Add values of two different php arrays











up vote
0
down vote

favorite












My question is about how to add the values from two different arrays, that each have 20 records.



$array1



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 220
[type] => 0
)


[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 70
[type] => 0
)


$array2



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 280
[type] => 0
)

[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 30
[type] => 0
)


I would like to get a third array like that (adding the values of $array1 and $array2):



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 500
[type] => 0
)

[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 100
[type] => 0
)


How do I do this? All operations I've tried only added the values one after another (new array with 40 rows), not adding them.



EDIT SOLUTION



$array3 = array();
for ($i = 0; $i < count($array2); $i++) {
array_push($array3, $array1[$i]->num_rows + $array2[$i]->num_rows);
}









share|improve this question
























  • Looks like your trying to add the count of rows in two SQL queries.
    – Nigel Ren
    Nov 10 at 18:54












  • 70 + 30 = 100 not 1000
    – Madhur Bhaiya
    Nov 10 at 18:54






  • 4




    Better to do this in MySQL than PHP
    – symlink
    Nov 10 at 18:57






  • 1




    This is XY problem. Somewhere else something is incorrect.
    – u_mulder
    Nov 10 at 19:03















up vote
0
down vote

favorite












My question is about how to add the values from two different arrays, that each have 20 records.



$array1



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 220
[type] => 0
)


[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 70
[type] => 0
)


$array2



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 280
[type] => 0
)

[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 30
[type] => 0
)


I would like to get a third array like that (adding the values of $array1 and $array2):



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 500
[type] => 0
)

[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 100
[type] => 0
)


How do I do this? All operations I've tried only added the values one after another (new array with 40 rows), not adding them.



EDIT SOLUTION



$array3 = array();
for ($i = 0; $i < count($array2); $i++) {
array_push($array3, $array1[$i]->num_rows + $array2[$i]->num_rows);
}









share|improve this question
























  • Looks like your trying to add the count of rows in two SQL queries.
    – Nigel Ren
    Nov 10 at 18:54












  • 70 + 30 = 100 not 1000
    – Madhur Bhaiya
    Nov 10 at 18:54






  • 4




    Better to do this in MySQL than PHP
    – symlink
    Nov 10 at 18:57






  • 1




    This is XY problem. Somewhere else something is incorrect.
    – u_mulder
    Nov 10 at 19:03













up vote
0
down vote

favorite









up vote
0
down vote

favorite











My question is about how to add the values from two different arrays, that each have 20 records.



$array1



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 220
[type] => 0
)


[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 70
[type] => 0
)


$array2



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 280
[type] => 0
)

[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 30
[type] => 0
)


I would like to get a third array like that (adding the values of $array1 and $array2):



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 500
[type] => 0
)

[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 100
[type] => 0
)


How do I do this? All operations I've tried only added the values one after another (new array with 40 rows), not adding them.



EDIT SOLUTION



$array3 = array();
for ($i = 0; $i < count($array2); $i++) {
array_push($array3, $array1[$i]->num_rows + $array2[$i]->num_rows);
}









share|improve this question















My question is about how to add the values from two different arrays, that each have 20 records.



$array1



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 220
[type] => 0
)


[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 70
[type] => 0
)


$array2



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 280
[type] => 0
)

[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 30
[type] => 0
)


I would like to get a third array like that (adding the values of $array1 and $array2):



Array
(
[0] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 500
[type] => 0
)

[1] => mysqli_result Object
(
[current_field] => 0
[field_count] => 1
[lengths] =>
[num_rows] => 100
[type] => 0
)


How do I do this? All operations I've tried only added the values one after another (new array with 40 rows), not adding them.



