Merging two arrays into a single array, to be plugged into a function
I have a way I would like to approach my problem, however am struggling with the syntax of the problem.
I have a function, lets call it f(a,b).
I also have an np.array of complex numbers for a and b.
Eg, a = [1+j, 2+j.....], and b = [3+2j, 4+4j....].
What I would like to do is combine these two arrays into an array called c, of the form c = [(1+j,3+2j),(2+j,4+4j)….], where the ith value of c = [(ai,bi)].
I feel I should then plug these ith values of c into my function f(a,b) in a loop (hopefully python can convert ith components of array into two arguments), which would then produce an array of the ith values of f.
I feel this method should work, however the main issue I'm having is syntactical. Does anyone know of any inbuilt functions which could merge two arrays in such a way?
First post on this so any replies would be appreciated! Thanks
python arrays list loops numpy
edited Nov 12 '18 at 17:56
Woody1193
2,246930
asked Nov 12 '18 at 15:57
Pox 219
1
add a comment |
I have a way I would like to approach my problem, however am struggling with the syntax of the problem.
I have a function, lets call it f(a,b).
I also have an np.array of complex numbers for a and b.
Eg, a = [1+j, 2+j.....], and b = [3+2j, 4+4j....].
What I would like to do is combine these two arrays into an array called c, of the form c = [(1+j,3+2j),(2+j,4+4j)….], where the ith value of c = [(ai,bi)].
I feel I should then plug these ith values of c into my function f(a,b) in a loop (hopefully python can convert ith components of array into two arguments), which would then produce an array of the ith values of f.
I feel this method should work, however the main issue I'm having is syntactical. Does anyone know of any inbuilt functions which could merge two arrays in such a way?
First post on this so any replies would be appreciated! Thanks
python arrays list loops numpy
edited Nov 12 '18 at 17:56
Woody1193
2,246930
asked Nov 12 '18 at 15:57
Pox 219
1
Thezipfunction should be useful. Tryc = list(zip(a, b))
– doodhwala
Nov 12 '18 at 15:59
c = np.stack((a,b), axis=1)can create a (n,2) array, but given your description offI'm not sure it will help. Sounds likeftakes 2 positional scalar arguments,aandb, and does some sort of math returning another number. Or can it work with a 2d array? Or even with a tuple?
– hpaulj
Nov 12 '18 at 17:01
I think you need to give an actual demof(a,b). It doesn't have to be exactly the one you'll need, but it should behave just the same with respect to inputs (type and size, etc).
– hpaulj
Nov 12 '18 at 18:31
I will be integrating f using scipy.integrate.simpson. I’ve simplified my function a lot here, but ultimately I’m aiming to produce and array of f(a,b) and then an array of b’s , since the b parameter is the integration variable . I believe scipy.integrate.simpson requires an array of f(a,b) and an array of , in this case, b values to be inputted in to it. So now you see why I’m a bit stuck on getting the syntax correct to produce an array of f(a,b) for different values of a and b in a set range.
– Pox 219
Nov 12 '18 at 19:06
add a comment |
I have a way I would like to approach my problem, however am struggling with the syntax of the problem.
I have a function, lets call it f(a,b).
I also have an np.array of complex numbers for a and b.
Eg, a = [1+j, 2+j.....], and b = [3+2j, 4+4j....].
What I would like to do is combine these two arrays into an array called c, of the form c = [(1+j,3+2j),(2+j,4+4j)….], where the ith value of c = [(ai,bi)].
I feel I should then plug these ith values of c into my function f(a,b) in a loop (hopefully python can convert ith components of array into two arguments), which would then produce an array of the ith values of f.
I feel this method should work, however the main issue I'm having is syntactical. Does anyone know of any inbuilt functions which could merge two arrays in such a way?
First post on this so any replies would be appreciated! Thanks
python arrays list loops numpy
edited Nov 12 '18 at 17:56
Woody1193
2,246930
asked Nov 12 '18 at 15:57
Pox 219
1
I have a way I would like to approach my problem, however am struggling with the syntax of the problem.
I have a function, lets call it f(a,b).
I also have an np.array of complex numbers for a and b.
Eg, a = [1+j, 2+j.....], and b = [3+2j, 4+4j....].
What I would like to do is combine these two arrays into an array called c, of the form c = [(1+j,3+2j),(2+j,4+4j)….], where the ith value of c = [(ai,bi)].
I feel I should then plug these ith values of c into my function f(a,b) in a loop (hopefully python can convert ith components of array into two arguments), which would then produce an array of the ith values of f.
I feel this method should work, however the main issue I'm having is syntactical. Does anyone know of any inbuilt functions which could merge two arrays in such a way?
