How to send both image(ndarray) and string data in single ZMQ send request
up vote
1
down vote
favorite
1
For sending string data, following codes works :
context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:5667")
socket.send_string("my string data")
For sending image(ndarray) following code works :
def send_array(socket, img, flags=0, copy=True, track=False):
"""send a numpy array with metadata"""
md = dict(
dtype = str(img.dtype),
shape = img.shape,
)
socket.send_json(md, flags|zmq.SNDMORE)
return socket.send(img, flags, copy=copy, track=track)
context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:5667")
send_array(socket, my_ndarray_image )
But I do need to send both the string message along with the image file. Is there any way to append the message in the same request ?
Any ideas are welcomed !
Thanks
python sockets zeromq pyzmq
edited Nov 10 at 12:21
Benyamin Jafari
2,26031732
asked Oct 29 at 15:46
Rohit
116
add a comment |
up vote
1
down vote
favorite
1
For sending string data, following codes works :
context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:5667")
socket.send_string("my string data")
For sending image(ndarray) following code works :
def send_array(socket, img, flags=0, copy=True, track=False):
"""send a numpy array with metadata"""
md = dict(
dtype = str(img.dtype),
shape = img.shape,
)
socket.send_json(md, flags|zmq.SNDMORE)
return socket.send(img, flags, copy=copy, track=track)
context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:5667")
send_array(socket, my_ndarray_image )
But I do need to send both the string message along with the image file. Is there any way to append the message in the same request ?
Any ideas are welcomed !
Thanks
python sockets zeromq pyzmq
edited Nov 10 at 12:21
Benyamin Jafari
2,26031732
asked Oct 29 at 15:46
Rohit
116
What do you mean of "request"? Why don't you add akey, valto you dictionary for sending your image and your string then parse it inSUBside?
– Benyamin Jafari
Nov 3 at 19:51
@BenyaminJafari By single "request", I meant single message queue request. Whats the need ? ---> As i mentioned, in my application I need to send an image & an associated string message along with it. If I send them in 2 separate requests. Great ! works good for single user instance. But, say there are 2 users who simultaneously run my code. If both requests are done at same time, there's no way to know which Image & String are together. Possible wrong combinations ( IMAGE1 + STRING2 ) instead of correct ( IMAGE1 + STRING1 ). I know, its has gone complicated. Feel free to query back.
– Rohit
Nov 10 at 11:29
@BenyaminJafari Secondly, adding image & string in key, value doesn't works out, I've already tried. It can't be encoded together at the sender end itself. So, no point I can parse it at SUBSCRIBER side
– Rohit
Nov 10 at 11:35
add a comment |
up vote
1
down vote
favorite
1
up vote
1
down vote
favorite
1
1
For sending string data, following codes works :
context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:5667")
socket.send_string("my string data")
For sending image(ndarray) following code works :
def send_array(socket, img, flags=0, copy=True, track=False):
"""send a numpy array with metadata"""
md = dict(
dtype = str(img.dtype),
shape = img.shape,
)
socket.send_json(md, flags|zmq.SNDMORE)
return socket.send(img, flags, copy=copy, track=track)
context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:5667")
send_array(socket, my_ndarray_image )
But I do need to send both the string message along with the image file. Is there any way to append the message in the same request ?
Any ideas are welcomed !
Thanks
python sockets zeromq pyzmq
edited Nov 10 at 12:21
Benyamin Jafari
2,26031732
asked Oct 29 at 15:46
Rohit
116
For sending string data, following codes works :
context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:5667")
socket.send_string("my string data")
For sending image(ndarray) following code works :
def send_array(socket, img, flags=0, copy=True, track=False):
"""send a numpy array with metadata"""
md = dict(
dtype = str(img.dtype),
shape = img.shape,
)
socket.send_json(md, flags|zmq.SNDMORE)
return socket.send(img, flags, copy=copy, track=track)
context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:5667")
send_array(socket, my_ndarray_image )
But I do need to send both the string message along with the image file. Is there any way to append the message in the same request ?
Any ideas are welcomed !
Thanks
python sockets zeromq pyzmq
python sockets zeromq pyzmq
edited Nov 10 at 12:21
Benyamin Jafari
2,26031732
asked Oct 29 at 15:46
Rohit
116
edited Nov 10 at 12:21
Benyamin Jafari
2,26031732
asked Oct 29 at 15:46
Rohit
116
edited Nov 10 at 12:21
Benyamin Jafari
2,26031732
edited Nov 10 at 12:21
Benyamin Jafari
2,26031732
edited Nov 10 at 12:21
Benyamin Jafari
2,26031732
2,26031732
asked Oct 29 at 15:46
Rohit
116
asked Oct 29 at 15:46
Rohit
116
asked Oct 29 at 15:46
Rohit
116
116
What do you mean of "request"? Why don't you add akey, valto you dictionary for sending your image and your string then parse it inSUBside?
