Simplify 2 Java variables into one
-4
I've got these 2 Java variables:
spiEuler = spiEuler + (1 / Math.pow(2 * k + 1, 2));
piEuler = Math.sqrt(spiEuler * 8);
...and I'd like to combine them into one.
Unfortunately,
piCombined = Math.sqrt((xPi + (1 / Math.pow(2 * k + 1, 2))) * 8);
doesn't do that. What did I do wrong here?
java pi
asked Nov 14 '18 at 21:09
Fabian SternFabian Stern
13
add a comment |
-4
I've got these 2 Java variables:
spiEuler = spiEuler + (1 / Math.pow(2 * k + 1, 2));
piEuler = Math.sqrt(spiEuler * 8);
...and I'd like to combine them into one.
Unfortunately,
piCombined = Math.sqrt((xPi + (1 / Math.pow(2 * k + 1, 2))) * 8);
doesn't do that. What did I do wrong here?
java pi
asked Nov 14 '18 at 21:09
Fabian SternFabian Stern
13
1
It doesn't do that? What does it do? What did you expect?
– khelwood
Nov 14 '18 at 21:13
add a comment |
-4
-4
-4
I've got these 2 Java variables:
spiEuler = spiEuler + (1 / Math.pow(2 * k + 1, 2));
piEuler = Math.sqrt(spiEuler * 8);
...and I'd like to combine them into one.
Unfortunately,
piCombined = Math.sqrt((xPi + (1 / Math.pow(2 * k + 1, 2))) * 8);
doesn't do that. What did I do wrong here?
java pi
asked Nov 14 '18 at 21:09
Fabian SternFabian Stern
13
I've got these 2 Java variables:
spiEuler = spiEuler + (1 / Math.pow(2 * k + 1, 2));
piEuler = Math.sqrt(spiEuler * 8);
...and I'd like to combine them into one.
Unfortunately,
piCombined = Math.sqrt((xPi + (1 / Math.pow(2 * k + 1, 2))) * 8);
doesn't do that. What did I do wrong here?
java pi
java pi
asked Nov 14 '18 at 21:09
Fabian SternFabian Stern
13
asked Nov 14 '18 at 21:09
Fabian SternFabian Stern
13
asked Nov 14 '18 at 21:09
Fabian SternFabian Stern
13
asked Nov 14 '18 at 21:09
Fabian SternFabian Stern
13
asked Nov 14 '18 at 21:09
Fabian SternFabian Stern
13
13
1
It doesn't do that? What does it do? What did you expect?
– khelwood
Nov 14 '18 at 21:13
add a comment |
1
It doesn't do that? What does it do? What did you expect?
– khelwood
Nov 14 '18 at 21:13
1
1
It doesn't do that? What does it do? What did you expect?
– khelwood
Nov 14 '18 at 21:13
It doesn't do that? What does it do? What did you expect?
– khelwood
Nov 14 '18 at 21:13
add a comment |
1 Answer
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the most you can get is
spiEuler += (1 / Math.pow(2 * k + 1, 2));
and then
piEuler = Math.sqrt(spiEuler * 8);
answered Nov 14 '18 at 21:13
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1 Answer
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1 Answer
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active
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0
the most you can get is
spiEuler += (1 / Math.pow(2 * k + 1, 2));
and then
piEuler = Math.sqrt(spiEuler * 8);
answered Nov 14 '18 at 21:13
ΦXocę 웃 Пepeúpa ツΦXocę 웃 Пepeúpa ツ
33.7k113963
add a comment |
0
the most you can get is
spiEuler += (1 / Math.pow(2 * k + 1, 2));
and then
piEuler = Math.sqrt(spiEuler * 8);
answered Nov 14 '18 at 21:13
ΦXocę 웃 Пepeúpa ツΦXocę 웃 Пepeúpa ツ
33.7k113963
add a comment |
0
0
0
the most you can get is
spiEuler += (1 / Math.pow(2 * k + 1, 2));
and then
piEuler = Math.sqrt(spiEuler * 8);
answered Nov 14 '18 at 21:13
ΦXocę 웃 Пepeúpa ツΦXocę 웃 Пepeúpa ツ
33.7k113963
the most you can get is
spiEuler += (1 / Math.pow(2 * k + 1, 2));
and then
piEuler = Math.sqrt(spiEuler * 8);
answered Nov 14 '18 at 21:13
ΦXocę 웃 Пepeúpa ツΦXocę 웃 Пepeúpa ツ
33.7k113963
answered Nov 14 '18 at 21:13
ΦXocę 웃 Пepeúpa ツΦXocę 웃 Пepeúpa ツ
33.7k113963
answered Nov 14 '18 at 21:13
ΦXocę 웃 Пepeúpa ツΦXocę 웃 Пepeúpa ツ
33.7k113963
answered Nov 14 '18 at 21:13
ΦXocę 웃 Пepeúpa ツΦXocę 웃 Пepeúpa ツ
33.7k113963
33.7k113963
add a comment |
add a comment |
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1
It doesn't do that? What does it do? What did you expect?
– khelwood
Nov 14 '18 at 21:13