First post on this so any replies would be appreciated! Thanks
python arrays list loops numpy
python arrays list loops numpy
edited Nov 12 '18 at 17:56
Woody1193
2,246930
asked Nov 12 '18 at 15:57
Pox 219
1
edited Nov 12 '18 at 17:56
Woody1193
2,246930
asked Nov 12 '18 at 15:57
Pox 219
1
edited Nov 12 '18 at 17:56
Woody1193
2,246930
edited Nov 12 '18 at 17:56
Woody1193
2,246930
edited Nov 12 '18 at 17:56
Woody1193
2,246930
2,246930
asked Nov 12 '18 at 15:57
Pox 219
1
asked Nov 12 '18 at 15:57
Pox 219
1
asked Nov 12 '18 at 15:57
Pox 219
1
1
Thezipfunction should be useful. Tryc = list(zip(a, b))
– doodhwala
Nov 12 '18 at 15:59
c = np.stack((a,b), axis=1)can create a (n,2) array, but given your description offI'm not sure it will help. Sounds likeftakes 2 positional scalar arguments,aandb, and does some sort of math returning another number. Or can it work with a 2d array? Or even with a tuple?
– hpaulj
Nov 12 '18 at 17:01
I think you need to give an actual demof(a,b). It doesn't have to be exactly the one you'll need, but it should behave just the same with respect to inputs (type and size, etc).
– hpaulj
Nov 12 '18 at 18:31
I will be integrating f using scipy.integrate.simpson. I’ve simplified my function a lot here, but ultimately I’m aiming to produce and array of f(a,b) and then an array of b’s , since the b parameter is the integration variable . I believe scipy.integrate.simpson requires an array of f(a,b) and an array of , in this case, b values to be inputted in to it. So now you see why I’m a bit stuck on getting the syntax correct to produce an array of f(a,b) for different values of a and b in a set range.
– Pox 219
Nov 12 '18 at 19:06
add a comment |
Thezipfunction should be useful. Tryc = list(zip(a, b))
– doodhwala
Nov 12 '18 at 15:59
c = np.stack((a,b), axis=1)can create a (n,2) array, but given your description offI'm not sure it will help. Sounds likeftakes 2 positional scalar arguments,aandb, and does some sort of math returning another number. Or can it work with a 2d array? Or even with a tuple?
– hpaulj
Nov 12 '18 at 17:01
I think you need to give an actual demof(a,b). It doesn't have to be exactly the one you'll need, but it should behave just the same with respect to inputs (type and size, etc).
– hpaulj
Nov 12 '18 at 18:31
I will be integrating f using scipy.integrate.simpson. I’ve simplified my function a lot here, but ultimately I’m aiming to produce and array of f(a,b) and then an array of b’s , since the b parameter is the integration variable . I believe scipy.integrate.simpson requires an array of f(a,b) and an array of , in this case, b values to be inputted in to it. So now you see why I’m a bit stuck on getting the syntax correct to produce an array of f(a,b) for different values of a and b in a set range.
– Pox 219
Nov 12 '18 at 19:06
The
zip function should be useful. Try c = list(zip(a, b))– doodhwala
Nov 12 '18 at 15:59
The
zip function should be useful. Try c = list(zip(a, b))– doodhwala
Nov 12 '18 at 15:59
c = np.stack((a,b), axis=1) can create a (n,2) array, but given your description of f I'm not sure it will help. Sounds like ftakes 2 positional scalar arguments, a and b, and does some sort of math returning another number. Or can it work with a 2d array? Or even with a tuple?– hpaulj
Nov 12 '18 at 17:01
c = np.stack((a,b), axis=1) can create a (n,2) array, but given your description of f I'm not sure it will help. Sounds like ftakes 2 positional scalar arguments, a and b, and does some sort of math returning another number. Or can it work with a 2d array? Or even with a tuple?– hpaulj
Nov 12 '18 at 17:01
I think you need to give an actual demo
f(a,b). It doesn't have to be exactly the one you'll need, but it should behave just the same with respect to inputs (type and size, etc).– hpaulj
Nov 12 '18 at 18:31
I think you need to give an actual demo
f(a,b). It doesn't have to be exactly the one you'll need, but it should behave just the same with respect to inputs (type and size, etc).– hpaulj
Nov 12 '18 at 18:31
I will be integrating f using scipy.integrate.simpson. I’ve simplified my function a lot here, but ultimately I’m aiming to produce and array of f(a,b) and then an array of b’s , since the b parameter is the integration variable . I believe scipy.integrate.simpson requires an array of f(a,b) and an array of , in this case, b values to be inputted in to it. So now you see why I’m a bit stuck on getting the syntax correct to produce an array of f(a,b) for different values of a and b in a set range.
– Pox 219
Nov 12 '18 at 19:06
I will be integrating f using scipy.integrate.simpson. I’ve simplified my function a lot here, but ultimately I’m aiming to produce and array of f(a,b) and then an array of b’s , since the b parameter is the integration variable . I believe scipy.integrate.simpson requires an array of f(a,b) and an array of , in this case, b values to be inputted in to it. So now you see why I’m a bit stuck on getting the syntax correct to produce an array of f(a,b) for different values of a and b in a set range.
