While doesn't break with a an input string
How can I break the while
with a string input? I was trying this, but the first if is ignored:
from itertools import cycle;
ewe=cycle([0]);
Nom_join="";
Principal_loop=True;
Cont_Error1=0;
while(Principal_loop==True):
for i in ewe:
Nom_join=input("give me a name to search: -> ");
if (Nom_join==""):
print("you cant do that");
Cont_Error1+=1;
elif(Nom_join==" "):
print("you cant do that");
Cont_Error1+=1;
elif(Nom_join.isdigit()):
print("you cant do that")
Cont_Error1+=1;
elif(Nom_join=="*"):
Principal_loop=False;
else:
break;
python
add a comment |
How can I break the while
with a string input? I was trying this, but the first if is ignored:
from itertools import cycle;
ewe=cycle([0]);
Nom_join="";
Principal_loop=True;
Cont_Error1=0;
while(Principal_loop==True):
for i in ewe:
Nom_join=input("give me a name to search: -> ");
if (Nom_join==""):
print("you cant do that");
Cont_Error1+=1;
elif(Nom_join==" "):
print("you cant do that");
Cont_Error1+=1;
elif(Nom_join.isdigit()):
print("you cant do that")
Cont_Error1+=1;
elif(Nom_join=="*"):
Principal_loop=False;
else:
break;
python
4
Please remove the semicolons, they hurt every Python developer's eyes.
– Klaus D.
Nov 14 '18 at 5:08
add a comment |
How can I break the while
with a string input? I was trying this, but the first if is ignored:
from itertools import cycle;
ewe=cycle([0]);
Nom_join="";
Principal_loop=True;
Cont_Error1=0;
while(Principal_loop==True):
for i in ewe:
Nom_join=input("give me a name to search: -> ");
if (Nom_join==""):
print("you cant do that");
Cont_Error1+=1;
elif(Nom_join==" "):
print("you cant do that");
Cont_Error1+=1;
elif(Nom_join.isdigit()):
print("you cant do that")
Cont_Error1+=1;
elif(Nom_join=="*"):
Principal_loop=False;
else:
break;
python
How can I break the while
with a string input? I was trying this, but the first if is ignored:
from itertools import cycle;
ewe=cycle([0]);
Nom_join="";
Principal_loop=True;
Cont_Error1=0;
while(Principal_loop==True):
for i in ewe:
Nom_join=input("give me a name to search: -> ");
if (Nom_join==""):
print("you cant do that");
Cont_Error1+=1;
elif(Nom_join==" "):
print("you cant do that");
Cont_Error1+=1;
elif(Nom_join.isdigit()):
print("you cant do that")
Cont_Error1+=1;
elif(Nom_join=="*"):
Principal_loop=False;
else:
break;
python
python
edited Nov 14 '18 at 5:23
Joel
1,5706719
1,5706719
asked Nov 14 '18 at 5:01
PanBASICPanBASIC
23
23
4
Please remove the semicolons, they hurt every Python developer's eyes.
– Klaus D.
Nov 14 '18 at 5:08
add a comment |
4
Please remove the semicolons, they hurt every Python developer's eyes.
– Klaus D.
Nov 14 '18 at 5:08
4
4
Please remove the semicolons, they hurt every Python developer's eyes.
– Klaus D.
Nov 14 '18 at 5:08
Please remove the semicolons, they hurt every Python developer's eyes.
– Klaus D.
Nov 14 '18 at 5:08
add a comment |
1 Answer
1
active
oldest
votes
Try adding a break
statement after Principal_loop=False
. And yes, please remove semicolons and add spaces before and after operators to conform with PEP 8 guidelines. Also, no parentheses after conditional statements.
from itertools import cycle
ewe = cycle([0])
Nom_join = ""
Principal_loop = True
Cont_Error1 = 0
while Principal_loop == True:
for i in ewe:
Nom_join = input("give me a name to search: -> ")
if Nom_join == "":
print("you cant do that")
Cont_Error1 += 1;
elif Nom_join == " ":
print("you cant do that")
Cont_Error1 += 1
elif Nom_join.isdigit():
print("you cant do that")
Cont_Error1 += 1
elif Nom_join == "*":
Principal_loop = False
break
else:
break
I'm really not sure why you need to initiate a cycle of infinite zeros... There's also a lot of other simplifications that can be made. It seems far simpler to do this:
Cont_Error1 = 0
while True:
Nom_join = input("give me a name to search: -> ")
if Nom_join in {"", " ", "*"} or Nom_join.isdigit():
print("you can't do that")
Cont_Error1 += 1;
else:
break
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try adding a break
statement after Principal_loop=False
. And yes, please remove semicolons and add spaces before and after operators to conform with PEP 8 guidelines. Also, no parentheses after conditional statements.
