Different results with intermediate prints












0















I have this function



def getDigits (num) :

    check = checkNum(num)

    #print('num: '+str(num))

    if check is False :

        strNum  = str(num)

        numList = map(toInt, strNum)

        #print(list(numList))

        squareList = map(getSquareOfDigits, numList)

        #print(list(squareList))

        sumOfSquares = sum(squareList)

        print('sumSqr: '+str(sumOfSquares))

        getDigits(sumOfSquares)

    else :

        return check


And the result of it is:



sumSqr: 4



sumSqr: 16



sumSqr: 37



sumSqr: 58



sumSqr: 89



sumSqr: 9



sumSqr: 81



sumSqr: 65



sumSqr: 61



sumSqr: 37



sumSqr: 58



sumSqr: 89



But if I uncomment all the prints, the result is:



[2]



sumSqr: 0

[3]



sumSqr: 0


ok, I know that the list method change the result, but I want to know it there's a way to print the object variables without changing the result, and not using an intermediate variable.



UPDATE



full example here






python python-3.x







share|improve this question




















  • 2





    Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.

    – GlobalTraveler
    Nov 17 '18 at 11:42






  • 1





    Traveler is talking about this. How would we know, what checkNum, toInt, getSquareOfDigits do?

    – Mr. T
    Nov 17 '18 at 13:07
















0















I have this function



def getDigits (num) :

    check = checkNum(num)

    #print('num: '+str(num))

    if check is False :

        strNum  = str(num)

        numList = map(toInt, strNum)

        #print(list(numList))

        squareList = map(getSquareOfDigits, numList)

        #print(list(squareList))

        sumOfSquares = sum(squareList)

        print('sumSqr: '+str(sumOfSquares))

        getDigits(sumOfSquares)

    else :

        return check


And the result of it is:



sumSqr: 4



sumSqr: 16



sumSqr: 37



sumSqr: 58



sumSqr: 89



sumSqr: 9



sumSqr: 81



sumSqr: 65



sumSqr: 61



sumSqr: 37



sumSqr: 58



sumSqr: 89



But if I uncomment all the prints, the result is:



[2]



sumSqr: 0

[3]



sumSqr: 0


ok, I know that the list method change the result, but I want to know it there's a way to print the object variables without changing the result, and not using an intermediate variable.



UPDATE



full example here






python python-3.x







share|improve this question




















  • 2





    Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.

    – GlobalTraveler
    Nov 17 '18 at 11:42






  • 1





    Traveler is talking about this. How would we know, what checkNum, toInt, getSquareOfDigits do?

    – Mr. T
    Nov 17 '18 at 13:07














0












0








0








I have this function



def getDigits (num) :

    check = checkNum(num)

    #print('num: '+str(num))

    if check is False :

        strNum  = str(num)

        numList = map(toInt, strNum)

        #print(list(numList))

        squareList = map(getSquareOfDigits, numList)

        #print(list(squareList))

        sumOfSquares = sum(squareList)

        print('sumSqr: '+str(sumOfSquares))

        getDigits(sumOfSquares)

    else :

        return check


And the result of it is:



sumSqr: 4



sumSqr: 16



sumSqr: 37



sumSqr: 58



sumSqr: 89



sumSqr: 9



sumSqr: 81



sumSqr: 65



sumSqr: 61



sumSqr: 37



sumSqr: 58



sumSqr: 89



But if I uncomment all the prints, the result is:



[2]



sumSqr: 0

[3]



sumSqr: 0


ok, I know that the list method change the result, but I want to know it there's a way to print the object variables without changing the result, and not using an intermediate variable.



UPDATE



full example here






python python-3.x







share|improve this question
















I have this function



def getDigits (num) :

    check = checkNum(num)

    #print('num: '+str(num))

    if check is False :

        strNum  = str(num)

        numList = map(toInt, strNum)

        #print(list(numList))

        squareList = map(getSquareOfDigits, numList)

        #print(list(squareList))

        sumOfSquares = sum(squareList)

        print('sumSqr: '+str(sumOfSquares))

        getDigits(sumOfSquares)

    else :

        return check


And the result of it is:



sumSqr: 4



sumSqr: 16



sumSqr: 37



sumSqr: 58



sumSqr: 89



sumSqr: 9



sumSqr: 81



sumSqr: 65



sumSqr: 61



sumSqr: 37



sumSqr: 58



sumSqr: 89



But if I uncomment all the prints, the result is:



[2]



sumSqr: 0

[3]



sumSqr: 0


ok, I know that the list method change the result, but I want to know it there's a way to print the object variables without changing the result, and not using an intermediate variable.



