How to add all integer from String in sequence?
for Example:
2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26
but i does not get desired results
when i add all char it gives
output as:
266
import java.util.Scanner;
public class ProjectEu {
public static void main(String...rDX) {
int degree = new Scanner(System.in).nextInt();
String store = Integer.toString((int)Math.pow(2,degree));
char finals = store.toCharArray();
int temp = 0;
for (int i = 0, n = store.length(); i < n; i++) {
System.out.printf("values[%d] --> %c n",i, finals[i]);
temp = temp + finals[i];
}
System.out.println(temp);
}
}
java
edited Nov 12 '18 at 15:01
Oussema Aroua
4,02611634
asked Nov 12 '18 at 14:03
Pratik Katariya
111
add a comment |
for Example:
2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26
but i does not get desired results
when i add all char it gives
output as:
266
import java.util.Scanner;
public class ProjectEu {
public static void main(String...rDX) {
int degree = new Scanner(System.in).nextInt();
String store = Integer.toString((int)Math.pow(2,degree));
char finals = store.toCharArray();
int temp = 0;
for (int i = 0, n = store.length(); i < n; i++) {
System.out.printf("values[%d] --> %c n",i, finals[i]);
temp = temp + finals[i];
}
System.out.println(temp);
}
}
java
edited Nov 12 '18 at 15:01
Oussema Aroua
4,02611634
asked Nov 12 '18 at 14:03
Pratik Katariya
111
Pratik did my answer help you?
– Ishaan Javali
Nov 23 '18 at 18:38
Pratik Katariya, if my answer helped you can you please mark it as accepted?
– Ishaan Javali
Dec 20 '18 at 20:13
add a comment |
for Example:
2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26
but i does not get desired results
when i add all char it gives
output as:
266
import java.util.Scanner;
public class ProjectEu {
public static void main(String...rDX) {
int degree = new Scanner(System.in).nextInt();
String store = Integer.toString((int)Math.pow(2,degree));
char finals = store.toCharArray();
int temp = 0;
for (int i = 0, n = store.length(); i < n; i++) {
System.out.printf("values[%d] --> %c n",i, finals[i]);
temp = temp + finals[i];
}
System.out.println(temp);
}
}
java
edited Nov 12 '18 at 15:01
Oussema Aroua
4,02611634
asked Nov 12 '18 at 14:03
Pratik Katariya
111
for Example:
2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26
but i does not get desired results
when i add all char it gives
output as:
266
import java.util.Scanner;
public class ProjectEu {
public static void main(String...rDX) {
int degree = new Scanner(System.in).nextInt();
String store = Integer.toString((int)Math.pow(2,degree));
char finals = store.toCharArray();
int temp = 0;
for (int i = 0, n = store.length(); i < n; i++) {
System.out.printf("values[%d] --> %c n",i, finals[i]);
temp = temp + finals[i];
}
System.out.println(temp);
}
}
java
java
edited Nov 12 '18 at 15:01
Oussema Aroua
4,02611634
asked Nov 12 '18 at 14:03
Pratik Katariya
111
edited Nov 12 '18 at 15:01
Oussema Aroua
4,02611634
asked Nov 12 '18 at 14:03
Pratik Katariya
111
edited Nov 12 '18 at 15:01
Oussema Aroua
4,02611634
edited Nov 12 '18 at 15:01
Oussema Aroua
4,02611634
edited Nov 12 '18 at 15:01
Oussema Aroua
4,02611634
4,02611634
asked Nov 12 '18 at 14:03
Pratik Katariya
111
asked Nov 12 '18 at 14:03
Pratik Katariya
111
asked Nov 12 '18 at 14:03
Pratik Katariya
111
111
Pratik did my answer help you?
– Ishaan Javali
Nov 23 '18 at 18:38
Pratik Katariya, if my answer helped you can you please mark it as accepted?
– Ishaan Javali
Dec 20 '18 at 20:13
add a comment |
Pratik did my answer help you?
– Ishaan Javali
Nov 23 '18 at 18:38
Pratik Katariya, if my answer helped you can you please mark it as accepted?
