How to set context variable of all Django generic views at once?
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I will have standard class-based views for CRUD operations that inherit from various generic views like ListView, DetailView and so on.
I will be setting all of their
context_object_name
attribute to the same value.
I was wondering if there is a way to do it more pythonic, to not repeat the operations many times in the code, but to be able to change that variable in one place if necessary?
ps. what comes to my mind is of course further inheritance, but maybe there is some more django-like way?
python django django-class-based-views
asked Nov 11 at 19:52
tikej
225
add a comment |
up vote
0
down vote
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I will have standard class-based views for CRUD operations that inherit from various generic views like ListView, DetailView and so on.
I will be setting all of their
context_object_name
attribute to the same value.
I was wondering if there is a way to do it more pythonic, to not repeat the operations many times in the code, but to be able to change that variable in one place if necessary?
ps. what comes to my mind is of course further inheritance, but maybe there is some more django-like way?
python django django-class-based-views
asked Nov 11 at 19:52
tikej
225
Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
– Daniel Roseman
Nov 11 at 20:10
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I will have standard class-based views for CRUD operations that inherit from various generic views like ListView, DetailView and so on.
I will be setting all of their
context_object_name
attribute to the same value.
I was wondering if there is a way to do it more pythonic, to not repeat the operations many times in the code, but to be able to change that variable in one place if necessary?
ps. what comes to my mind is of course further inheritance, but maybe there is some more django-like way?
python django django-class-based-views
asked Nov 11 at 19:52
tikej
225
I will have standard class-based views for CRUD operations that inherit from various generic views like ListView, DetailView and so on.
I will be setting all of their
context_object_name
attribute to the same value.
I was wondering if there is a way to do it more pythonic, to not repeat the operations many times in the code, but to be able to change that variable in one place if necessary?
ps. what comes to my mind is of course further inheritance, but maybe there is some more django-like way?
python django django-class-based-views
python django django-class-based-views
asked Nov 11 at 19:52
tikej
225
asked Nov 11 at 19:52
tikej
225
asked Nov 11 at 19:52
tikej
225
asked Nov 11 at 19:52
tikej
225
asked Nov 11 at 19:52
tikej
225
225
Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
– Daniel Roseman
Nov 11 at 20:10
add a comment |
Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
– Daniel Roseman
Nov 11 at 20:10
Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
– Daniel Roseman
Nov 11 at 20:10
Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
– Daniel Roseman
Nov 11 at 20:10
add a comment |
2 Answers
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0
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Middleware can do the trick
class SetContextObjectNameMiddleware:
def process_template_response(self, request, response):
if 'object' in response.context_data:
response.context_data['foo'] = response.context_data['object']
return response
Then add the middleware to your settings.py
It's not really setting the view's context_object_name but it achieves the same outcome.
answered Nov 12 at 0:50
rikAtee
4,76042956
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0
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You can also use a mixin, instead of a middleware app:
class CommonContextMixin(object):
def get_context_data(self, *args, **kwargs):
context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
context['foo'] = 'bar'
return context
Then use that mixin in your views:
class MyView(TemplateView, CommonContextMixin):
""" This view now has the foo variable as part of its context. """
Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/
answered Nov 12 at 1:01
Victor Bruno
886610
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Middleware can do the trick
class SetContextObjectNameMiddleware:
def process_template_response(self, request, response):
if 'object' in response.context_data:
response.context_data['foo'] = response.context_data['object']
return response
Then add the middleware to your settings.py
It's not really setting the view's context_object_name but it achieves the same outcome.
answered Nov 12 at 0:50
rikAtee
4,76042956
add a comment |
up vote
0
down vote
Middleware can do the trick
class SetContextObjectNameMiddleware:
def process_template_response(self, request, response):
if 'object' in response.context_data:
response.context_data['foo'] = response.context_data['object']
return response
Then add the middleware to your settings.py
It's not really setting the view's context_object_name but it achieves the same outcome.
answered Nov 12 at 0:50
rikAtee
4,76042956
add a comment |
up vote
0
down vote
up vote
0
down vote
Middleware can do the trick
class SetContextObjectNameMiddleware:
def process_template_response(self, request, response):
if 'object' in response.context_data:
response.context_data['foo'] = response.context_data['object']
return response
Then add the middleware to your settings.py
It's not really setting the view's context_object_name but it achieves the same outcome.
answered Nov 12 at 0:50
rikAtee
4,76042956
Middleware can do the trick
class SetContextObjectNameMiddleware:
def process_template_response(self, request, response):
if 'object' in response.context_data:
response.context_data['foo'] = response.context_data['object']
return response
Then add the middleware to your settings.py
It's not really setting the view's context_object_name but it achieves the same outcome.
answered Nov 12 at 0:50
rikAtee
4,76042956
answered Nov 12 at 0:50
rikAtee
4,76042956
answered Nov 12 at 0:50
rikAtee
4,76042956
answered Nov 12 at 0:50
rikAtee
4,76042956
4,76042956
add a comment |
add a comment |
up vote
0
down vote
You can also use a mixin, instead of a middleware app:
class CommonContextMixin(object):
def get_context_data(self, *args, **kwargs):
context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
context['foo'] = 'bar'
return context
Then use that mixin in your views:
class MyView(TemplateView, CommonContextMixin):
""" This view now has the foo variable as part of its context. """
Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/
answered Nov 12 at 1:01
Victor Bruno
886610
add a comment |
up vote
0
down vote
You can also use a mixin, instead of a middleware app:
class CommonContextMixin(object):
def get_context_data(self, *args, **kwargs):
context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
context['foo'] = 'bar'
return context
Then use that mixin in your views:
class MyView(TemplateView, CommonContextMixin):
""" This view now has the foo variable as part of its context. """
Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/
answered Nov 12 at 1:01
Victor Bruno
886610
add a comment |
up vote
0
down vote
up vote
0
down vote
You can also use a mixin, instead of a middleware app:
class CommonContextMixin(object):
def get_context_data(self, *args, **kwargs):
context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
context['foo'] = 'bar'
return context
Then use that mixin in your views:
class MyView(TemplateView, CommonContextMixin):
""" This view now has the foo variable as part of its context. """
Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/
answered Nov 12 at 1:01
Victor Bruno
886610
You can also use a mixin, instead of a middleware app:
class CommonContextMixin(object):
def get_context_data(self, *args, **kwargs):
context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
context['foo'] = 'bar'
return context
Then use that mixin in your views:
class MyView(TemplateView, CommonContextMixin):
""" This view now has the foo variable as part of its context. """
Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/
answered Nov 12 at 1:01
Victor Bruno
886610
answered Nov 12 at 1:01
Victor Bruno
886610
answered Nov 12 at 1:01
Victor Bruno
886610
answered Nov 12 at 1:01
Victor Bruno
886610
886610
add a comment |
add a comment |
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Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
– Daniel Roseman
Nov 11 at 20:10