Convert ES6 array of string to an array of object with the same key
How can I convert this array of fruits,
['Apple', 'Banana', 'Orange', 'Peach']
to an array of object with the same key,
[{
name: 'Apple',
},{
name: 'Banana',
},{
name: 'Orange'
},{
name: 'Peach'
}]
javascript ecmascript-6
add a comment |
How can I convert this array of fruits,
['Apple', 'Banana', 'Orange', 'Peach']
to an array of object with the same key,
[{
name: 'Apple',
},{
name: 'Banana',
},{
name: 'Orange'
},{
name: 'Peach'
}]
javascript ecmascript-6
2
The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.
– CertainPerformance
Nov 16 '18 at 7:13
add a comment |
How can I convert this array of fruits,
['Apple', 'Banana', 'Orange', 'Peach']
to an array of object with the same key,
[{
name: 'Apple',
},{
name: 'Banana',
},{
name: 'Orange'
},{
name: 'Peach'
}]
javascript ecmascript-6
How can I convert this array of fruits,
['Apple', 'Banana', 'Orange', 'Peach']
to an array of object with the same key,
[{
name: 'Apple',
},{
name: 'Banana',
},{
name: 'Orange'
},{
name: 'Peach'
}]
javascript ecmascript-6
javascript ecmascript-6
asked Nov 16 '18 at 7:12
JahmJahm
5071026
5071026
2
The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.
– CertainPerformance
Nov 16 '18 at 7:13
add a comment |
2
The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.
– CertainPerformance
Nov 16 '18 at 7:13
2
2
The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.
– CertainPerformance
Nov 16 '18 at 7:13
The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.
– CertainPerformance
Nov 16 '18 at 7:13
add a comment |
1 Answer
1
active
oldest
votes
You can use array#map
with Object shorthand property.
let data = ['Apple', 'Banana', 'Orange', 'Peach'],
result = data.map(name => ({name}));
console.log(result);
Thank you for the help.
– Jahm
Nov 17 '18 at 13:59
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use array#map
with Object shorthand property.
let data = ['Apple', 'Banana', 'Orange', 'Peach'],
result = data.map(name => ({name}));
console.log(result);
Thank you for the help.
– Jahm
Nov 17 '18 at 13:59
add a comment |
You can use array#map
with Object shorthand property.
let data = ['Apple', 'Banana', 'Orange', 'Peach'],
result = data.map(name => ({name}));
console.log(result);
Thank you for the help.
– Jahm
Nov 17 '18 at 13:59
add a comment |
You can use array#map
with Object shorthand property.
let data = ['Apple', 'Banana', 'Orange', 'Peach'],
result = data.map(name => ({name}));
console.log(result);
You can use array#map
with Object shorthand property.
let data = ['Apple', 'Banana', 'Orange', 'Peach'],
result = data.map(name => ({name}));
console.log(result);
let data = ['Apple', 'Banana', 'Orange', 'Peach'],
result = data.map(name => ({name}));
console.log(result);
let data = ['Apple', 'Banana', 'Orange', 'Peach'],
result = data.map(name => ({name}));
console.log(result);
answered Nov 16 '18 at 7:17
Hassan ImamHassan Imam
11.9k31532
11.9k31532
Thank you for the help.
– Jahm
Nov 17 '18 at 13:59
add a comment |
Thank you for the help.
– Jahm
Nov 17 '18 at 13:59
Thank you for the help.
– Jahm
Nov 17 '18 at 13:59
Thank you for the help.
– Jahm
Nov 17 '18 at 13:59
add a comment |
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2
The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.
– CertainPerformance
Nov 16 '18 at 7:13