– Pox 219
Nov 12 '18 at 19:06
add a comment |
2 Answers
2
active
oldest
votes
Use a list comprehension:
c = [ci for ci in zip(a, b)]
zip will return a iterator over tuples containing one element from a and b.
With more verbosity, this is:
c = [(ai, bi) for (ai, bi) in zip(a, b)]
answered Nov 12 '18 at 15:58
Matthieu Brucher
12.6k22140
add a comment |
You just need to use zip :
c = zip(a, b)
a = ['x', 'y', 'z']
b = [1, 2, 3]
c = zip(a, b)
c[1]
>>> ('y', 2)
Edit : added the example
answered Nov 12 '18 at 16:06
Q-life
666
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use a list comprehension:
c = [ci for ci in zip(a, b)]
zip will return a iterator over tuples containing one element from a and b.
With more verbosity, this is:
c = [(ai, bi) for (ai, bi) in zip(a, b)]
answered Nov 12 '18 at 15:58
Matthieu Brucher
12.6k22140
add a comment |
Use a list comprehension:
c = [ci for ci in zip(a, b)]
zip will return a iterator over tuples containing one element from a and b.
With more verbosity, this is:
c = [(ai, bi) for (ai, bi) in zip(a, b)]
answered Nov 12 '18 at 15:58
Matthieu Brucher
12.6k22140
add a comment |
Use a list comprehension:
c = [ci for ci in zip(a, b)]
zip will return a iterator over tuples containing one element from a and b.
With more verbosity, this is:
c = [(ai, bi) for (ai, bi) in zip(a, b)]
answered Nov 12 '18 at 15:58
Matthieu Brucher
12.6k22140
Use a list comprehension:
c = [ci for ci in zip(a, b)]
zip will return a iterator over tuples containing one element from a and b.
With more verbosity, this is:
c = [(ai, bi) for (ai, bi) in zip(a, b)]
answered Nov 12 '18 at 15:58
Matthieu Brucher
12.6k22140
answered Nov 12 '18 at 15:58
Matthieu Brucher
12.6k22140
answered Nov 12 '18 at 15:58
Matthieu Brucher
12.6k22140
answered Nov 12 '18 at 15:58
Matthieu Brucher
12.6k22140
12.6k22140
add a comment |
add a comment |
You just need to use zip :
c = zip(a, b)
a = ['x', 'y', 'z']
b = [1, 2, 3]
c = zip(a, b)
c[1]
>>> ('y', 2)
Edit : added the example
answered Nov 12 '18 at 16:06
Q-life
666
add a comment |
You just need to use zip :
c = zip(a, b)
a = ['x', 'y', 'z']
b = [1, 2, 3]
c = zip(a, b)
c[1]
>>> ('y', 2)
Edit : added the example
answered Nov 12 '18 at 16:06
Q-life
666
add a comment |
You just need to use zip :
c = zip(a, b)
a = ['x', 'y', 'z']
b = [1, 2, 3]
c = zip(a, b)
c[1]
>>> ('y', 2)
Edit : added the example
answered Nov 12 '18 at 16:06
Q-life
666
You just need to use zip :
c = zip(a, b)
a = ['x', 'y', 'z']
b = [1, 2, 3]
c = zip(a, b)
c[1]
>>> ('y', 2)
Edit : added the example
answered Nov 12 '18 at 16:06
Q-life
666
answered Nov 12 '18 at 16:06
Q-life
666
answered Nov 12 '18 at 16:06
Q-life
666
answered Nov 12 '18 at 16:06
Q-life
666
666
add a comment |
add a comment |
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The
zipfunction should be useful. Tryc = list(zip(a, b))– doodhwala
Nov 12 '18 at 15:59
c = np.stack((a,b), axis=1)can create a (n,2) array, but given your description offI'm not sure it will help. Sounds likeftakes 2 positional scalar arguments,aandb, and does some sort of math returning another number. Or can it work with a 2d array? Or even with a tuple?– hpaulj
Nov 12 '18 at 17:01
I think you need to give an actual demo
f(a,b). It doesn't have to be exactly the one you'll need, but it should behave just the same with respect to inputs (type and size, etc).– hpaulj
Nov 12 '18 at 18:31
I will be integrating f using scipy.integrate.simpson. I’ve simplified my function a lot here, but ultimately I’m aiming to produce and array of f(a,b) and then an array of b’s , since the b parameter is the integration variable . I believe scipy.integrate.simpson requires an array of f(a,b) and an array of , in this case, b values to be inputted in to it. So now you see why I’m a bit stuck on getting the syntax correct to produce an array of f(a,b) for different values of a and b in a set range.
– Pox 219
Nov 12 '18 at 19:06