matplotlib - Remove undefined number from plot [duplicate]
This question already has an answer here:
Omit joining lines in matplotlib plot e.g. y = tan(x)
4 answers
I'm trying to plot f(x) = 1/x using Python and matplotlib. Currently, my code is:
import numpy as np
import matplotlib.pyplot as plt
def f(x):
return 1/x
t1 = np.arange(-4.0, 4.0, 1)
t2 = np.arange(-4.0, 4.0, 0.02)
figure = plt.figure(1)
ax = figure.add_subplot(111)
ax.tick_params(labeltop = True)
ax.set_ylim([-40,40])
plt.plot(t1, f(t1), 'bo', t2, f(t2), 'k')
The output is the following: 
It's obviously incorrect, and I'm certain that the problem occurs due to the fact that Python can't calculate the function at point x = 0 (as 1/0 is undefined)
Is it possible to somehow exclude x = 0 from the function?
(There is a question that's pretty much the same as this one, but I was unable to solve the problem with the answers there.)
Thanks!
python matplotlib
asked Nov 14 '18 at 15:06
werckwerck
6010
marked as duplicate by ImportanceOfBeingErnest matplotlib
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Nov 14 '18 at 15:27
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
Omit joining lines in matplotlib plot e.g. y = tan(x)
4 answers
I'm trying to plot f(x) = 1/x using Python and matplotlib. Currently, my code is:
import numpy as np
import matplotlib.pyplot as plt
def f(x):
return 1/x
t1 = np.arange(-4.0, 4.0, 1)
t2 = np.arange(-4.0, 4.0, 0.02)
figure = plt.figure(1)
ax = figure.add_subplot(111)
ax.tick_params(labeltop = True)
ax.set_ylim([-40,40])
plt.plot(t1, f(t1), 'bo', t2, f(t2), 'k')
The output is the following:
It's obviously incorrect, and I'm certain that the problem occurs due to the fact that Python can't calculate the function at point x = 0 (as 1/0 is undefined)
Is it possible to somehow exclude x = 0 from the function?
(There is a question that's pretty much the same as this one, but I was unable to solve the problem with the answers there.)
Thanks!
python matplotlib
asked Nov 14 '18 at 15:06
werckwerck
6010
marked as duplicate by ImportanceOfBeingErnest matplotlib
Users with the matplotlib badge can single-handedly close matplotlib questions as duplicates and reopen them as needed.
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Nov 14 '18 at 15:27
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
The solution is in the question itself using np.errstate.
– Scott Boston
Nov 14 '18 at 15:16
add a comment |
This question already has an answer here:
Omit joining lines in matplotlib plot e.g. y = tan(x)
4 answers
I'm trying to plot f(x) = 1/x using Python and matplotlib. Currently, my code is:
import numpy as np
import matplotlib.pyplot as plt
def f(x):
return 1/x
t1 = np.arange(-4.0, 4.0, 1)
t2 = np.arange(-4.0, 4.0, 0.02)
figure = plt.figure(1)
ax = figure.add_subplot(111)
ax.tick_params(labeltop = True)
ax.set_ylim([-40,40])
plt.plot(t1, f(t1), 'bo', t2, f(t2), 'k')
The output is the following:
It's obviously incorrect, and I'm certain that the problem occurs due to the fact that Python can't calculate the function at point x = 0 (as 1/0 is undefined)
Is it possible to somehow exclude x = 0 from the function?
(There is a question that's pretty much the same as this one, but I was unable to solve the problem with the answers there.)
Thanks!
python matplotlib
asked Nov 14 '18 at 15:06
werckwerck
6010
This question already has an answer here:
Omit joining lines in matplotlib plot e.g. y = tan(x)
4 answers
I'm trying to plot f(x) = 1/x using Python and matplotlib. Currently, my code is:
import numpy as np
import matplotlib.pyplot as plt
def f(x):
return 1/x
t1 = np.arange(-4.0, 4.0, 1)
t2 = np.arange(-4.0, 4.0, 0.02)
figure = plt.figure(1)
ax = figure.add_subplot(111)
ax.tick_params(labeltop = True)
ax.set_ylim([-40,40])
plt.plot(t1, f(t1), 'bo', t2, f(t2), 'k')
The output is the following:
It's obviously incorrect, and I'm certain that the problem occurs due to the fact that Python can't calculate the function at point x = 0 (as 1/0 is undefined)
Is it possible to somehow exclude x = 0 from the function?
(There is a question that's pretty much the same as this one, but I was unable to solve the problem with the answers there.)
Thanks!
This question already has an answer here:
Omit joining lines in matplotlib plot e.g. y = tan(x)
4 answers
python matplotlib
python matplotlib
asked Nov 14 '18 at 15:06
werckwerck
6010
asked Nov 14 '18 at 15:06
werckwerck
6010
asked Nov 14 '18 at 15:06
werckwerck
6010
asked Nov 14 '18 at 15:06
werckwerck
6010
asked Nov 14 '18 at 15:06
werckwerck
6010
6010
marked as duplicate by ImportanceOfBeingErnest matplotlib
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Nov 14 '18 at 15:27
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by ImportanceOfBeingErnest matplotlib
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Nov 14 '18 at 15:27
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
The solution is in the question itself using np.errstate.
– Scott Boston
Nov 14 '18 at 15:16
add a comment |
The solution is in the question itself using np.errstate.
– Scott Boston
Nov 14 '18 at 15:16
The solution is in the question itself using np.errstate.
– Scott Boston
Nov 14 '18 at 15:16
The solution is in the question itself using np.errstate.