EDIT SOLUTION



$array3 = array();
for ($i = 0; $i < count($array2); $i++) {
array_push($array3, $array1[$i]->num_rows + $array2[$i]->num_rows);
}






php arrays






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 10 at 19:45

























asked Nov 10 at 18:53









Lama222

82




82












  • Looks like your trying to add the count of rows in two SQL queries.
    – Nigel Ren
    Nov 10 at 18:54












  • 70 + 30 = 100 not 1000
    – Madhur Bhaiya
    Nov 10 at 18:54






  • 4




    Better to do this in MySQL than PHP
    – symlink
    Nov 10 at 18:57






  • 1




    This is XY problem. Somewhere else something is incorrect.
    – u_mulder
    Nov 10 at 19:03


















  • Looks like your trying to add the count of rows in two SQL queries.
    – Nigel Ren
    Nov 10 at 18:54












  • 70 + 30 = 100 not 1000
    – Madhur Bhaiya
    Nov 10 at 18:54






  • 4




    Better to do this in MySQL than PHP
    – symlink
    Nov 10 at 18:57






  • 1




    This is XY problem. Somewhere else something is incorrect.
    – u_mulder
    Nov 10 at 19:03
















Looks like your trying to add the count of rows in two SQL queries.
– Nigel Ren
Nov 10 at 18:54






Looks like your trying to add the count of rows in two SQL queries.
– Nigel Ren
Nov 10 at 18:54














70 + 30 = 100 not 1000
– Madhur Bhaiya
Nov 10 at 18:54




70 + 30 = 100 not 1000
– Madhur Bhaiya
Nov 10 at 18:54




4




4




Better to do this in MySQL than PHP
– symlink
Nov 10 at 18:57




Better to do this in MySQL than PHP
– symlink
Nov 10 at 18:57




1




1




This is XY problem. Somewhere else something is incorrect.
– u_mulder
Nov 10 at 19:03




This is XY problem. Somewhere else something is incorrect.
– u_mulder
Nov 10 at 19:03












3 Answers
3






active

oldest

votes

















up vote
0
down vote



accepted










One possible way to do that could be using a for loop and use the index of the arrays to add the num_rows of $array1 to $array2:



for ($i = 0; $i < count($array1); $i++) {
$array2[$i]->num_rows += $array1[$i]->num_rows;
}





share|improve this answer





















  • this way the values stayed the same
    – Lama222
    Nov 10 at 19:38










  • @Lama222 Did you run a print_r($array2); For example lik 3v4l.org/J8LJd
    – The fourth bird
    Nov 10 at 19:39








  • 1




    Thanks, got it working with your solution
    – Lama222
    Nov 10 at 19:44


















up vote
0
down vote













if you want to add every single value of an array($array1) to another array($array3) you need to take a foreach like this :



foreach($array1 as $array) {
$array3 = $array;
}





share|improve this answer




























    up vote
    0
    down vote













    Try



    $resultArray = array_merge($array1,$array2);





    share|improve this answer





















    • this way the values of the second array add to the first, giving 40 records instead of 20, and the values are not additioned
      – Lama222
      Nov 10 at 19:37










    • This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
      – Stephen C
      Nov 11 at 7:02











    Your Answer






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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote



    accepted










    One possible way to do that could be using a for loop and use the index of the arrays to add the num_rows of $array1 to $array2:



    for ($i = 0; $i < count($array1); $i++) {
    $array2[$i]->num_rows += $array1[$i]->num_rows;
    }





    share|improve this answer





















    • this way the values stayed the same
      – Lama222
      Nov 10 at 19:38










    • @Lama222 Did you run a print_r($array2); For example lik 3v4l.org/J8LJd
      – The fourth bird
      Nov 10 at 19:39








    • 1




      Thanks, got it working with your solution
      – Lama222
      Nov 10 at 19:44















    up vote
    0
    down vote



    accepted










    One possible way to do that could be using a for loop and use the index of the arrays to add the num_rows of $array1 to $array2:



    for ($i = 0; $i < count($array1); $i++) {
    $array2[$i]->num_rows += $array1[$i]->num_rows;
    }





    share|improve this answer





















    • this way the values stayed the same
      – Lama222
      Nov 10 at 19:38










    • @Lama222 Did you run a print_r($array2); For example lik 3v4l.org/J8LJd
      – The fourth bird
      Nov 10 at 19:39








    • 1




      Thanks, got it working with your solution
      – Lama222
      Nov 10 at 19:44













    up vote
    0
    down vote



    accepted







    up vote
    0
    down vote



    accepted






    One possible way to do that could be using a for loop and use the index of the arrays to add the num_rows of $array1 to $array2:



    for ($i = 0; $i < count($array1); $i++) {
    $array2[$i]->num_rows += $array1[$i]->num_rows;
    }





    share|improve this answer












    One possible way to do that could be using a for loop and use the index of the arrays to add the num_rows of $array1 to $array2:



    for ($i = 0; $i < count($array1); $i++) {
    $array2[$i]->num_rows += $array1[$i]->num_rows;
    }






