How does a var inside While Loop intercept Print function and manipulate outside var?
I'm new to Python but having a hard time to understand the following While Loop code as it behaves very differently. I know this code work but I do not know HOW IT WORK. Top Python experts also have no idea.
x = 1
while x < 10:
print x
x = x + 1 ## How does this VAR manipulate Print as the VAR comes late in the code?
I do not know whether this related to control flow or global var. Please help me out to understand deeper.
python python-2.7
|
show 2 more comments
I'm new to Python but having a hard time to understand the following While Loop code as it behaves very differently. I know this code work but I do not know HOW IT WORK. Top Python experts also have no idea.
x = 1
while x < 10:
print x
x = x + 1 ## How does this VAR manipulate Print as the VAR comes late in the code?
I do not know whether this related to control flow or global var. Please help me out to understand deeper.
python python-2.7
It's unclear what you're asking. What are you confused about? I think this is a question of declaration and I initialization vs reassignment.
– Carcigenicate
Nov 13 '18 at 18:11
Is this a question about scope?
– Matt Cremeens
Nov 13 '18 at 18:12
You're increasing the value ofx
by 1 in each iteration of the loop. Whenx=10
you'll break out of the loop. When you exit the loop:x=10
.
– Adam Mitchell
Nov 13 '18 at 18:12
There is only 1 variable namedx
in your script.
– Johnny Mopp
Nov 13 '18 at 18:13
2
Top Python experts also have no idea.
This seems highly unlikely! Beware of learning from people who don't really know what they are doing.
– Kirk Broadhurst
Nov 13 '18 at 19:25
|
show 2 more comments
I'm new to Python but having a hard time to understand the following While Loop code as it behaves very differently. I know this code work but I do not know HOW IT WORK. Top Python experts also have no idea.
x = 1
while x < 10:
print x
x = x + 1 ## How does this VAR manipulate Print as the VAR comes late in the code?
I do not know whether this related to control flow or global var. Please help me out to understand deeper.
python python-2.7
I'm new to Python but having a hard time to understand the following While Loop code as it behaves very differently. I know this code work but I do not know HOW IT WORK. Top Python experts also have no idea.
x = 1
while x < 10:
print x
x = x + 1 ## How does this VAR manipulate Print as the VAR comes late in the code?
I do not know whether this related to control flow or global var. Please help me out to understand deeper.
python python-2.7
python python-2.7
edited Nov 13 '18 at 18:19
user2722968
2,67211637
2,67211637
asked Nov 13 '18 at 18:09
GashexGashex
76
76
It's unclear what you're asking. What are you confused about? I think this is a question of declaration and I initialization vs reassignment.
– Carcigenicate
Nov 13 '18 at 18:11
Is this a question about scope?
– Matt Cremeens
Nov 13 '18 at 18:12
You're increasing the value ofx
by 1 in each iteration of the loop. Whenx=10
you'll break out of the loop. When you exit the loop:x=10
.
– Adam Mitchell
Nov 13 '18 at 18:12
There is only 1 variable namedx
in your script.
– Johnny Mopp
Nov 13 '18 at 18:13
2
Top Python experts also have no idea.
This seems highly unlikely! Beware of learning from people who don't really know what they are doing.
– Kirk Broadhurst
Nov 13 '18 at 19:25
|
show 2 more comments
It's unclear what you're asking. What are you confused about? I think this is a question of declaration and I initialization vs reassignment.
– Carcigenicate
Nov 13 '18 at 18:11
Is this a question about scope?
– Matt Cremeens
Nov 13 '18 at 18:12
You're increasing the value ofx
by 1 in each iteration of the loop. Whenx=10
you'll break out of the loop. When you exit the loop:x=10
.
– Adam Mitchell
Nov 13 '18 at 18:12
There is only 1 variable namedx
in your script.
– Johnny Mopp
Nov 13 '18 at 18:13
2
Top Python experts also have no idea.
This seems highly unlikely! Beware of learning from people who don't really know what they are doing.
– Kirk Broadhurst
Nov 13 '18 at 19:25
It's unclear what you're asking. What are you confused about? I think this is a question of declaration and I initialization vs reassignment.
– Carcigenicate
Nov 13 '18 at 18:11
It's unclear what you're asking. What are you confused about? I think this is a question of declaration and I initialization vs reassignment.