from itertools import cycle
ewe = cycle([0])
Nom_join = ""
Principal_loop = True
Cont_Error1 = 0
while Principal_loop == True:
for i in ewe:
Nom_join = input("give me a name to search: -> ")
if Nom_join == "":
print("you cant do that")
Cont_Error1 += 1;
elif Nom_join == " ":
print("you cant do that")
Cont_Error1 += 1
elif Nom_join.isdigit():
print("you cant do that")
Cont_Error1 += 1
elif Nom_join == "*":
Principal_loop = False
break
else:
break
I'm really not sure why you need to initiate a cycle of infinite zeros... There's also a lot of other simplifications that can be made. It seems far simpler to do this:
Cont_Error1 = 0
while True:
Nom_join = input("give me a name to search: -> ")
if Nom_join in {"", " ", "*"} or Nom_join.isdigit():
print("you can't do that")
Cont_Error1 += 1;
else:
break
add a comment |
Try adding a break
statement after Principal_loop=False
. And yes, please remove semicolons and add spaces before and after operators to conform with PEP 8 guidelines. Also, no parentheses after conditional statements.
from itertools import cycle
ewe = cycle([0])
Nom_join = ""
Principal_loop = True
Cont_Error1 = 0
while Principal_loop == True:
for i in ewe:
Nom_join = input("give me a name to search: -> ")
if Nom_join == "":
print("you cant do that")
Cont_Error1 += 1;
elif Nom_join == " ":
print("you cant do that")
Cont_Error1 += 1
elif Nom_join.isdigit():
print("you cant do that")
Cont_Error1 += 1
elif Nom_join == "*":
Principal_loop = False
break
else:
break
I'm really not sure why you need to initiate a cycle of infinite zeros... There's also a lot of other simplifications that can be made. It seems far simpler to do this:
Cont_Error1 = 0
while True:
Nom_join = input("give me a name to search: -> ")
if Nom_join in {"", " ", "*"} or Nom_join.isdigit():
print("you can't do that")
Cont_Error1 += 1;
else:
break
add a comment |
Try adding a break
statement after Principal_loop=False
. And yes, please remove semicolons and add spaces before and after operators to conform with PEP 8 guidelines. Also, no parentheses after conditional statements.
from itertools import cycle
ewe = cycle([0])
Nom_join = ""
Principal_loop = True
Cont_Error1 = 0
while Principal_loop == True:
for i in ewe:
Nom_join = input("give me a name to search: -> ")
if Nom_join == "":
print("you cant do that")
Cont_Error1 += 1;
elif Nom_join == " ":
print("you cant do that")
Cont_Error1 += 1
elif Nom_join.isdigit():
print("you cant do that")
Cont_Error1 += 1
elif Nom_join == "*":
Principal_loop = False
break
else:
break
I'm really not sure why you need to initiate a cycle of infinite zeros... There's also a lot of other simplifications that can be made. It seems far simpler to do this:
Cont_Error1 = 0
while True:
Nom_join = input("give me a name to search: -> ")
if Nom_join in {"", " ", "*"} or Nom_join.isdigit():
print("you can't do that")
Cont_Error1 += 1;
else:
break
Try adding a break
statement after Principal_loop=False
. And yes, please remove semicolons and add spaces before and after operators to conform with PEP 8 guidelines. Also, no parentheses after conditional statements.
from itertools import cycle
ewe = cycle([0])
Nom_join = ""
Principal_loop = True
Cont_Error1 = 0
while Principal_loop == True:
for i in ewe:
Nom_join = input("give me a name to search: -> ")
if Nom_join == "":
print("you cant do that")
Cont_Error1 += 1;
elif Nom_join == " ":
print("you cant do that")
Cont_Error1 += 1
elif Nom_join.isdigit():
print("you cant do that")
Cont_Error1 += 1
elif Nom_join == "*":
Principal_loop = False
break
else:
break
I'm really not sure why you need to initiate a cycle of infinite zeros... There's also a lot of other simplifications that can be made. It seems far simpler to do this:
Cont_Error1 = 0
while True:
Nom_join = input("give me a name to search: -> ")
if Nom_join in {"", " ", "*"} or Nom_join.isdigit():
print("you can't do that")
Cont_Error1 += 1;
else:
break
answered Nov 14 '18 at 5:34
Tomothy32Tomothy32
5,7121425
5,7121425
add a comment |
add a comment |
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4
Please remove the semicolons, they hurt every Python developer's eyes.
– Klaus D.
Nov 14 '18 at 5:08