validate google docs and office 365 url












0















I am using regex for validating if the provided url is valid or not. To test validity(either google docs url or office 365 docs), I did the following but it's not working 



var url = "https://hello-my.sharepoint.com/:w:/r/personal/;

var urlRegx = new RegExp('^(docs.google.com|(http|https)://[A-Za-z]-.my.sharepoint.com)', 'i');

console.log(urlRegx.test(url));


This is giving me false when i have the sharepoint url but true when i have the `url = "docs.google.com/document/"






javascript regex







share|improve this question























  • Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

    – Wiktor Stribiżew
    Nov 15 '18 at 9:14


















0















I am using regex for validating if the provided url is valid or not. To test validity(either google docs url or office 365 docs), I did the following but it's not working 



var url = "https://hello-my.sharepoint.com/:w:/r/personal/;

var urlRegx = new RegExp('^(docs.google.com|(http|https)://[A-Za-z]-.my.sharepoint.com)', 'i');

console.log(urlRegx.test(url));


This is giving me false when i have the sharepoint url but true when i have the `url = "docs.google.com/document/"






javascript regex







share|improve this question























  • Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

    – Wiktor Stribiżew
    Nov 15 '18 at 9:14
















0












0








0


1






I am using regex for validating if the provided url is valid or not. To test validity(either google docs url or office 365 docs), I did the following but it's not working 



var url = "https://hello-my.sharepoint.com/:w:/r/personal/;

var urlRegx = new RegExp('^(docs.google.com|(http|https)://[A-Za-z]-.my.sharepoint.com)', 'i');

console.log(urlRegx.test(url));


This is giving me false when i have the sharepoint url but true when i have the `url = "docs.google.com/document/"






javascript regex







share|improve this question














I am using regex for validating if the provided url is valid or not. To test validity(either google docs url or office 365 docs), I did the following but it's not working 



var url = "https://hello-my.sharepoint.com/:w:/r/personal/;

var urlRegx = new RegExp('^(docs.google.com|(http|https)://[A-Za-z]-.my.sharepoint.com)', 'i');

console.log(urlRegx.test(url));


This is giving me false when i have the sharepoint url but true when i have the `url = "docs.google.com/document/"






javascript regex




javascript regex






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 15 '18 at 9:12









milanmilan

810929




810929













  • Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

    – Wiktor Stribiżew
    Nov 15 '18 at 9:14





















  • Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

    – Wiktor Stribiżew
    Nov 15 '18 at 9:14



















Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

– Wiktor Stribiżew
Nov 15 '18 at 9:14







Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

– Wiktor Stribiżew
Nov 15 '18 at 9:14














1 Answer
1






active

oldest

votes


















1














You've got an additional closing bracket ) at the end of your expression which you should remove.



You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).



Here is a working example: 






var url = "https://hello-my.sharepoint.com/:w:/r/personal/";

var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');

console.log(urlRegx.test(url));





Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:



var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;






share|improve this answer


























  • You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

    – Wiktor Stribiżew
    Nov 15 '18 at 9:25













  • @WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

    – Nick Parsons
    Nov 15 '18 at 9:36











  • if you try to validate the url 'docs.google.com' it gives you false as an output

    – milan
    Nov 19 '18 at 4:40











  • @milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

    – Nick Parsons
    Nov 19 '18 at 4:46













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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









1














You've got an additional closing bracket ) at the end of your expression which you should remove.



You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).



Here is a working example: 






var url = "https://hello-my.sharepoint.com/:w:/r/personal/";

var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');

console.log(urlRegx.test(url));





Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:



var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;






share|improve this answer


























  • You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

    – Wiktor Stribiżew
    Nov 15 '18 at 9:25













  • @WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

    – Nick Parsons
    Nov 15 '18 at 9:36











  • if you try to validate the url 'docs.google.com' it gives you false as an output

    – milan
    Nov 19 '18 at 4:40











  • @milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

    – Nick Parsons
    Nov 19 '18 at 4:46


















1














You've got an additional closing bracket ) at the end of your expression which you should remove.



You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).



Here is a working example: 






var url = "https://hello-my.sharepoint.com/:w:/r/personal/";

var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');

console.log(urlRegx.test(url));





Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:



var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;






share|improve this answer


























  • You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

    – Wiktor Stribiżew
    Nov 15 '18 at 9:25













  • @WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

    – Nick Parsons
    Nov 15 '18 at 9:36











  • if you try to validate the url 'docs.google.com' it gives you false as an output

    – milan
    Nov 19 '18 at 4:40











  • @milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

    – Nick Parsons
    Nov 19 '18 at 4:46
















1












1








1







You've got an additional closing bracket ) at the end of your expression which you should remove.



You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).



Here is a working example: 






var url = "https://hello-my.sharepoint.com/:w:/r/personal/";

var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');

console.log(urlRegx.test(url));





Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:



var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;






share|improve this answer















You've got an additional closing bracket ) at the end of your expression which you should remove.



You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).



Here is a working example: 






var url = "https://hello-my.sharepoint.com/:w:/r/personal/";

var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');

console.log(urlRegx.test(url));





Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:



var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;






var url = "https://hello-my.sharepoint.com/:w:/r/personal/";

var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');

console.log(urlRegx.test(url));





var url = "https://hello-my.sharepoint.com/:w:/r/personal/";

var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');

console.log(urlRegx.test(url));






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 19 '18 at 4:46

























answered Nov 15 '18 at 9:22









Nick ParsonsNick Parsons

9,2332825




9,2332825













  • You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

    – Wiktor Stribiżew
    Nov 15 '18 at 9:25













  • @WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

    – Nick Parsons
    Nov 15 '18 at 9:36











  • if you try to validate the url 'docs.google.com' it gives you false as an output

    – milan
    Nov 19 '18 at 4:40











  • @milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

    – Nick Parsons
    Nov 19 '18 at 4:46





















  • You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

    – Wiktor Stribiżew
    Nov 15 '18 at 9:25













  • @WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

    – Nick Parsons
    Nov 15 '18 at 9:36











  • if you try to validate the url 'docs.google.com' it gives you false as an output

    – milan
    Nov 19 '18 at 4:40











  • @milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

    – Nick Parsons
    Nov 19 '18 at 4:46



















You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

– Wiktor Stribiżew
Nov 15 '18 at 9:25







You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

– Wiktor Stribiżew
Nov 15 '18 at 9:25















@WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

– Nick Parsons
Nov 15 '18 at 9:36





@WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

– Nick Parsons
Nov 15 '18 at 9:36













if you try to validate the url 'docs.google.com' it gives you false as an output

– milan
Nov 19 '18 at 4:40





if you try to validate the url 'docs.google.com' it gives you false as an output

– milan
Nov 19 '18 at 4:40













@milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

– Nick Parsons
Nov 19 '18 at 4:46







@milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

– Nick Parsons
Nov 19 '18 at 4:46






















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