How to pass vector to pointer array winapi?












0















I want to stop using manual allocated memory to work with all winapi. for testing i try to change my code. but i get




no suitable conversion from vector DWORD to DWORD * exists.




std::vector<DWORD> aProcesses;

DWORD cbNeeded;

if (!EnumProcesses(aProcesses, aProcesses.capacity(), &cbNeeded))

{

    return 1;

}

for (auto& p : aProcesses)

{

    std::cout << p << std::endl;

}


Manual Allocated memory below



    DWORD aProcesses[1024], cbNeeded, cProcesses;

unsigned int i;

if (!EnumProcesses(aProcesses, sizeof(aProcesses), &cbNeeded))

{

    return 1;

}





// Calculate how many process identifiers were returned.



cProcesses = cbNeeded / sizeof(DWORD);



// Print the name and process identifier for each process.



for (i = 0; i < cProcesses; i++)

{

    if (aProcesses[i] != 0)

    {

        std::cout << aProcesses[i] << std::endl;



}





c++ windows visual-studio winapi







share|improve this question




















  • 2





    instead of aProcesses` use aProcesses.data() or alternately &aProcesses[0] see: en.cppreference.com/w/cpp/container/vector/data

    – doug
    Nov 15 '18 at 4:48








  • 1





    Note that you need to call resize() on the vector yourself before passing a pointer to the data buffer to an API function, since Windows doesn't know anything about c++.

    – Jonathan Potter
    Nov 15 '18 at 4:51











  • It would be helpful to include the code you anticipate replacing to provide more specific advice.

    – doug
    Nov 15 '18 at 4:58











  • @doug i include manual allocate memory ways

    – Dwerson busch
    Nov 15 '18 at 5:04











  • Just declare your vector like so: std::vector<DWORD> aProcesses(1024); and use aProcesses.data() which is a pointer to the first vector element.

    – doug
    Nov 15 '18 at 5:08


















0















I want to stop using manual allocated memory to work with all winapi. for testing i try to change my code. but i get




no suitable conversion from vector DWORD to DWORD * exists.




std::vector<DWORD> aProcesses;

DWORD cbNeeded;

if (!EnumProcesses(aProcesses, aProcesses.capacity(), &cbNeeded))

{

    return 1;

}

for (auto& p : aProcesses)

{

    std::cout << p << std::endl;

}


Manual Allocated memory below



    DWORD aProcesses[1024], cbNeeded, cProcesses;

unsigned int i;

if (!EnumProcesses(aProcesses, sizeof(aProcesses), &cbNeeded))

{

    return 1;

}





// Calculate how many process identifiers were returned.



cProcesses = cbNeeded / sizeof(DWORD);



// Print the name and process identifier for each process.



for (i = 0; i < cProcesses; i++)

{

    if (aProcesses[i] != 0)

    {

        std::cout << aProcesses[i] << std::endl;



}





c++ windows visual-studio winapi







share|improve this question




















  • 2





    instead of aProcesses` use aProcesses.data() or alternately &aProcesses[0] see: en.cppreference.com/w/cpp/container/vector/data

    – doug
    Nov 15 '18 at 4:48








  • 1





    Note that you need to call resize() on the vector yourself before passing a pointer to the data buffer to an API function, since Windows doesn't know anything about c++.

    – Jonathan Potter
    Nov 15 '18 at 4:51











  • It would be helpful to include the code you anticipate replacing to provide more specific advice.

    – doug
    Nov 15 '18 at 4:58











  • @doug i include manual allocate memory ways

    – Dwerson busch
    Nov 15 '18 at 5:04











  • Just declare your vector like so: std::vector<DWORD> aProcesses(1024); and use aProcesses.data() which is a pointer to the first vector element.

