Not able to append elements in python list
I am writing a program, to find the character that occurs maximum number of odd times, in a given string using python. However i am not able to append characters to a list, if two or more characters occur maximum number of odd times.
input used : AAAbbccc
Error i am getting :
Traceback (most recent call last):
File "./prog.py", line 18, in
AttributeError: 'str' object has no attribute 'append'
inputString = input()
dict = {}
for i in inputString:
if i in dict:
dict[i] += 1
else:
dict[i] = 1
print(dict)
max = -1
lst =
for i in dict:
if(dict[i]%2!=0 and max<=dict[i]):
if(max == dict[i]):
lst.append(i)
else:
max = dict[i]
lst = i
print(lst)
python string python-3.x list counter
edited Nov 14 '18 at 12:39
ctrl-alt-delor
4,24632444
asked Nov 14 '18 at 11:52
AnandAnand
226
add a comment |
I am writing a program, to find the character that occurs maximum number of odd times, in a given string using python. However i am not able to append characters to a list, if two or more characters occur maximum number of odd times.
input used : AAAbbccc
Error i am getting :
Traceback (most recent call last):
File "./prog.py", line 18, in
AttributeError: 'str' object has no attribute 'append'
inputString = input()
dict = {}
for i in inputString:
if i in dict:
dict[i] += 1
else:
dict[i] = 1
print(dict)
max = -1
lst =
for i in dict:
if(dict[i]%2!=0 and max<=dict[i]):
if(max == dict[i]):
lst.append(i)
else:
max = dict[i]
lst = i
print(lst)
python string python-3.x list counter
edited Nov 14 '18 at 12:39
ctrl-alt-delor
4,24632444
asked Nov 14 '18 at 11:52
AnandAnand
226
2
In line 21 you have an assignment 'lst' to 'i' which is not an array, then when when line 18 occurs lst is not an array anymore so it doesn't have an append method
– szogoon
Nov 14 '18 at 11:57
Thanks but that's not the issue that's working completely fine i'm getting error for line " lst.append(i) " where i am trying to append character into the list but i'm getting the above mentioned error
– Anand
Nov 14 '18 at 12:01
add a comment |
I am writing a program, to find the character that occurs maximum number of odd times, in a given string using python. However i am not able to append characters to a list, if two or more characters occur maximum number of odd times.
input used : AAAbbccc
Error i am getting :
Traceback (most recent call last):
File "./prog.py", line 18, in
AttributeError: 'str' object has no attribute 'append'
inputString = input()
dict = {}
for i in inputString:
if i in dict:
dict[i] += 1
else:
dict[i] = 1
print(dict)
max = -1
lst =
for i in dict:
if(dict[i]%2!=0 and max<=dict[i]):
if(max == dict[i]):
lst.append(i)
else:
max = dict[i]
lst = i
print(lst)
python string python-3.x list counter
edited Nov 14 '18 at 12:39
ctrl-alt-delor
4,24632444
asked Nov 14 '18 at 11:52
AnandAnand
226
I am writing a program, to find the character that occurs maximum number of odd times, in a given string using python. However i am not able to append characters to a list, if two or more characters occur maximum number of odd times.
