Python: How to check if a word appears more than once in a text. (No Sets)

-1

In my assignment, I have a text and I want to count how many times that words appeared in the text. For example, let's say I have a text file saying.

I have lots of cats and dogs. I have 3 cats and 16 dogs. I love dogs!

Since the words dogs appeared 3 times, I need the output to be that number. However, how would I do this for a random text?

So far I've come up with the following.

file = open('phrases.txt')

text = file.read()

file.close()



count  = countWords()

duplicates = 0 



for words in text:

    if words #appear twice or more 



    #if duplicates 

    duplicates+=1 



unique = count - duplicates 

#subtract the total, by the amount of duplicates.

print(unique)

countWords() is another function I made which counts the amount of total words inside the text**

asked Nov 12 '18 at 20:42

Alegria

1

dictionaries`? collections.Counter?
– Patrick Artner
Nov 12 '18 at 20:49

Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. 5N particular, we expect you to research your question before posting here.
– Prune
Nov 12 '18 at 21:02

add a comment |

-1

In my assignment, I have a text and I want to count how many times that words appeared in the text. For example, let's say I have a text file saying.

I have lots of cats and dogs. I have 3 cats and 16 dogs. I love dogs!

Since the words dogs appeared 3 times, I need the output to be that number. However, how would I do this for a random text?

So far I've come up with the following.

file = open('phrases.txt')

text = file.read()

file.close()



count  = countWords()

duplicates = 0 



for words in text:

    if words #appear twice or more 



    #if duplicates 

    duplicates+=1 



unique = count - duplicates 

#subtract the total, by the amount of duplicates.

print(unique)

countWords() is another function I made which counts the amount of total words inside the text**

asked Nov 12 '18 at 20:42

Alegria

1

dictionaries`? collections.Counter?
– Patrick Artner
Nov 12 '18 at 20:49

Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. 5N particular, we expect you to research your question before posting here.
– Prune
Nov 12 '18 at 21:02

add a comment |

-1

In my assignment, I have a text and I want to count how many times that words appeared in the text. For example, let's say I have a text file saying.

I have lots of cats and dogs. I have 3 cats and 16 dogs. I love dogs!

Since the words dogs appeared 3 times, I need the output to be that number. However, how would I do this for a random text?

So far I've come up with the following.

file = open('phrases.txt')

text = file.read()

file.close()



count  = countWords()

duplicates = 0 



for words in text:

    if words #appear twice or more 



    #if duplicates 

    duplicates+=1 



unique = count - duplicates 

#subtract the total, by the amount of duplicates.

print(unique)

countWords() is another function I made which counts the amount of total words inside the text**

asked Nov 12 '18 at 20:42

Alegria

In my assignment, I have a text and I want to count how many times that words appeared in the text. For example, let's say I have a text file saying.

I have lots of cats and dogs. I have 3 cats and 16 dogs. I love dogs!

Since the words dogs appeared 3 times, I need the output to be that number. However, how would I do this for a random text?

So far I've come up with the following.

file = open('phrases.txt')

text = file.read()

file.close()



count  = countWords()

duplicates = 0 



for words in text:

    if words #appear twice or more 



    #if duplicates 

    duplicates+=1 



unique = count - duplicates 

#subtract the total, by the amount of duplicates.

print(unique)

countWords() is another function I made which counts the amount of total words inside the text**

python string python-3.x list file-io

asked Nov 12 '18 at 20:42

Alegria

asked Nov 12 '18 at 20:42

Alegria

asked Nov 12 '18 at 20:42

Alegria

asked Nov 12 '18 at 20:42

Alegria

asked Nov 12 '18 at 20:42

Alegria

1

dictionaries`? collections.Counter?
– Patrick Artner
Nov 12 '18 at 20:49

Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. 5N particular, we expect you to research your question before posting here.
– Prune
Nov 12 '18 at 21:02

add a comment |

1

dictionaries`? collections.Counter?
– Patrick Artner
Nov 12 '18 at 20:49

Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. 5N particular, we expect you to research your question before posting here.
– Prune
Nov 12 '18 at 21:02

dictionaries`? collections.Counter?
– Patrick Artner
Nov 12 '18 at 20:49

Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. 5N particular, we expect you to research your question before posting here.
– Prune
Nov 12 '18 at 21:02

add a comment |

2 Answers
2

active

oldest

votes

words = text.split()

counts = {}

for word in words:

if word not in counts:

    counts[word] = 0

counts[word] += 1



for k,v in counts.items() :

    if v==1 :

        print(k)

edited Nov 12 '18 at 20:50

answered Nov 12 '18 at 20:44

Sari Masri

1297

I'm getting KeyError at count[words]+=1
– Alegria
Nov 12 '18 at 23:14

Also can you explain your code?
– Alegria
Nov 12 '18 at 23:14

I tried my code it works perfectly, the idea is you read lines from a file, and store it in array using split() to remove whitespace from a line ,then you make a dictionary and store the world in a key and the count in a value, so you have every world with its count ,and that it, in the last for loop you are printing the unique words which have count =1, please vote up and choose the question as best answer and if you have any problem please contact me
– Sari Masri
Nov 13 '18 at 5:58

add a comment |

    text = "I have lots of cats and dogs. I have 3 cats and 16 dogs. I love dogs!"