    – doug
    Nov 15 '18 at 5:08
















0












0








0








I want to stop using manual allocated memory to work with all winapi. for testing i try to change my code. but i get




no suitable conversion from vector DWORD to DWORD * exists.




std::vector<DWORD> aProcesses;

DWORD cbNeeded;

if (!EnumProcesses(aProcesses, aProcesses.capacity(), &cbNeeded))

{

    return 1;

}

for (auto& p : aProcesses)

{

    std::cout << p << std::endl;

}


Manual Allocated memory below



    DWORD aProcesses[1024], cbNeeded, cProcesses;

unsigned int i;

if (!EnumProcesses(aProcesses, sizeof(aProcesses), &cbNeeded))

{

    return 1;

}





// Calculate how many process identifiers were returned.



cProcesses = cbNeeded / sizeof(DWORD);



// Print the name and process identifier for each process.



for (i = 0; i < cProcesses; i++)

{

    if (aProcesses[i] != 0)

    {

        std::cout << aProcesses[i] << std::endl;



}





c++ windows visual-studio winapi







share|improve this question
















I want to stop using manual allocated memory to work with all winapi. for testing i try to change my code. but i get




no suitable conversion from vector DWORD to DWORD * exists.




std::vector<DWORD> aProcesses;

DWORD cbNeeded;

if (!EnumProcesses(aProcesses, aProcesses.capacity(), &cbNeeded))

{

    return 1;

}

for (auto& p : aProcesses)

{

    std::cout << p << std::endl;

}


Manual Allocated memory below



    DWORD aProcesses[1024], cbNeeded, cProcesses;

unsigned int i;

if (!EnumProcesses(aProcesses, sizeof(aProcesses), &cbNeeded))

{

    return 1;

}





// Calculate how many process identifiers were returned.



cProcesses = cbNeeded / sizeof(DWORD);



// Print the name and process identifier for each process.



for (i = 0; i < cProcesses; i++)

{

    if (aProcesses[i] != 0)

    {

        std::cout << aProcesses[i] << std::endl;



}





c++ windows visual-studio winapi




c++ windows visual-studio winapi






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 5:02







Dwerson busch

















asked Nov 15 '18 at 4:43









Dwerson buschDwerson busch

64




64








  • 2





    instead of aProcesses` use aProcesses.data() or alternately &aProcesses[0] see: en.cppreference.com/w/cpp/container/vector/data

    – doug
    Nov 15 '18 at 4:48








  • 1





    Note that you need to call resize() on the vector yourself before passing a pointer to the data buffer to an API function, since Windows doesn't know anything about c++.

    – Jonathan Potter
    Nov 15 '18 at 4:51











  • It would be helpful to include the code you anticipate replacing to provide more specific advice.

    – doug
    Nov 15 '18 at 4:58











  • @doug i include manual allocate memory ways

    – Dwerson busch
    Nov 15 '18 at 5:04











  • Just declare your vector like so: std::vector<DWORD> aProcesses(1024); and use aProcesses.data() which is a pointer to the first vector element.

    – doug
    Nov 15 '18 at 5:08
















  • 2





    instead of aProcesses` use aProcesses.data() or alternately &aProcesses[0] see: en.cppreference.com/w/cpp/container/vector/data

    – doug
    Nov 15 '18 at 4:48








  • 1





    Note that you need to call resize() on the vector yourself before passing a pointer to the data buffer to an API function, since Windows doesn't know anything about c++.

    – Jonathan Potter
    Nov 15 '18 at 4:51











  • It would be helpful to include the code you anticipate replacing to provide more specific advice.

    – doug
    Nov 15 '18 at 4:58











  • @doug i include manual allocate memory ways

    – Dwerson busch
    Nov 15 '18 at 5:04











  • Just declare your vector like so: std::vector<DWORD> aProcesses(1024); and use aProcesses.data() which is a pointer to the first vector element.

    – doug
    Nov 15 '18 at 5:08










2




2





instead of aProcesses` use aProcesses.data() or alternately &aProcesses[0] see: en.cppreference.com/w/cpp/container/vector/data

– doug
Nov 15 '18 at 4:48







instead of aProcesses` use aProcesses.data() or alternately &aProcesses[0] see: en.cppreference.com/w/cpp/container/vector/data

– doug
Nov 15 '18 at 4:48






1




1





Note that you need to call resize() on the vector yourself before passing a pointer to the data buffer to an API function, since Windows doesn't know anything about c++.

