Saving DICOM images using Imebra library
In my Android project I am currently using Imebra library to extract image frames from a dicom file and save them as Bitmaps. After that I use ffmpeg to create a video from these frames. Every thing is working well so far, but my only concern is whether I will loose any quality or information by using following methods from Imebra library:
Image image = imageIterator.next();
TransformsChain chain = transform(image);
Bitmap bitmap = getBitmap(image, chain);
Furthermore, if I am using any information by saving my image frames as bitmaps, can I save them as the raw format (by raw I mean imebra.Image, I am not sure if that's the same as .raw format?) and use them directly with ffmpeg?
dicom imebra
asked Nov 15 '18 at 22:24
TheEngineerTheEngineer
373111
add a comment |
In my Android project I am currently using Imebra library to extract image frames from a dicom file and save them as Bitmaps. After that I use ffmpeg to create a video from these frames. Every thing is working well so far, but my only concern is whether I will loose any quality or information by using following methods from Imebra library:
Image image = imageIterator.next();
TransformsChain chain = transform(image);
Bitmap bitmap = getBitmap(image, chain);
Furthermore, if I am using any information by saving my image frames as bitmaps, can I save them as the raw format (by raw I mean imebra.Image, I am not sure if that's the same as .raw format?) and use them directly with ffmpeg?
dicom imebra
asked Nov 15 '18 at 22:24
TheEngineerTheEngineer
373111
add a comment |
In my Android project I am currently using Imebra library to extract image frames from a dicom file and save them as Bitmaps. After that I use ffmpeg to create a video from these frames. Every thing is working well so far, but my only concern is whether I will loose any quality or information by using following methods from Imebra library:
Image image = imageIterator.next();
TransformsChain chain = transform(image);
Bitmap bitmap = getBitmap(image, chain);
Furthermore, if I am using any information by saving my image frames as bitmaps, can I save them as the raw format (by raw I mean imebra.Image, I am not sure if that's the same as .raw format?) and use them directly with ffmpeg?
dicom imebra
asked Nov 15 '18 at 22:24
TheEngineerTheEngineer
373111
In my Android project I am currently using Imebra library to extract image frames from a dicom file and save them as Bitmaps. After that I use ffmpeg to create a video from these frames. Every thing is working well so far, but my only concern is whether I will loose any quality or information by using following methods from Imebra library:
Image image = imageIterator.next();
TransformsChain chain = transform(image);
Bitmap bitmap = getBitmap(image, chain);
Furthermore, if I am using any information by saving my image frames as bitmaps, can I save them as the raw format (by raw I mean imebra.Image, I am not sure if that's the same as .raw format?) and use them directly with ffmpeg?
dicom imebra
dicom imebra
asked Nov 15 '18 at 22:24
TheEngineerTheEngineer
373111
asked Nov 15 '18 at 22:24
TheEngineerTheEngineer
373111
asked Nov 15 '18 at 22:24
TheEngineerTheEngineer
373111
asked Nov 15 '18 at 22:24
TheEngineerTheEngineer
373111
asked Nov 15 '18 at 22:24
TheEngineerTheEngineer
373111
373111
add a comment |
add a comment |
1 Answer
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The image you get with DrawBitmap::getBitmap is always an RGB 24 bit per pixel one: you will lose information in the case that the image uses more than 8 bit per color channel (e.g. a 16 bit grayscale image will lose the lower 8 bit of the pixel information).
You could get an higher bit per pixel number by avoiding using DrawBitmap::getBitmap and by applying directly the transforms yourself (VOI/LUT, color transformation, high bit transform).
After you have an Image with the desired color space and bit per pixel, than use the Image::GetReadingDataHandler to access the image underlying memory and generate the bitmap for ffmpeg.
Disclosure: I'm the author of Imebra.
answered Nov 16 '18 at 7:57
Paolo BrandoliPaolo Brandoli
3,7521834
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
The image you get with DrawBitmap::getBitmap is always an RGB 24 bit per pixel one: you will lose information in the case that the image uses more than 8 bit per color channel (e.g. a 16 bit grayscale image will lose the lower 8 bit of the pixel information).
You could get an higher bit per pixel number by avoiding using DrawBitmap::getBitmap and by applying directly the transforms yourself (VOI/LUT, color transformation, high bit transform).
After you have an Image with the desired color space and bit per pixel, than use the Image::GetReadingDataHandler to access the image underlying memory and generate the bitmap for ffmpeg.
Disclosure: I'm the author of Imebra.
answered Nov 16 '18 at 7:57
Paolo BrandoliPaolo Brandoli
3,7521834
add a comment |
The image you get with DrawBitmap::getBitmap is always an RGB 24 bit per pixel one: you will lose information in the case that the image uses more than 8 bit per color channel (e.g. a 16 bit grayscale image will lose the lower 8 bit of the pixel information).
You could get an higher bit per pixel number by avoiding using DrawBitmap::getBitmap and by applying directly the transforms yourself (VOI/LUT, color transformation, high bit transform).
After you have an Image with the desired color space and bit per pixel, than use the Image::GetReadingDataHandler to access the image underlying memory and generate the bitmap for ffmpeg.
Disclosure: I'm the author of Imebra.
answered Nov 16 '18 at 7:57
Paolo BrandoliPaolo Brandoli
3,7521834
add a comment |
The image you get with DrawBitmap::getBitmap is always an RGB 24 bit per pixel one: you will lose information in the case that the image uses more than 8 bit per color channel (e.g. a 16 bit grayscale image will lose the lower 8 bit of the pixel information).
You could get an higher bit per pixel number by avoiding using DrawBitmap::getBitmap and by applying directly the transforms yourself (VOI/LUT, color transformation, high bit transform).
After you have an Image with the desired color space and bit per pixel, than use the Image::GetReadingDataHandler to access the image underlying memory and generate the bitmap for ffmpeg.
Disclosure: I'm the author of Imebra.
answered Nov 16 '18 at 7:57
Paolo BrandoliPaolo Brandoli
3,7521834
The image you get with DrawBitmap::getBitmap is always an RGB 24 bit per pixel one: you will lose information in the case that the image uses more than 8 bit per color channel (e.g. a 16 bit grayscale image will lose the lower 8 bit of the pixel information).
You could get an higher bit per pixel number by avoiding using DrawBitmap::getBitmap and by applying directly the transforms yourself (VOI/LUT, color transformation, high bit transform).
After you have an Image with the desired color space and bit per pixel, than use the Image::GetReadingDataHandler to access the image underlying memory and generate the bitmap for ffmpeg.
Disclosure: I'm the author of Imebra.
answered Nov 16 '18 at 7:57
Paolo BrandoliPaolo Brandoli
3,7521834
answered Nov 16 '18 at 7:57
Paolo BrandoliPaolo Brandoli
3,7521834
answered Nov 16 '18 at 7:57
Paolo BrandoliPaolo Brandoli
3,7521834
answered Nov 16 '18 at 7:57
Paolo BrandoliPaolo Brandoli
3,7521834
3,7521834
add a comment |
add a comment |
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