System verilog process::state
Playing with systemverilog, I'm trying to get the status of some processes that are forked.
In order to do that I create a variable where I can get state of a process.
From part 9.7 of 1800-2012 SV-LRM
process::state pstat;
But I get the following error with irun :
xmvlog: *E,EXPIDN expecting an identifier [3.2][3.8][3.9(IEEE)].
verilog system-verilog
asked Nov 16 '18 at 8:03
ViktorinoxViktorinox
847
add a comment |
Playing with systemverilog, I'm trying to get the status of some processes that are forked.
In order to do that I create a variable where I can get state of a process.
From part 9.7 of 1800-2012 SV-LRM
process::state pstat;
But I get the following error with irun :
xmvlog: *E,EXPIDN expecting an identifier [3.2][3.8][3.9(IEEE)].
verilog system-verilog
asked Nov 16 '18 at 8:03
ViktorinoxViktorinox
847
add a comment |
Playing with systemverilog, I'm trying to get the status of some processes that are forked.
In order to do that I create a variable where I can get state of a process.
From part 9.7 of 1800-2012 SV-LRM
process::state pstat;
But I get the following error with irun :
xmvlog: *E,EXPIDN expecting an identifier [3.2][3.8][3.9(IEEE)].
verilog system-verilog
asked Nov 16 '18 at 8:03
ViktorinoxViktorinox
847
Playing with systemverilog, I'm trying to get the status of some processes that are forked.
In order to do that I create a variable where I can get state of a process.
From part 9.7 of 1800-2012 SV-LRM
process::state pstat;
But I get the following error with irun :
xmvlog: *E,EXPIDN expecting an identifier [3.2][3.8][3.9(IEEE)].
verilog system-verilog
verilog system-verilog
asked Nov 16 '18 at 8:03
ViktorinoxViktorinox
847
asked Nov 16 '18 at 8:03
ViktorinoxViktorinox
847
asked Nov 16 '18 at 8:03
ViktorinoxViktorinox
847
asked Nov 16 '18 at 8:03
ViktorinoxViktorinox
847
asked Nov 16 '18 at 8:03
ViktorinoxViktorinox
847
847
add a comment |
add a comment |
2 Answers
2
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oldest
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state is a method of the class process. You can't create a variable of type process::state - that makes no sense. There is an example in section 9.7 of IEEE 1800-2012, which shows how to use the process class.
answered Nov 16 '18 at 10:01
Matthew TaylorMatthew Taylor
7,8762832
add a comment |
state is a type embedded in a class. The BNF does allow you to use it directly, but some tools allow it. You should be able to do:
typedef process::state state_e;
state_e pstat;
// or
type(process::state) pstat;
answered Nov 16 '18 at 16:27
dave_59dave_59
20.8k21639
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
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active
oldest
votes
state is a method of the class process. You can't create a variable of type process::state - that makes no sense. There is an example in section 9.7 of IEEE 1800-2012, which shows how to use the process class.
answered Nov 16 '18 at 10:01
Matthew TaylorMatthew Taylor
7,8762832
add a comment |
state is a method of the class process. You can't create a variable of type process::state - that makes no sense. There is an example in section 9.7 of IEEE 1800-2012, which shows how to use the process class.
answered Nov 16 '18 at 10:01
Matthew TaylorMatthew Taylor
7,8762832
add a comment |
state is a method of the class process. You can't create a variable of type process::state - that makes no sense. There is an example in section 9.7 of IEEE 1800-2012, which shows how to use the process class.
answered Nov 16 '18 at 10:01
Matthew TaylorMatthew Taylor
7,8762832
state is a method of the class process. You can't create a variable of type process::state - that makes no sense. There is an example in section 9.7 of IEEE 1800-2012, which shows how to use the process class.
answered Nov 16 '18 at 10:01
Matthew TaylorMatthew Taylor
7,8762832
answered Nov 16 '18 at 10:01
Matthew TaylorMatthew Taylor
7,8762832
answered Nov 16 '18 at 10:01
Matthew TaylorMatthew Taylor
7,8762832
answered Nov 16 '18 at 10:01
Matthew TaylorMatthew Taylor
7,8762832
7,8762832
add a comment |
add a comment |
state is a type embedded in a class. The BNF does allow you to use it directly, but some tools allow it. You should be able to do:
typedef process::state state_e;
state_e pstat;
// or
type(process::state) pstat;
answered Nov 16 '18 at 16:27
dave_59dave_59
20.8k21639
add a comment |
state is a type embedded in a class. The BNF does allow you to use it directly, but some tools allow it. You should be able to do:
typedef process::state state_e;
state_e pstat;
// or
type(process::state) pstat;
answered Nov 16 '18 at 16:27
dave_59dave_59
20.8k21639
add a comment |
state is a type embedded in a class. The BNF does allow you to use it directly, but some tools allow it. You should be able to do:
typedef process::state state_e;
state_e pstat;
// or
type(process::state) pstat;
answered Nov 16 '18 at 16:27
dave_59dave_59
20.8k21639
state is a type embedded in a class. The BNF does allow you to use it directly, but some tools allow it. You should be able to do:
typedef process::state state_e;
state_e pstat;
// or
type(process::state) pstat;
answered Nov 16 '18 at 16:27
dave_59dave_59
20.8k21639
answered Nov 16 '18 at 16:27
dave_59dave_59
20.8k21639
answered Nov 16 '18 at 16:27
dave_59dave_59
20.8k21639
answered Nov 16 '18 at 16:27
dave_59dave_59
20.8k21639
20.8k21639
add a comment |
add a comment |
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