– Jonathan Potter
Nov 15 '18 at 4:51





Note that you need to call resize() on the vector yourself before passing a pointer to the data buffer to an API function, since Windows doesn't know anything about c++.

– Jonathan Potter
Nov 15 '18 at 4:51













It would be helpful to include the code you anticipate replacing to provide more specific advice.

– doug
Nov 15 '18 at 4:58





It would be helpful to include the code you anticipate replacing to provide more specific advice.

– doug
Nov 15 '18 at 4:58













@doug i include manual allocate memory ways

– Dwerson busch
Nov 15 '18 at 5:04





@doug i include manual allocate memory ways

– Dwerson busch
Nov 15 '18 at 5:04













Just declare your vector like so: std::vector<DWORD> aProcesses(1024); and use aProcesses.data() which is a pointer to the first vector element.

– doug
Nov 15 '18 at 5:08







Just declare your vector like so: std::vector<DWORD> aProcesses(1024); and use aProcesses.data() which is a pointer to the first vector element.

– doug
Nov 15 '18 at 5:08














2 Answers
2






active

oldest

votes


















0















if (!EnumProcesses(aProcesses, aProcesses.capacity(), &cbNeeded))



won't work well. First thing is, you need to pass aProcesses.data() as the first parameter and the number of *bytes* aProcess can hold as the 2nd: aProcesses.size() * sizeof(DOWD).



If cbNeeded >= aProcess.size() * sizeof(DWORD) after the call, you have to resize the vector to cbNeeded / sizeof(DWORD) and call EnumProcesses() again to make sure you got all processes.






share|improve this answer
























  • if like that. is it call EnumProcesses twice. it make execution slow?

    – Dwerson busch
    Nov 15 '18 at 5:20











  • You have no other choice if you don't pass an array that is big enough the first time you call EnumProcesses().

    – Swordfish
    Nov 15 '18 at 5:44



















0














A vector isn't a pointer to DWORD; however, this vector happens to contain one so you can 



if (!EnumProcesses(aProcesses.data(), aProcesses.capacity(), &cbNeeded))


if your compiler is compiling for the C++11 Standard revision or more recent or 



if (!EnumProcesses(&aProcesses[0], aProcesses.capacity(), &cbNeeded))


if it is not.



But that just gets things compiling



There are logic problems yet to be dealt with.



const int MAX_PROCESSES = 1024; // very few Windows systems will exceed 1024 processes



std::vector<DWORD> aProcesses(MAX_PROCESSES); // allocate space

DWORD cbNeeded;

if (!EnumProcesses(aProcesses.data(), 

                   aProcesses.capacity() * sizeof(DWORD), // size in bytes, not elements  

                   &cbNeeded))

{

    return 1;

}

//for (auto& p : aProcesses) Not all processes may have been filled. The unused portions 

//are zeroed, so this is safe, but wasteful

for (int i = 0; i < cbNeeded / sizeof(DWORD); ++i)

{

    std::cout << aProcesses[i] << std::endl;

}





share|improve this answer


























  • is not MAX_NUM_DWORDS macro manually allocated memory? i should knows max possible the value?

    – Dwerson busch
    Nov 15 '18 at 5:06











  • @Dwersonbusch No, that was a stub. There is pretty much no way to know how many processes are running, but this rarely gets above a few hundred on all but the busiest of servers. Will update question.

    – user4581301
    Nov 15 '18 at 5:12













  • EnumProcesses api it just example. i knows if max processes will not run above 1k. but there's other winapi it will return above 1k value.

    – Dwerson busch
    Nov 15 '18 at 5:18











  • Why do you say that &aProcesses[0] isn't legal? aProcesses[0] returns a reference, T&, and taking the address of a reference is just a pointer to the referenced object. A DWORD in this case.

    – doug
    Nov 15 '18 at 5:58













  • @doug I can't imagine how you could do vector and the overload so that &vec[0] won't work, but it's not guaranteed. It's only an issue with C++ 98 and 03, so I did some old school standard diving and in 2005 drafts the wording looks like obeys the identity &v[n] == &v[0] + n for all 0 <= n < v.size(). Looks pretty conclusive that it ought to work and I'm gonna have to stop. It's too damn late and I work in the morning. And I'm having trouble typing work. Always a bad sign.

