How to get specific properties from a JSON object from HTTP request using URLSession

With the following code I'm able to effectively get a JSON object, what I'm not sure how to do is retrieve the specific properties from the object.

Swift Code

@IBAction func testing(_ sender: Any) {

    let url = URL(string: "http://example.com/cars/mustang")



    let task = URLSession.shared.dataTask(with: url!) { data, response, error in

        guard error == nil else {

            print(error!)

            return

        }

        guard let data = data else {

            print("Data is empty")

            return

        }

        let json = try! JSONSerialization.jsonObject(with: data, options: )

        print(json)

    }

    task.resume()

}

Here is what I see when I run the above code...

Output - JSON Object

(

    {

    color = "red";

    engine = "5.0";

    }

)

How can I get just the property color?

Thanks

edited Nov 14 '18 at 0:26

rmaddy

239k27311376

asked Nov 12 '18 at 23:45

fs_tigre

4,57273972

3

json is an array of dictionary. Access your data accordingly.

– rmaddy
Nov 12 '18 at 23:46

Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?

– fs_tigre
Nov 13 '18 at 2:23

2

The Collection Types chapter of the Swift book is a good start.

– rmaddy
Nov 13 '18 at 2:24

1

Try this stackoverflow.com/questions/38743156/…

– Alex Bailey
Nov 13 '18 at 5:01

Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.

– rmaddy
Nov 14 '18 at 0:27

|
show 1 more comment

With the following code I'm able to effectively get a JSON object, what I'm not sure how to do is retrieve the specific properties from the object.

Swift Code

@IBAction func testing(_ sender: Any) {

    let url = URL(string: "http://example.com/cars/mustang")



    let task = URLSession.shared.dataTask(with: url!) { data, response, error in

        guard error == nil else {

            print(error!)

            return

        }

        guard let data = data else {

            print("Data is empty")

            return

        }

        let json = try! JSONSerialization.jsonObject(with: data, options: )

        print(json)

    }

    task.resume()

}

Here is what I see when I run the above code...

Output - JSON Object

(

    {

    color = "red";

    engine = "5.0";

    }

)

How can I get just the property color?

Thanks

edited Nov 14 '18 at 0:26

rmaddy

239k27311376

asked Nov 12 '18 at 23:45

fs_tigre

4,57273972

3

json is an array of dictionary. Access your data accordingly.

– rmaddy
Nov 12 '18 at 23:46

Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?

– fs_tigre
Nov 13 '18 at 2:23

2

The Collection Types chapter of the Swift book is a good start.

– rmaddy
Nov 13 '18 at 2:24

1

Try this stackoverflow.com/questions/38743156/…

– Alex Bailey
Nov 13 '18 at 5:01

Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.

– rmaddy
Nov 14 '18 at 0:27

|
show 1 more comment

With the following code I'm able to effectively get a JSON object, what I'm not sure how to do is retrieve the specific properties from the object.

Swift Code

@IBAction func testing(_ sender: Any) {

    let url = URL(string: "http://example.com/cars/mustang")



    let task = URLSession.shared.dataTask(with: url!) { data, response, error in

        guard error == nil else {

            print(error!)

            return

        }

        guard let data = data else {

            print("Data is empty")

            return

        }

        let json = try! JSONSerialization.jsonObject(with: data, options: )

        print(json)

    }

    task.resume()

}

Here is what I see when I run the above code...

Output - JSON Object

(

    {

    color = "red";

    engine = "5.0";

    }

)

How can I get just the property color?

Thanks

edited Nov 14 '18 at 0:26

rmaddy

239k27311376

asked Nov 12 '18 at 23:45

fs_tigre

4,57273972

With the following code I'm able to effectively get a JSON object, what I'm not sure how to do is retrieve the specific properties from the object.

Swift Code

@IBAction func testing(_ sender: Any) {

    let url = URL(string: "http://example.com/cars/mustang")



    let task = URLSession.shared.dataTask(with: url!) { data, response, error in

        guard error == nil else {

            print(error!)

            return

        }

        guard let data = data else {

            print("Data is empty")

            return

        }

        let json = try! JSONSerialization.jsonObject(with: data, options: )

        print(json)

    }

    task.resume()

}

Here is what I see when I run the above code...

