Update input value dynamically & update another element after dynamic input change












0














Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p> tags outside of the form. I have been able to update the first two <p> tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p> tag to update when the third input value has dynamically changed.



Here is a Codepen for the problem.



HTML



<form>

  <input id="one" type="number" class="sumVari" name="a"> 

  <input id="two" type="number" class="sumVari" name="b">

  <input id="three" type="number" name="sum" placeholder="sum of a & b">

</form>

<div id="displayValues">

  <p>The value of a is: <span id="a"></span> </p>

  <p>The value of a is: <span id="b"></span></p>

  <p>The value of the sum is: <span id="sum"></span></p>

</div>


JS



let one = $('#one');

let two = $('#two');

let three = $('#three');



$('form').on('change', 'input', function() {

  let target = $(this);

  let attrName = target.attr('name');



  $('#'+attrName).text(target.val());

});



function sum(a,b) {

  return a+b;

}



$('.sumVari').each(function(){

  $(this).change(function(){

    if(one.val() != '' && two.val() != '') {

      three.val(sum(one.val(), two.val()));

    }

  });

});





jquery forms events input dynamically-generated







share|improve this question



























    0














    Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p> tags outside of the form. I have been able to update the first two <p> tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p> tag to update when the third input value has dynamically changed.



    Here is a Codepen for the problem.



    HTML



    <form>
    
  <input id="one" type="number" class="sumVari" name="a"> 
    
  <input id="two" type="number" class="sumVari" name="b">
    
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
    
</form>
    
<div id="displayValues">
    
  <p>The value of a is: <span id="a"></span> </p>
    
  <p>The value of a is: <span id="b"></span></p>
    
  <p>The value of the sum is: <span id="sum"></span></p>
    
</div>


    JS



    let one = $('#one');
    
let two = $('#two');
    
let three = $('#three');
    

    
$('form').on('change', 'input', function() {
    
  let target = $(this);
    
  let attrName = target.attr('name');
    

    
  $('#'+attrName).text(target.val());
    
});
    

    
function sum(a,b) {
    
  return a+b;
    
}
    

    
$('.sumVari').each(function(){
    
  $(this).change(function(){
    
    if(one.val() != '' && two.val() != '') {
    
      three.val(sum(one.val(), two.val()));
    
    }
    
  });
    
});





    jquery forms events input dynamically-generated







    share|improve this question

























      0












      0








      0







      Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p> tags outside of the form. I have been able to update the first two <p> tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p> tag to update when the third input value has dynamically changed.



      Here is a Codepen for the problem.



      HTML



      <form>
      
  <input id="one" type="number" class="sumVari" name="a"> 
      
  <input id="two" type="number" class="sumVari" name="b">
      
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
      
</form>
      
<div id="displayValues">
      
  <p>The value of a is: <span id="a"></span> </p>
      
  <p>The value of a is: <span id="b"></span></p>
      
  <p>The value of the sum is: <span id="sum"></span></p>
      
</div>


      JS



      let one = $('#one');
      
let two = $('#two');
      
let three = $('#three');
      

      
$('form').on('change', 'input', function() {
      
  let target = $(this);
      
  let attrName = target.attr('name');
      

      
  $('#'+attrName).text(target.val());
      
});
      

      
function sum(a,b) {
      
  return a+b;
      
}
      

      
$('.sumVari').each(function(){
      
  $(this).change(function(){
      
    if(one.val() != '' && two.val() != '') {
      
      three.val(sum(one.val(), two.val()));
      
    }
      
  });
      
});





      jquery forms events input dynamically-generated







      share|improve this question













      Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p> tags outside of the form. I have been able to update the first two <p> tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p> tag to update when the third input value has dynamically changed.



      Here is a Codepen for the problem.



