Compare if one tuple is greater when mixing `str` and `None` types in Python
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1
I have two lists of tuples that have a mix of str and None types and need to compare them considering None to be greater.
a = tuple([None, 4])
b = tuple(['pencil', 12])
a > b
Results in:
TypeError: '>' not supported between instances of 'NoneType' and 'str'
How can I compare these items without getting that error?
python tuples comparison
asked Nov 16 '18 at 16:56
ZevZev
2,25111227
add a comment |
1
I have two lists of tuples that have a mix of str and None types and need to compare them considering None to be greater.
a = tuple([None, 4])
b = tuple(['pencil', 12])
a > b
Results in:
TypeError: '>' not supported between instances of 'NoneType' and 'str'
How can I compare these items without getting that error?
python tuples comparison
asked Nov 16 '18 at 16:56
ZevZev
2,25111227
add a comment |
1
1
1
I have two lists of tuples that have a mix of str and None types and need to compare them considering None to be greater.
a = tuple([None, 4])
b = tuple(['pencil', 12])
a > b
Results in:
TypeError: '>' not supported between instances of 'NoneType' and 'str'
How can I compare these items without getting that error?
python tuples comparison
asked Nov 16 '18 at 16:56
ZevZev
2,25111227
I have two lists of tuples that have a mix of str and None types and need to compare them considering None to be greater.
a = tuple([None, 4])
b = tuple(['pencil', 12])
a > b
Results in:
TypeError: '>' not supported between instances of 'NoneType' and 'str'
How can I compare these items without getting that error?
python tuples comparison
python tuples comparison
asked Nov 16 '18 at 16:56
ZevZev
2,25111227
asked Nov 16 '18 at 16:56
ZevZev
2,25111227
asked Nov 16 '18 at 16:56
ZevZev
2,25111227
asked Nov 16 '18 at 16:56
ZevZev
2,25111227
asked Nov 16 '18 at 16:56
ZevZev
2,25111227
2,25111227
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
You can also subclass tuple and create your own tuple class with the __lt__ and __gt__ methods appropriately implemented:
class MyTuple(tuple):
def __lt__(self, other):
for s, o in zip(self, other):
if s == o:
continue
if s is None:
return False
if o is None:
return True
return super().__lt__(other)
def __gt__(self, other):
return not self.__lt__(other)
a = MyTuple([None, 4])
b = MyTuple(['pencil', 12])
print(a < b) # False
print(a > b) # True
answered Nov 16 '18 at 17:29
sliderslider
8,56811331
1
Gotcha, I like that use of super to fall back on.
– Zev
Nov 16 '18 at 18:10
My only question with doing it this way is that I think it'd loop through the tuple an extra time when there isn't aNonevalue.
– Zev
Nov 16 '18 at 18:16
1
That is correct. However, you're doing the same thing in your approach as well (item1 > item2in thetryblock) for the case where there is aNonepresent.
– slider
Nov 16 '18 at 18:20
1
Good point! It depends on the use case (whether None is likely to be present). I think I'll end up putting thereturn super().__lt__(other)in a try-except block for my use case.
– Zev
Nov 16 '18 at 18:24
add a comment |
0
You can replace item > item2 with a function like this:
def compare_tuples(item1, item2):
try:
return item1 > item2
# if they can be compared, just do so directly
except TypeError:
for field1, field2 in zip(item1, item2):
# otherwise go through the fields in the tuples
# and compare them checking if they are none
if field1 == field2:
continue
if field1 is None:
return True
if field2 is None:
return False
answered Nov 16 '18 at 16:56
ZevZev
2,25111227
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can also subclass tuple and create your own tuple class with the __lt__ and __gt__ methods appropriately implemented:
class MyTuple(tuple):
def __lt__(self, other):
for s, o in zip(self, other):
if s == o:
continue
if s is None:
return False
if o is None:
return True
return super().__lt__(other)
def __gt__(self, other):
return not self.__lt__(other)
a = MyTuple([None, 4])
b = MyTuple(['pencil', 12])
print(a < b) # False
print(a > b) # True
answered Nov 16 '18 at 17:29
sliderslider
8,56811331
1
Gotcha, I like that use of super to fall back on.
