Unrecognized request: { _request: evaluate } in visual studio code
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This is my java code on visual studio code when I try to run it on visual studio code and enter a number it says: Unrecognized request: { _request: evaluate } ...
What should I do to disappear this message when I use visual studio code?
import java.util.Scanner;
public class Test{
public static void main(String args){
System.out.println("Hello");
Scanner sc = new Scanner(System.in);
System.out.print("input number : ");
int number = sc.nextInt();
System.out.println(number);
int result = (number >= 0) ? number : -number ;
System.out.println(result);
sc.close();
}
}
java visual-studio-code
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This is my java code on visual studio code when I try to run it on visual studio code and enter a number it says: Unrecognized request: { _request: evaluate } ...
What should I do to disappear this message when I use visual studio code?
import java.util.Scanner;
public class Test{
public static void main(String args){
System.out.println("Hello");
Scanner sc = new Scanner(System.in);
System.out.print("input number : ");
int number = sc.nextInt();
System.out.println(number);
int result = (number >= 0) ? number : -number ;
System.out.println(result);
sc.close();
}
}
java visual-studio-code
add a comment |
This is my java code on visual studio code when I try to run it on visual studio code and enter a number it says: Unrecognized request: { _request: evaluate } ...
What should I do to disappear this message when I use visual studio code?
import java.util.Scanner;
public class Test{
public static void main(String args){
System.out.println("Hello");
Scanner sc = new Scanner(System.in);
System.out.print("input number : ");
int number = sc.nextInt();
System.out.println(number);
int result = (number >= 0) ? number : -number ;
System.out.println(result);
sc.close();
}
}
java visual-studio-code
This is my java code on visual studio code when I try to run it on visual studio code and enter a number it says: Unrecognized request: { _request: evaluate } ...
What should I do to disappear this message when I use visual studio code?
import java.util.Scanner;
public class Test{
public static void main(String args){
System.out.println("Hello");
Scanner sc = new Scanner(System.in);
System.out.print("input number : ");
int number = sc.nextInt();
System.out.println(number);
int result = (number >= 0) ? number : -number ;
System.out.println(result);
sc.close();
}
}
java visual-studio-code
java visual-studio-code
asked Sep 27 '18 at 8:09
Mcnamara_JohnMcnamara_John
1113
1113
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1 Answer
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According to the VSCode Java Debugging Doc you have to use a terminal as console like the integrated Terminal instead of the internal console.
The default Debug Console in VS Code doesn't support inputs. If your program need inputs from a terminal , you can use the Integrated Terminal (Ctrl+`) within VS Code or an external terminal to launch it.
You also can set the console property in your launch.json to integratedTerminal or externalTerminal, so you will use it every debug session.
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
According to the VSCode Java Debugging Doc you have to use a terminal as console like the integrated Terminal instead of the internal console.
The default Debug Console in VS Code doesn't support inputs. If your program need inputs from a terminal , you can use the Integrated Terminal (Ctrl+`) within VS Code or an external terminal to launch it.
You also can set the console property in your launch.json to integratedTerminal or externalTerminal, so you will use it every debug session.
add a comment |
According to the VSCode Java Debugging Doc you have to use a terminal as console like the integrated Terminal instead of the internal console.
The default Debug Console in VS Code doesn't support inputs. If your program need inputs from a terminal , you can use the Integrated Terminal (Ctrl+`) within VS Code or an external terminal to launch it.
You also can set the console property in your launch.json to integratedTerminal or externalTerminal, so you will use it every debug session.
add a comment |
According to the VSCode Java Debugging Doc you have to use a terminal as console like the integrated Terminal instead of the internal console.
The default Debug Console in VS Code doesn't support inputs. If your program need inputs from a terminal , you can use the Integrated Terminal (Ctrl+`) within VS Code or an external terminal to launch it.
You also can set the console property in your launch.json to integratedTerminal or externalTerminal, so you will use it every debug session.
According to the VSCode Java Debugging Doc you have to use a terminal as console like the integrated Terminal instead of the internal console.
The default Debug Console in VS Code doesn't support inputs. If your program need inputs from a terminal , you can use the Integrated Terminal (Ctrl+`) within VS Code or an external terminal to launch it.
You also can set the console property in your launch.json to integratedTerminal or externalTerminal, so you will use it every debug session.
answered Sep 28 '18 at 14:46
BimpfiBimpfi
411
411
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