– Scott Boston
Nov 14 '18 at 15:16
add a comment |
1 Answer
1
active
oldest
votes
It's not incorrect. It simply connects each of the points, and when you have one point at + infinity and the other at - infinity at x = 0, you'll get this line connecting the two. The easiest way of plotting it without the line is by plotting two graphs: one for x < 0 and one for x > 0:
import numpy as np
import matplotlib.pyplot as plt
def f(x):
return 1/x
t1a = np.arange(-4.0, 0, 1)
t1b = np.arange( 0, 4.0, 1)
t2a = np.arange(-4.0, 0, 0.02)
t2b = np.arange( 0, 4.0, 0.02)
figure = plt.figure(1)
ax = figure.add_subplot(111)
ax.tick_params(labeltop = True)
ax.set_ylim([-40,40])
plt.plot(t1a, f(t1a), 'bo', t2a, f(t2a), 'k')
plt.plot(t1b, f(t1b), 'bo', t2b, f(t2b), 'k')
plt.show()
resulting in:
answered Nov 14 '18 at 15:18
NathanNathan
1,239518
Perfect, thank you!
– werck
Nov 14 '18 at 15:21
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
It's not incorrect. It simply connects each of the points, and when you have one point at + infinity and the other at - infinity at x = 0, you'll get this line connecting the two. The easiest way of plotting it without the line is by plotting two graphs: one for x < 0 and one for x > 0:
import numpy as np
import matplotlib.pyplot as plt
def f(x):
return 1/x
t1a = np.arange(-4.0, 0, 1)
t1b = np.arange( 0, 4.0, 1)
t2a = np.arange(-4.0, 0, 0.02)
t2b = np.arange( 0, 4.0, 0.02)
figure = plt.figure(1)
ax = figure.add_subplot(111)
ax.tick_params(labeltop = True)
ax.set_ylim([-40,40])
plt.plot(t1a, f(t1a), 'bo', t2a, f(t2a), 'k')
plt.plot(t1b, f(t1b), 'bo', t2b, f(t2b), 'k')
plt.show()
resulting in:
answered Nov 14 '18 at 15:18
NathanNathan
1,239518
Perfect, thank you!
– werck
Nov 14 '18 at 15:21
add a comment |
It's not incorrect. It simply connects each of the points, and when you have one point at + infinity and the other at - infinity at x = 0, you'll get this line connecting the two. The easiest way of plotting it without the line is by plotting two graphs: one for x < 0 and one for x > 0:
import numpy as np
import matplotlib.pyplot as plt
def f(x):
return 1/x
t1a = np.arange(-4.0, 0, 1)
t1b = np.arange( 0, 4.0, 1)
t2a = np.arange(-4.0, 0, 0.02)
t2b = np.arange( 0, 4.0, 0.02)
figure = plt.figure(1)
ax = figure.add_subplot(111)
ax.tick_params(labeltop = True)
ax.set_ylim([-40,40])
plt.plot(t1a, f(t1a), 'bo', t2a, f(t2a), 'k')
plt.plot(t1b, f(t1b), 'bo', t2b, f(t2b), 'k')
plt.show()
resulting in:
answered Nov 14 '18 at 15:18
NathanNathan
1,239518
Perfect, thank you!
– werck
Nov 14 '18 at 15:21
add a comment |
It's not incorrect. It simply connects each of the points, and when you have one point at + infinity and the other at - infinity at x = 0, you'll get this line connecting the two. The easiest way of plotting it without the line is by plotting two graphs: one for x < 0 and one for x > 0:
import numpy as np
import matplotlib.pyplot as plt
def f(x):
return 1/x
t1a = np.arange(-4.0, 0, 1)
t1b = np.arange( 0, 4.0, 1)
t2a = np.arange(-4.0, 0, 0.02)
t2b = np.arange( 0, 4.0, 0.02)
figure = plt.figure(1)
ax = figure.add_subplot(111)
ax.tick_params(labeltop = True)
ax.set_ylim([-40,40])
plt.plot(t1a, f(t1a), 'bo', t2a, f(t2a), 'k')
plt.plot(t1b, f(t1b), 'bo', t2b, f(t2b), 'k')
plt.show()
resulting in:
answered Nov 14 '18 at 15:18
NathanNathan
1,239518
It's not incorrect. It simply connects each of the points, and when you have one point at + infinity and the other at - infinity at x = 0, you'll get this line connecting the two. The easiest way of plotting it without the line is by plotting two graphs: one for x < 0 and one for x > 0:
import numpy as np
import matplotlib.pyplot as plt
def f(x):
return 1/x
t1a = np.arange(-4.0, 0, 1)
t1b = np.arange( 0, 4.0, 1)
t2a = np.arange(-4.0, 0, 0.02)
t2b = np.arange( 0, 4.0, 0.02)
figure = plt.figure(1)
ax = figure.add_subplot(111)
ax.tick_params(labeltop = True)
ax.set_ylim([-40,40])
plt.plot(t1a, f(t1a), 'bo', t2a, f(t2a), 'k')
plt.plot(t1b, f(t1b), 'bo', t2b, f(t2b), 'k')
plt.show()
resulting in:
answered Nov 14 '18 at 15:18
NathanNathan
1,239518
answered Nov 14 '18 at 15:18
NathanNathan
1,239518
answered Nov 14 '18 at 15:18
NathanNathan
1,239518
answered Nov 14 '18 at 15:18
NathanNathan
1,239518
1,239518
Perfect, thank you!
– werck
Nov 14 '18 at 15:21
add a comment |
Perfect, thank you!
– werck
Nov 14 '18 at 15:21
Perfect, thank you!
– werck
Nov 14 '18 at 15:21
Perfect, thank you!
– werck
Nov 14 '18 at 15:21
add a comment |
The solution is in the question itself using np.errstate.
– Scott Boston
Nov 14 '18 at 15:16