input used : AAAbbccc
Error i am getting :
Traceback (most recent call last):
File "./prog.py", line 18, in
AttributeError: 'str' object has no attribute 'append'
inputString = input()
dict = {}
for i in inputString:
if i in dict:
dict[i] += 1
else:
dict[i] = 1
print(dict)
max = -1
lst =
for i in dict:
if(dict[i]%2!=0 and max<=dict[i]):
if(max == dict[i]):
lst.append(i)
else:
max = dict[i]
lst = i
print(lst)
python string python-3.x list counter
python string python-3.x list counter
edited Nov 14 '18 at 12:39
ctrl-alt-delor
4,24632444
asked Nov 14 '18 at 11:52
AnandAnand
226
edited Nov 14 '18 at 12:39
ctrl-alt-delor
4,24632444
asked Nov 14 '18 at 11:52
AnandAnand
226
edited Nov 14 '18 at 12:39
ctrl-alt-delor
4,24632444
edited Nov 14 '18 at 12:39
ctrl-alt-delor
4,24632444
edited Nov 14 '18 at 12:39
ctrl-alt-delor
4,24632444
4,24632444
asked Nov 14 '18 at 11:52
AnandAnand
226
asked Nov 14 '18 at 11:52
AnandAnand
226
asked Nov 14 '18 at 11:52
AnandAnand
226
226
2
In line 21 you have an assignment 'lst' to 'i' which is not an array, then when when line 18 occurs lst is not an array anymore so it doesn't have an append method
– szogoon
Nov 14 '18 at 11:57
Thanks but that's not the issue that's working completely fine i'm getting error for line " lst.append(i) " where i am trying to append character into the list but i'm getting the above mentioned error
– Anand
Nov 14 '18 at 12:01
add a comment |
2
In line 21 you have an assignment 'lst' to 'i' which is not an array, then when when line 18 occurs lst is not an array anymore so it doesn't have an append method
– szogoon
Nov 14 '18 at 11:57
Thanks but that's not the issue that's working completely fine i'm getting error for line " lst.append(i) " where i am trying to append character into the list but i'm getting the above mentioned error
– Anand
Nov 14 '18 at 12:01
2
2
In line 21 you have an assignment 'lst' to 'i' which is not an array, then when when line 18 occurs lst is not an array anymore so it doesn't have an append method
– szogoon
Nov 14 '18 at 11:57
In line 21 you have an assignment 'lst' to 'i' which is not an array, then when when line 18 occurs lst is not an array anymore so it doesn't have an append method
– szogoon
Nov 14 '18 at 11:57
Thanks but that's not the issue that's working completely fine i'm getting error for line " lst.append(i) " where i am trying to append character into the list but i'm getting the above mentioned error
– Anand
Nov 14 '18 at 12:01
Thanks but that's not the issue that's working completely fine i'm getting error for line " lst.append(i) " where i am trying to append character into the list but i'm getting the above mentioned error
– Anand
Nov 14 '18 at 12:01
add a comment |
1 Answer
1
active
oldest
votes
There are some issues with your code:
- Don't name variables after built-ins (even as an example). Use
dordict_instead ofdict. Dittomax. - Your
max(fixed at-1) will always be<= dict[i], since counts are always>= 1. - You define
lstas a list, then assign a string to it.
Much simpler, use collections.Counter, calculate the maximum value, then use max with a custom function:
from collections import Counter
inputString = input()
c = Counter(inputString)
print(c)
maxval = max(c.values())
def max_logic(x):
cond1 = x[1] % 2
cond2 = x[1] - maxval
return cond1, cond2
key, val = max(c.items(), key=max_logic)
Example run:
print(key, val)
thisisateststring
Counter({'t': 4, 's': 4, 'i': 3, 'h': 1, 'a': 1, 'e': 1, 'r': 1, 'n': 1, 'g': 1})
i 3
The solution assumes a valid odd count does exist in your string. If it doesn't and you need to apply special treatment, you'll need to add additional logic. I leave that as an exercise.
answered Nov 14 '18 at 12:11
jppjpp
100k2162111
1
Thanks a lot...
– Anand
Nov 14 '18 at 12:16
add a comment |
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1 Answer
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oldest
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1 Answer
1
active
oldest
votes
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oldest
votes
active
oldest
votes
There are some issues with your code:
- Don't name variables after built-ins (even as an example). Use
dordict_instead ofdict. Dittomax. - Your
max(fixed at-1) will always be<= dict[i], since counts are always>= 1. - You define
lstas a list, then assign a string to it.
Much simpler, use collections.Counter, calculate the maximum value, then use max with a custom function:
from collections import Counter
inputString = input()
c = Counter(inputString)
print(c)
maxval = max(c.values())
def max_logic(x):
cond1 = x[1] % 2
cond2 = x[1] - maxval
return cond1, cond2
key, val = max(c.items(), key=max_logic)
Example run:
print(key, val)
thisisateststring
Counter({'t': 4, 's': 4, 'i': 3, 'h': 1, 'a': 1, 'e': 1, 'r': 1, 'n': 1, 'g': 1})
i 3
The solution assumes a valid odd count does exist in your string. If it doesn't and you need to apply special treatment, you'll need to add additional logic. I leave that as an exercise.
answered Nov 14 '18 at 12:11
jppjpp
100k2162111
1
Thanks a lot...
