Search from Array with custom fields Swift

I have an arrays

var searchArray = [(

    ean: String,

    name: String,

    weight: String,

    brand: String,

    percent: String,

    inside: String,

    img: String,

    packet: String,

    date: String)

    ]()



var searchArrayFiltered = [(

    ean: String,

    name: String,

    weight: String,

    brand: String,

    percent: String,

    inside: String,

    img: String,

    packet: String,

    date: String)

    ]()

I have a code for search from arrays and show result in table:

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchArrayFiltered = searchText.isEmpty ? searchArray : searchArray.filter({(dataString: String) -> Bool in

        return dataString.(of: searchText, options: .caseInsensitive) != nil

    })



    tableView.reloadData()

}

But in line return dataString.String(of: searchText, options: .caseInsensitive) != nil i have an error:

Value of tuple type '(ean: String, name: String, weight: String,
brand: String, percent: String, inside: String, img: String, packet:
String, date: String)' has no member 'String'

If I change dataString.String to dataString.name, I have an error:

Cannot call value of non-function type 'String'

Please help me to do search from searchArray for "name".

asked Nov 13 '18 at 11:16

Артем Ильинский

889

add a comment |

I have an arrays

var searchArray = [(

    ean: String,

    name: String,

    weight: String,

    brand: String,

    percent: String,

    inside: String,

    img: String,

    packet: String,

    date: String)

    ]()



var searchArrayFiltered = [(

    ean: String,

    name: String,

    weight: String,

    brand: String,

    percent: String,

    inside: String,

    img: String,

    packet: String,

    date: String)

    ]()

I have a code for search from arrays and show result in table:

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchArrayFiltered = searchText.isEmpty ? searchArray : searchArray.filter({(dataString: String) -> Bool in

        return dataString.(of: searchText, options: .caseInsensitive) != nil

    })



    tableView.reloadData()

}

But in line return dataString.String(of: searchText, options: .caseInsensitive) != nil i have an error:

Value of tuple type '(ean: String, name: String, weight: String,
brand: String, percent: String, inside: String, img: String, packet:
String, date: String)' has no member 'String'

If I change dataString.String to dataString.name, I have an error:

Cannot call value of non-function type 'String'

Please help me to do search from searchArray for "name".

asked Nov 13 '18 at 11:16

Артем Ильинский

889

add a comment |

I have an arrays

var searchArray = [(

    ean: String,

    name: String,

    weight: String,

    brand: String,

    percent: String,

    inside: String,

    img: String,

    packet: String,

    date: String)

    ]()



var searchArrayFiltered = [(

    ean: String,

    name: String,

    weight: String,

    brand: String,

    percent: String,

    inside: String,

    img: String,

    packet: String,

    date: String)

    ]()

I have a code for search from arrays and show result in table:

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchArrayFiltered = searchText.isEmpty ? searchArray : searchArray.filter({(dataString: String) -> Bool in

        return dataString.(of: searchText, options: .caseInsensitive) != nil

    })



    tableView.reloadData()

}

But in line return dataString.String(of: searchText, options: .caseInsensitive) != nil i have an error:

Value of tuple type '(ean: String, name: String, weight: String,
brand: String, percent: String, inside: String, img: String, packet:
String, date: String)' has no member 'String'

If I change dataString.String to dataString.name, I have an error:

Cannot call value of non-function type 'String'

Please help me to do search from searchArray for "name".

asked Nov 13 '18 at 11:16

Артем Ильинский

889

I have an arrays

var searchArray = [(

    ean: String,

    name: String,

    weight: String,

    brand: String,

    percent: String,

    inside: String,

    img: String,

    packet: String,

    date: String)

    ]()



var searchArrayFiltered = [(

    ean: String,

    name: String,

    weight: String,

    brand: String,

    percent: String,

    inside: String,

    img: String,

    packet: String,

    date: String)

    ]()

I have a code for search from arrays and show result in table:

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchArrayFiltered = searchText.isEmpty ? searchArray : searchArray.filter({(dataString: String) -> Bool in

        return dataString.(of: searchText, options: .caseInsensitive) != nil

    })



    tableView.reloadData()

}

But in line return dataString.String(of: searchText, options: .caseInsensitive) != nil i have an error:

Value of tuple type '(ean: String, name: String, weight: String,
brand: String, percent: String, inside: String, img: String, packet:
String, date: String)' has no member 'String'

If I change dataString.String to dataString.name, I have an error:

Cannot call value of non-function type 'String'

Please help me to do search from searchArray for "name".

ios arrays swift search

asked Nov 13 '18 at 11:16

Артем Ильинский

889

asked Nov 13 '18 at 11:16

Артем Ильинский

889

asked Nov 13 '18 at 11:16

Артем Ильинский

889

asked Nov 13 '18 at 11:16

Артем Ильинский

889

asked Nov 13 '18 at 11:16

Артем Ильинский

889

add a comment |

2 Answers
2

active

oldest

votes

First of all you are discouraged from using a tuple as array type. Use a custom struct or class

Apple says:

Tuples are useful for temporary groups of related values. They’re not suited to the creation of complex data structures. If your data structure is likely to persist beyond a temporary scope, model it as a class or structure, rather than as a tuple.

There are two major issues:

Copy&Paste mistake, you mean dataString.range(of...

dataString is not a string, it's a tuple (the type annotation is redundant)

Change the function to

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchArrayFiltered = searchText.isEmpty ? searchArray : searchArray.filter({tuple -> Bool in

        return tuple.name.range(of: searchText, options: .caseInsensitive) != nil

    })



    tableView.reloadData()

}

answered Nov 13 '18 at 11:27

vadian

146k13157175

Thank you very much. I'm always working with javaandroid, and swift for me is Hell.

