Subprocess STDOUT is not Live
After looking through pretty much all relevant articles and trying everything, I can't make this work, so many thanks in advance for taking a look.
I wrote the following code to activate second script from the first script:
proc = subprocess.Popen(['python', path_calculator +
'calculator.py'], stdout=subprocess.PIPE)
for line in proc.stdout:
sys.stdout.buffer.write(line)
sys.stdout.buffer.flush()
line = str(line)
line = line[2:]
line = line[:-3]
The point of this code is to get the live output of the 'calculator' in the first script, because other scripts are depending on that output.
The code does provide the correct output, but only when the 'calculator' finishes. It then outputs all data in one go. That's not sufficient. I need the output the moment it comes out of the 'calculator'.
Funny thing is that it actually works on my mac, but I can't get it to work on Windows.
** A few hours later now, I found out that it's not my Mac that it works on, but it's Pycharm (which I use on my mac) that it works on. If I run it in the terminal on my mac it doesn't work either.
Any suggestions?
python-3.x subprocess stdout
asked Nov 15 '18 at 16:29
KoenKoen
11
add a comment |
After looking through pretty much all relevant articles and trying everything, I can't make this work, so many thanks in advance for taking a look.
I wrote the following code to activate second script from the first script:
proc = subprocess.Popen(['python', path_calculator +
'calculator.py'], stdout=subprocess.PIPE)
for line in proc.stdout:
sys.stdout.buffer.write(line)
sys.stdout.buffer.flush()
line = str(line)
line = line[2:]
line = line[:-3]
The point of this code is to get the live output of the 'calculator' in the first script, because other scripts are depending on that output.
The code does provide the correct output, but only when the 'calculator' finishes. It then outputs all data in one go. That's not sufficient. I need the output the moment it comes out of the 'calculator'.
Funny thing is that it actually works on my mac, but I can't get it to work on Windows.
** A few hours later now, I found out that it's not my Mac that it works on, but it's Pycharm (which I use on my mac) that it works on. If I run it in the terminal on my mac it doesn't work either.
Any suggestions?
python-3.x subprocess stdout
asked Nov 15 '18 at 16:29
KoenKoen
11
Because u said it worked on mac but not Windows, I think you should changepath_calculator + 'calculator.py'intoos.path.join(path_calculator, 'calculator.py')
– Canh
Nov 15 '18 at 16:38
Thanks for replying. After a day of programming, I was not so clear in explaining the problem. I edited the explanation. Hope that clears up!
– Koen
Nov 15 '18 at 17:26
Possible duplicate of Constantly print Subprocess output while process is running
– Matt Messersmith
Nov 15 '18 at 21:43
add a comment |
After looking through pretty much all relevant articles and trying everything, I can't make this work, so many thanks in advance for taking a look.
I wrote the following code to activate second script from the first script:
proc = subprocess.Popen(['python', path_calculator +
'calculator.py'], stdout=subprocess.PIPE)
for line in proc.stdout:
sys.stdout.buffer.write(line)
sys.stdout.buffer.flush()
line = str(line)
line = line[2:]
line = line[:-3]
The point of this code is to get the live output of the 'calculator' in the first script, because other scripts are depending on that output.
The code does provide the correct output, but only when the 'calculator' finishes. It then outputs all data in one go. That's not sufficient. I need the output the moment it comes out of the 'calculator'.
Funny thing is that it actually works on my mac, but I can't get it to work on Windows.
** A few hours later now, I found out that it's not my Mac that it works on, but it's Pycharm (which I use on my mac) that it works on. If I run it in the terminal on my mac it doesn't work either.
Any suggestions?
python-3.x subprocess stdout
asked Nov 15 '18 at 16:29
KoenKoen
11
After looking through pretty much all relevant articles and trying everything, I can't make this work, so many thanks in advance for taking a look.
I wrote the following code to activate second script from the first script:
proc = subprocess.Popen(['python', path_calculator +
'calculator.py'], stdout=subprocess.PIPE)
for line in proc.stdout:
sys.stdout.buffer.write(line)
sys.stdout.buffer.flush()
line = str(line)
line = line[2:]
line = line[:-3]
The point of this code is to get the live output of the 'calculator' in the first script, because other scripts are depending on that output.
The code does provide the correct output, but only when the 'calculator' finishes. It then outputs all data in one go. That's not sufficient. I need the output the moment it comes out of the 'calculator'.
Funny thing is that it actually works on my mac, but I can't get it to work on Windows.
** A few hours later now, I found out that it's not my Mac that it works on, but it's Pycharm (which I use on my mac) that it works on. If I run it in the terminal on my mac it doesn't work either.
Any suggestions?
python-3.x subprocess stdout
python-3.x subprocess stdout
asked Nov 15 '18 at 16:29
KoenKoen
11
asked Nov 15 '18 at 16:29
KoenKoen
11
edited Nov 15 '18 at 21:35
Koen
asked Nov 15 '18 at 16:29
KoenKoen
11
asked Nov 15 '18 at 16:29
KoenKoen
11
asked Nov 15 '18 at 16:29
KoenKoen
11
11
Because u said it worked on mac but not Windows, I think you should changepath_calculator + 'calculator.py'intoos.path.join(path_calculator, 'calculator.py')
– Canh
Nov 15 '18 at 16:38
Thanks for replying. After a day of programming, I was not so clear in explaining the problem. I edited the explanation. Hope that clears up!
– Koen
Nov 15 '18 at 17:26
Possible duplicate of Constantly print Subprocess output while process is running
– Matt Messersmith
Nov 15 '18 at 21:43
add a comment |
Because u said it worked on mac but not Windows, I think you should changepath_calculator + 'calculator.py'intoos.path.join(path_calculator, 'calculator.py')
– Canh
Nov 15 '18 at 16:38
Thanks for replying. After a day of programming, I was not so clear in explaining the problem. I edited the explanation. Hope that clears up!
– Koen
Nov 15 '18 at 17:26
Possible duplicate of Constantly print Subprocess output while process is running
– Matt Messersmith
Nov 15 '18 at 21:43
Because u said it worked on mac but not Windows, I think you should change
path_calculator + 'calculator.py' into os.path.join(path_calculator, 'calculator.py')– Canh
Nov 15 '18 at 16:38
Because u said it worked on mac but not Windows, I think you should change
path_calculator + 'calculator.py' into os.path.join(path_calculator, 'calculator.py')– Canh
Nov 15 '18 at 16:38
Thanks for replying. After a day of programming, I was not so clear in explaining the problem. I edited the explanation. Hope that clears up!
– Koen
Nov 15 '18 at 17:26
Thanks for replying. After a day of programming, I was not so clear in explaining the problem. I edited the explanation. Hope that clears up!
– Koen
Nov 15 '18 at 17:26
Possible duplicate of Constantly print Subprocess output while process is running
– Matt Messersmith
Nov 15 '18 at 21:43
Possible duplicate of Constantly print Subprocess output while process is running
– Matt Messersmith
Nov 15 '18 at 21:43
add a comment |
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Because u said it worked on mac but not Windows, I think you should change
path_calculator + 'calculator.py'intoos.path.join(path_calculator, 'calculator.py')– Canh
Nov 15 '18 at 16:38
Thanks for replying. After a day of programming, I was not so clear in explaining the problem. I edited the explanation. Hope that clears up!
– Koen
Nov 15 '18 at 17:26
Possible duplicate of Constantly print Subprocess output while process is running
– Matt Messersmith
Nov 15 '18 at 21:43