      HTML



      <form>
      
  <input id="one" type="number" class="sumVari" name="a"> 
      
  <input id="two" type="number" class="sumVari" name="b">
      
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
      
</form>
      
<div id="displayValues">
      
  <p>The value of a is: <span id="a"></span> </p>
      
  <p>The value of a is: <span id="b"></span></p>
      
  <p>The value of the sum is: <span id="sum"></span></p>
      
</div>


      JS



      let one = $('#one');
      
let two = $('#two');
      
let three = $('#three');
      

      
$('form').on('change', 'input', function() {
      
  let target = $(this);
      
  let attrName = target.attr('name');
      

      
  $('#'+attrName).text(target.val());
      
});
      

      
function sum(a,b) {
      
  return a+b;
      
}
      

      
$('.sumVari').each(function(){
      
  $(this).change(function(){
      
    if(one.val() != '' && two.val() != '') {
      
      three.val(sum(one.val(), two.val()));
      
    }
      
  });
      
});





      jquery forms events input dynamically-generated




      jquery forms events input dynamically-generated






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 12 at 0:24









      prestondoris

      395




      395
























          1 Answer
          1






          active

          oldest

          votes


















          1















          1. Call the change event manually when putting value on the sum





          let one = $('#one');
          
let two = $('#two');
          
let three = $('#three');
          

          
$('form').on('change', 'input', function() {
          
  let target = $(this);
          
  let attrName = target.attr('name');
          

          
  $('#' + attrName).text(target.val());
          
});
          

          
function sum(a, b) {
          
  return a + b;
          
}
          

          
$('.sumVari').each(function() {
          
  $(this).change(function() {
          
    if (one.val() != '' && two.val() != '') {
          
      three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
          
    }
          
  });
          
});

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          
<form>
          
  <input id="one" type="number" class="sumVari" name="a">
          
  <input id="two" type="number" class="sumVari" name="b">
          
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
          
</form>
          
<div id="displayValues">
          
  <p>The value of a is: <span id="a"></span> </p>
          
  <p>The value of a is: <span id="b"></span></p>
          
  <p>The value of the sum is: <span id="sum"></span></p>
          
</div>








          share|improve this answer





















          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25











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          1 Answer
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          active

          oldest

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          active

          oldest

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          1















          1. Call the change event manually when putting value on the sum





          let one = $('#one');
          
let two = $('#two');
          
let three = $('#three');
          

          
$('form').on('change', 'input', function() {
          
  let target = $(this);
          
  let attrName = target.attr('name');
          

          
  $('#' + attrName).text(target.val());
          
});
          

          
function sum(a, b) {
          
  return a + b;
          
}
          

          
$('.sumVari').each(function() {
          
  $(this).change(function() {
          
    if (one.val() != '' && two.val() != '') {
          
      three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
          
    }
          
  });
          
});

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          
<form>
          
  <input id="one" type="number" class="sumVari" name="a">
          
  <input id="two" type="number" class="sumVari" name="b">
          
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
          
</form>
          
<div id="displayValues">
          
  <p>The value of a is: <span id="a"></span> </p>
          
  <p>The value of a is: <span id="b"></span></p>
          
  <p>The value of the sum is: <span id="sum"></span></p>
          
</div>








          share|improve this answer





















          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25
















          1















          1. Call the change event manually when putting value on the sum





          let one = $('#one');
          
let two = $('#two');
          
let three = $('#three');
          

          
$('form').on('change', 'input', function() {
          
  let target = $(this);
          
  let attrName = target.attr('name');
          

          
  $('#' + attrName).text(target.val());
          
});
          

          
function sum(a, b) {
          
  return a + b;
          
}
          

          
$('.sumVari').each(function() {
          
  $(this).change(function() {
          
    if (one.val() != '' && two.val() != '') {
          
      three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
          
    }
          
  });
          
});

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          
<form>
          
  <input id="one" type="number" class="sumVari" name="a">
          
  <input id="two" type="number" class="sumVari" name="b">
          
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
          
</form>
          
<div id="displayValues">
          
  <p>The value of a is: <span id="a"></span> </p>
          
  <p>The value of a is: <span id="b"></span></p>
          
  <p>The value of the sum is: <span id="sum"></span></p>
          
</div>








          share|improve this answer





















          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25














          1












          1








          1







          1. Call the change event manually when putting value on the sum





          let one = $('#one');
          
let two = $('#two');
          
let three = $('#three');
          