– Anand
Nov 14 '18 at 12:16
add a comment |
There are some issues with your code:
- Don't name variables after built-ins (even as an example). Use
dordict_instead ofdict. Dittomax. - Your
max(fixed at-1) will always be<= dict[i], since counts are always>= 1. - You define
lstas a list, then assign a string to it.
Much simpler, use collections.Counter, calculate the maximum value, then use max with a custom function:
from collections import Counter
inputString = input()
c = Counter(inputString)
print(c)
maxval = max(c.values())
def max_logic(x):
cond1 = x[1] % 2
cond2 = x[1] - maxval
return cond1, cond2
key, val = max(c.items(), key=max_logic)
Example run:
print(key, val)
thisisateststring
Counter({'t': 4, 's': 4, 'i': 3, 'h': 1, 'a': 1, 'e': 1, 'r': 1, 'n': 1, 'g': 1})
i 3
The solution assumes a valid odd count does exist in your string. If it doesn't and you need to apply special treatment, you'll need to add additional logic. I leave that as an exercise.
answered Nov 14 '18 at 12:11
jppjpp
100k2162111
1
Thanks a lot...
– Anand
Nov 14 '18 at 12:16
add a comment |
There are some issues with your code:
- Don't name variables after built-ins (even as an example). Use
dordict_instead ofdict. Dittomax. - Your
max(fixed at-1) will always be<= dict[i], since counts are always>= 1. - You define
lstas a list, then assign a string to it.
Much simpler, use collections.Counter, calculate the maximum value, then use max with a custom function:
from collections import Counter
inputString = input()
c = Counter(inputString)
print(c)
maxval = max(c.values())
def max_logic(x):
cond1 = x[1] % 2
cond2 = x[1] - maxval
return cond1, cond2
key, val = max(c.items(), key=max_logic)
Example run:
print(key, val)
thisisateststring
Counter({'t': 4, 's': 4, 'i': 3, 'h': 1, 'a': 1, 'e': 1, 'r': 1, 'n': 1, 'g': 1})
i 3
The solution assumes a valid odd count does exist in your string. If it doesn't and you need to apply special treatment, you'll need to add additional logic. I leave that as an exercise.
answered Nov 14 '18 at 12:11
jppjpp
100k2162111
There are some issues with your code:
- Don't name variables after built-ins (even as an example). Use
dordict_instead ofdict. Dittomax. - Your
max(fixed at-1) will always be<= dict[i], since counts are always>= 1. - You define
lstas a list, then assign a string to it.
Much simpler, use collections.Counter, calculate the maximum value, then use max with a custom function:
from collections import Counter
inputString = input()
c = Counter(inputString)
print(c)
maxval = max(c.values())
def max_logic(x):
cond1 = x[1] % 2
cond2 = x[1] - maxval
return cond1, cond2
key, val = max(c.items(), key=max_logic)
Example run:
print(key, val)
thisisateststring
Counter({'t': 4, 's': 4, 'i': 3, 'h': 1, 'a': 1, 'e': 1, 'r': 1, 'n': 1, 'g': 1})
i 3
The solution assumes a valid odd count does exist in your string. If it doesn't and you need to apply special treatment, you'll need to add additional logic. I leave that as an exercise.
answered Nov 14 '18 at 12:11
jppjpp
100k2162111
edited Nov 14 '18 at 12:17
answered Nov 14 '18 at 12:11
jppjpp
100k2162111
answered Nov 14 '18 at 12:11
jppjpp
100k2162111
answered Nov 14 '18 at 12:11
jppjpp
100k2162111
100k2162111
1
Thanks a lot...
– Anand
Nov 14 '18 at 12:16
add a comment |
1
Thanks a lot...
– Anand
Nov 14 '18 at 12:16
1
1
Thanks a lot...
– Anand
Nov 14 '18 at 12:16
Thanks a lot...
– Anand
Nov 14 '18 at 12:16
add a comment |
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2
In line 21 you have an assignment 'lst' to 'i' which is not an array, then when when line 18 occurs lst is not an array anymore so it doesn't have an append method
– szogoon
Nov 14 '18 at 11:57
Thanks but that's not the issue that's working completely fine i'm getting error for line " lst.append(i) " where i am trying to append character into the list but i'm getting the above mentioned error
– Anand
Nov 14 '18 at 12:01