    – user4581301
    Nov 15 '18 at 6:59











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2 Answers
2






active

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votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0















if (!EnumProcesses(aProcesses, aProcesses.capacity(), &cbNeeded))



won't work well. First thing is, you need to pass aProcesses.data() as the first parameter and the number of *bytes* aProcess can hold as the 2nd: aProcesses.size() * sizeof(DOWD).



If cbNeeded >= aProcess.size() * sizeof(DWORD) after the call, you have to resize the vector to cbNeeded / sizeof(DWORD) and call EnumProcesses() again to make sure you got all processes.






share|improve this answer
























  • if like that. is it call EnumProcesses twice. it make execution slow?

    – Dwerson busch
    Nov 15 '18 at 5:20











  • You have no other choice if you don't pass an array that is big enough the first time you call EnumProcesses().

    – Swordfish
    Nov 15 '18 at 5:44
















0















if (!EnumProcesses(aProcesses, aProcesses.capacity(), &cbNeeded))



won't work well. First thing is, you need to pass aProcesses.data() as the first parameter and the number of *bytes* aProcess can hold as the 2nd: aProcesses.size() * sizeof(DOWD).



If cbNeeded >= aProcess.size() * sizeof(DWORD) after the call, you have to resize the vector to cbNeeded / sizeof(DWORD) and call EnumProcesses() again to make sure you got all processes.






share|improve this answer
























  • if like that. is it call EnumProcesses twice. it make execution slow?

    – Dwerson busch
    Nov 15 '18 at 5:20











  • You have no other choice if you don't pass an array that is big enough the first time you call EnumProcesses().

    – Swordfish
    Nov 15 '18 at 5:44














0












0








0








if (!EnumProcesses(aProcesses, aProcesses.capacity(), &cbNeeded))



won't work well. First thing is, you need to pass aProcesses.data() as the first parameter and the number of *bytes* aProcess can hold as the 2nd: aProcesses.size() * sizeof(DOWD).



If cbNeeded >= aProcess.size() * sizeof(DWORD) after the call, you have to resize the vector to cbNeeded / sizeof(DWORD) and call EnumProcesses() again to make sure you got all processes.






share|improve this answer














if (!EnumProcesses(aProcesses, aProcesses.capacity(), &cbNeeded))



won't work well. First thing is, you need to pass aProcesses.data() as the first parameter and the number of *bytes* aProcess can hold as the 2nd: aProcesses.size() * sizeof(DOWD).



If cbNeeded >= aProcess.size() * sizeof(DWORD) after the call, you have to resize the vector to cbNeeded / sizeof(DWORD) and call EnumProcesses() again to make sure you got all processes.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 5:06









SwordfishSwordfish

10.2k11436




10.2k11436













  • if like that. is it call EnumProcesses twice. it make execution slow?

    – Dwerson busch
    Nov 15 '18 at 5:20











  • You have no other choice if you don't pass an array that is big enough the first time you call EnumProcesses().

    – Swordfish
    Nov 15 '18 at 5:44



















  • if like that. is it call EnumProcesses twice. it make execution slow?

    – Dwerson busch
    Nov 15 '18 at 5:20











  • You have no other choice if you don't pass an array that is big enough the first time you call EnumProcesses().

    – Swordfish
    Nov 15 '18 at 5:44

















if like that. is it call EnumProcesses twice. it make execution slow?

– Dwerson busch
Nov 15 '18 at 5:20





if like that. is it call EnumProcesses twice. it make execution slow?

– Dwerson busch
Nov 15 '18 at 5:20













You have no other choice if you don't pass an array that is big enough the first time you call EnumProcesses().

– Swordfish
Nov 15 '18 at 5:44





You have no other choice if you don't pass an array that is big enough the first time you call EnumProcesses().