– Carcigenicate
Nov 13 '18 at 18:11
Is this a question about scope?
– Matt Cremeens
Nov 13 '18 at 18:12
Is this a question about scope?
– Matt Cremeens
Nov 13 '18 at 18:12
You're increasing the value of
x
by 1 in each iteration of the loop. When x=10
you'll break out of the loop. When you exit the loop: x=10
.– Adam Mitchell
Nov 13 '18 at 18:12
You're increasing the value of
x
by 1 in each iteration of the loop. When x=10
you'll break out of the loop. When you exit the loop: x=10
.– Adam Mitchell
Nov 13 '18 at 18:12
There is only 1 variable named
x
in your script.– Johnny Mopp
Nov 13 '18 at 18:13
There is only 1 variable named
x
in your script.– Johnny Mopp
Nov 13 '18 at 18:13
2
2
Top Python experts also have no idea.
This seems highly unlikely! Beware of learning from people who don't really know what they are doing.– Kirk Broadhurst
Nov 13 '18 at 19:25
Top Python experts also have no idea.
This seems highly unlikely! Beware of learning from people who don't really know what they are doing.– Kirk Broadhurst
Nov 13 '18 at 19:25
|
show 2 more comments
3 Answers
3
active
oldest
votes
I believe your question is about scope. In the above example, a new memory address for var x
is created on the first line and any code on lines 2,3,4 that access x
can read/write to that variable.
There are only two rules here that we need to follow:
x
must be declared beforeprint
so that print can access that piece of memory
print
must be in the same or inner scope to access 'x'
Example 1 - valid (because we follow rules 1 and 2)
x = 1
print x
Example 2 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
Example 3 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
print x
Example 4 - NOT valid (because we don't follow rule 1 and print
is accessing a variable that has not yet been created in memory)
print x
x = 1
Example 5 - NOT valid (because we don't follow rule 2 and print
doesn't have access to our variable's scope, x
no longer exists in memory)
y = 1
while y < 5:
x = 1
y = y + 1
print x
It would do you good to read this entire section on variable lifetime and scope in python all the way through Exercise 1 for good practice.
What bout this one? x = 1 while x < 10: x = x + 1 print x
– Gashex
Nov 13 '18 at 19:00
The results start from 2 to 9 in other code I mentioned in the above comment while the main question code results start from 1 to 9.
– Gashex
Nov 13 '18 at 19:19
I actually understand that basic example 1 but when it comes to while loop related binding things getting messy for me.
– Gashex
Nov 13 '18 at 19:22
i can't understand your example because in python tabbing is important
– Max
Nov 16 '18 at 7:02
check [link] (pastebin.com/mUXXdDsw)
– Gashex
Nov 16 '18 at 18:19
|
show 3 more comments
x = 1 #Declares the variable
while x < 10: #checks whether the value of x is less than 10 every time the loop runs
print x #prints value of x for the each iterations(1 for first iteration, 2 for second and so on)
x = x + 1 #this is the update part
Let me tell you one more thing, you do not have any case of global variable here.
If you have trouble in understanding whether its global or local declaration, I would recommend you to follow this link
add a comment |
Counter variable act like a tiny persistent storage. While loop checks whether the stored value in that tiny persistent storage Less than 11. If the value less than 10 then it starts the loop. Inside the loop, it instructs to Print value 1 because it's the current value in that tiny persistent storage after that the other "x" inside loop instruct that tiny persistent storage to update value by adding +1. This loop continues until it gets alert from persistent storage that value stored in persistent storage met 10 value. The loop will successfully exist.
This little software helped me to understand behind scenes http://pythontutor.com/visualize.html
Conclusion:
It seems For loops better for this kind things because it's clean and easy to maintain but understanding this concept is also important
This answer to your own question is ridden with errors and misunderstandings. There is no comparison to 11, only to 10. There is no 'other' x variable, as all of your code is part of the same scope. There is no such thing as an 'alert from persistent storage to the loop'. This shouldn't be the accepted answer.
– Thierry Lathuille
Nov 17 '18 at 22:40
@ThierryLathuille I'm sorry but I made it easier for a newbie to understand. You are correct about 10. I put 11 by mistake. "alert from persistent storage to the loop" means the code check current memory.