– Zev
Nov 16 '18 at 18:10
My only question with doing it this way is that I think it'd loop through the tuple an extra time when there isn't aNonevalue.
– Zev
Nov 16 '18 at 18:16
1
That is correct. However, you're doing the same thing in your approach as well (item1 > item2in thetryblock) for the case where there is aNonepresent.
– slider
Nov 16 '18 at 18:20
1
Good point! It depends on the use case (whether None is likely to be present). I think I'll end up putting thereturn super().__lt__(other)in a try-except block for my use case.
– Zev
Nov 16 '18 at 18:24
add a comment |
1
You can also subclass tuple and create your own tuple class with the __lt__ and __gt__ methods appropriately implemented:
class MyTuple(tuple):
def __lt__(self, other):
for s, o in zip(self, other):
if s == o:
continue
if s is None:
return False
if o is None:
return True
return super().__lt__(other)
def __gt__(self, other):
return not self.__lt__(other)
a = MyTuple([None, 4])
b = MyTuple(['pencil', 12])
print(a < b) # False
print(a > b) # True
answered Nov 16 '18 at 17:29
sliderslider
8,56811331
1
Gotcha, I like that use of super to fall back on.
– Zev
Nov 16 '18 at 18:10
My only question with doing it this way is that I think it'd loop through the tuple an extra time when there isn't aNonevalue.
– Zev
Nov 16 '18 at 18:16
1
That is correct. However, you're doing the same thing in your approach as well (item1 > item2in thetryblock) for the case where there is aNonepresent.
– slider
Nov 16 '18 at 18:20
1
Good point! It depends on the use case (whether None is likely to be present). I think I'll end up putting thereturn super().__lt__(other)in a try-except block for my use case.
– Zev
Nov 16 '18 at 18:24
add a comment |
1
1
1
You can also subclass tuple and create your own tuple class with the __lt__ and __gt__ methods appropriately implemented:
class MyTuple(tuple):
def __lt__(self, other):
for s, o in zip(self, other):
if s == o:
continue
if s is None:
return False
if o is None:
return True
return super().__lt__(other)
def __gt__(self, other):
return not self.__lt__(other)
a = MyTuple([None, 4])
b = MyTuple(['pencil', 12])
print(a < b) # False
print(a > b) # True
answered Nov 16 '18 at 17:29
sliderslider
8,56811331
You can also subclass tuple and create your own tuple class with the __lt__ and __gt__ methods appropriately implemented:
class MyTuple(tuple):
def __lt__(self, other):
for s, o in zip(self, other):
if s == o:
continue
if s is None:
return False
if o is None:
return True
return super().__lt__(other)
def __gt__(self, other):
return not self.__lt__(other)
a = MyTuple([None, 4])
b = MyTuple(['pencil', 12])
print(a < b) # False
print(a > b) # True
answered Nov 16 '18 at 17:29
sliderslider
8,56811331
answered Nov 16 '18 at 17:29
sliderslider
8,56811331
answered Nov 16 '18 at 17:29
sliderslider
8,56811331
answered Nov 16 '18 at 17:29
sliderslider
8,56811331
8,56811331
1
Gotcha, I like that use of super to fall back on.
– Zev
Nov 16 '18 at 18:10
My only question with doing it this way is that I think it'd loop through the tuple an extra time when there isn't aNonevalue.
– Zev
Nov 16 '18 at 18:16
1
That is correct. However, you're doing the same thing in your approach as well (item1 > item2in thetryblock) for the case where there is aNonepresent.
– slider
Nov 16 '18 at 18:20
1
Good point! It depends on the use case (whether None is likely to be present). I think I'll end up putting thereturn super().__lt__(other)in a try-except block for my use case.
