How to trigger submit from parent?
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I would like to call the submit method of the child component. Therefore I use the ref prop.
But it looks like I just get a WithContext object.
So how to call TodoForm > submit inside App > submitForm.
Here is a running example: https://codesandbox.io/s/92nm15pnqr
reactjs formik
asked Nov 16 '18 at 11:45
user3481997user3481997
2611313
add a comment |
I would like to call the submit method of the child component. Therefore I use the ref prop.
But it looks like I just get a WithContext object.
So how to call TodoForm > submit inside App > submitForm.
Here is a running example: https://codesandbox.io/s/92nm15pnqr
reactjs formik
asked Nov 16 '18 at 11:45
user3481997user3481997
2611313
from App.js passonSubmit={this.submitForm}and from TodoForm inFormikonSubmit addthis.props.onSubmit()
– Rutvik Bhatt
Nov 16 '18 at 12:02
The submit button is outside of the TodoForm. Thus, submit should be triggered outside of the TodoForm.Therefore onSubmit prop for TodoForm will not help.
– user3481997
Nov 16 '18 at 12:09
why do you put submit button outside?
– Rutvik Bhatt
Nov 16 '18 at 12:13
For example bootstrap modal where submit button is in the modal footer and the form itself is in the modal body.
– user3481997
Nov 16 '18 at 12:55
add a comment |
I would like to call the submit method of the child component. Therefore I use the ref prop.
But it looks like I just get a WithContext object.
So how to call TodoForm > submit inside App > submitForm.
Here is a running example: https://codesandbox.io/s/92nm15pnqr
reactjs formik
asked Nov 16 '18 at 11:45
user3481997user3481997
2611313
I would like to call the submit method of the child component. Therefore I use the ref prop.
But it looks like I just get a WithContext object.
So how to call TodoForm > submit inside App > submitForm.
Here is a running example: https://codesandbox.io/s/92nm15pnqr
reactjs formik
reactjs formik
asked Nov 16 '18 at 11:45
user3481997user3481997
2611313
asked Nov 16 '18 at 11:45
user3481997user3481997
2611313
asked Nov 16 '18 at 11:45
user3481997user3481997
2611313
asked Nov 16 '18 at 11:45
user3481997user3481997
2611313
asked Nov 16 '18 at 11:45
user3481997user3481997
2611313
2611313
from App.js passonSubmit={this.submitForm}and from TodoForm inFormikonSubmit addthis.props.onSubmit()
– Rutvik Bhatt
Nov 16 '18 at 12:02
The submit button is outside of the TodoForm. Thus, submit should be triggered outside of the TodoForm.Therefore onSubmit prop for TodoForm will not help.
– user3481997
Nov 16 '18 at 12:09
why do you put submit button outside?
– Rutvik Bhatt
Nov 16 '18 at 12:13
For example bootstrap modal where submit button is in the modal footer and the form itself is in the modal body.
– user3481997
Nov 16 '18 at 12:55
add a comment |
from App.js passonSubmit={this.submitForm}and from TodoForm inFormikonSubmit addthis.props.onSubmit()
– Rutvik Bhatt
Nov 16 '18 at 12:02
The submit button is outside of the TodoForm. Thus, submit should be triggered outside of the TodoForm.Therefore onSubmit prop for TodoForm will not help.
– user3481997
Nov 16 '18 at 12:09
why do you put submit button outside?
– Rutvik Bhatt
Nov 16 '18 at 12:13
For example bootstrap modal where submit button is in the modal footer and the form itself is in the modal body.
– user3481997
Nov 16 '18 at 12:55
from App.js pass
onSubmit={this.submitForm} and from TodoForm in Formik onSubmit add this.props.onSubmit()– Rutvik Bhatt
Nov 16 '18 at 12:02
from App.js pass
onSubmit={this.submitForm} and from TodoForm in Formik onSubmit add this.props.onSubmit()– Rutvik Bhatt
Nov 16 '18 at 12:02
The submit button is outside of the TodoForm. Thus, submit should be triggered outside of the TodoForm.Therefore onSubmit prop for TodoForm will not help.
– user3481997
Nov 16 '18 at 12:09
The submit button is outside of the TodoForm. Thus, submit should be triggered outside of the TodoForm.Therefore onSubmit prop for TodoForm will not help.
– user3481997
Nov 16 '18 at 12:09
why do you put submit button outside?
– Rutvik Bhatt
Nov 16 '18 at 12:13
why do you put submit button outside?
– Rutvik Bhatt
Nov 16 '18 at 12:13
For example bootstrap modal where submit button is in the modal footer and the form itself is in the modal body.