Output - JSON Object

(

    {

    color = "red";

    engine = "5.0";

    }

)

How can I get just the property color?

Thanks

swift nsurlsession

edited Nov 14 '18 at 0:26

rmaddy

239k27311376

asked Nov 12 '18 at 23:45

fs_tigre

4,57273972

edited Nov 14 '18 at 0:26

rmaddy

239k27311376

asked Nov 12 '18 at 23:45

fs_tigre

4,57273972

edited Nov 14 '18 at 0:26

rmaddy

239k27311376

edited Nov 14 '18 at 0:26

rmaddy

239k27311376

edited Nov 14 '18 at 0:26

rmaddy

239k27311376

asked Nov 12 '18 at 23:45

fs_tigre

4,57273972

asked Nov 12 '18 at 23:45

fs_tigre

4,57273972

asked Nov 12 '18 at 23:45

fs_tigre

4,57273972

3

json is an array of dictionary. Access your data accordingly.

– rmaddy
Nov 12 '18 at 23:46

Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?

– fs_tigre
Nov 13 '18 at 2:23

2

The Collection Types chapter of the Swift book is a good start.

– rmaddy
Nov 13 '18 at 2:24

1

Try this stackoverflow.com/questions/38743156/…

– Alex Bailey
Nov 13 '18 at 5:01

Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.

– rmaddy
Nov 14 '18 at 0:27

|
show 1 more comment

3

json is an array of dictionary. Access your data accordingly.

– rmaddy
Nov 12 '18 at 23:46

Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?

– fs_tigre
Nov 13 '18 at 2:23

2

The Collection Types chapter of the Swift book is a good start.

– rmaddy
Nov 13 '18 at 2:24

1

Try this stackoverflow.com/questions/38743156/…

– Alex Bailey
Nov 13 '18 at 5:01

Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.

– rmaddy
Nov 14 '18 at 0:27

json is an array of dictionary. Access your data accordingly.

– rmaddy
Nov 12 '18 at 23:46

Hmm, I cannot figure it out. Can you please direct me to where I can find information on how to get items from an array of dictionaries in Swift?

– fs_tigre
Nov 13 '18 at 2:23

The Collection Types chapter of the Swift book is a good start.

– rmaddy
Nov 13 '18 at 2:24

Try this stackoverflow.com/questions/38743156/…

– Alex Bailey
Nov 13 '18 at 5:01

Please do not put the answer in your question. Either accept an answer below if it best helped or post your own showing your chosen solution.

– rmaddy
Nov 14 '18 at 0:27

|
show 1 more comment

2 Answers
2

active

oldest

votes

Create a class which confirm the decodable protocol; CarInfo for example in your case

class CarInfo: Decodable

Create attributes of the class

var color: String



var engine: String

Create JSON key enum which inherits from CodingKey

enum CarInfoCodingKey: String, CodingKey {

   case color 

   case engine 

}

implement init

required init(from decoder: Decoder) throws

the class will be

class CarInfo: Decodable {

var color: String

var engine: String

enum CarInfoCodingKey: String, CodingKey {

case color

case engine

}

public init(from decoder: Decodabler) throws {

let container = try decoder.container(keyedBy: CarInfoCodingKey.self)

self.color = try container.decode(String.self, forKey: .color)

self.engine = try contaire.decode(String.self, forKey: .engine)

}

}

call decoder

let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)

answered Nov 12 '18 at 23:59

Mohamed Mahdi Allani

213

Is this the simplest way to do it?

– fs_tigre
Nov 13 '18 at 2:18

1

@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over using JSONSerialization.

– rmaddy
Nov 13 '18 at 3:09

@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.

– fs_tigre
Nov 13 '18 at 23:13

add a comment |

Here is how I did it...

@IBAction func testing(_ sender: Any) {

    let url = URL(string: "http://example.com/cars/mustang")



    let task = URLSession.shared.dataTask(with: url!) { data, response, error in

        guard error == nil else {

            print(error!)

            return

        }

        guard let data = data else {

            print("Data is empty")

            return

        }

        let json = try! JSONSerialization.jsonObject(with: data, options: )



        guard let jsonArray = json as? [[String: String]] else {

            return

        }

        let mustangColor = jsonArray[0]["color"]



        print(mustangColor!)