– Zev
Nov 16 '18 at 18:24
add a comment |
1
Gotcha, I like that use of super to fall back on.
– Zev
Nov 16 '18 at 18:10
My only question with doing it this way is that I think it'd loop through the tuple an extra time when there isn't aNonevalue.
– Zev
Nov 16 '18 at 18:16
1
That is correct. However, you're doing the same thing in your approach as well (item1 > item2in thetryblock) for the case where there is aNonepresent.
– slider
Nov 16 '18 at 18:20
1
Good point! It depends on the use case (whether None is likely to be present). I think I'll end up putting thereturn super().__lt__(other)in a try-except block for my use case.
– Zev
Nov 16 '18 at 18:24
1
1
Gotcha, I like that use of super to fall back on.
– Zev
Nov 16 '18 at 18:10
Gotcha, I like that use of super to fall back on.
– Zev
Nov 16 '18 at 18:10
My only question with doing it this way is that I think it'd loop through the tuple an extra time when there isn't a
None value.– Zev
Nov 16 '18 at 18:16
My only question with doing it this way is that I think it'd loop through the tuple an extra time when there isn't a
None value.– Zev
Nov 16 '18 at 18:16
1
1
That is correct. However, you're doing the same thing in your approach as well (
item1 > item2 in the try block) for the case where there is a None present.– slider
Nov 16 '18 at 18:20
That is correct. However, you're doing the same thing in your approach as well (
item1 > item2 in the try block) for the case where there is a None present.– slider
Nov 16 '18 at 18:20
1
1
Good point! It depends on the use case (whether None is likely to be present). I think I'll end up putting the
return super().__lt__(other) in a try-except block for my use case.– Zev
Nov 16 '18 at 18:24
Good point! It depends on the use case (whether None is likely to be present). I think I'll end up putting the
return super().__lt__(other) in a try-except block for my use case.– Zev
Nov 16 '18 at 18:24
add a comment |
0
You can replace item > item2 with a function like this:
def compare_tuples(item1, item2):
try:
return item1 > item2
# if they can be compared, just do so directly
except TypeError:
for field1, field2 in zip(item1, item2):
# otherwise go through the fields in the tuples
# and compare them checking if they are none
if field1 == field2:
continue
if field1 is None:
return True
if field2 is None:
return False
answered Nov 16 '18 at 16:56
ZevZev
2,25111227
add a comment |
0
You can replace item > item2 with a function like this:
def compare_tuples(item1, item2):
try:
return item1 > item2
# if they can be compared, just do so directly
except TypeError:
for field1, field2 in zip(item1, item2):
# otherwise go through the fields in the tuples
# and compare them checking if they are none
if field1 == field2:
continue
if field1 is None:
return True
if field2 is None:
return False
answered Nov 16 '18 at 16:56
ZevZev
2,25111227
add a comment |
0
0
0
You can replace item > item2 with a function like this:
def compare_tuples(item1, item2):
try:
return item1 > item2
# if they can be compared, just do so directly
except TypeError:
for field1, field2 in zip(item1, item2):
# otherwise go through the fields in the tuples
# and compare them checking if they are none
if field1 == field2:
continue
if field1 is None:
return True
if field2 is None:
return False
answered Nov 16 '18 at 16:56
ZevZev
2,25111227
You can replace item > item2 with a function like this:
def compare_tuples(item1, item2):
try:
return item1 > item2
# if they can be compared, just do so directly
except TypeError:
for field1, field2 in zip(item1, item2):
# otherwise go through the fields in the tuples
# and compare them checking if they are none
if field1 == field2:
continue
if field1 is None:
return True
if field2 is None:
return False
answered Nov 16 '18 at 16:56
ZevZev
2,25111227
answered Nov 16 '18 at 16:56
ZevZev
2,25111227
answered Nov 16 '18 at 16:56
ZevZev
2,25111227
answered Nov 16 '18 at 16:56
ZevZev
2,25111227
2,25111227
add a comment |
add a comment |
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