– user3481997
Nov 16 '18 at 12:55
For example bootstrap modal where submit button is in the modal footer and the form itself is in the modal body.
– user3481997
Nov 16 '18 at 12:55
add a comment |
1 Answer
1
active
oldest
votes
Because you wrap your TodoForm component in withNamespaces HOC, getting the reference to your TodoForm is not as easy as calling ref={..}, since that returns reference to the HOC. To get the reference to your component, you have to leverage the innerRef parameter, when creating the HOC (see docs)
const TodoFormTranslated = withNamespaces("", {
innerRef: (ref) => VARIABLE_WHICH_WILL_NOW_CONTAIN_REF_TO_YOUR_EL = ref
})(TodoForm);
fast but working solution to your problem would look something like this: https://codesandbox.io/s/n55yvw1o2m
Maybe you don't want variables outside of your class, so I'll leave that to you in which way do you want to handle this. You can get inspiration for example from this post.
answered Nov 16 '18 at 13:19
Matej P.Matej P.
4,19011633
have this helped solving your issue?
– Matej P.
Nov 16 '18 at 16:06
Unfortunately not. I was able to access the method in child component but I had no access to formik specific props like submitForm. So I decided to solve this issue with an additional props in TodoForm to trigger the form submit. This has the disadvantage that I need to write additional code but I see no other way.
– user3481997
Nov 16 '18 at 18:30
but you were able to run thesubmitmethod of the TodoForm then right? that what the question stated. You can post another question for the next issue.
– Matej P.
Nov 16 '18 at 21:59
OK, from that perspective the problem is solved. :-)
– user3481997
Nov 19 '18 at 6:51
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Because you wrap your TodoForm component in withNamespaces HOC, getting the reference to your TodoForm is not as easy as calling ref={..}, since that returns reference to the HOC. To get the reference to your component, you have to leverage the innerRef parameter, when creating the HOC (see docs)
const TodoFormTranslated = withNamespaces("", {
innerRef: (ref) => VARIABLE_WHICH_WILL_NOW_CONTAIN_REF_TO_YOUR_EL = ref
})(TodoForm);
fast but working solution to your problem would look something like this: https://codesandbox.io/s/n55yvw1o2m
Maybe you don't want variables outside of your class, so I'll leave that to you in which way do you want to handle this. You can get inspiration for example from this post.
answered Nov 16 '18 at 13:19
Matej P.Matej P.
4,19011633
have this helped solving your issue?
– Matej P.
Nov 16 '18 at 16:06
Unfortunately not. I was able to access the method in child component but I had no access to formik specific props like submitForm. So I decided to solve this issue with an additional props in TodoForm to trigger the form submit. This has the disadvantage that I need to write additional code but I see no other way.
– user3481997
Nov 16 '18 at 18:30
but you were able to run thesubmitmethod of the TodoForm then right? that what the question stated. You can post another question for the next issue.
– Matej P.
Nov 16 '18 at 21:59
OK, from that perspective the problem is solved. :-)
– user3481997
Nov 19 '18 at 6:51
add a comment |
Because you wrap your TodoForm component in withNamespaces HOC, getting the reference to your TodoForm is not as easy as calling ref={..}, since that returns reference to the HOC. To get the reference to your component, you have to leverage the innerRef parameter, when creating the HOC (see docs)
const TodoFormTranslated = withNamespaces("", {
innerRef: (ref) => VARIABLE_WHICH_WILL_NOW_CONTAIN_REF_TO_YOUR_EL = ref
})(TodoForm);
fast but working solution to your problem would look something like this: https://codesandbox.io/s/n55yvw1o2m
Maybe you don't want variables outside of your class, so I'll leave that to you in which way do you want to handle this. You can get inspiration for example from this post.
answered Nov 16 '18 at 13:19
Matej P.Matej P.
4,19011633
have this helped solving your issue?
– Matej P.
Nov 16 '18 at 16:06
Unfortunately not. I was able to access the method in child component but I had no access to formik specific props like submitForm. So I decided to solve this issue with an additional props in TodoForm to trigger the form submit. This has the disadvantage that I need to write additional code but I see no other way.
– user3481997
Nov 16 '18 at 18:30
but you were able to run thesubmitmethod of the TodoForm then right? that what the question stated. You can post another question for the next issue.
– Matej P.
