How to get specific properties from a JSON object from HTTP request using URLSession
0
With the following code I'm able to effectively get a JSON object, what I'm not sure how to do is retrieve the specific properties from the object.
Swift Code
@IBAction func testing(_ sender: Any) {
let url = URL(string: "http://example.com/cars/mustang")
let task = URLSession.shared.dataTask(with: url!) { data, response, error in
guard error == nil else {
print(error!)
return
}
guard let data = data else {
print("Data is empty")
return
}
let json = try! JSONSerialization.jsonObject(with: data, options: )
print(json)
}
task.resume()
}
Here is what I see when I run the above code...
Output - JSON Object
(
{
color = "red";
engine = "5.0";
}
)
How can I get just the property color?
Thanks
swift nsurlsession
edited Nov 14 '18 at 0:26
rmaddy
239k27311376
asked Nov 12 '18 at 23:45
fs_tigrefs_tigre
4,57273972
|
show 1 more comment
0
With the following code I'm able to effectively get a JSON object, what I'm not sure how to do is retrieve the specific properties from the object.
Swift Code
@IBAction func testing(_ sender: Any) {
let url = URL(string: "http://example.com/cars/mustang")
let task = URLSession.shared.dataTask(with: url!) { data, response, error in
guard error == nil else {
print(error!)
return
}
guard let data = data else {
print("Data is empty")
return
}
let json = try! JSONSerialization.jsonObject(with: data, options: )
print(json)
}
task.resume()
}
Here is what I see when I run the above code...
Output - JSON Object
(
{
color = "red";
engine = "5.0";
}
)
How can I get just the property color?
Thanks
swift nsurlsession
edited Nov 14 '18 at 0:26
rmaddy
239k27311376
asked Nov 12 '18 at 23:45
fs_tigrefs_tigre
4,57273972
3
jsonis an array of dictionary. Access your data accordingly.
– rmaddy
Nov 12 '18 at 23:46
Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?
– fs_tigre
Nov 13 '18 at 2:23
2
The Collection Types chapter of the Swift book is a good start.
– rmaddy
Nov 13 '18 at 2:24
1
Try this stackoverflow.com/questions/38743156/…
– Alex Bailey
Nov 13 '18 at 5:01
Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.
– rmaddy
Nov 14 '18 at 0:27
|
show 1 more comment
0
0
0
With the following code I'm able to effectively get a JSON object, what I'm not sure how to do is retrieve the specific properties from the object.
Swift Code
@IBAction func testing(_ sender: Any) {
let url = URL(string: "http://example.com/cars/mustang")
let task = URLSession.shared.dataTask(with: url!) { data, response, error in
guard error == nil else {
print(error!)
return
}
guard let data = data else {
print("Data is empty")
return
}
let json = try! JSONSerialization.jsonObject(with: data, options: )
print(json)
}
task.resume()
}
Here is what I see when I run the above code...
Output - JSON Object
(
{
color = "red";
engine = "5.0";
}
)
How can I get just the property color?
Thanks
swift nsurlsession
edited Nov 14 '18 at 0:26
rmaddy
239k27311376
asked Nov 12 '18 at 23:45
fs_tigrefs_tigre
4,57273972
With the following code I'm able to effectively get a JSON object, what I'm not sure how to do is retrieve the specific properties from the object.
Swift Code
@IBAction func testing(_ sender: Any) {
let url = URL(string: "http://example.com/cars/mustang")
let task = URLSession.shared.dataTask(with: url!) { data, response, error in
guard error == nil else {
print(error!)
return
}
guard let data = data else {
print("Data is empty")
return
}
let json = try! JSONSerialization.jsonObject(with: data, options: )
print(json)
}
task.resume()
}
Here is what I see when I run the above code...
Output - JSON Object
(
{
color = "red";
engine = "5.0";
}
)
How can I get just the property color?
