Instagram Bot: Click Button in Firefox with Selenium Python











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I'm making an Instagram Bot (from a YT tutorial) and I can't get past the "Turn On Notifications" pop-up that appears after login.



I want to click "Turn On"



How do I click the button? Here's the xpath and what I see after inspection.



Xpath:



/html/body/div[2]/div/div/div/div[3]/button[1]


Inspection:



<button class="aOOlW  bIiDR  " tabindex="0">Turn On</button>


Here's my code. Can anyone tell me what to add and where? I'm attempting to click the button at the very bottom...



from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import time

def print_same_line(text):
sys.stdout.write('r')
sys.stdout.flush()
sys.stdout.write(text)
sys.stdout.flush()


class InstagramBot:

def __init__(self, username, password):
self.username = username
self.password = password
self.driver = webdriver.Firefox()

def closeBrowser(self):
self.driver.close()

def login(self):
driver = self.driver
driver.get("https://www.instagram.com/")
time.sleep(2)
login_button = driver.find_element_by_xpath("//a[@href='/accounts/login/?source=auth_switcher']")
login_button.click()
time.sleep(2)
user_name_elem = driver.find_element_by_xpath("//input[@name='username']")
user_name_elem.clear()
user_name_elem.send_keys(self.username)
passworword_elem = driver.find_element_by_xpath("//input[@name='password']")
passworword_elem.clear()
passworword_elem.send_keys(self.password)
passworword_elem.send_keys(Keys.RETURN)
time.sleep(2)
notify_button = browser.find_element_by_xpath('//button[text()="Turn On"]')
notify_button.click()
time.sleep(2)









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    up vote
    0
    down vote

    favorite












    I'm making an Instagram Bot (from a YT tutorial) and I can't get past the "Turn On Notifications" pop-up that appears after login.



    I want to click "Turn On"



    How do I click the button? Here's the xpath and what I see after inspection.



    Xpath:



    /html/body/div[2]/div/div/div/div[3]/button[1]


    Inspection:



    <button class="aOOlW  bIiDR  " tabindex="0">Turn On</button>


    Here's my code. Can anyone tell me what to add and where? I'm attempting to click the button at the very bottom...



    from selenium import webdriver
    from selenium.webdriver.common.keys import Keys
    import time

    def print_same_line(text):
    sys.stdout.write('r')
    sys.stdout.flush()
    sys.stdout.write(text)
    sys.stdout.flush()


    class InstagramBot:

    def __init__(self, username, password):
    self.username = username
    self.password = password
    self.driver = webdriver.Firefox()

    def closeBrowser(self):
    self.driver.close()

    def login(self):
    driver = self.driver
    driver.get("https://www.instagram.com/")
    time.sleep(2)
    login_button = driver.find_element_by_xpath("//a[@href='/accounts/login/?source=auth_switcher']")
    login_button.click()
    time.sleep(2)
    user_name_elem = driver.find_element_by_xpath("//input[@name='username']")
    user_name_elem.clear()
    user_name_elem.send_keys(self.username)
    passworword_elem = driver.find_element_by_xpath("//input[@name='password']")
    passworword_elem.clear()
    passworword_elem.send_keys(self.password)
    passworword_elem.send_keys(Keys.RETURN)
    time.sleep(2)
    notify_button = browser.find_element_by_xpath('//button[text()="Turn On"]')
    notify_button.click()
    time.sleep(2)









    share|improve this question







    New contributor




    BlockyBlock is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm making an Instagram Bot (from a YT tutorial) and I can't get past the "Turn On Notifications" pop-up that appears after login.



      I want to click "Turn On"



      How do I click the button? Here's the xpath and what I see after inspection.



      Xpath:



      /html/body/div[2]/div/div/div/div[3]/button[1]


      Inspection:



      <button class="aOOlW  bIiDR  " tabindex="0">Turn On</button>


      Here's my code. Can anyone tell me what to add and where? I'm attempting to click the button at the very bottom...



      from selenium import webdriver
      from selenium.webdriver.common.keys import Keys
      import time

      def print_same_line(text):
      sys.stdout.write('r')
      sys.stdout.flush()
      sys.stdout.write(text)
      sys.stdout.flush()


      class InstagramBot:

      def __init__(self, username, password):
      self.username = username
      self.password = password
      self.driver = webdriver.Firefox()

      def closeBrowser(self):
      self.driver.close()

      def login(self):
      driver = self.driver
      driver.get("https://www.instagram.com/")
      time.sleep(2)
      login_button = driver.find_element_by_xpath("//a[@href='/accounts/login/?source=auth_switcher']")
      login_button.click()
      time.sleep(2)
      user_name_elem = driver.find_element_by_xpath("//input[@name='username']")
      user_name_elem.clear()
      user_name_elem.send_keys(self.username)
      passworword_elem = driver.find_element_by_xpath("//input[@name='password']")
      passworword_elem.clear()
      passworword_elem.send_keys(self.password)
      passworword_elem.send_keys(Keys.RETURN)
      time.sleep(2)
      notify_button = browser.find_element_by_xpath('//button[text()="Turn On"]')
      notify_button.click()
      time.sleep(2)









      share|improve this question







      New contributor




      BlockyBlock is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I'm making an Instagram Bot (from a YT tutorial) and I can't get past the "Turn On Notifications" pop-up that appears after login.



