How can we put element of vector to symsum?












1















I am trying to use symsum using Matlab. But I get a strange error.



I am trying to put elements of a vector into symsum:



a=[1,2,3,40,51,61];

syms u n

S1(u) = symsum((a(n+1)*(-u)^n)/factorial(n),n,[0,6])


Error is:




Invalid indexing or function definition. When defining a function, ensure that the arguments are symbolic variables and the body of the function is a SYM expression. When indexing, the input must be numeric, logical, or ':'.











share|improve this question





























    1















    I am trying to use symsum using Matlab. But I get a strange error.



    I am trying to put elements of a vector into symsum:



    a=[1,2,3,40,51,61];

    syms u n

    S1(u) = symsum((a(n+1)*(-u)^n)/factorial(n),n,[0,6])


    Error is:




    Invalid indexing or function definition. When defining a function, ensure that the arguments are symbolic variables and the body of the function is a SYM expression. When indexing, the input must be numeric, logical, or ':'.











    share|improve this question



























      1












      1








      1








      I am trying to use symsum using Matlab. But I get a strange error.



      I am trying to put elements of a vector into symsum:



      a=[1,2,3,40,51,61];

      syms u n

      S1(u) = symsum((a(n+1)*(-u)^n)/factorial(n),n,[0,6])


      Error is:




      Invalid indexing or function definition. When defining a function, ensure that the arguments are symbolic variables and the body of the function is a SYM expression. When indexing, the input must be numeric, logical, or ':'.











      share|improve this question
















      I am trying to use symsum using Matlab. But I get a strange error.



      I am trying to put elements of a vector into symsum:



      a=[1,2,3,40,51,61];

      syms u n

      S1(u) = symsum((a(n+1)*(-u)^n)/factorial(n),n,[0,6])


      Error is:




      Invalid indexing or function definition. When defining a function, ensure that the arguments are symbolic variables and the body of the function is a SYM expression. When indexing, the input must be numeric, logical, or ':'.








      matlab vector series






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      edited Nov 15 '18 at 14:59









      Alex Feinman

      3,82212547




      3,82212547










      asked Nov 5 '18 at 12:36









      Hamid RezaHamid Reza

      132




      132
























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          First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.



          Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).



          Does n really need to be a symbol and do you really need to use symsum? If not, you can try:



          a = [1,2,3,40,51,61];
          n = 0:5;
          syms u
          S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )


          This returns:



          S1(u) =

          - (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1





          share|improve this answer


























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            1 Answer
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            oldest

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            1 Answer
            1






            active

            oldest

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            oldest

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            active

            oldest

            votes









            1














            First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.



            Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).



            Does n really need to be a symbol and do you really need to use symsum? If not, you can try:



            a = [1,2,3,40,51,61];
            n = 0:5;
            syms u
            S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )


            This returns:



            S1(u) =

            - (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1





            share|improve this answer






























              1














              First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.



              Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).



              Does n really need to be a symbol and do you really need to use symsum? If not, you can try:



              a = [1,2,3,40,51,61];
              n = 0:5;
              syms u
              S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )


              This returns:



              S1(u) =

              - (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1





              share|improve this answer




























                1












                1








                1







                First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.



                Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).



                Does n really need to be a symbol and do you really need to use symsum? If not, you can try:



                a = [1,2,3,40,51,61];
                n = 0:5;
                syms u
                S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )


                This returns:



                S1(u) =

                - (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1





                share|improve this answer















                First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.



                Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).



                Does n really need to be a symbol and do you really need to use symsum? If not, you can try:



                a = [1,2,3,40,51,61];
                n = 0:5;
                syms u
                S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )


                This returns:



                S1(u) =

                - (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 16 '18 at 10:11

























                answered Nov 15 '18 at 13:59









                BebsBebs

                1,27331424




                1,27331424
































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