UPDATE



full example here






python python-3.x




python python-3.x






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 17 '18 at 19:10

























asked Nov 15 '18 at 18:05







user10608741















  • 2





    Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.

    – GlobalTraveler
    Nov 17 '18 at 11:42






  • 1





    Traveler is talking about this. How would we know, what checkNum, toInt, getSquareOfDigits do?

    – Mr. T
    Nov 17 '18 at 13:07














  • 2





    Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.

    – GlobalTraveler
    Nov 17 '18 at 11:42






  • 1





    Traveler is talking about this. How would we know, what checkNum, toInt, getSquareOfDigits do?

    – Mr. T
    Nov 17 '18 at 13:07








2




2





Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.

– GlobalTraveler
Nov 17 '18 at 11:42





Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.

– GlobalTraveler
Nov 17 '18 at 11:42




1




1





Traveler is talking about this. How would we know, what checkNum, toInt, getSquareOfDigits do?

– Mr. T
Nov 17 '18 at 13:07





Traveler is talking about this. How would we know, what checkNum, toInt, getSquareOfDigits do?

– Mr. T
Nov 17 '18 at 13:07












1 Answer
1






active

oldest

votes


















0














The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.



To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.






share|improve this answer
























  • ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?

    – user10608741
    Nov 21 '18 at 17:04






  • 1





    I honestly dont understand: Not add it to the code?

    – user2722968
    Nov 21 '18 at 19:21











  • in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable

    – user10608741
    Nov 22 '18 at 16:01











  • As I said above, use numList = list(map(toInt, strNum)) instead of just numList = map(...). This will cause numList to be a list-object, not an iterator. You can then print(numList) without side-effects.

    – user2722968
    Nov 22 '18 at 16:25











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53325461%2fdifferent-results-with-intermediate-prints%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown
























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.



To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.






share|improve this answer
























  • ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?

    – user10608741
    Nov 21 '18 at 17:04






  • 1





    I honestly dont understand: Not add it to the code?

    – user2722968
    Nov 21 '18 at 19:21











  • in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable

    – user10608741
    Nov 22 '18 at 16:01











  • As I said above, use numList = list(map(toInt, strNum)) instead of just numList = map(...). This will cause numList to be a list-object, not an iterator. You can then print(numList) without side-effects.

    – user2722968
    Nov 22 '18 at 16:25
















0














The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.



To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.






share|improve this answer
























  • ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?

    – user10608741
    Nov 21 '18 at 17:04






  • 1





    I honestly dont understand: Not add it to the code?

    – user2722968
    Nov 21 '18 at 19:21











  • in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable

    – user10608741
    Nov 22 '18 at 16:01











  • As I said above, use numList = list(map(toInt, strNum)) instead of just numList = map(...). This will cause numList to be a list-object, not an iterator. You can then print(numList) without side-effects.

    – user2722968
    Nov 22 '18 at 16:25














0












0








0







The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.



To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.






share|improve this answer













The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.



To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 17 '18 at 15:16









user2722968user2722968

2,74911637




2,74911637













  • ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?

    – user10608741
    Nov 21 '18 at 17:04






  • 1





    I honestly dont understand: Not add it to the code?

    – user2722968
    Nov 21 '18 at 19:21











  • in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable

    – user10608741
    Nov 22 '18 at 16:01











  • As I said above, use numList = list(map(toInt, strNum)) instead of just numList = map(...). This will cause numList to be a list-object, not an iterator. You can then print(numList) without side-effects.

    – user2722968
    Nov 22 '18 at 16:25



















  • ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?

    – user10608741
    Nov 21 '18 at 17:04






  • 1





    I honestly dont understand: Not add it to the code?

    – user2722968
    Nov 21 '18 at 19:21











  • in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable

    – user10608741
    Nov 22 '18 at 16:01











  • As I said above, use numList = list(map(toInt, strNum)) instead of just numList = map(...). This will cause numList to be a list-object, not an iterator. You can then print(numList) without side-effects.