Thanks
swift nsurlsession
swift nsurlsession
edited Nov 14 '18 at 0:26
rmaddy
239k27311376
asked Nov 12 '18 at 23:45
fs_tigrefs_tigre
4,57273972
edited Nov 14 '18 at 0:26
rmaddy
239k27311376
asked Nov 12 '18 at 23:45
fs_tigrefs_tigre
4,57273972
edited Nov 14 '18 at 0:26
rmaddy
239k27311376
edited Nov 14 '18 at 0:26
rmaddy
239k27311376
edited Nov 14 '18 at 0:26
rmaddy
239k27311376
239k27311376
asked Nov 12 '18 at 23:45
fs_tigrefs_tigre
4,57273972
asked Nov 12 '18 at 23:45
fs_tigrefs_tigre
4,57273972
asked Nov 12 '18 at 23:45
fs_tigrefs_tigre
4,57273972
4,57273972
3
jsonis an array of dictionary. Access your data accordingly.
– rmaddy
Nov 12 '18 at 23:46
Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?
– fs_tigre
Nov 13 '18 at 2:23
2
The Collection Types chapter of the Swift book is a good start.
– rmaddy
Nov 13 '18 at 2:24
1
Try this stackoverflow.com/questions/38743156/…
– Alex Bailey
Nov 13 '18 at 5:01
Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.
– rmaddy
Nov 14 '18 at 0:27
|
show 1 more comment
3
jsonis an array of dictionary. Access your data accordingly.
– rmaddy
Nov 12 '18 at 23:46
Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?
– fs_tigre
Nov 13 '18 at 2:23
2
The Collection Types chapter of the Swift book is a good start.
– rmaddy
Nov 13 '18 at 2:24
1
Try this stackoverflow.com/questions/38743156/…
– Alex Bailey
Nov 13 '18 at 5:01
Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.
– rmaddy
Nov 14 '18 at 0:27
3
3
json is an array of dictionary. Access your data accordingly.– rmaddy
Nov 12 '18 at 23:46
json is an array of dictionary. Access your data accordingly.– rmaddy
Nov 12 '18 at 23:46
Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?
– fs_tigre
Nov 13 '18 at 2:23
Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?
– fs_tigre
Nov 13 '18 at 2:23
2
2
The Collection Types chapter of the Swift book is a good start.
– rmaddy
Nov 13 '18 at 2:24
The Collection Types chapter of the Swift book is a good start.
– rmaddy
Nov 13 '18 at 2:24
1
1
Try this stackoverflow.com/questions/38743156/…
– Alex Bailey
Nov 13 '18 at 5:01
Try this stackoverflow.com/questions/38743156/…
– Alex Bailey
Nov 13 '18 at 5:01
Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.
– rmaddy
Nov 14 '18 at 0:27
Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.
– rmaddy
Nov 14 '18 at 0:27
|
show 1 more comment
2 Answers
2
active
oldest
votes
2
Create a class which confirm the decodable protocol; CarInfo for example in your case
class CarInfo: Decodable
Create attributes of the class
var color: String
var engine: String
Create JSON key enum which inherits from CodingKey
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
implement init
required init(from decoder: Decoder) throws
the class will be
class CarInfo: Decodable {
var color: String
var engine: String
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
public init(from decoder: Decodabler) throws {
let container = try decoder.container(keyedBy: CarInfoCodingKey.self)
self.color = try container.decode(String.self, forKey: .color)
self.engine = try contaire.decode(String.self, forKey: .engine)
}
}
call decoder
let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)
answered Nov 12 '18 at 23:59
Mohamed Mahdi AllaniMohamed Mahdi Allani
213
Is this the simplest way to do it?
– fs_tigre
Nov 13 '18 at 2:18
1
@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over usingJSONSerialization.
– rmaddy
Nov 13 '18 at 3:09
@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.
– fs_tigre
Nov 13 '18 at 23:13
add a comment |
0
Here is how I did it...
@IBAction func testing(_ sender: Any) {
let url = URL(string: "http://example.com/cars/mustang")
let task = URLSession.shared.dataTask(with: url!) { data, response, error in
guard error == nil else {
print(error!)
return
}
guard let data = data else {
print("Data is empty")
return
}
let json = try! JSONSerialization.jsonObject(with: data, options: )
guard let jsonArray = json as? [[String: String]] else {
return
}
let mustangColor = jsonArray[0]["color"]
print(mustangColor!)