          
$('form').on('change', 'input', function() {
          
  let target = $(this);
          
  let attrName = target.attr('name');
          

          
  $('#' + attrName).text(target.val());
          
});
          

          
function sum(a, b) {
          
  return a + b;
          
}
          

          
$('.sumVari').each(function() {
          
  $(this).change(function() {
          
    if (one.val() != '' && two.val() != '') {
          
      three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
          
    }
          
  });
          
});

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          
<form>
          
  <input id="one" type="number" class="sumVari" name="a">
          
  <input id="two" type="number" class="sumVari" name="b">
          
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
          
</form>
          
<div id="displayValues">
          
  <p>The value of a is: <span id="a"></span> </p>
          
  <p>The value of a is: <span id="b"></span></p>
          
  <p>The value of the sum is: <span id="sum"></span></p>
          
</div>








          share|improve this answer













          1. Call the change event manually when putting value on the sum





          let one = $('#one');
          
let two = $('#two');
          
let three = $('#three');
          

          
$('form').on('change', 'input', function() {
          
  let target = $(this);
          
  let attrName = target.attr('name');
          

          
  $('#' + attrName).text(target.val());
          
});
          

          
function sum(a, b) {
          
  return a + b;
          
}
          

          
$('.sumVari').each(function() {
          
  $(this).change(function() {
          
    if (one.val() != '' && two.val() != '') {
          
      three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
          
    }
          
  });
          
});

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          
<form>
          
  <input id="one" type="number" class="sumVari" name="a">
          
  <input id="two" type="number" class="sumVari" name="b">
          
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
          
</form>
          
<div id="displayValues">
          
  <p>The value of a is: <span id="a"></span> </p>
          
  <p>The value of a is: <span id="b"></span></p>
          
  <p>The value of the sum is: <span id="sum"></span></p>
          
</div>








          let one = $('#one');
          
let two = $('#two');
          
let three = $('#three');
          

          
$('form').on('change', 'input', function() {
          
  let target = $(this);
          
  let attrName = target.attr('name');
          

          
  $('#' + attrName).text(target.val());
          
});
          

          
function sum(a, b) {
          
  return a + b;
          
}
          

          
$('.sumVari').each(function() {
          
  $(this).change(function() {
          
    if (one.val() != '' && two.val() != '') {
          
      three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
          
    }
          
  });
          
});

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          
<form>
          
  <input id="one" type="number" class="sumVari" name="a">
          
  <input id="two" type="number" class="sumVari" name="b">
          
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
          
</form>
          
<div id="displayValues">
          
  <p>The value of a is: <span id="a"></span> </p>
          
  <p>The value of a is: <span id="b"></span></p>
          
  <p>The value of the sum is: <span id="sum"></span></p>
          
</div>





          let one = $('#one');
          
let two = $('#two');
          
let three = $('#three');
          

          
$('form').on('change', 'input', function() {
          
  let target = $(this);
          
  let attrName = target.attr('name');
          

          
  $('#' + attrName).text(target.val());
          
});
          

          
function sum(a, b) {
          
  return a + b;
          
}
          

          
$('.sumVari').each(function() {
          
  $(this).change(function() {
          
    if (one.val() != '' && two.val() != '') {
          
      three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
          
    }
          
  });
          
});

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          
<form>
          
  <input id="one" type="number" class="sumVari" name="a">
          
  <input id="two" type="number" class="sumVari" name="b">
          
  <input id="three" type="number" name="sum" placeholder="sum of a & b">
          
</form>
          
<div id="displayValues">
          
  <p>The value of a is: <span id="a"></span> </p>
          
  <p>The value of a is: <span id="b"></span></p>
          
  <p>The value of the sum is: <span id="sum"></span></p>
          
</div>






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 12 at 0:28









          guradio

          13.7k31836




          13.7k31836












          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25


















          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25
















          @prestondoris glad it works for you happy coding mate :)
          – guradio
          Nov 13 at 0:25




          @prestondoris glad it works for you happy coding mate :)
          – guradio
          Nov 13 at 0:25


















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