Bellman-ford algorithm with capacity constraint - Python





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I am implementing a Bellman-ford shortest path algorithm. Based on the source and destination node, it outputs the shortest distance, and the path through a network.



Now, I need to add a capacity component to the algorithm. So if the demand is 2 but the capacity is 1, that path is no longer usable.



My initial idea was to add a dictionary for the capacity and a variable for the demand. Then if the demand exceeded the capacity of a node, the lenght of the path would be arbritrarily large. I was thinking something like:



           if capacity[neighbour] < demand:
distance[neighbour], predecessor[neighbour] = 999


This gives me the following error message:



TypeError: '<' not supported between instances of 'dict' and 'int'


Is there a workaround for this issue, or could I potentially add the demand-constraint in a smarter way?



Full code:



source = 'e'
destination = 'd'
demand = 2

def bellman_ford(graph, source, capacity):
# Step 1: Prepare the distance and predecessor for each node
distance, predecessor = dict(), dict()

for node in capacity:
for node in graph:
distance[node], predecessor[node] = float('inf'), None
distance[source] = 0

# Step 2: Relax the edges
for _ in range(len(graph) - 1):
for node in graph:
for neighbour in graph[node]:
# If the distance between the node and the neighbour is lower than the current, store it
if distance[neighbour] > distance[node] + graph[node][neighbour]:
distance[neighbour], predecessor[neighbour] = distance[node] + graph[node][neighbour], node
if capacity[node] < demand:
distance[neighbour], predecessor[neighbour] = 100


# Step 3: Check for negative weight cycles
for node in graph:
for neighbour in graph[node]:
assert distance[neighbour] <= distance[node] + graph[node][neighbour], "Negative weight cycle."

return distance, predecessor

#Initial graph

graph = {
'a': {'b': 1, 'd': 1},
'b': {'c': 1, 'd': 2},
'c': {},
'd': {'b': 1, 'c': 8, 'e': 1},
'e': {'a': 2, 'd': 7}
}


capacity = {
'a': {'b': 4, 'd': 1},
'b': {'c': 5, 'd': 4},
'c': {},
'd': {'b': 1, 'c': 3, 'e': 3},
'e': {'a': 5, 'd': 3}
}


distance, predecessor = bellman_ford(graph, source, capacity)

print("The cost of shipping from from", source, "to", destination, "is", distance[destination])

for i in graph:
print("node",i,"is reached through node", predecessor[i])









share|improve this question




















  • 1





    There is no if capacity[neighbour] < demand: in full code

    – Corentin Limier
    Nov 16 '18 at 14:25








  • 1





    + it may be if capacity[node][neighbour] < demand

    – Corentin Limier
    Nov 16 '18 at 14:25











  • Ill update the original question with the non-functioning part of the code I get the same error with [node][neighbour]

    – Daugaard
    Nov 16 '18 at 14:48











  • You cannot have the same error with capacity[node][neighbour], but you may have a KeyError

    – Corentin Limier
    Nov 16 '18 at 14:55











  • It still gives me the dict vs. int error

    – Daugaard
    Nov 16 '18 at 15:05


















0















I am implementing a Bellman-ford shortest path algorithm. Based on the source and destination node, it outputs the shortest distance, and the path through a network.



Now, I need to add a capacity component to the algorithm. So if the demand is 2 but the capacity is 1, that path is no longer usable.



My initial idea was to add a dictionary for the capacity and a variable for the demand. Then if the demand exceeded the capacity of a node, the lenght of the path would be arbritrarily large. I was thinking something like:



           if capacity[neighbour] < demand:
distance[neighbour], predecessor[neighbour] = 999


This gives me the following error message:



TypeError: '<' not supported between instances of 'dict' and 'int'


Is there a workaround for this issue, or could I potentially add the demand-constraint in a smarter way?



Full code:



source = 'e'
destination = 'd'
demand = 2

def bellman_ford(graph, source, capacity):
# Step 1: Prepare the distance and predecessor for each node
distance, predecessor = dict(), dict()

for node in capacity:
for node in graph:
distance[node], predecessor[node] = float('inf'), None
distance[source] = 0

# Step 2: Relax the edges
for _ in range(len(graph) - 1):
for node in graph:
for neighbour in graph[node]:
# If the distance between the node and the neighbour is lower than the current, store it
if distance[neighbour] > distance[node] + graph[node][neighbour]:
distance[neighbour], predecessor[neighbour] = distance[node] + graph[node][neighbour], node
if capacity[node] < demand:
distance[neighbour], predecessor[neighbour] = 100