}
task.resume()
}
answered Nov 14 '18 at 12:45
fs_tigrefs_tigre
4,57273972
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
Create a class which confirm the decodable protocol; CarInfo for example in your case
class CarInfo: Decodable
Create attributes of the class
var color: String
var engine: String
Create JSON key enum which inherits from CodingKey
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
implement init
required init(from decoder: Decoder) throws
the class will be
class CarInfo: Decodable {
var color: String
var engine: String
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
public init(from decoder: Decodabler) throws {
let container = try decoder.container(keyedBy: CarInfoCodingKey.self)
self.color = try container.decode(String.self, forKey: .color)
self.engine = try contaire.decode(String.self, forKey: .engine)
}
}
call decoder
let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)
answered Nov 12 '18 at 23:59
Mohamed Mahdi AllaniMohamed Mahdi Allani
213
Is this the simplest way to do it?
– fs_tigre
Nov 13 '18 at 2:18
1
@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over usingJSONSerialization.
– rmaddy
Nov 13 '18 at 3:09
@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.
– fs_tigre
Nov 13 '18 at 23:13
add a comment |
2
Create a class which confirm the decodable protocol; CarInfo for example in your case
class CarInfo: Decodable
Create attributes of the class
var color: String
var engine: String
Create JSON key enum which inherits from CodingKey
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
implement init
required init(from decoder: Decoder) throws
the class will be
class CarInfo: Decodable {
var color: String
var engine: String
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
public init(from decoder: Decodabler) throws {
let container = try decoder.container(keyedBy: CarInfoCodingKey.self)
self.color = try container.decode(String.self, forKey: .color)
self.engine = try contaire.decode(String.self, forKey: .engine)
}
}
call decoder
let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)
answered Nov 12 '18 at 23:59
Mohamed Mahdi AllaniMohamed Mahdi Allani
213
Is this the simplest way to do it?
– fs_tigre
Nov 13 '18 at 2:18
1
@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over usingJSONSerialization.
– rmaddy
Nov 13 '18 at 3:09
@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.
– fs_tigre
Nov 13 '18 at 23:13
add a comment |
2
2
2
Create a class which confirm the decodable protocol; CarInfo for example in your case
class CarInfo: Decodable
Create attributes of the class
var color: String
var engine: String
Create JSON key enum which inherits from CodingKey
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
implement init
required init(from decoder: Decoder) throws
the class will be
class CarInfo: Decodable {
var color: String
var engine: String
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
public init(from decoder: Decodabler) throws {
let container = try decoder.container(keyedBy: CarInfoCodingKey.self)
self.color = try container.decode(String.self, forKey: .color)
self.engine = try contaire.decode(String.self, forKey: .engine)
}
}
call decoder
let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)
answered Nov 12 '18 at 23:59
Mohamed Mahdi AllaniMohamed Mahdi Allani
213
Create a class which confirm the decodable protocol; CarInfo for example in your case
class CarInfo: Decodable
Create attributes of the class
var color: String
var engine: String
Create JSON key enum which inherits from CodingKey
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
implement init
required init(from decoder: Decoder) throws
the class will be
class CarInfo: Decodable {
var color: String
var engine: String
enum CarInfoCodingKey: String, CodingKey {
case color
case engine
}
public init(from decoder: Decodabler) throws {
let container = try decoder.container(keyedBy: CarInfoCodingKey.self)
self.color = try container.decode(String.self, forKey: .color)
self.engine = try contaire.decode(String.self, forKey: .engine)
}
}
call decoder
let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)
answered Nov 12 '18 at 23:59
Mohamed Mahdi AllaniMohamed Mahdi Allani
213
answered Nov 12 '18 at 23:59
Mohamed Mahdi AllaniMohamed Mahdi Allani
213
answered Nov 12 '18 at 23:59
Mohamed Mahdi AllaniMohamed Mahdi Allani
213
answered Nov 12 '18 at 23:59
Mohamed Mahdi AllaniMohamed Mahdi Allani
213
213
Is this the simplest way to do it?
– fs_tigre
Nov 13 '18 at 2:18
1
@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over usingJSONSerialization.
– rmaddy
Nov 13 '18 at 3:09
@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.
– fs_tigre
Nov 13 '18 at 23:13
add a comment |
Is this the simplest way to do it?