    }

    task.resume()

}

answered Nov 14 '18 at 12:45

fs_tigre

4,57273972

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

Create a class which confirm the decodable protocol; CarInfo for example in your case

class CarInfo: Decodable

Create attributes of the class

var color: String



var engine: String

Create JSON key enum which inherits from CodingKey

enum CarInfoCodingKey: String, CodingKey {

   case color 

   case engine 

}

implement init

required init(from decoder: Decoder) throws

the class will be

class CarInfo: Decodable {

var color: String

var engine: String

enum CarInfoCodingKey: String, CodingKey {

case color

case engine

}

public init(from decoder: Decodabler) throws {

let container = try decoder.container(keyedBy: CarInfoCodingKey.self)

self.color = try container.decode(String.self, forKey: .color)

self.engine = try contaire.decode(String.self, forKey: .engine)

}

}

call decoder

let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)

answered Nov 12 '18 at 23:59

Mohamed Mahdi Allani

213

Is this the simplest way to do it?

– fs_tigre
Nov 13 '18 at 2:18

1

@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over using JSONSerialization.

– rmaddy
Nov 13 '18 at 3:09

@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.

– fs_tigre
Nov 13 '18 at 23:13

add a comment |

Create a class which confirm the decodable protocol; CarInfo for example in your case

class CarInfo: Decodable

Create attributes of the class

var color: String



var engine: String

Create JSON key enum which inherits from CodingKey

enum CarInfoCodingKey: String, CodingKey {

   case color 

   case engine 

}

implement init

required init(from decoder: Decoder) throws

the class will be

class CarInfo: Decodable {

var color: String

var engine: String

enum CarInfoCodingKey: String, CodingKey {

case color

case engine

}

public init(from decoder: Decodabler) throws {

let container = try decoder.container(keyedBy: CarInfoCodingKey.self)

self.color = try container.decode(String.self, forKey: .color)

self.engine = try contaire.decode(String.self, forKey: .engine)

}

}

call decoder

let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)

answered Nov 12 '18 at 23:59

Mohamed Mahdi Allani

213

Is this the simplest way to do it?

– fs_tigre
Nov 13 '18 at 2:18

1

@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over using JSONSerialization.

– rmaddy
Nov 13 '18 at 3:09

@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.

– fs_tigre
Nov 13 '18 at 23:13

add a comment |

Create a class which confirm the decodable protocol; CarInfo for example in your case

class CarInfo: Decodable

Create attributes of the class

var color: String



var engine: String

Create JSON key enum which inherits from CodingKey

enum CarInfoCodingKey: String, CodingKey {

   case color 

   case engine 

}

implement init

required init(from decoder: Decoder) throws

the class will be

class CarInfo: Decodable {

var color: String

var engine: String

enum CarInfoCodingKey: String, CodingKey {

case color

case engine

}

public init(from decoder: Decodabler) throws {

let container = try decoder.container(keyedBy: CarInfoCodingKey.self)

self.color = try container.decode(String.self, forKey: .color)

self.engine = try contaire.decode(String.self, forKey: .engine)

}

}

call decoder

let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)

answered Nov 12 '18 at 23:59

Mohamed Mahdi Allani

213

Create a class which confirm the decodable protocol; CarInfo for example in your case

class CarInfo: Decodable

Create attributes of the class

var color: String



var engine: String

Create JSON key enum which inherits from CodingKey

enum CarInfoCodingKey: String, CodingKey {

   case color 

   case engine 

}

implement init

required init(from decoder: Decoder) throws

the class will be

class CarInfo: Decodable {

var color: String

var engine: String

enum CarInfoCodingKey: String, CodingKey {

case color

case engine

}

public init(from decoder: Decodabler) throws {

let container = try decoder.container(keyedBy: CarInfoCodingKey.self)

self.color = try container.decode(String.self, forKey: .color)

self.engine = try contaire.decode(String.self, forKey: .engine)

}

}

call decoder

let carinfo = try JsonDecoder().decode(CarInfo.self, from: jsonData)

answered Nov 12 '18 at 23:59

Mohamed Mahdi Allani

213

answered Nov 12 '18 at 23:59

Mohamed Mahdi Allani

213

answered Nov 12 '18 at 23:59

Mohamed Mahdi Allani

213

answered Nov 12 '18 at 23:59

Mohamed Mahdi Allani

213

Is this the simplest way to do it?