    – user2722968
    Nov 22 '18 at 16:25

















ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?

– user10608741
Nov 21 '18 at 17:04





ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?

– user10608741
Nov 21 '18 at 17:04




1




1





I honestly dont understand: Not add it to the code?

– user2722968
Nov 21 '18 at 19:21





I honestly dont understand: Not add it to the code?

– user2722968
Nov 21 '18 at 19:21













in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable

– user10608741
Nov 22 '18 at 16:01





in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable

– user10608741
Nov 22 '18 at 16:01













As I said above, use numList = list(map(toInt, strNum)) instead of just numList = map(...). This will cause numList to be a list-object, not an iterator. You can then print(numList) without side-effects.

– user2722968
Nov 22 '18 at 16:25





As I said above, use numList = list(map(toInt, strNum)) instead of just numList = map(...). This will cause numList to be a list-object, not an iterator. You can then print(numList) without side-effects.

– user2722968
Nov 22 '18 at 16:25




















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid …



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53325461%2fdifferent-results-with-intermediate-prints%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







-

Popular posts from this blog

Florida Star v. B. J. F.

Image
Florida Star v. B. J. F. From Wikipedia, the free encyclopedia Jump to navigation Jump to search United States Supreme Court case Florida Star v. B. J. F. Supreme Court of the United States Argued March 21, 1989 Decided June 21, 1989 Full case name The Florida Star v. B. J. F. Citations 491 U.S. 524 ( more ) 109 S. Ct. 2603; 105 L. Ed. 2d 443; 1989 U.S. LEXIS 3120; 57 U.S.L.W. 4816; 16 Media L. Rep. 1801 Prior history The Florida Star v. B.J.F., 530 So.2d 286 (1988) Supreme Court of Florida; Florida Star v. B.J.F., 499 So.2d 883 (1986) Fla. Dist. Court of Appeals Holding Florida Stat. § 794.03 is unconstitutional to the extent it makes the truthful reporting of information that was a matter of public record unlawful, as it violates the First Amendment. Court membership Chief Justice William Rehnquist Associate Justices William J. Brennan Jr.  · Byron White Thurgood Marshall  · Harry Blac...
Read more

Danny Elfman

Image
Danny Elfman From Wikipedia, the free encyclopedia Jump to navigation Jump to search Danny Elfman Elfman at the 2010 San Diego Comic-Con Born Daniel Robert Elfman ( 1953-05-29 ) May 29, 1953 (age 65) Los Angeles, California, U.S. Spouse(s) Bridget Fonda ( m.  2003) Children 1 Musical career Genres Rock [1] ska [2] new wave film music video game music Occupation(s) Composer, singer, songwriter, record producer Instruments Trombone guitar percussion vocals keyboards [3] Years active 1972–present Associated acts Oingo Boingo James Newton Howard Daniel Robert Elfman (born May 29, 1953) is an American composer, singer, songwriter, and record producer. Elfman first became known for being the lead singer and songwriter for the band Oingo Boingo from 1974 to 1995. He is well known for scoring films and television shows, particularly his frequent collabora...
Read more

Lugert, Oklahoma

Image
Unincorporated community in Oklahoma, United States Lugert, Oklahoma Unincorporated community Foundations from the town of Lugert at the bottom of Lake Altus-Lugert Lugert, Oklahoma Location within the state of Oklahoma Coordinates: 34°53′45″N 99°16′31″W  /  34.89583°N 99.27528°W  / 34.89583; -99.27528 Coordinates: 34°53′45″N 99°16′31″W  /  34.89583°N 99.27528°W  / 34.89583; -99.27528 Country United States State Oklahoma County Kiowa Time zone UTC-6 (Central (CST))  • Summer (DST) UTC-5 (CDT) GNIS feature ID 1100597 Lugert is an unincorporated community in Kiowa County, Oklahoma. [1] The town of Lugert was founded in 1901 on 80 acres (320,000 m 2 ). In the town, there was a general store that housed the Post office and sold dry goods, school supplies, groceries, harnesses, axes and much more. It was named for Frank Lugert, who had moved to the area in 1898. Lugert owned land where the town was sited and also owned the general st...
Read more