete the cards by color of the suit:



            fun Card.color(): String {     
            return if(listof("diamonds","hearts").contains(this.suit))
            "red"
            else
            "black"
            }

            for(value in values) {
            numberOfOccurrences = hand.groupingBy{it.color()}.eachCount()
            }





            share|improve this answer

























              up vote
              0
              down vote













              You can, you just need to return the string that will classify the interation. For instance, to separete the cards by color of the suit:



              fun Card.color(): String {     
              return if(listof("diamonds","hearts").contains(this.suit))
              "red"
              else
              "black"
              }

              for(value in values) {
              numberOfOccurrences = hand.groupingBy{it.color()}.eachCount()
              }





              share|improve this answer























                up vote
                0
                down vote










                up vote
                0
                down vote









                You can, you just need to return the string that will classify the interation. For instance, to separete the cards by color of the suit:



                fun Card.color(): String {     
                return if(listof("diamonds","hearts").contains(this.suit))
                "red"
                else
                "black"
                }

                for(value in values) {
                numberOfOccurrences = hand.groupingBy{it.color()}.eachCount()
                }





                share|improve this answer












                You can, you just need to return the string that will classify the interation. For instance, to separete the cards by color of the suit:



                fun Card.color(): String {     
                return if(listof("diamonds","hearts").contains(this.suit))
                "red"
                else
                "black"
                }

                for(value in values) {
                numberOfOccurrences = hand.groupingBy{it.color()}.eachCount()
                }






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 10 at 20:08









                Raphael

                1,30511020




                1,30511020






























                     

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