– Swordfish
Nov 15 '18 at 5:44













0














A vector isn't a pointer to DWORD; however, this vector happens to contain one so you can 



if (!EnumProcesses(aProcesses.data(), aProcesses.capacity(), &cbNeeded))


if your compiler is compiling for the C++11 Standard revision or more recent or 



if (!EnumProcesses(&aProcesses[0], aProcesses.capacity(), &cbNeeded))


if it is not.



But that just gets things compiling



There are logic problems yet to be dealt with.



const int MAX_PROCESSES = 1024; // very few Windows systems will exceed 1024 processes



std::vector<DWORD> aProcesses(MAX_PROCESSES); // allocate space

DWORD cbNeeded;

if (!EnumProcesses(aProcesses.data(), 

                   aProcesses.capacity() * sizeof(DWORD), // size in bytes, not elements  

                   &cbNeeded))

{

    return 1;

}

//for (auto& p : aProcesses) Not all processes may have been filled. The unused portions 

//are zeroed, so this is safe, but wasteful

for (int i = 0; i < cbNeeded / sizeof(DWORD); ++i)

{

    std::cout << aProcesses[i] << std::endl;

}





share|improve this answer


























  • is not MAX_NUM_DWORDS macro manually allocated memory? i should knows max possible the value?

    – Dwerson busch
    Nov 15 '18 at 5:06











  • @Dwersonbusch No, that was a stub. There is pretty much no way to know how many processes are running, but this rarely gets above a few hundred on all but the busiest of servers. Will update question.

    – user4581301
    Nov 15 '18 at 5:12













  • EnumProcesses api it just example. i knows if max processes will not run above 1k. but there's other winapi it will return above 1k value.

    – Dwerson busch
    Nov 15 '18 at 5:18











  • Why do you say that &aProcesses[0] isn't legal? aProcesses[0] returns a reference, T&, and taking the address of a reference is just a pointer to the referenced object. A DWORD in this case.

    – doug
    Nov 15 '18 at 5:58













  • @doug I can't imagine how you could do vector and the overload so that &vec[0] won't work, but it's not guaranteed. It's only an issue with C++ 98 and 03, so I did some old school standard diving and in 2005 drafts the wording looks like obeys the identity &v[n] == &v[0] + n for all 0 <= n < v.size(). Looks pretty conclusive that it ought to work and I'm gonna have to stop. It's too damn late and I work in the morning. And I'm having trouble typing work. Always a bad sign.

    – user4581301
    Nov 15 '18 at 6:59
















0














A vector isn't a pointer to DWORD; however, this vector happens to contain one so you can 



if (!EnumProcesses(aProcesses.data(), aProcesses.capacity(), &cbNeeded))


if your compiler is compiling for the C++11 Standard revision or more recent or 



if (!EnumProcesses(&aProcesses[0], aProcesses.capacity(), &cbNeeded))


if it is not.



But that just gets things compiling



There are logic problems yet to be dealt with.



const int MAX_PROCESSES = 1024; // very few Windows systems will exceed 1024 processes



std::vector<DWORD> aProcesses(MAX_PROCESSES); // allocate space

DWORD cbNeeded;

if (!EnumProcesses(aProcesses.data(), 

                   aProcesses.capacity() * sizeof(DWORD), // size in bytes, not elements  

                   &cbNeeded))

{

    return 1;

}

//for (auto& p : aProcesses) Not all processes may have been filled. The unused portions 

//are zeroed, so this is safe, but wasteful

for (int i = 0; i < cbNeeded / sizeof(DWORD); ++i)

{

    std::cout << aProcesses[i] << std::endl;

}





share|improve this answer


























  • is not MAX_NUM_DWORDS macro manually allocated memory? i should knows max possible the value?

    – Dwerson busch
    Nov 15 '18 at 5:06











  • @Dwersonbusch No, that was a stub. There is pretty much no way to know how many processes are running, but this rarely gets above a few hundred on all but the busiest of servers. Will update question.

    – user4581301
    Nov 15 '18 at 5:12













  • EnumProcesses api it just example. i knows if max processes will not run above 1k. but there's other winapi it will return above 1k value.

    – Dwerson busch
    Nov 15 '18 at 5:18











  • Why do you say that &aProcesses[0] isn't legal? aProcesses[0] returns a reference, T&, and taking the address of a reference is just a pointer to the referenced object. A DWORD in this case.