– Gashex
Nov 18 '18 at 5:04
@ThierryLathuille What kind of definition you have for other "x' inside the code if it, not a variable?
– Gashex
Nov 18 '18 at 5:07
@ThierryLathuille Are you there?
– Gashex
Dec 1 '18 at 21:38
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
I believe your question is about scope. In the above example, a new memory address for var x
is created on the first line and any code on lines 2,3,4 that access x
can read/write to that variable.
There are only two rules here that we need to follow:
x
must be declared beforeprint
so that print can access that piece of memory
print
must be in the same or inner scope to access 'x'
Example 1 - valid (because we follow rules 1 and 2)
x = 1
print x
Example 2 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
Example 3 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
print x
Example 4 - NOT valid (because we don't follow rule 1 and print
is accessing a variable that has not yet been created in memory)
print x
x = 1
Example 5 - NOT valid (because we don't follow rule 2 and print
doesn't have access to our variable's scope, x
no longer exists in memory)
y = 1
while y < 5:
x = 1
y = y + 1
print x
It would do you good to read this entire section on variable lifetime and scope in python all the way through Exercise 1 for good practice.
What bout this one? x = 1 while x < 10: x = x + 1 print x
– Gashex
Nov 13 '18 at 19:00
The results start from 2 to 9 in other code I mentioned in the above comment while the main question code results start from 1 to 9.
– Gashex
Nov 13 '18 at 19:19
I actually understand that basic example 1 but when it comes to while loop related binding things getting messy for me.
– Gashex
Nov 13 '18 at 19:22
i can't understand your example because in python tabbing is important
– Max
Nov 16 '18 at 7:02
check [link] (pastebin.com/mUXXdDsw)
– Gashex
Nov 16 '18 at 18:19
|
show 3 more comments
I believe your question is about scope. In the above example, a new memory address for var x
is created on the first line and any code on lines 2,3,4 that access x
can read/write to that variable.
There are only two rules here that we need to follow:
x
must be declared beforeprint
so that print can access that piece of memory
print
must be in the same or inner scope to access 'x'
Example 1 - valid (because we follow rules 1 and 2)
x = 1
print x
Example 2 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
Example 3 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
print x
Example 4 - NOT valid (because we don't follow rule 1 and print
is accessing a variable that has not yet been created in memory)
print x
x = 1
Example 5 - NOT valid (because we don't follow rule 2 and print
doesn't have access to our variable's scope, x
no longer exists in memory)
y = 1
while y < 5:
x = 1
y = y + 1
print x
It would do you good to read this entire section on variable lifetime and scope in python all the way through Exercise 1 for good practice.
What bout this one? x = 1 while x < 10: x = x + 1 print x
– Gashex
Nov 13 '18 at 19:00
The results start from 2 to 9 in other code I mentioned in the above comment while the main question code results start from 1 to 9.
– Gashex
Nov 13 '18 at 19:19
I actually understand that basic example 1 but when it comes to while loop related binding things getting messy for me.
– Gashex
Nov 13 '18 at 19:22
i can't understand your example because in python tabbing is important
– Max
Nov 16 '18 at 7:02
check [link] (pastebin.com/mUXXdDsw)
– Gashex
Nov 16 '18 at 18:19
|
show 3 more comments
I believe your question is about scope. In the above example, a new memory address for var x
is created on the first line and any code on lines 2,3,4 that access x
can read/write to that variable.
There are only two rules here that we need to follow:
x
must be declared beforeprint
so that print can access that piece of memory
print
must be in the same or inner scope to access 'x'
Example 1 - valid (because we follow rules 1 and 2)
x = 1
print x
Example 2 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
Example 3 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
print x
Example 4 - NOT valid (because we don't follow rule 1 and print
is accessing a variable that has not yet been created in memory)
print x
x = 1
Example 5 - NOT valid (because we don't follow rule 2 and print
doesn't have access to our variable's scope, x
no longer exists in memory)
y = 1
while y < 5:
x = 1
y = y + 1
print x
It would do you good to read this entire section on variable lifetime and scope in python all the way through Exercise 1 for good practice.
I believe your question is about scope. In the above example, a new memory address for var x
is created on the first line and any code on lines 2,3,4 that access x
can read/write to that variable.
