Spring Boot Websocket and SPA Natural Routing
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I am currently implementing a Spring Boot application with an SPA React front-end. To route every every request which is not exactly mapped to a route I use the following controller to forward the requests to my React application (as seen here: https://stackoverflow.com/a/40769350/4454752 with a little change to also support not mapped requests to URL of the form /a/b/c/...):
@Controller
public class BaseController {
private static final Logger LOGGER = LogManager.getLogger(BaseController.class);
// Match everything without a suffix (so not a static resource)
@RequestMapping(value = "/**/{[path:[^\.]*}")
public String redirect() {
LOGGER.info("Redirect request to React app");
// Forward to home page so that route is preserved.
return "forward:/";
}
}
In addition to that I want to a have a plain Websocket route at /socket
which handles both text and binary Websocket messages. I do not want to use the STOMP
protocol at this endpoint.
I configured my Websockets like so:
@Configuration
@EnableWebSocket
@CrossOrigin(origins = "*")
public class WebSocketConfiguration implements WebSocketConfigurer {
@Override
public void registerWebSocketHandlers(WebSocketHandlerRegistry registry) {
registry.addHandler(new MyWebsocketHandler(), "/socket").setAllowedOrigins("*").withSockJS();
}
}
The problem I have is that Websocket requests made to the /socket
endpoint are getting mapped to the BaseController#redirect()
and so the Websocket client does not get a valid connection.
The question I have is, how can I exclude the /socket
route from the mapping rule of the BaseController
? I thought if a route is already mapped it will not get picked up the BaseController
. Or do I have to lower the precedence of the BaseController
in some way?
If anyone knows a method on how to accomplish this I would be very happy.
Thanks in advance :)
java spring spring-boot websocket single-page-application
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I am currently implementing a Spring Boot application with an SPA React front-end. To route every every request which is not exactly mapped to a route I use the following controller to forward the requests to my React application (as seen here: https://stackoverflow.com/a/40769350/4454752 with a little change to also support not mapped requests to URL of the form /a/b/c/...):
@Controller
public class BaseController {
private static final Logger LOGGER = LogManager.getLogger(BaseController.class);
// Match everything without a suffix (so not a static resource)
@RequestMapping(value = "/**/{[path:[^\.]*}")
public String redirect() {
LOGGER.info("Redirect request to React app");
// Forward to home page so that route is preserved.
return "forward:/";
}
}
In addition to that I want to a have a plain Websocket route at /socket
which handles both text and binary Websocket messages. I do not want to use the STOMP
protocol at this endpoint.
I configured my Websockets like so:
@Configuration
@EnableWebSocket
@CrossOrigin(origins = "*")
public class WebSocketConfiguration implements WebSocketConfigurer {
@Override
public void registerWebSocketHandlers(WebSocketHandlerRegistry registry) {
registry.addHandler(new MyWebsocketHandler(), "/socket").setAllowedOrigins("*").withSockJS();
}
}
The problem I have is that Websocket requests made to the /socket
endpoint are getting mapped to the BaseController#redirect()
and so the Websocket client does not get a valid connection.
The question I have is, how can I exclude the /socket
route from the mapping rule of the BaseController
? I thought if a route is already mapped it will not get picked up the BaseController
. Or do I have to lower the precedence of the BaseController
in some way?
If anyone knows a method on how to accomplish this I would be very happy.
Thanks in advance :)
java spring spring-boot websocket single-page-application
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am currently implementing a Spring Boot application with an SPA React front-end. To route every every request which is not exactly mapped to a route I use the following controller to forward the requests to my React application (as seen here: https://stackoverflow.com/a/40769350/4454752 with a little change to also support not mapped requests to URL of the form /a/b/c/...):
@Controller
public class BaseController {
private static final Logger LOGGER = LogManager.getLogger(BaseController.class);
// Match everything without a suffix (so not a static resource)
@RequestMapping(value = "/**/{[path:[^\.]*}")
public String redirect() {
LOGGER.info("Redirect request to React app");
// Forward to home page so that route is preserved.
return "forward:/";
}
}
In addition to that I want to a have a plain Websocket route at /socket
which handles both text and binary Websocket messages. I do not want to use the STOMP
protocol at this endpoint.
I configured my Websockets like so:
@Configuration
@EnableWebSocket
@CrossOrigin(origins = "*")
public class WebSocketConfiguration implements WebSocketConfigurer {
@Override
public void registerWebSocketHandlers(WebSocketHandlerRegistry registry) {
registry.addHandler(new MyWebsocketHandler(), "/socket").setAllowedOrigins("*").withSockJS();
}
}
The problem I have is that Websocket requests made to the /socket
endpoint are getting mapped to the BaseController#redirect()
and so the Websocket client does not get a valid connection.
The question I have is, how can I exclude the /socket
route from the mapping rule of the BaseController
? I thought if a route is already mapped it will not get picked up the BaseController
. Or do I have to lower the precedence of the BaseController
in some way?
If anyone knows a method on how to accomplish this I would be very happy.
Thanks in advance :)
java spring spring-boot websocket single-page-application
I am currently implementing a Spring Boot application with an SPA React front-end. To route every every request which is not exactly mapped to a route I use the following controller to forward the requests to my React application (as seen here: https://stackoverflow.com/a/40769350/4454752 with a little change to also support not mapped requests to URL of the form /a/b/c/...):
@Controller
public class BaseController {
private static final Logger LOGGER = LogManager.getLogger(BaseController.class);
// Match everything without a suffix (so not a static resource)
@RequestMapping(value = "/**/{[path:[^\.]*}")
public String redirect() {
LOGGER.info("Redirect request to React app");
// Forward to home page so that route is preserved.
return "forward:/";
}
}
In addition to that I want to a have a plain Websocket route at /socket
which handles both text and binary Websocket messages. I do not want to use the STOMP
protocol at this endpoint.
I configured my Websockets like so:
@Configuration
@EnableWebSocket
@CrossOrigin(origins = "*")
public class WebSocketConfiguration implements WebSocketConfigurer {
@Override
public void registerWebSocketHandlers(WebSocketHandlerRegistry registry) {
registry.addHandler(new MyWebsocketHandler(), "/socket").setAllowedOrigins("*").withSockJS();
}
}
The problem I have is that Websocket requests made to the /socket
endpoint are getting mapped to the BaseController#redirect()
and so the Websocket client does not get a valid connection.
The question I have is, how can I exclude the /socket
route from the mapping rule of the BaseController
? I thought if a route is already mapped it will not get picked up the BaseController
. Or do I have to lower the precedence of the BaseController
in some way?
If anyone knows a method on how to accomplish this I would be very happy.
Thanks in advance :)
java spring spring-boot websocket single-page-application
java spring spring-boot websocket single-page-application
edited Nov 11 at 19:06
asked Nov 11 at 18:57
grahan
3681515
3681515
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