– Артем Ильинский
Nov 13 '18 at 11:39

add a comment |

create a struct for

struct Model {

    var ean: String

    var name: String

    var weight: String

    var brand: String

    var percent: String

    var inside: String

    var img: String

    var packet: String

    var date: String

}

then apply filter on your [Model]

answered Nov 13 '18 at 11:31

Viren Malhan

755

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

First of all you are discouraged from using a tuple as array type. Use a custom struct or class

Apple says:

Tuples are useful for temporary groups of related values. They’re not suited to the creation of complex data structures. If your data structure is likely to persist beyond a temporary scope, model it as a class or structure, rather than as a tuple.

There are two major issues:

Copy&Paste mistake, you mean dataString.range(of...

dataString is not a string, it's a tuple (the type annotation is redundant)

Change the function to

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchArrayFiltered = searchText.isEmpty ? searchArray : searchArray.filter({tuple -> Bool in

        return tuple.name.range(of: searchText, options: .caseInsensitive) != nil

    })



    tableView.reloadData()

}

answered Nov 13 '18 at 11:27

vadian

146k13157175

Thank you very much. I'm always working with javaandroid, and swift for me is Hell.

– Артем Ильинский
Nov 13 '18 at 11:39

add a comment |

First of all you are discouraged from using a tuple as array type. Use a custom struct or class

Apple says:

Tuples are useful for temporary groups of related values. They’re not suited to the creation of complex data structures. If your data structure is likely to persist beyond a temporary scope, model it as a class or structure, rather than as a tuple.

There are two major issues:

Copy&Paste mistake, you mean dataString.range(of...

dataString is not a string, it's a tuple (the type annotation is redundant)

Change the function to

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchArrayFiltered = searchText.isEmpty ? searchArray : searchArray.filter({tuple -> Bool in

        return tuple.name.range(of: searchText, options: .caseInsensitive) != nil

    })



    tableView.reloadData()

}

answered Nov 13 '18 at 11:27

vadian

146k13157175

Thank you very much. I'm always working with javaandroid, and swift for me is Hell.

– Артем Ильинский
Nov 13 '18 at 11:39

add a comment |

First of all you are discouraged from using a tuple as array type. Use a custom struct or class

Apple says:

Tuples are useful for temporary groups of related values. They’re not suited to the creation of complex data structures. If your data structure is likely to persist beyond a temporary scope, model it as a class or structure, rather than as a tuple.

There are two major issues:

Copy&Paste mistake, you mean dataString.range(of...

dataString is not a string, it's a tuple (the type annotation is redundant)

Change the function to

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchArrayFiltered = searchText.isEmpty ? searchArray : searchArray.filter({tuple -> Bool in

        return tuple.name.range(of: searchText, options: .caseInsensitive) != nil

    })



    tableView.reloadData()

}

answered Nov 13 '18 at 11:27

vadian

146k13157175

First of all you are discouraged from using a tuple as array type. Use a custom struct or class

Apple says:

Tuples are useful for temporary groups of related values. They’re not suited to the creation of complex data structures. If your data structure is likely to persist beyond a temporary scope, model it as a class or structure, rather than as a tuple.

There are two major issues:

Copy&Paste mistake, you mean dataString.range(of...

dataString is not a string, it's a tuple (the type annotation is redundant)

Change the function to

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchArrayFiltered = searchText.isEmpty ? searchArray : searchArray.filter({tuple -> Bool in

        return tuple.name.range(of: searchText, options: .caseInsensitive) != nil

    })



    tableView.reloadData()

}

answered Nov 13 '18 at 11:27

vadian

146k13157175

answered Nov 13 '18 at 11:27

vadian

146k13157175

answered Nov 13 '18 at 11:27

vadian

146k13157175

answered Nov 13 '18 at 11:27

vadian

146k13157175

Thank you very much. I'm always working with javaandroid, and swift for me is Hell.

– Артем Ильинский
Nov 13 '18 at 11:39

add a comment |

Thank you very much. I'm always working with javaandroid, and swift for me is Hell.

– Артем Ильинский
Nov 13 '18 at 11:39

Thank you very much. I'm always working with javaandroid, and swift for me is Hell.

– Артем Ильинский
Nov 13 '18 at 11:39

add a comment |

create a struct for

struct Model {

    var ean: String

    var name: String

    var weight: String

    var brand: String

    var percent: String

    var inside: String

    var img: String

    var packet: String

    var date: String

}

then apply filter on your [Model]

answered Nov 13 '18 at 11:31

Viren Malhan

755

add a comment |

create a struct for

struct Model {

    var ean: String

    var name: String

    var weight: String

    var brand: String

    var percent: String

    var inside: String

    var img: String

    var packet: String

    var date: String

}

then apply filter on your [Model]

answered Nov 13 '18 at 11:31

Viren Malhan

755

add a comment |

create a struct for

struct Model {

    var ean: String

    var name: String

    var weight: String

    var brand: String

    var percent: String

    var inside: String

    var img: String

    var packet: String

    var date: String

}

then apply filter on your [Model]

answered Nov 13 '18 at 11:31

Viren Malhan

755

create a struct for

struct Model {

    var ean: String

    var name: String

    var weight: String

    var brand: String

    var percent: String

    var inside: String

    var img: String

    var packet: String

    var date: String

}

then apply filter on your [Model]

answered Nov 13 '18 at 11:31

Viren Malhan

755

answered Nov 13 '18 at 11:31

Viren Malhan

755

answered Nov 13 '18 at 11:31

Viren Malhan

755

answered Nov 13 '18 at 11:31

Viren Malhan

755

add a comment |

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