Is there a “fingerprinting algorithm” devoid of any collisions?












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I'm looking for a "fingerprinting algorithm" that is truly devoid of any probability of collision*. The "Rabin's algorithm", for example, is a very good scheme for being fast and easy to implement; but yet, it does have a "negligible" probability of a collision!



Please shed some lights on this.




* Collision: Two inputs yielding the same fingerprint








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  • 3





    No, not in general. A fingerprint is (generally) smaller than the object from which it is generated, therefore it is impossible to have a different fingerprint for every possible input. Read about hash functions and hash collisions for more information.

    – jdehesa
    Nov 14 '18 at 16:30


















0















I'm looking for a "fingerprinting algorithm" that is truly devoid of any probability of collision*. The "Rabin's algorithm", for example, is a very good scheme for being fast and easy to implement; but yet, it does have a "negligible" probability of a collision!



Please shed some lights on this.




* Collision: Two inputs yielding the same fingerprint








share|improve this question


















  • 3





    No, not in general. A fingerprint is (generally) smaller than the object from which it is generated, therefore it is impossible to have a different fingerprint for every possible input. Read about hash functions and hash collisions for more information.

    – jdehesa
    Nov 14 '18 at 16:30
















0












0








0








I'm looking for a "fingerprinting algorithm" that is truly devoid of any probability of collision*. The "Rabin's algorithm", for example, is a very good scheme for being fast and easy to implement; but yet, it does have a "negligible" probability of a collision!



Please shed some lights on this.




* Collision: Two inputs yielding the same fingerprint








share|improve this question














I'm looking for a "fingerprinting algorithm" that is truly devoid of any probability of collision*. The "Rabin's algorithm", for example, is a very good scheme for being fast and easy to implement; but yet, it does have a "negligible" probability of a collision!



Please shed some lights on this.




* Collision: Two inputs yielding the same fingerprint





algorithm






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share|improve this question











share|improve this question




share|improve this question










asked Nov 14 '18 at 16:13









goodUsergoodUser

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7817








  • 3





    No, not in general. A fingerprint is (generally) smaller than the object from which it is generated, therefore it is impossible to have a different fingerprint for every possible input. Read about hash functions and hash collisions for more information.

    – jdehesa
    Nov 14 '18 at 16:30
















  • 3





    No, not in general. A fingerprint is (generally) smaller than the object from which it is generated, therefore it is impossible to have a different fingerprint for every possible input. Read about hash functions and hash collisions for more information.

    – jdehesa
    Nov 14 '18 at 16:30










3




3





No, not in general. A fingerprint is (generally) smaller than the object from which it is generated, therefore it is impossible to have a different fingerprint for every possible input. Read about hash functions and hash collisions for more information.

– jdehesa
Nov 14 '18 at 16:30







No, not in general. A fingerprint is (generally) smaller than the object from which it is generated, therefore it is impossible to have a different fingerprint for every possible input. Read about hash functions and hash collisions for more information.

– jdehesa
Nov 14 '18 at 16:30














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