– fs_tigre
Nov 13 '18 at 2:18
1
@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over usingJSONSerialization.
– rmaddy
Nov 13 '18 at 3:09
@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.
– fs_tigre
Nov 13 '18 at 23:13
Is this the simplest way to do it?
– fs_tigre
Nov 13 '18 at 2:18
Is this the simplest way to do it?
– fs_tigre
Nov 13 '18 at 2:18
1
1
@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over using
JSONSerialization.– rmaddy
Nov 13 '18 at 3:09
@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over using
JSONSerialization.– rmaddy
Nov 13 '18 at 3:09
@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.
– fs_tigre
Nov 13 '18 at 23:13
@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.
– fs_tigre
Nov 13 '18 at 23:13
add a comment |
0
Here is how I did it...
@IBAction func testing(_ sender: Any) {
let url = URL(string: "http://example.com/cars/mustang")
let task = URLSession.shared.dataTask(with: url!) { data, response, error in
guard error == nil else {
print(error!)
return
}
guard let data = data else {
print("Data is empty")
return
}
let json = try! JSONSerialization.jsonObject(with: data, options: )
guard let jsonArray = json as? [[String: String]] else {
return
}
let mustangColor = jsonArray[0]["color"]
print(mustangColor!)
}
task.resume()
}
answered Nov 14 '18 at 12:45
fs_tigrefs_tigre
4,57273972
add a comment |
0
Here is how I did it...
@IBAction func testing(_ sender: Any) {
let url = URL(string: "http://example.com/cars/mustang")
let task = URLSession.shared.dataTask(with: url!) { data, response, error in
guard error == nil else {
print(error!)
return
}
guard let data = data else {
print("Data is empty")
return
}
let json = try! JSONSerialization.jsonObject(with: data, options: )
guard let jsonArray = json as? [[String: String]] else {
return
}
let mustangColor = jsonArray[0]["color"]
print(mustangColor!)
}
task.resume()
}
answered Nov 14 '18 at 12:45
fs_tigrefs_tigre
4,57273972
add a comment |
0
0
0
Here is how I did it...
@IBAction func testing(_ sender: Any) {
let url = URL(string: "http://example.com/cars/mustang")
let task = URLSession.shared.dataTask(with: url!) { data, response, error in
guard error == nil else {
print(error!)
return
}
guard let data = data else {
print("Data is empty")
return
}
let json = try! JSONSerialization.jsonObject(with: data, options: )
guard let jsonArray = json as? [[String: String]] else {
return
}
let mustangColor = jsonArray[0]["color"]
print(mustangColor!)
}
task.resume()
}
answered Nov 14 '18 at 12:45
fs_tigrefs_tigre
4,57273972
Here is how I did it...
@IBAction func testing(_ sender: Any) {
let url = URL(string: "http://example.com/cars/mustang")
let task = URLSession.shared.dataTask(with: url!) { data, response, error in
guard error == nil else {
print(error!)
return
}
guard let data = data else {
print("Data is empty")
return
}
let json = try! JSONSerialization.jsonObject(with: data, options: )
guard let jsonArray = json as? [[String: String]] else {
return
}
let mustangColor = jsonArray[0]["color"]
print(mustangColor!)
}
task.resume()
}
answered Nov 14 '18 at 12:45
fs_tigrefs_tigre
4,57273972
answered Nov 14 '18 at 12:45
fs_tigrefs_tigre
4,57273972
answered Nov 14 '18 at 12:45
fs_tigrefs_tigre
4,57273972
answered Nov 14 '18 at 12:45
fs_tigrefs_tigre
4,57273972
4,57273972
add a comment |
add a comment |
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3
jsonis an array of dictionary. Access your data accordingly.– rmaddy
Nov 12 '18 at 23:46
Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?
– fs_tigre
Nov 13 '18 at 2:23
2
The Collection Types chapter of the Swift book is a good start.
– rmaddy
Nov 13 '18 at 2:24
1
Try this stackoverflow.com/questions/38743156/…
– Alex Bailey
Nov 13 '18 at 5:01
Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.
– rmaddy
Nov 14 '18 at 0:27