How can we put element of vector to symsum?
I am trying to use symsum using Matlab. But I get a strange error.
I am trying to put elements of a vector into symsum:
a=[1,2,3,40,51,61];
syms u n
S1(u) = symsum((a(n+1)*(-u)^n)/factorial(n),n,[0,6])
Error is:
Invalid indexing or function definition. When defining a function, ensure that the arguments are symbolic variables and the body of the function is a SYM expression. When indexing, the input must be numeric, logical, or ':'.
matlab vector series
edited Nov 15 '18 at 14:59
Alex Feinman
3,82212547
asked Nov 5 '18 at 12:36
Hamid RezaHamid Reza
132
add a comment |
I am trying to use symsum using Matlab. But I get a strange error.
I am trying to put elements of a vector into symsum:
a=[1,2,3,40,51,61];
syms u n
S1(u) = symsum((a(n+1)*(-u)^n)/factorial(n),n,[0,6])
Error is:
Invalid indexing or function definition. When defining a function, ensure that the arguments are symbolic variables and the body of the function is a SYM expression. When indexing, the input must be numeric, logical, or ':'.
matlab vector series
edited Nov 15 '18 at 14:59
Alex Feinman
3,82212547
asked Nov 5 '18 at 12:36
Hamid RezaHamid Reza
132
add a comment |
I am trying to use symsum using Matlab. But I get a strange error.
I am trying to put elements of a vector into symsum:
a=[1,2,3,40,51,61];
syms u n
S1(u) = symsum((a(n+1)*(-u)^n)/factorial(n),n,[0,6])
Error is:
Invalid indexing or function definition. When defining a function, ensure that the arguments are symbolic variables and the body of the function is a SYM expression. When indexing, the input must be numeric, logical, or ':'.
matlab vector series
edited Nov 15 '18 at 14:59
Alex Feinman
3,82212547
asked Nov 5 '18 at 12:36
Hamid RezaHamid Reza
132
I am trying to use symsum using Matlab. But I get a strange error.
I am trying to put elements of a vector into symsum:
a=[1,2,3,40,51,61];
syms u n
S1(u) = symsum((a(n+1)*(-u)^n)/factorial(n),n,[0,6])
Error is:
Invalid indexing or function definition. When defining a function, ensure that the arguments are symbolic variables and the body of the function is a SYM expression. When indexing, the input must be numeric, logical, or ':'.
matlab vector series
matlab vector series
edited Nov 15 '18 at 14:59
Alex Feinman
3,82212547
asked Nov 5 '18 at 12:36
Hamid RezaHamid Reza
132
edited Nov 15 '18 at 14:59
Alex Feinman
3,82212547
asked Nov 5 '18 at 12:36
Hamid RezaHamid Reza
132
edited Nov 15 '18 at 14:59
Alex Feinman
3,82212547
edited Nov 15 '18 at 14:59
Alex Feinman
3,82212547
edited Nov 15 '18 at 14:59
Alex Feinman
3,82212547
3,82212547
asked Nov 5 '18 at 12:36
Hamid RezaHamid Reza
132
asked Nov 5 '18 at 12:36
Hamid RezaHamid Reza
132
asked Nov 5 '18 at 12:36
Hamid RezaHamid Reza
132
132
add a comment |
add a comment |
1 Answer
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First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.
Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).
Does n really need to be a symbol and do you really need to use symsum? If not, you can try:
a = [1,2,3,40,51,61];
n = 0:5;
syms u
S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )
This returns:
S1(u) =
- (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1
answered Nov 15 '18 at 13:59
BebsBebs
1,27331424
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.
Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).
Does n really need to be a symbol and do you really need to use symsum? If not, you can try:
a = [1,2,3,40,51,61];
n = 0:5;
syms u
S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )
This returns:
S1(u) =
- (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1
answered Nov 15 '18 at 13:59
BebsBebs
1,27331424
add a comment |
First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.
Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).
Does n really need to be a symbol and do you really need to use symsum? If not, you can try:
a = [1,2,3,40,51,61];
n = 0:5;
syms u
S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )
This returns:
S1(u) =
- (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1
answered Nov 15 '18 at 13:59
BebsBebs
1,27331424
add a comment |
First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.
Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).
Does n really need to be a symbol and do you really need to use symsum? If not, you can try:
a = [1,2,3,40,51,61];
n = 0:5;
syms u
S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )
This returns:
S1(u) =
- (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1
answered Nov 15 '18 at 13:59
BebsBebs
1,27331424
First, I can see a mistake where you write a(n+1), for n going from 0 to 6. When n equals 6, you will have a(7) which doesn't exist. a only has 6 elements.
Then, you have another problem because you are indexing a with a symbol, and symbolic indexing is not allowed (see this post).
Does n really need to be a symbol and do you really need to use symsum? If not, you can try:
a = [1,2,3,40,51,61];
n = 0:5;
syms u
S1(u) = sum( sym( (a(n+1).*(-u).^n)./factorial(n) ) )
This returns:
S1(u) =
- (61*u^5)/120 + (17*u^4)/8 - (20*u^3)/3 + (3*u^2)/2 - 2*u + 1
answered Nov 15 '18 at 13:59
BebsBebs
1,27331424
edited Nov 16 '18 at 10:11
answered Nov 15 '18 at 13:59
BebsBebs
1,27331424
answered Nov 15 '18 at 13:59
BebsBebs
1,27331424
answered Nov 15 '18 at 13:59
BebsBebs
1,27331424
1,27331424
add a comment |
add a comment |
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