– Ishaan Javali
Dec 20 '18 at 20:13
Pratik did my answer help you?
– Ishaan Javali
Nov 23 '18 at 18:38
Pratik did my answer help you?
– Ishaan Javali
Nov 23 '18 at 18:38
Pratik Katariya, if my answer helped you can you please mark it as accepted?
– Ishaan Javali
Dec 20 '18 at 20:13
Pratik Katariya, if my answer helped you can you please mark it as accepted?
– Ishaan Javali
Dec 20 '18 at 20:13
add a comment |
4 Answers
4
active
oldest
votes
The reason that you are getting this error is because temp is an integer, but finals[i] is a character, so it converts the characters into ASCII values and adds them. You can fix this problem by doing:
for (int i = 0, n = store.length(); i < n; i++) {
char ch = store.charAt(i);
int digit = Integer.parseInt(Character.toString(ch));
temp = temp + digits;
}
answered Nov 12 '18 at 14:10
Ishaan Javali
9271418
add a comment |
Try this:
int sum = store.chars()
.boxed()
.map(Character::getNumericValue)
.mapToInt(Integer::intValue)
.sum();
answered Nov 12 '18 at 14:16
ETO
1,708321
add a comment |
This line:
temp = temp + finals[i];
sums temp and the ASCII code of the char stored in finals[i].
You can get the value of the digit by this:
temp = temp + finals[i] - '0';
This means that by subtracting from the digit's ASCII code the ASCII code of 0 you get the number value of the digit.
answered Nov 12 '18 at 14:09
forpas
8,7641421
add a comment |
When you are adding a character to an integer, you are adding the integer code of the character, not its actual numeric value .
What you need is Character.getNumericValue :
temp = temp + Character.getNumericValue(finals[i]);
answered Nov 12 '18 at 14:10
Arnaud
13.4k21730
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
The reason that you are getting this error is because temp is an integer, but finals[i] is a character, so it converts the characters into ASCII values and adds them. You can fix this problem by doing:
for (int i = 0, n = store.length(); i < n; i++) {
char ch = store.charAt(i);
int digit = Integer.parseInt(Character.toString(ch));
temp = temp + digits;
}
answered Nov 12 '18 at 14:10
Ishaan Javali
9271418
add a comment |
The reason that you are getting this error is because temp is an integer, but finals[i] is a character, so it converts the characters into ASCII values and adds them. You can fix this problem by doing:
for (int i = 0, n = store.length(); i < n; i++) {
char ch = store.charAt(i);
int digit = Integer.parseInt(Character.toString(ch));
temp = temp + digits;
}
answered Nov 12 '18 at 14:10
Ishaan Javali
9271418
add a comment |
The reason that you are getting this error is because temp is an integer, but finals[i] is a character, so it converts the characters into ASCII values and adds them. You can fix this problem by doing:
for (int i = 0, n = store.length(); i < n; i++) {
char ch = store.charAt(i);
int digit = Integer.parseInt(Character.toString(ch));
temp = temp + digits;
}
answered Nov 12 '18 at 14:10
Ishaan Javali
9271418
The reason that you are getting this error is because temp is an integer, but finals[i] is a character, so it converts the characters into ASCII values and adds them. You can fix this problem by doing:
for (int i = 0, n = store.length(); i < n; i++) {
char ch = store.charAt(i);
int digit = Integer.parseInt(Character.toString(ch));
temp = temp + digits;
}
answered Nov 12 '18 at 14:10
Ishaan Javali
9271418
answered Nov 12 '18 at 14:10
Ishaan Javali
9271418
answered Nov 12 '18 at 14:10
Ishaan Javali
9271418
answered Nov 12 '18 at 14:10
Ishaan Javali
9271418
9271418
add a comment |
add a comment |
Try this:
int sum = store.chars()
.boxed()
.map(Character::getNumericValue)
.mapToInt(Integer::intValue)
.sum();
answered Nov 12 '18 at 14:16
ETO
1,708321
add a comment |
Try this:
int sum = store.chars()
.boxed()
.map(Character::getNumericValue)
.mapToInt(Integer::intValue)
.sum();
answered Nov 12 '18 at 14:16
ETO
1,708321
add a comment |
Try this:
int sum = store.chars()
.boxed()
.map(Character::getNumericValue)
.mapToInt(Integer::intValue)
.sum();
answered Nov 12 '18 at 14:16
ETO
1,708321
Try this:
int sum = store.chars()
.boxed()
.map(Character::getNumericValue)
.mapToInt(Integer::intValue)
.sum();
answered Nov 12 '18 at 14:16
ETO
1,708321
answered Nov 12 '18 at 14:16
ETO
1,708321
answered Nov 12 '18 at 14:16
ETO
1,708321
answered Nov 12 '18 at 14:16
ETO
1,708321
1,708321
add a comment |
add a comment |
This line:
temp = temp + finals[i];
sums temp and the ASCII code of the char stored in finals[i].