    – doug
    Nov 15 '18 at 5:58













  • @doug I can't imagine how you could do vector and the overload so that &vec[0] won't work, but it's not guaranteed. It's only an issue with C++ 98 and 03, so I did some old school standard diving and in 2005 drafts the wording looks like obeys the identity &v[n] == &v[0] + n for all 0 <= n < v.size(). Looks pretty conclusive that it ought to work and I'm gonna have to stop. It's too damn late and I work in the morning. And I'm having trouble typing work. Always a bad sign.

    – user4581301
    Nov 15 '18 at 6:59














0












0








0







A vector isn't a pointer to DWORD; however, this vector happens to contain one so you can 



if (!EnumProcesses(aProcesses.data(), aProcesses.capacity(), &cbNeeded))


if your compiler is compiling for the C++11 Standard revision or more recent or 



if (!EnumProcesses(&aProcesses[0], aProcesses.capacity(), &cbNeeded))


if it is not.



But that just gets things compiling



There are logic problems yet to be dealt with.



const int MAX_PROCESSES = 1024; // very few Windows systems will exceed 1024 processes



std::vector<DWORD> aProcesses(MAX_PROCESSES); // allocate space

DWORD cbNeeded;

if (!EnumProcesses(aProcesses.data(), 

                   aProcesses.capacity() * sizeof(DWORD), // size in bytes, not elements  

                   &cbNeeded))

{

    return 1;

}

//for (auto& p : aProcesses) Not all processes may have been filled. The unused portions 

//are zeroed, so this is safe, but wasteful

for (int i = 0; i < cbNeeded / sizeof(DWORD); ++i)

{

    std::cout << aProcesses[i] << std::endl;

}





share|improve this answer















A vector isn't a pointer to DWORD; however, this vector happens to contain one so you can 



if (!EnumProcesses(aProcesses.data(), aProcesses.capacity(), &cbNeeded))


if your compiler is compiling for the C++11 Standard revision or more recent or 



if (!EnumProcesses(&aProcesses[0], aProcesses.capacity(), &cbNeeded))


if it is not.



But that just gets things compiling



There are logic problems yet to be dealt with.



const int MAX_PROCESSES = 1024; // very few Windows systems will exceed 1024 processes



std::vector<DWORD> aProcesses(MAX_PROCESSES); // allocate space

DWORD cbNeeded;

if (!EnumProcesses(aProcesses.data(), 

                   aProcesses.capacity() * sizeof(DWORD), // size in bytes, not elements  

                   &cbNeeded))

{

    return 1;

}

//for (auto& p : aProcesses) Not all processes may have been filled. The unused portions 

//are zeroed, so this is safe, but wasteful

for (int i = 0; i < cbNeeded / sizeof(DWORD); ++i)

{

    std::cout << aProcesses[i] << std::endl;

}






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 15 '18 at 7:00

























answered Nov 15 '18 at 4:51









user4581301user4581301

20.5k51931




20.5k51931













  • is not MAX_NUM_DWORDS macro manually allocated memory? i should knows max possible the value?

    – Dwerson busch
    Nov 15 '18 at 5:06











  • @Dwersonbusch No, that was a stub. There is pretty much no way to know how many processes are running, but this rarely gets above a few hundred on all but the busiest of servers. Will update question.

    – user4581301
    Nov 15 '18 at 5:12













  • EnumProcesses api it just example. i knows if max processes will not run above 1k. but there's other winapi it will return above 1k value.

    – Dwerson busch
    Nov 15 '18 at 5:18











  • Why do you say that &aProcesses[0] isn't legal? aProcesses[0] returns a reference, T&, and taking the address of a reference is just a pointer to the referenced object. A DWORD in this case.

    – doug
    Nov 15 '18 at 5:58













  • @doug I can't imagine how you could do vector and the overload so that &vec[0] won't work, but it's not guaranteed. It's only an issue with C++ 98 and 03, so I did some old school standard diving and in 2005 drafts the wording looks like obeys the identity &v[n] == &v[0] + n for all 0 <= n < v.size(). Looks pretty conclusive that it ought to work and I'm gonna have to stop. It's too damn late and I work in the morning. And I'm having trouble typing work. Always a bad sign.