There are only two rules here that we need to follow:
x
must be declared beforeprint
so that print can access that piece of memory
print
must be in the same or inner scope to access 'x'
Example 1 - valid (because we follow rules 1 and 2)
x = 1
print x
Example 2 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
Example 3 - valid (because we follow rules 1 and 2)
x = 1
while x < 10:
print x
x = x + 1
print x
Example 4 - NOT valid (because we don't follow rule 1 and print
is accessing a variable that has not yet been created in memory)
print x
x = 1
Example 5 - NOT valid (because we don't follow rule 2 and print
doesn't have access to our variable's scope, x
no longer exists in memory)
y = 1
while y < 5:
x = 1
y = y + 1
print x
It would do you good to read this entire section on variable lifetime and scope in python all the way through Exercise 1 for good practice.
edited Nov 13 '18 at 18:46
answered Nov 13 '18 at 18:33
MaxMax
6041824
6041824
What bout this one? x = 1 while x < 10: x = x + 1 print x
– Gashex
Nov 13 '18 at 19:00
The results start from 2 to 9 in other code I mentioned in the above comment while the main question code results start from 1 to 9.
– Gashex
Nov 13 '18 at 19:19
I actually understand that basic example 1 but when it comes to while loop related binding things getting messy for me.
– Gashex
Nov 13 '18 at 19:22
i can't understand your example because in python tabbing is important
– Max
Nov 16 '18 at 7:02
check [link] (pastebin.com/mUXXdDsw)
– Gashex
Nov 16 '18 at 18:19
|
show 3 more comments
What bout this one? x = 1 while x < 10: x = x + 1 print x
– Gashex
Nov 13 '18 at 19:00
The results start from 2 to 9 in other code I mentioned in the above comment while the main question code results start from 1 to 9.
– Gashex
Nov 13 '18 at 19:19
I actually understand that basic example 1 but when it comes to while loop related binding things getting messy for me.
– Gashex
Nov 13 '18 at 19:22
i can't understand your example because in python tabbing is important
– Max
Nov 16 '18 at 7:02
check [link] (pastebin.com/mUXXdDsw)
– Gashex
Nov 16 '18 at 18:19
What bout this one? x = 1 while x < 10: x = x + 1 print x
– Gashex
Nov 13 '18 at 19:00
What bout this one? x = 1 while x < 10: x = x + 1 print x
– Gashex
Nov 13 '18 at 19:00
The results start from 2 to 9 in other code I mentioned in the above comment while the main question code results start from 1 to 9.
– Gashex
Nov 13 '18 at 19:19
The results start from 2 to 9 in other code I mentioned in the above comment while the main question code results start from 1 to 9.
– Gashex
Nov 13 '18 at 19:19
I actually understand that basic example 1 but when it comes to while loop related binding things getting messy for me.
– Gashex
Nov 13 '18 at 19:22
I actually understand that basic example 1 but when it comes to while loop related binding things getting messy for me.
– Gashex
Nov 13 '18 at 19:22
i can't understand your example because in python tabbing is important
– Max
Nov 16 '18 at 7:02
i can't understand your example because in python tabbing is important
– Max
Nov 16 '18 at 7:02
check [link] (pastebin.com/mUXXdDsw)
– Gashex
Nov 16 '18 at 18:19
check [link] (pastebin.com/mUXXdDsw)
– Gashex
Nov 16 '18 at 18:19
|
show 3 more comments
x = 1 #Declares the variable
while x < 10: #checks whether the value of x is less than 10 every time the loop runs
print x #prints value of x for the each iterations(1 for first iteration, 2 for second and so on)
x = x + 1 #this is the update part
Let me tell you one more thing, you do not have any case of global variable here.
If you have trouble in understanding whether its global or local declaration, I would recommend you to follow this link
add a comment |
x = 1 #Declares the variable
while x < 10: #checks whether the value of x is less than 10 every time the loop runs
print x #prints value of x for the each iterations(1 for first iteration, 2 for second and so on)
x = x + 1 #this is the update part
Let me tell you one more thing, you do not have any case of global variable here.
If you have trouble in understanding whether its global or local declaration, I would recommend you to follow this link
add a comment |
x = 1 #Declares the variable
while x < 10: #checks whether the value of x is less than 10 every time the loop runs
print x #prints value of x for the each iterations(1 for first iteration, 2 for second and so on)
x = x + 1 #this is the update part
Let me tell you one more thing, you do not have any case of global variable here.