# Step 3: Check for negative weight cycles
for node in graph:
for neighbour in graph[node]:
assert distance[neighbour] <= distance[node] + graph[node][neighbour], "Negative weight cycle."

return distance, predecessor

#Initial graph

graph = {
'a': {'b': 1, 'd': 1},
'b': {'c': 1, 'd': 2},
'c': {},
'd': {'b': 1, 'c': 8, 'e': 1},
'e': {'a': 2, 'd': 7}
}


capacity = {
'a': {'b': 4, 'd': 1},
'b': {'c': 5, 'd': 4},
'c': {},
'd': {'b': 1, 'c': 3, 'e': 3},
'e': {'a': 5, 'd': 3}
}


distance, predecessor = bellman_ford(graph, source, capacity)

print("The cost of shipping from from", source, "to", destination, "is", distance[destination])

for i in graph:
print("node",i,"is reached through node", predecessor[i])









share|improve this question




















  • 1





    There is no if capacity[neighbour] < demand: in full code

    – Corentin Limier
    Nov 16 '18 at 14:25








  • 1





    + it may be if capacity[node][neighbour] < demand

    – Corentin Limier
    Nov 16 '18 at 14:25











  • Ill update the original question with the non-functioning part of the code I get the same error with [node][neighbour]

    – Daugaard
    Nov 16 '18 at 14:48











  • You cannot have the same error with capacity[node][neighbour], but you may have a KeyError

    – Corentin Limier
    Nov 16 '18 at 14:55











  • It still gives me the dict vs. int error

    – Daugaard
    Nov 16 '18 at 15:05














0












0








0








I am implementing a Bellman-ford shortest path algorithm. Based on the source and destination node, it outputs the shortest distance, and the path through a network.



Now, I need to add a capacity component to the algorithm. So if the demand is 2 but the capacity is 1, that path is no longer usable.



My initial idea was to add a dictionary for the capacity and a variable for the demand. Then if the demand exceeded the capacity of a node, the lenght of the path would be arbritrarily large. I was thinking something like:



           if capacity[neighbour] < demand:
distance[neighbour], predecessor[neighbour] = 999


This gives me the following error message:



TypeError: '<' not supported between instances of 'dict' and 'int'


Is there a workaround for this issue, or could I potentially add the demand-constraint in a smarter way?



Full code:



source = 'e'
destination = 'd'
demand = 2

def bellman_ford(graph, source, capacity):
# Step 1: Prepare the distance and predecessor for each node
distance, predecessor = dict(), dict()

for node in capacity:
for node in graph:
distance[node], predecessor[node] = float('inf'), None
distance[source] = 0

# Step 2: Relax the edges
for _ in range(len(graph) - 1):
for node in graph:
for neighbour in graph[node]:
# If the distance between the node and the neighbour is lower than the current, store it
if distance[neighbour] > distance[node] + graph[node][neighbour]:
distance[neighbour], predecessor[neighbour] = distance[node] + graph[node][neighbour], node
if capacity[node] < demand:
distance[neighbour], predecessor[neighbour] = 100


# Step 3: Check for negative weight cycles
for node in graph:
for neighbour in graph[node]:
assert distance[neighbour] <= distance[node] + graph[node][neighbour], "Negative weight cycle."

return distance, predecessor

#Initial graph

graph = {
'a': {'b': 1, 'd': 1},
'b': {'c': 1, 'd': 2},
'c': {},
'd': {'b': 1, 'c': 8, 'e': 1},
'e': {'a': 2, 'd': 7}
}


capacity = {
'a': {'b': 4, 'd': 1},
'b': {'c': 5, 'd': 4},
'c': {},
'd': {'b': 1, 'c': 3, 'e': 3},
'e': {'a': 5, 'd': 3}
}


distance, predecessor = bellman_ford(graph, source, capacity)

print("The cost of shipping from from", source, "to", destination, "is", distance[destination])

for i in graph:
print("node",i,"is reached through node", predecessor[i])









share|improve this question
















I am implementing a Bellman-ford shortest path algorithm. Based on the source and destination node, it outputs the shortest distance, and the path through a network.



Now, I need to add a capacity component to the algorithm. So if the demand is 2 but the capacity is 1, that path is no longer usable.



My initial idea was to add a dictionary for the capacity and a variable for the demand. Then if the demand exceeded the capacity of a node, the lenght of the path would be arbritrarily large. I was thinking something like:



           if capacity[neighbour] < demand:
distance[neighbour], predecessor[neighbour] = 999


This gives me the following error message:



TypeError: '<' not supported between instances of 'dict' and 'int'


Is there a workaround for this issue, or could I potentially add the demand-constraint in a smarter way?



