Python: run a class method that takes an argument in a new thread
I am trying to do the same thing as in this question: Run Class methods in threads (python), but the class method I want to invoke in a separate thread takes an extra argument, apart from self. A.Rodas's solution does not work: if I try Thread(target=self.class_method, args=(self, arg2)).start(), it says I have 3 arguments instead of 2, while if try args=(arg2), it is breaking my arg2 string into constituent elements and saying 334234 arguments! Any ideas? Thanks
python-multithreading
asked Nov 13 '18 at 21:05
cbasavarajcbasavaraj
132
add a comment |
I am trying to do the same thing as in this question: Run Class methods in threads (python), but the class method I want to invoke in a separate thread takes an extra argument, apart from self. A.Rodas's solution does not work: if I try Thread(target=self.class_method, args=(self, arg2)).start(), it says I have 3 arguments instead of 2, while if try args=(arg2), it is breaking my arg2 string into constituent elements and saying 334234 arguments! Any ideas? Thanks
python-multithreading
asked Nov 13 '18 at 21:05
cbasavarajcbasavaraj
132
Found the solution! Turns out it wasn't the class method that was causing the error, but the fact that I was sending a tuple of one arg. So I needed to sent args=(arg2,). Note the comma! Got the solution from here: stackoverflow.com/questions/37116721/…
– cbasavaraj
Nov 13 '18 at 21:32
add a comment |
I am trying to do the same thing as in this question: Run Class methods in threads (python), but the class method I want to invoke in a separate thread takes an extra argument, apart from self. A.Rodas's solution does not work: if I try Thread(target=self.class_method, args=(self, arg2)).start(), it says I have 3 arguments instead of 2, while if try args=(arg2), it is breaking my arg2 string into constituent elements and saying 334234 arguments! Any ideas? Thanks
python-multithreading
asked Nov 13 '18 at 21:05
cbasavarajcbasavaraj
132
I am trying to do the same thing as in this question: Run Class methods in threads (python), but the class method I want to invoke in a separate thread takes an extra argument, apart from self. A.Rodas's solution does not work: if I try Thread(target=self.class_method, args=(self, arg2)).start(), it says I have 3 arguments instead of 2, while if try args=(arg2), it is breaking my arg2 string into constituent elements and saying 334234 arguments! Any ideas? Thanks
python-multithreading
python-multithreading
asked Nov 13 '18 at 21:05
cbasavarajcbasavaraj
132
asked Nov 13 '18 at 21:05
cbasavarajcbasavaraj
132
asked Nov 13 '18 at 21:05
cbasavarajcbasavaraj
132
asked Nov 13 '18 at 21:05
cbasavarajcbasavaraj
132
asked Nov 13 '18 at 21:05
cbasavarajcbasavaraj
132
132
Found the solution! Turns out it wasn't the class method that was causing the error, but the fact that I was sending a tuple of one arg. So I needed to sent args=(arg2,). Note the comma! Got the solution from here: stackoverflow.com/questions/37116721/…
– cbasavaraj
Nov 13 '18 at 21:32
add a comment |
Found the solution! Turns out it wasn't the class method that was causing the error, but the fact that I was sending a tuple of one arg. So I needed to sent args=(arg2,). Note the comma! Got the solution from here: stackoverflow.com/questions/37116721/…
– cbasavaraj
Nov 13 '18 at 21:32
Found the solution! Turns out it wasn't the class method that was causing the error, but the fact that I was sending a tuple of one arg. So I needed to sent args=(arg2,). Note the comma! Got the solution from here: stackoverflow.com/questions/37116721/…
– cbasavaraj
Nov 13 '18 at 21:32
Found the solution! Turns out it wasn't the class method that was causing the error, but the fact that I was sending a tuple of one arg. So I needed to sent args=(arg2,). Note the comma! Got the solution from here: stackoverflow.com/questions/37116721/…
– cbasavaraj
Nov 13 '18 at 21:32
add a comment |
1 Answer
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It is hard to tell from the format of your question, but I think the issue is that you shouldn't be including self in the args tuple.
i.e.
threading.Thread(target=self.class_method, args=(arg2)).start()
answered Nov 13 '18 at 21:11
Ian MacDonaldIan MacDonald
9,01111230
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
It is hard to tell from the format of your question, but I think the issue is that you shouldn't be including self in the args tuple.
i.e.
threading.Thread(target=self.class_method, args=(arg2)).start()
answered Nov 13 '18 at 21:11
Ian MacDonaldIan MacDonald
9,01111230
add a comment |
It is hard to tell from the format of your question, but I think the issue is that you shouldn't be including self in the args tuple.
i.e.
threading.Thread(target=self.class_method, args=(arg2)).start()
answered Nov 13 '18 at 21:11
Ian MacDonaldIan MacDonald
9,01111230
add a comment |
It is hard to tell from the format of your question, but I think the issue is that you shouldn't be including self in the args tuple.
i.e.
threading.Thread(target=self.class_method, args=(arg2)).start()
answered Nov 13 '18 at 21:11
Ian MacDonaldIan MacDonald
9,01111230
It is hard to tell from the format of your question, but I think the issue is that you shouldn't be including self in the args tuple.
i.e.
threading.Thread(target=self.class_method, args=(arg2)).start()
answered Nov 13 '18 at 21:11
Ian MacDonaldIan MacDonald
9,01111230
answered Nov 13 '18 at 21:11
Ian MacDonaldIan MacDonald
9,01111230
answered Nov 13 '18 at 21:11
Ian MacDonaldIan MacDonald
9,01111230
answered Nov 13 '18 at 21:11
Ian MacDonaldIan MacDonald
9,01111230
9,01111230
add a comment |
add a comment |
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Found the solution! Turns out it wasn't the class method that was causing the error, but the fact that I was sending a tuple of one arg. So I needed to sent args=(arg2,). Note the comma! Got the solution from here: stackoverflow.com/questions/37116721/…
– cbasavaraj
Nov 13 '18 at 21:32