If you have trouble in understanding whether its global or local declaration, I would recommend you to follow this link
x = 1 #Declares the variable
while x < 10: #checks whether the value of x is less than 10 every time the loop runs
print x #prints value of x for the each iterations(1 for first iteration, 2 for second and so on)
x = x + 1 #this is the update part
Let me tell you one more thing, you do not have any case of global variable here.
If you have trouble in understanding whether its global or local declaration, I would recommend you to follow this link
answered Nov 13 '18 at 18:33
Sushant DahalSushant Dahal
162
162
add a comment |
add a comment |
Counter variable act like a tiny persistent storage. While loop checks whether the stored value in that tiny persistent storage Less than 11. If the value less than 10 then it starts the loop. Inside the loop, it instructs to Print value 1 because it's the current value in that tiny persistent storage after that the other "x" inside loop instruct that tiny persistent storage to update value by adding +1. This loop continues until it gets alert from persistent storage that value stored in persistent storage met 10 value. The loop will successfully exist.
This little software helped me to understand behind scenes http://pythontutor.com/visualize.html
Conclusion:
It seems For loops better for this kind things because it's clean and easy to maintain but understanding this concept is also important
This answer to your own question is ridden with errors and misunderstandings. There is no comparison to 11, only to 10. There is no 'other' x variable, as all of your code is part of the same scope. There is no such thing as an 'alert from persistent storage to the loop'. This shouldn't be the accepted answer.
– Thierry Lathuille
Nov 17 '18 at 22:40
@ThierryLathuille I'm sorry but I made it easier for a newbie to understand. You are correct about 10. I put 11 by mistake. "alert from persistent storage to the loop" means the code check current memory.
– Gashex
Nov 18 '18 at 5:04
@ThierryLathuille What kind of definition you have for other "x' inside the code if it, not a variable?
– Gashex
Nov 18 '18 at 5:07
@ThierryLathuille Are you there?
– Gashex
Dec 1 '18 at 21:38
add a comment |
Counter variable act like a tiny persistent storage. While loop checks whether the stored value in that tiny persistent storage Less than 11. If the value less than 10 then it starts the loop. Inside the loop, it instructs to Print value 1 because it's the current value in that tiny persistent storage after that the other "x" inside loop instruct that tiny persistent storage to update value by adding +1. This loop continues until it gets alert from persistent storage that value stored in persistent storage met 10 value. The loop will successfully exist.
This little software helped me to understand behind scenes http://pythontutor.com/visualize.html
Conclusion:
It seems For loops better for this kind things because it's clean and easy to maintain but understanding this concept is also important
This answer to your own question is ridden with errors and misunderstandings. There is no comparison to 11, only to 10. There is no 'other' x variable, as all of your code is part of the same scope. There is no such thing as an 'alert from persistent storage to the loop'. This shouldn't be the accepted answer.
– Thierry Lathuille
Nov 17 '18 at 22:40
@ThierryLathuille I'm sorry but I made it easier for a newbie to understand. You are correct about 10. I put 11 by mistake. "alert from persistent storage to the loop" means the code check current memory.
– Gashex
Nov 18 '18 at 5:04
@ThierryLathuille What kind of definition you have for other "x' inside the code if it, not a variable?
– Gashex
Nov 18 '18 at 5:07
@ThierryLathuille Are you there?
– Gashex
Dec 1 '18 at 21:38
add a comment |
Counter variable act like a tiny persistent storage. While loop checks whether the stored value in that tiny persistent storage Less than 11. If the value less than 10 then it starts the loop. Inside the loop, it instructs to Print value 1 because it's the current value in that tiny persistent storage after that the other "x" inside loop instruct that tiny persistent storage to update value by adding +1. This loop continues until it gets alert from persistent storage that value stored in persistent storage met 10 value. The loop will successfully exist.
This little software helped me to understand behind scenes http://pythontutor.com/visualize.html
Conclusion:
It seems For loops better for this kind things because it's clean and easy to maintain but understanding this concept is also important
Counter variable act like a tiny persistent storage. While loop checks whether the stored value in that tiny persistent storage Less than 11. If the value less than 10 then it starts the loop. Inside the loop, it instructs to Print value 1 because it's the current value in that tiny persistent storage after that the other "x" inside loop instruct that tiny persistent storage to update value by adding +1. This loop continues until it gets alert from persistent storage that value stored in persistent storage met 10 value. The loop will successfully exist.