– Benyamin Jafari
Nov 3 at 19:51
@BenyaminJafari By single "request", I meant single message queue request. Whats the need ? ---> As i mentioned, in my application I need to send an image & an associated string message along with it. If I send them in 2 separate requests. Great ! works good for single user instance. But, say there are 2 users who simultaneously run my code. If both requests are done at same time, there's no way to know which Image & String are together. Possible wrong combinations ( IMAGE1 + STRING2 ) instead of correct ( IMAGE1 + STRING1 ). I know, its has gone complicated. Feel free to query back.
– Rohit
Nov 10 at 11:29
@BenyaminJafari Secondly, adding image & string in key, value doesn't works out, I've already tried. It can't be encoded together at the sender end itself. So, no point I can parse it at SUBSCRIBER side
– Rohit
Nov 10 at 11:35
add a comment |
What do you mean of "request"? Why don't you add akey, valto you dictionary for sending your image and your string then parse it inSUBside?
– Benyamin Jafari
Nov 3 at 19:51
@BenyaminJafari By single "request", I meant single message queue request. Whats the need ? ---> As i mentioned, in my application I need to send an image & an associated string message along with it. If I send them in 2 separate requests. Great ! works good for single user instance. But, say there are 2 users who simultaneously run my code. If both requests are done at same time, there's no way to know which Image & String are together. Possible wrong combinations ( IMAGE1 + STRING2 ) instead of correct ( IMAGE1 + STRING1 ). I know, its has gone complicated. Feel free to query back.
– Rohit
Nov 10 at 11:29
@BenyaminJafari Secondly, adding image & string in key, value doesn't works out, I've already tried. It can't be encoded together at the sender end itself. So, no point I can parse it at SUBSCRIBER side
– Rohit
Nov 10 at 11:35
What do you mean of "request"? Why don't you add a
key, val to you dictionary for sending your image and your string then parse it in SUB side?– Benyamin Jafari
Nov 3 at 19:51
What do you mean of "request"? Why don't you add a
key, val to you dictionary for sending your image and your string then parse it in SUB side?– Benyamin Jafari
Nov 3 at 19:51
@BenyaminJafari By single "request", I meant single message queue request. Whats the need ? ---> As i mentioned, in my application I need to send an image & an associated string message along with it. If I send them in 2 separate requests. Great ! works good for single user instance. But, say there are 2 users who simultaneously run my code. If both requests are done at same time, there's no way to know which Image & String are together. Possible wrong combinations ( IMAGE1 + STRING2 ) instead of correct ( IMAGE1 + STRING1 ). I know, its has gone complicated. Feel free to query back.
– Rohit
Nov 10 at 11:29
@BenyaminJafari By single "request", I meant single message queue request. Whats the need ? ---> As i mentioned, in my application I need to send an image & an associated string message along with it. If I send them in 2 separate requests. Great ! works good for single user instance. But, say there are 2 users who simultaneously run my code. If both requests are done at same time, there's no way to know which Image & String are together. Possible wrong combinations ( IMAGE1 + STRING2 ) instead of correct ( IMAGE1 + STRING1 ). I know, its has gone complicated. Feel free to query back.
– Rohit
Nov 10 at 11:29
@BenyaminJafari Secondly, adding image & string in key, value doesn't works out, I've already tried. It can't be encoded together at the sender end itself. So, no point I can parse it at SUBSCRIBER side
– Rohit
Nov 10 at 11:35
@BenyaminJafari Secondly, adding image & string in key, value doesn't works out, I've already tried. It can't be encoded together at the sender end itself. So, no point I can parse it at SUBSCRIBER side
– Rohit
Nov 10 at 11:35
add a comment |
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What do you mean of "request"? Why don't you add a
key, valto you dictionary for sending your image and your string then parse it inSUBside?– Benyamin Jafari
Nov 3 at 19:51
@BenyaminJafari By single "request", I meant single message queue request. Whats the need ? ---> As i mentioned, in my application I need to send an image & an associated string message along with it. If I send them in 2 separate requests. Great ! works good for single user instance. But, say there are 2 users who simultaneously run my code. If both requests are done at same time, there's no way to know which Image & String are together. Possible wrong combinations ( IMAGE1 + STRING2 ) instead of correct ( IMAGE1 + STRING1 ). I know, its has gone complicated. Feel free to query back.
– Rohit
Nov 10 at 11:29
@BenyaminJafari Secondly, adding image & string in key, value doesn't works out, I've already tried. It can't be encoded together at the sender end itself. So, no point I can parse it at SUBSCRIBER side
– Rohit
Nov 10 at 11:35