Pytorch 0.4.0: There are three ways to create tensors on CUDA device. Is there some difference between them?












3















I failed in the third way. t3 is still on CPU. No idea why.



a = np.random.randn(1, 1, 2, 3)

t1 = torch.tensor(a)
t1 = t3.to(torch.device('cuda'))

t2 = torch.tensor(a)
t2 = t2.cuda()

t3 = torch.tensor(a, device=torch.device('cuda'))









share|improve this question





























    3















    I failed in the third way. t3 is still on CPU. No idea why.



    a = np.random.randn(1, 1, 2, 3)

    t1 = torch.tensor(a)
    t1 = t3.to(torch.device('cuda'))

    t2 = torch.tensor(a)
    t2 = t2.cuda()

    t3 = torch.tensor(a, device=torch.device('cuda'))









    share|improve this question



























      3












      3








      3








      I failed in the third way. t3 is still on CPU. No idea why.



      a = np.random.randn(1, 1, 2, 3)

      t1 = torch.tensor(a)
      t1 = t3.to(torch.device('cuda'))

      t2 = torch.tensor(a)
      t2 = t2.cuda()

      t3 = torch.tensor(a, device=torch.device('cuda'))









      share|improve this question
















      I failed in the third way. t3 is still on CPU. No idea why.



      a = np.random.randn(1, 1, 2, 3)

      t1 = torch.tensor(a)
      t1 = t3.to(torch.device('cuda'))

      t2 = torch.tensor(a)
      t2 = t2.cuda()

      t3 = torch.tensor(a, device=torch.device('cuda'))






      pytorch tensor






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 16 '18 at 6:37









      Umang Gupta

      3,71211840




      3,71211840










      asked Nov 16 '18 at 4:01









      laridzhanglaridzhang

      706




      706
























          1 Answer
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          6














          All three methods worked for me.



          In 1 and 2, you create a tensor on CPU and then move it to GPU when you use .to(device) or .cuda(). They are same here.



          However, when you use .to(device) method you can explicitly tell torch to move to specific GPU by setting device=torch.device("cuda:<id>"). with .cuda() you have to do .cuda(<id>) to move to some particular GPU.





          Why do these two methods exist then?



          .to(device) was introduced in 0.4 because it is easier to declare device variable at top of the code as



          device = torch.device("cuda") if torch.cuda.is_available() else torch.device("cpu")



          and use .to(device) everywhere. This makes it quite easy to switch from CPU to GPU and vice-versa



          Before this, we had to use .cuda() and your code will have if check for cuda.is_available() everywhere which made it cumbersome to switch between GPU/CPU.





          The third method doesn't create a tensor on CPU and directly copies data to GPU, which is more efficient.






          share|improve this answer


























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            6














            All three methods worked for me.



            In 1 and 2, you create a tensor on CPU and then move it to GPU when you use .to(device) or .cuda(). They are same here.



            However, when you use .to(device) method you can explicitly tell torch to move to specific GPU by setting device=torch.device("cuda:<id>"). with .cuda() you have to do .cuda(<id>) to move to some particular GPU.





            Why do these two methods exist then?



            .to(device) was introduced in 0.4 because it is easier to declare device variable at top of the code as



            device = torch.device("cuda") if torch.cuda.is_available() else torch.device("cpu")



            and use .to(device) everywhere. This makes it quite easy to switch from CPU to GPU and vice-versa



            Before this, we had to use .cuda() and your code will have if check for cuda.is_available() everywhere which made it cumbersome to switch between GPU/CPU.





            The third method doesn't create a tensor on CPU and directly copies data to GPU, which is more efficient.






            share|improve this answer






























              6














              All three methods worked for me.



              In 1 and 2, you create a tensor on CPU and then move it to GPU when you use .to(device) or .cuda(). They are same here.



              However, when you use .to(device) method you can explicitly tell torch to move to specific GPU by setting device=torch.device("cuda:<id>"). with .cuda() you have to do .cuda(<id>) to move to some particular GPU.





              Why do these two methods exist then?



              .to(device) was introduced in 0.4 because it is easier to declare device variable at top of the code as



              device = torch.device("cuda") if torch.cuda.is_available() else torch.device("cpu")



              and use .to(device) everywhere. This makes it quite easy to switch from CPU to GPU and vice-versa



              Before this, we had to use .cuda() and your code will have if check for cuda.is_available() everywhere which made it cumbersome to switch between GPU/CPU.





              The third method doesn't create a tensor on CPU and directly copies data to GPU, which is more efficient.






              share|improve this answer




























                6












                6








                6







                All three methods worked for me.



                In 1 and 2, you create a tensor on CPU and then move it to GPU when you use .to(device) or .cuda(). They are same here.



                However, when you use .to(device) method you can explicitly tell torch to move to specific GPU by setting device=torch.device("cuda:<id>"). with .cuda() you have to do .cuda(<id>) to move to some particular GPU.





                Why do these two methods exist then?



                .to(device) was introduced in 0.4 because it is easier to declare device variable at top of the code as



                device = torch.device("cuda") if torch.cuda.is_available() else torch.device("cpu")



                and use .to(device) everywhere. This makes it quite easy to switch from CPU to GPU and vice-versa



                Before this, we had to use .cuda() and your code will have if check for cuda.is_available() everywhere which made it cumbersome to switch between GPU/CPU.





                The third method doesn't create a tensor on CPU and directly copies data to GPU, which is more efficient.






                share|improve this answer















                All three methods worked for me.



                In 1 and 2, you create a tensor on CPU and then move it to GPU when you use .to(device) or .cuda(). They are same here.



                However, when you use .to(device) method you can explicitly tell torch to move to specific GPU by setting device=torch.device("cuda:<id>"). with .cuda() you have to do .cuda(<id>) to move to some particular GPU.





                Why do these two methods exist then?



                .to(device) was introduced in 0.4 because it is easier to declare device variable at top of the code as



                device = torch.device("cuda") if torch.cuda.is_available() else torch.device("cpu")



                and use .to(device) everywhere. This makes it quite easy to switch from CPU to GPU and vice-versa



                Before this, we had to use .cuda() and your code will have if check for cuda.is_available() everywhere which made it cumbersome to switch between GPU/CPU.





                The third method doesn't create a tensor on CPU and directly copies data to GPU, which is more efficient.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 16 '18 at 6:45

























                answered Nov 16 '18 at 6:37









                Umang GuptaUmang Gupta

                3,71211840




                3,71211840
































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