This little software helped me to understand behind scenes http://pythontutor.com/visualize.html
Conclusion:
It seems For loops better for this kind things because it's clean and easy to maintain but understanding this concept is also important
edited Nov 18 '18 at 5:04
answered Nov 17 '18 at 20:42
GashexGashex
76
76
This answer to your own question is ridden with errors and misunderstandings. There is no comparison to 11, only to 10. There is no 'other' x variable, as all of your code is part of the same scope. There is no such thing as an 'alert from persistent storage to the loop'. This shouldn't be the accepted answer.
– Thierry Lathuille
Nov 17 '18 at 22:40
@ThierryLathuille I'm sorry but I made it easier for a newbie to understand. You are correct about 10. I put 11 by mistake. "alert from persistent storage to the loop" means the code check current memory.
– Gashex
Nov 18 '18 at 5:04
@ThierryLathuille What kind of definition you have for other "x' inside the code if it, not a variable?
– Gashex
Nov 18 '18 at 5:07
@ThierryLathuille Are you there?
– Gashex
Dec 1 '18 at 21:38
add a comment |
This answer to your own question is ridden with errors and misunderstandings. There is no comparison to 11, only to 10. There is no 'other' x variable, as all of your code is part of the same scope. There is no such thing as an 'alert from persistent storage to the loop'. This shouldn't be the accepted answer.
– Thierry Lathuille
Nov 17 '18 at 22:40
@ThierryLathuille I'm sorry but I made it easier for a newbie to understand. You are correct about 10. I put 11 by mistake. "alert from persistent storage to the loop" means the code check current memory.
– Gashex
Nov 18 '18 at 5:04
@ThierryLathuille What kind of definition you have for other "x' inside the code if it, not a variable?
– Gashex
Nov 18 '18 at 5:07
@ThierryLathuille Are you there?
– Gashex
Dec 1 '18 at 21:38
This answer to your own question is ridden with errors and misunderstandings. There is no comparison to 11, only to 10. There is no 'other' x variable, as all of your code is part of the same scope. There is no such thing as an 'alert from persistent storage to the loop'. This shouldn't be the accepted answer.
– Thierry Lathuille
Nov 17 '18 at 22:40
This answer to your own question is ridden with errors and misunderstandings. There is no comparison to 11, only to 10. There is no 'other' x variable, as all of your code is part of the same scope. There is no such thing as an 'alert from persistent storage to the loop'. This shouldn't be the accepted answer.
– Thierry Lathuille
Nov 17 '18 at 22:40
@ThierryLathuille I'm sorry but I made it easier for a newbie to understand. You are correct about 10. I put 11 by mistake. "alert from persistent storage to the loop" means the code check current memory.
– Gashex
Nov 18 '18 at 5:04
@ThierryLathuille I'm sorry but I made it easier for a newbie to understand. You are correct about 10. I put 11 by mistake. "alert from persistent storage to the loop" means the code check current memory.
– Gashex
Nov 18 '18 at 5:04
@ThierryLathuille What kind of definition you have for other "x' inside the code if it, not a variable?
– Gashex
Nov 18 '18 at 5:07
@ThierryLathuille What kind of definition you have for other "x' inside the code if it, not a variable?
– Gashex
Nov 18 '18 at 5:07
@ThierryLathuille Are you there?
– Gashex
Dec 1 '18 at 21:38
@ThierryLathuille Are you there?
– Gashex
Dec 1 '18 at 21:38
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It's unclear what you're asking. What are you confused about? I think this is a question of declaration and I initialization vs reassignment.
– Carcigenicate
Nov 13 '18 at 18:11
Is this a question about scope?
– Matt Cremeens
Nov 13 '18 at 18:12
You're increasing the value of
x
by 1 in each iteration of the loop. Whenx=10
you'll break out of the loop. When you exit the loop:x=10
.– Adam Mitchell
Nov 13 '18 at 18:12
There is only 1 variable named
x
in your script.– Johnny Mopp
Nov 13 '18 at 18:13
2
Top Python experts also have no idea.
This seems highly unlikely! Beware of learning from people who don't really know what they are doing.– Kirk Broadhurst
Nov 13 '18 at 19:25