    – user4581301
    Nov 15 '18 at 6:59



















  • is not MAX_NUM_DWORDS macro manually allocated memory? i should knows max possible the value?

    – Dwerson busch
    Nov 15 '18 at 5:06











  • @Dwersonbusch No, that was a stub. There is pretty much no way to know how many processes are running, but this rarely gets above a few hundred on all but the busiest of servers. Will update question.

    – user4581301
    Nov 15 '18 at 5:12













  • EnumProcesses api it just example. i knows if max processes will not run above 1k. but there's other winapi it will return above 1k value.

    – Dwerson busch
    Nov 15 '18 at 5:18











  • Why do you say that &aProcesses[0] isn't legal? aProcesses[0] returns a reference, T&, and taking the address of a reference is just a pointer to the referenced object. A DWORD in this case.

    – doug
    Nov 15 '18 at 5:58













  • @doug I can't imagine how you could do vector and the overload so that &vec[0] won't work, but it's not guaranteed. It's only an issue with C++ 98 and 03, so I did some old school standard diving and in 2005 drafts the wording looks like obeys the identity &v[n] == &v[0] + n for all 0 <= n < v.size(). Looks pretty conclusive that it ought to work and I'm gonna have to stop. It's too damn late and I work in the morning. And I'm having trouble typing work. Always a bad sign.

    – user4581301
    Nov 15 '18 at 6:59

















is not MAX_NUM_DWORDS macro manually allocated memory? i should knows max possible the value?

– Dwerson busch
Nov 15 '18 at 5:06





is not MAX_NUM_DWORDS macro manually allocated memory? i should knows max possible the value?

– Dwerson busch
Nov 15 '18 at 5:06













@Dwersonbusch No, that was a stub. There is pretty much no way to know how many processes are running, but this rarely gets above a few hundred on all but the busiest of servers. Will update question.

– user4581301
Nov 15 '18 at 5:12







@Dwersonbusch No, that was a stub. There is pretty much no way to know how many processes are running, but this rarely gets above a few hundred on all but the busiest of servers. Will update question.

– user4581301
Nov 15 '18 at 5:12















EnumProcesses api it just example. i knows if max processes will not run above 1k. but there's other winapi it will return above 1k value.

– Dwerson busch
Nov 15 '18 at 5:18





EnumProcesses api it just example. i knows if max processes will not run above 1k. but there's other winapi it will return above 1k value.

– Dwerson busch
Nov 15 '18 at 5:18













Why do you say that &aProcesses[0] isn't legal? aProcesses[0] returns a reference, T&, and taking the address of a reference is just a pointer to the referenced object. A DWORD in this case.

– doug
Nov 15 '18 at 5:58







Why do you say that &aProcesses[0] isn't legal? aProcesses[0] returns a reference, T&, and taking the address of a reference is just a pointer to the referenced object. A DWORD in this case.

– doug
Nov 15 '18 at 5:58















@doug I can't imagine how you could do vector and the overload so that &vec[0] won't work, but it's not guaranteed. It's only an issue with C++ 98 and 03, so I did some old school standard diving and in 2005 drafts the wording looks like obeys the identity &v[n] == &v[0] + n for all 0 <= n < v.size(). Looks pretty conclusive that it ought to work and I'm gonna have to stop. It's too damn late and I work in the morning. And I'm having trouble typing work. Always a bad sign.

– user4581301
Nov 15 '18 at 6:59





@doug I can't imagine how you could do vector and the overload so that &vec[0] won't work, but it's not guaranteed. It's only an issue with C++ 98 and 03, so I did some old school standard diving and in 2005 drafts the wording looks like obeys the identity &v[n] == &v[0] + n for all 0 <= n < v.size(). Looks pretty conclusive that it ought to work and I'm gonna have to stop. It's too damn late and I work in the morning. And I'm having trouble typing work. Always a bad sign.

– user4581301
Nov 15 '18 at 6:59


















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