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 10 at 19:16









    The fourth bird

    18.2k71323




    18.2k71323












    • this way the values stayed the same
      – Lama222
      Nov 10 at 19:38










    • @Lama222 Did you run a print_r($array2); For example lik 3v4l.org/J8LJd
      – The fourth bird
      Nov 10 at 19:39








    • 1




      Thanks, got it working with your solution
      – Lama222
      Nov 10 at 19:44


















    • this way the values stayed the same
      – Lama222
      Nov 10 at 19:38










    • @Lama222 Did you run a print_r($array2); For example lik 3v4l.org/J8LJd
      – The fourth bird
      Nov 10 at 19:39








    • 1




      Thanks, got it working with your solution
      – Lama222
      Nov 10 at 19:44
















    this way the values stayed the same
    – Lama222
    Nov 10 at 19:38




    this way the values stayed the same
    – Lama222
    Nov 10 at 19:38












    @Lama222 Did you run a print_r($array2); For example lik 3v4l.org/J8LJd
    – The fourth bird
    Nov 10 at 19:39






    @Lama222 Did you run a print_r($array2); For example lik 3v4l.org/J8LJd
    – The fourth bird
    Nov 10 at 19:39






    1




    1




    Thanks, got it working with your solution
    – Lama222
    Nov 10 at 19:44




    Thanks, got it working with your solution
    – Lama222
    Nov 10 at 19:44












    up vote
    0
    down vote













    if you want to add every single value of an array($array1) to another array($array3) you need to take a foreach like this :



    foreach($array1 as $array) {
    $array3 = $array;
    }





    share|improve this answer

























      up vote
      0
      down vote













      if you want to add every single value of an array($array1) to another array($array3) you need to take a foreach like this :



      foreach($array1 as $array) {
      $array3 = $array;
      }





      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        if you want to add every single value of an array($array1) to another array($array3) you need to take a foreach like this :



        foreach($array1 as $array) {
        $array3 = $array;
        }





        share|improve this answer












        if you want to add every single value of an array($array1) to another array($array3) you need to take a foreach like this :



        foreach($array1 as $array) {
        $array3 = $array;
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 10 at 18:59









        k-kaufmann

        1




        1






















            up vote
            0
            down vote













            Try



            $resultArray = array_merge($array1,$array2);





            share|improve this answer





















            • this way the values of the second array add to the first, giving 40 records instead of 20, and the values are not additioned
              – Lama222
              Nov 10 at 19:37










            • This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
              – Stephen C
              Nov 11 at 7:02















            up vote
            0
            down vote













            Try



            $resultArray = array_merge($array1,$array2);





            share|improve this answer





















            • this way the values of the second array add to the first, giving 40 records instead of 20, and the values are not additioned
              – Lama222
              Nov 10 at 19:37










            • This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
              – Stephen C
              Nov 11 at 7:02













            up vote
            0
            down vote










            up vote
            0
            down vote









            Try



            $resultArray = array_merge($array1,$array2);





            share|improve this answer












            Try



            $resultArray = array_merge($array1,$array2);






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 10 at 19:19









            doron

            1




            1












            • this way the values of the second array add to the first, giving 40 records instead of 20, and the values are not additioned
              – Lama222
              Nov 10 at 19:37










            • This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
              – Stephen C
              Nov 11 at 7:02


















            • this way the values of the second array add to the first, giving 40 records instead of 20, and the values are not additioned
              – Lama222
              Nov 10 at 19:37










            • This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
              – Stephen C
              Nov 11 at 7:02
















            this way the values of the second array add to the first, giving 40 records instead of 20, and the values are not additioned
            – Lama222
            Nov 10 at 19:37




            this way the values of the second array add to the first, giving 40 records instead of 20, and the values are not additioned
            – Lama222
            Nov 10 at 19:37












            This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
            – Stephen C
            Nov 11 at 7:02




            This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
            – Stephen C
            Nov 11 at 7:02


















             

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