      I want to click "Turn On"



      How do I click the button? Here's the xpath and what I see after inspection.



      Xpath:



      /html/body/div[2]/div/div/div/div[3]/button[1]


      Inspection:



      <button class="aOOlW  bIiDR  " tabindex="0">Turn On</button>


      Here's my code. Can anyone tell me what to add and where? I'm attempting to click the button at the very bottom...



      from selenium import webdriver
      from selenium.webdriver.common.keys import Keys
      import time

      def print_same_line(text):
      sys.stdout.write('r')
      sys.stdout.flush()
      sys.stdout.write(text)
      sys.stdout.flush()


      class InstagramBot:

      def __init__(self, username, password):
      self.username = username
      self.password = password
      self.driver = webdriver.Firefox()

      def closeBrowser(self):
      self.driver.close()

      def login(self):
      driver = self.driver
      driver.get("https://www.instagram.com/")
      time.sleep(2)
      login_button = driver.find_element_by_xpath("//a[@href='/accounts/login/?source=auth_switcher']")
      login_button.click()
      time.sleep(2)
      user_name_elem = driver.find_element_by_xpath("//input[@name='username']")
      user_name_elem.clear()
      user_name_elem.send_keys(self.username)
      passworword_elem = driver.find_element_by_xpath("//input[@name='password']")
      passworword_elem.clear()
      passworword_elem.send_keys(self.password)
      passworword_elem.send_keys(Keys.RETURN)
      time.sleep(2)
      notify_button = browser.find_element_by_xpath('//button[text()="Turn On"]')
      notify_button.click()
      time.sleep(2)






      python macos selenium firefox instagram






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      asked 22 hours ago









      BlockyBlock

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          Solution!



          Instead of using this...



          notify_button = browser.find_element_by_xpath('//button[text()="Turn On"]')
          notify_button.click()
          time.sleep(2)


          Use this!



          notify_element = driver.find_element_by_css_selector("COPY PASTE CSS SELECTOR HERE")
          notify_element.send_keys(Keys.TAB)
          time.sleep(1)
          notify_element.send_keys(Keys.RETURN)
          time.sleep(2)





          share|improve this answer










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            1 Answer
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            1 Answer
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            up vote
            0
            down vote













            Solution!



            Instead of using this...



            notify_button = browser.find_element_by_xpath('//button[text()="Turn On"]')
            notify_button.click()
            time.sleep(2)


            Use this!



            notify_element = driver.find_element_by_css_selector("COPY PASTE CSS SELECTOR HERE")
            notify_element.send_keys(Keys.TAB)
            time.sleep(1)
            notify_element.send_keys(Keys.RETURN)
            time.sleep(2)





            share|improve this answer










            New contributor




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              up vote
              0
              down vote













              Solution!



              Instead of using this...



              notify_button = browser.find_element_by_xpath('//button[text()="Turn On"]')
              notify_button.click()
              time.sleep(2)


              Use this!



              notify_element = driver.find_element_by_css_selector("COPY PASTE CSS SELECTOR HERE")
              notify_element.send_keys(Keys.TAB)
              time.sleep(1)
              notify_element.send_keys(Keys.RETURN)
              time.sleep(2)





              share|improve this answer










              New contributor




              BlockyBlock is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.




















                up vote
                0
                down vote










                up vote
                0
                down vote









                Solution!



                Instead of using this...



                notify_button = browser.find_element_by_xpath('//button[text()="Turn On"]')
                notify_button.click()
                time.sleep(2)


                Use this!



                notify_element = driver.find_element_by_css_selector("COPY PASTE CSS SELECTOR HERE")
                notify_element.send_keys(Keys.TAB)
                time.sleep(1)
                notify_element.send_keys(Keys.RETURN)
                time.sleep(2)





                share|improve this answer










                New contributor




                BlockyBlock is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                Solution!



                Instead of using this...



                notify_button = browser.find_element_by_xpath('//button[text()="Turn On"]')
                notify_button.click()
                time.sleep(2)


                Use this!



                notify_element = driver.find_element_by_css_selector("COPY PASTE CSS SELECTOR HERE")
                notify_element.send_keys(Keys.TAB)
                time.sleep(1)
                notify_element.send_keys(Keys.RETURN)
                time.sleep(2)






                share|improve this answer










                New contributor




                BlockyBlock is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                share|improve this answer



                share|improve this answer








                edited 19 hours ago









                William Jones

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                6110






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                answered 19 hours ago









                BlockyBlock

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