You can get the value of the digit by this:
temp = temp + finals[i] - '0';
This means that by subtracting from the digit's ASCII code the ASCII code of 0 you get the number value of the digit.
answered Nov 12 '18 at 14:09
forpas
8,7641421
add a comment |
This line:
temp = temp + finals[i];
sums temp and the ASCII code of the char stored in finals[i].
You can get the value of the digit by this:
temp = temp + finals[i] - '0';
This means that by subtracting from the digit's ASCII code the ASCII code of 0 you get the number value of the digit.
answered Nov 12 '18 at 14:09
forpas
8,7641421
add a comment |
This line:
temp = temp + finals[i];
sums temp and the ASCII code of the char stored in finals[i].
You can get the value of the digit by this:
temp = temp + finals[i] - '0';
This means that by subtracting from the digit's ASCII code the ASCII code of 0 you get the number value of the digit.
answered Nov 12 '18 at 14:09
forpas
8,7641421
This line:
temp = temp + finals[i];
sums temp and the ASCII code of the char stored in finals[i].
You can get the value of the digit by this:
temp = temp + finals[i] - '0';
This means that by subtracting from the digit's ASCII code the ASCII code of 0 you get the number value of the digit.
answered Nov 12 '18 at 14:09
forpas
8,7641421
edited Nov 12 '18 at 14:18
answered Nov 12 '18 at 14:09
forpas
8,7641421
answered Nov 12 '18 at 14:09
forpas
8,7641421
answered Nov 12 '18 at 14:09
forpas
8,7641421
8,7641421
add a comment |
add a comment |
When you are adding a character to an integer, you are adding the integer code of the character, not its actual numeric value .
What you need is Character.getNumericValue :
temp = temp + Character.getNumericValue(finals[i]);
answered Nov 12 '18 at 14:10
Arnaud
13.4k21730
add a comment |
When you are adding a character to an integer, you are adding the integer code of the character, not its actual numeric value .
What you need is Character.getNumericValue :
temp = temp + Character.getNumericValue(finals[i]);
answered Nov 12 '18 at 14:10
Arnaud
13.4k21730
add a comment |
When you are adding a character to an integer, you are adding the integer code of the character, not its actual numeric value .
What you need is Character.getNumericValue :
temp = temp + Character.getNumericValue(finals[i]);
answered Nov 12 '18 at 14:10
Arnaud
13.4k21730
When you are adding a character to an integer, you are adding the integer code of the character, not its actual numeric value .
What you need is Character.getNumericValue :
temp = temp + Character.getNumericValue(finals[i]);
answered Nov 12 '18 at 14:10
Arnaud
13.4k21730
edited Nov 12 '18 at 14:23
answered Nov 12 '18 at 14:10
Arnaud
13.4k21730
answered Nov 12 '18 at 14:10
Arnaud
13.4k21730
answered Nov 12 '18 at 14:10
Arnaud
13.4k21730
13.4k21730
add a comment |
add a comment |
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Pratik did my answer help you?
– Ishaan Javali
Nov 23 '18 at 18:38
Pratik Katariya, if my answer helped you can you please mark it as accepted?
– Ishaan Javali
Dec 20 '18 at 20:13