Nov 16 '18 at 21:59
OK, from that perspective the problem is solved. :-)
– user3481997
Nov 19 '18 at 6:51
add a comment |
Because you wrap your TodoForm component in withNamespaces HOC, getting the reference to your TodoForm is not as easy as calling ref={..}, since that returns reference to the HOC. To get the reference to your component, you have to leverage the innerRef parameter, when creating the HOC (see docs)
const TodoFormTranslated = withNamespaces("", {
innerRef: (ref) => VARIABLE_WHICH_WILL_NOW_CONTAIN_REF_TO_YOUR_EL = ref
})(TodoForm);
fast but working solution to your problem would look something like this: https://codesandbox.io/s/n55yvw1o2m
Maybe you don't want variables outside of your class, so I'll leave that to you in which way do you want to handle this. You can get inspiration for example from this post.
answered Nov 16 '18 at 13:19
Matej P.Matej P.
4,19011633
Because you wrap your TodoForm component in withNamespaces HOC, getting the reference to your TodoForm is not as easy as calling ref={..}, since that returns reference to the HOC. To get the reference to your component, you have to leverage the innerRef parameter, when creating the HOC (see docs)
const TodoFormTranslated = withNamespaces("", {
innerRef: (ref) => VARIABLE_WHICH_WILL_NOW_CONTAIN_REF_TO_YOUR_EL = ref
})(TodoForm);
fast but working solution to your problem would look something like this: https://codesandbox.io/s/n55yvw1o2m
Maybe you don't want variables outside of your class, so I'll leave that to you in which way do you want to handle this. You can get inspiration for example from this post.
answered Nov 16 '18 at 13:19
Matej P.Matej P.
4,19011633
answered Nov 16 '18 at 13:19
Matej P.Matej P.
4,19011633
answered Nov 16 '18 at 13:19
Matej P.Matej P.
4,19011633
answered Nov 16 '18 at 13:19
Matej P.Matej P.
4,19011633
4,19011633
have this helped solving your issue?
– Matej P.
Nov 16 '18 at 16:06
Unfortunately not. I was able to access the method in child component but I had no access to formik specific props like submitForm. So I decided to solve this issue with an additional props in TodoForm to trigger the form submit. This has the disadvantage that I need to write additional code but I see no other way.
– user3481997
Nov 16 '18 at 18:30
but you were able to run thesubmitmethod of the TodoForm then right? that what the question stated. You can post another question for the next issue.
– Matej P.
Nov 16 '18 at 21:59
OK, from that perspective the problem is solved. :-)
– user3481997
Nov 19 '18 at 6:51
add a comment |
have this helped solving your issue?
– Matej P.
Nov 16 '18 at 16:06
Unfortunately not. I was able to access the method in child component but I had no access to formik specific props like submitForm. So I decided to solve this issue with an additional props in TodoForm to trigger the form submit. This has the disadvantage that I need to write additional code but I see no other way.
– user3481997
Nov 16 '18 at 18:30
but you were able to run thesubmitmethod of the TodoForm then right? that what the question stated. You can post another question for the next issue.
– Matej P.
Nov 16 '18 at 21:59
OK, from that perspective the problem is solved. :-)
– user3481997
Nov 19 '18 at 6:51
have this helped solving your issue?
– Matej P.
Nov 16 '18 at 16:06
have this helped solving your issue?
– Matej P.
Nov 16 '18 at 16:06
Unfortunately not. I was able to access the method in child component but I had no access to formik specific props like submitForm. So I decided to solve this issue with an additional props in TodoForm to trigger the form submit. This has the disadvantage that I need to write additional code but I see no other way.
– user3481997
Nov 16 '18 at 18:30
Unfortunately not. I was able to access the method in child component but I had no access to formik specific props like submitForm. So I decided to solve this issue with an additional props in TodoForm to trigger the form submit. This has the disadvantage that I need to write additional code but I see no other way.
– user3481997
Nov 16 '18 at 18:30
but you were able to run the
submit method of the TodoForm then right? that what the question stated. You can post another question for the next issue.– Matej P.
Nov 16 '18 at 21:59
but you were able to run the
submit method of the TodoForm then right? that what the question stated. You can post another question for the next issue.– Matej P.
Nov 16 '18 at 21:59
OK, from that perspective the problem is solved. :-)
– user3481997
Nov 19 '18 at 6:51
OK, from that perspective the problem is solved. :-)
– user3481997
Nov 19 '18 at 6:51
add a comment |
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from App.js pass
onSubmit={this.submitForm}and from TodoForm inFormikonSubmit addthis.props.onSubmit()– Rutvik Bhatt
Nov 16 '18 at 12:02
The submit button is outside of the TodoForm. Thus, submit should be triggered outside of the TodoForm.Therefore onSubmit prop for TodoForm will not help.
– user3481997
Nov 16 '18 at 12:09
why do you put submit button outside?
– Rutvik Bhatt
Nov 16 '18 at 12:13
For example bootstrap modal where submit button is in the modal footer and the form itself is in the modal body.
– user3481997
Nov 16 '18 at 12:55