Full code:



source = 'e'
destination = 'd'
demand = 2

def bellman_ford(graph, source, capacity):
# Step 1: Prepare the distance and predecessor for each node
distance, predecessor = dict(), dict()

for node in capacity:
for node in graph:
distance[node], predecessor[node] = float('inf'), None
distance[source] = 0

# Step 2: Relax the edges
for _ in range(len(graph) - 1):
for node in graph:
for neighbour in graph[node]:
# If the distance between the node and the neighbour is lower than the current, store it
if distance[neighbour] > distance[node] + graph[node][neighbour]:
distance[neighbour], predecessor[neighbour] = distance[node] + graph[node][neighbour], node
if capacity[node] < demand:
distance[neighbour], predecessor[neighbour] = 100


# Step 3: Check for negative weight cycles
for node in graph:
for neighbour in graph[node]:
assert distance[neighbour] <= distance[node] + graph[node][neighbour], "Negative weight cycle."

return distance, predecessor

#Initial graph

graph = {
'a': {'b': 1, 'd': 1},
'b': {'c': 1, 'd': 2},
'c': {},
'd': {'b': 1, 'c': 8, 'e': 1},
'e': {'a': 2, 'd': 7}
}


capacity = {
'a': {'b': 4, 'd': 1},
'b': {'c': 5, 'd': 4},
'c': {},
'd': {'b': 1, 'c': 3, 'e': 3},
'e': {'a': 5, 'd': 3}
}


distance, predecessor = bellman_ford(graph, source, capacity)

print("The cost of shipping from from", source, "to", destination, "is", distance[destination])

for i in graph:
print("node",i,"is reached through node", predecessor[i])






python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 14:49







Daugaard

















asked Nov 16 '18 at 14:18









DaugaardDaugaard

32




32








  • 1





    There is no if capacity[neighbour] < demand: in full code

    – Corentin Limier
    Nov 16 '18 at 14:25








  • 1





    + it may be if capacity[node][neighbour] < demand

    – Corentin Limier
    Nov 16 '18 at 14:25











  • Ill update the original question with the non-functioning part of the code I get the same error with [node][neighbour]

    – Daugaard
    Nov 16 '18 at 14:48











  • You cannot have the same error with capacity[node][neighbour], but you may have a KeyError

    – Corentin Limier
    Nov 16 '18 at 14:55











  • It still gives me the dict vs. int error

    – Daugaard
    Nov 16 '18 at 15:05














  • 1





    There is no if capacity[neighbour] < demand: in full code

    – Corentin Limier
    Nov 16 '18 at 14:25








  • 1





    + it may be if capacity[node][neighbour] < demand

    – Corentin Limier
    Nov 16 '18 at 14:25











  • Ill update the original question with the non-functioning part of the code I get the same error with [node][neighbour]

    – Daugaard
    Nov 16 '18 at 14:48











  • You cannot have the same error with capacity[node][neighbour], but you may have a KeyError

    – Corentin Limier
    Nov 16 '18 at 14:55











  • It still gives me the dict vs. int error

    – Daugaard
    Nov 16 '18 at 15:05








1




1





There is no if capacity[neighbour] < demand: in full code

– Corentin Limier
Nov 16 '18 at 14:25







There is no if capacity[neighbour] < demand: in full code

– Corentin Limier
Nov 16 '18 at 14:25






1




1





+ it may be if capacity[node][neighbour] < demand

– Corentin Limier
Nov 16 '18 at 14:25





+ it may be if capacity[node][neighbour] < demand

– Corentin Limier
Nov 16 '18 at 14:25













Ill update the original question with the non-functioning part of the code I get the same error with [node][neighbour]

– Daugaard
Nov 16 '18 at 14:48





Ill update the original question with the non-functioning part of the code I get the same error with [node][neighbour]

– Daugaard
Nov 16 '18 at 14:48













You cannot have the same error with capacity[node][neighbour], but you may have a KeyError

– Corentin Limier
Nov 16 '18 at 14:55





You cannot have the same error with capacity[node][neighbour], but you may have a KeyError

– Corentin Limier
Nov 16 '18 at 14:55













It still gives me the dict vs. int error

– Daugaard
Nov 16 '18 at 15:05





It still gives me the dict vs. int error

– Daugaard
Nov 16 '18 at 15:05












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