– fs_tigre
Nov 13 '18 at 2:18

1

@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over using JSONSerialization.

– rmaddy
Nov 13 '18 at 3:09

@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.

– fs_tigre
Nov 13 '18 at 23:13

add a comment |

Is this the simplest way to do it?

– fs_tigre
Nov 13 '18 at 2:18

1

@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over using JSONSerialization.

– rmaddy
Nov 13 '18 at 3:09

@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.

– fs_tigre
Nov 13 '18 at 23:13

Is this the simplest way to do it?

– fs_tigre
Nov 13 '18 at 2:18

@fs_tigre You only need one or two more lines in the code you posted in your question. Using this answer's solution is just a different solution over using JSONSerialization.

– rmaddy
Nov 13 '18 at 3:09

@rmaddy - Thank you for the clarification, I edited my original question with my solution. @-Mohamed Mahdi Allani - Thanks a lot for demonstrating other methods, I when with the simples approach.

– fs_tigre
Nov 13 '18 at 23:13

add a comment |

Here is how I did it...

@IBAction func testing(_ sender: Any) {

    let url = URL(string: "http://example.com/cars/mustang")



    let task = URLSession.shared.dataTask(with: url!) { data, response, error in

        guard error == nil else {

            print(error!)

            return

        }

        guard let data = data else {

            print("Data is empty")

            return

        }

        let json = try! JSONSerialization.jsonObject(with: data, options: )



        guard let jsonArray = json as? [[String: String]] else {

            return

        }

        let mustangColor = jsonArray[0]["color"]



        print(mustangColor!)

    }

    task.resume()

}

answered Nov 14 '18 at 12:45

fs_tigre

4,57273972

add a comment |

Here is how I did it...

@IBAction func testing(_ sender: Any) {

    let url = URL(string: "http://example.com/cars/mustang")



    let task = URLSession.shared.dataTask(with: url!) { data, response, error in

        guard error == nil else {

            print(error!)

            return

        }

        guard let data = data else {

            print("Data is empty")

            return

        }

        let json = try! JSONSerialization.jsonObject(with: data, options: )



        guard let jsonArray = json as? [[String: String]] else {

            return

        }

        let mustangColor = jsonArray[0]["color"]



        print(mustangColor!)

    }

    task.resume()

}

answered Nov 14 '18 at 12:45

fs_tigre

4,57273972

add a comment |

Here is how I did it...

@IBAction func testing(_ sender: Any) {

    let url = URL(string: "http://example.com/cars/mustang")



    let task = URLSession.shared.dataTask(with: url!) { data, response, error in

        guard error == nil else {

            print(error!)

            return

        }

        guard let data = data else {

            print("Data is empty")

            return

        }

        let json = try! JSONSerialization.jsonObject(with: data, options: )



        guard let jsonArray = json as? [[String: String]] else {

            return

        }

        let mustangColor = jsonArray[0]["color"]



        print(mustangColor!)

    }

    task.resume()

}

answered Nov 14 '18 at 12:45

fs_tigre

4,57273972

Here is how I did it...

@IBAction func testing(_ sender: Any) {

    let url = URL(string: "http://example.com/cars/mustang")



    let task = URLSession.shared.dataTask(with: url!) { data, response, error in

        guard error == nil else {

            print(error!)

            return

        }

        guard let data = data else {

            print("Data is empty")

            return

        }

        let json = try! JSONSerialization.jsonObject(with: data, options: )



        guard let jsonArray = json as? [[String: String]] else {

            return

        }

        let mustangColor = jsonArray[0]["color"]



        print(mustangColor!)

    }

    task.resume()

}

answered Nov 14 '18 at 12:45

fs_tigre

4,57273972

answered Nov 14 '18 at 12:45

fs_tigre

4,57273972

answered Nov 14 '18 at 12:45

fs_tigre

4,57273972

answered Nov 14 '18 at 12:45

fs_tigre

4,57273972

add a comment |

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