    find = "dogs"

    count = 0



    for index, letter in enumerate(text):

        if letter == find[0]:

            word = text[index: index + len(find)]



            if word == find:

                count += 1



    print(count)

answered Nov 12 '18 at 21:06

Baryon

365

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

words = text.split()

counts = {}

for word in words:

if word not in counts:

    counts[word] = 0

counts[word] += 1



for k,v in counts.items() :

    if v==1 :

        print(k)

edited Nov 12 '18 at 20:50

answered Nov 12 '18 at 20:44

Sari Masri

1297

I'm getting KeyError at count[words]+=1
– Alegria
Nov 12 '18 at 23:14

Also can you explain your code?
– Alegria
Nov 12 '18 at 23:14

I tried my code it works perfectly, the idea is you read lines from a file, and store it in array using split() to remove whitespace from a line ,then you make a dictionary and store the world in a key and the count in a value, so you have every world with its count ,and that it, in the last for loop you are printing the unique words which have count =1, please vote up and choose the question as best answer and if you have any problem please contact me
– Sari Masri
Nov 13 '18 at 5:58

add a comment |

words = text.split()

counts = {}

for word in words:

if word not in counts:

    counts[word] = 0

counts[word] += 1



for k,v in counts.items() :

    if v==1 :

        print(k)

edited Nov 12 '18 at 20:50

answered Nov 12 '18 at 20:44

Sari Masri

1297

I'm getting KeyError at count[words]+=1
– Alegria
Nov 12 '18 at 23:14

Also can you explain your code?
– Alegria
Nov 12 '18 at 23:14

I tried my code it works perfectly, the idea is you read lines from a file, and store it in array using split() to remove whitespace from a line ,then you make a dictionary and store the world in a key and the count in a value, so you have every world with its count ,and that it, in the last for loop you are printing the unique words which have count =1, please vote up and choose the question as best answer and if you have any problem please contact me
– Sari Masri
Nov 13 '18 at 5:58

add a comment |

words = text.split()

counts = {}

for word in words:

if word not in counts:

    counts[word] = 0

counts[word] += 1



for k,v in counts.items() :

    if v==1 :

        print(k)

edited Nov 12 '18 at 20:50

answered Nov 12 '18 at 20:44

Sari Masri

1297

words = text.split()

counts = {}

for word in words:

if word not in counts:

    counts[word] = 0

counts[word] += 1



for k,v in counts.items() :

    if v==1 :

        print(k)

edited Nov 12 '18 at 20:50

answered Nov 12 '18 at 20:44

Sari Masri

1297

edited Nov 12 '18 at 20:50

answered Nov 12 '18 at 20:44

Sari Masri

1297

answered Nov 12 '18 at 20:44

Sari Masri

1297

answered Nov 12 '18 at 20:44

Sari Masri

1297

I'm getting KeyError at count[words]+=1
– Alegria
Nov 12 '18 at 23:14

Also can you explain your code?
– Alegria
Nov 12 '18 at 23:14

I tried my code it works perfectly, the idea is you read lines from a file, and store it in array using split() to remove whitespace from a line ,then you make a dictionary and store the world in a key and the count in a value, so you have every world with its count ,and that it, in the last for loop you are printing the unique words which have count =1, please vote up and choose the question as best answer and if you have any problem please contact me
– Sari Masri
Nov 13 '18 at 5:58

add a comment |

I'm getting KeyError at count[words]+=1
– Alegria
Nov 12 '18 at 23:14

Also can you explain your code?
– Alegria
Nov 12 '18 at 23:14

I tried my code it works perfectly, the idea is you read lines from a file, and store it in array using split() to remove whitespace from a line ,then you make a dictionary and store the world in a key and the count in a value, so you have every world with its count ,and that it, in the last for loop you are printing the unique words which have count =1, please vote up and choose the question as best answer and if you have any problem please contact me
– Sari Masri
Nov 13 '18 at 5:58

I'm getting KeyError at count[words]+=1
– Alegria
Nov 12 '18 at 23:14

Also can you explain your code?
– Alegria
Nov 12 '18 at 23:14

I tried my code it works perfectly, the idea is you read lines from a file, and store it in array using split() to remove whitespace from a line ,then you make a dictionary and store the world in a key and the count in a value, so you have every world with its count ,and that it, in the last for loop you are printing the unique words which have count =1, please vote up and choose the question as best answer and if you have any problem please contact me
– Sari Masri
Nov 13 '18 at 5:58

add a comment |

    text = "I have lots of cats and dogs. I have 3 cats and 16 dogs. I love dogs!"



    find = "dogs"

    count = 0



    for index, letter in enumerate(text):

        if letter == find[0]:

            word = text[index: index + len(find)]



            if word == find:

                count += 1



    print(count)

answered Nov 12 '18 at 21:06

Baryon

365

add a comment |

    text = "I have lots of cats and dogs. I have 3 cats and 16 dogs. I love dogs!"



    find = "dogs"

    count = 0



    for index, letter in enumerate(text):

        if letter == find[0]:

            word = text[index: index + len(find)]



            if word == find:

                count += 1



    print(count)

answered Nov 12 '18 at 21:06

Baryon

365

add a comment |

    text = "I have lots of cats and dogs. I have 3 cats and 16 dogs. I love dogs!"



    find = "dogs"

    count = 0



    for index, letter in enumerate(text):

        if letter == find[0]:

            word = text[index: index + len(find)]



            if word == find:

                count += 1



    print(count)

answered Nov 12 '18 at 21:06

Baryon

365

    text = "I have lots of cats and dogs. I have 3 cats and 16 dogs. I love dogs!"



    find = "dogs"

    count = 0



    for index, letter in enumerate(text):

        if letter == find[0]:

            word = text[index: index + len(find)]



            if word == find:

                count += 1



    print(count)

answered Nov 12 '18 at 21:06

Baryon

365

answered Nov 12 '18 at 21:06

Baryon

365

answered Nov 12 '18 at 21:06

Baryon

365

answered Nov 12 '18 at 21:06

Baryon

365

add a comment |

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