what is wrong with my code in this “Escape Sequences in Strings” challenge on FreeCodeCamp?

I can't seem to get past this challenge and it's driving me nuts. I thought I followed the instructions correctly. Can someone please figure out what the error is? (I have a feeling it's something stupidly simple.)

The challenge is here: https://www.freecodecamp.com/challenges/escape-sequences-in-strings, below is my code.

var myStr =

FirstLinen

\SecondLine\

rThirdLine;

Thanks in advance!

Edit: 1st line error: unexpected '' and missing semicolon; 2nd line error: unexpected ''; 3rd line error: unexpected ''

edited Jul 22 '16 at 2:14

s952163

5,07331840

asked Jul 22 '16 at 0:36

Bethany Hible

2536

add a comment |

The challenge is here: https://www.freecodecamp.com/challenges/escape-sequences-in-strings, below is my code.

var myStr =

FirstLinen

\SecondLine\

rThirdLine;

Thanks in advance!

Edit: 1st line error: unexpected '' and missing semicolon; 2nd line error: unexpected ''; 3rd line error: unexpected ''

edited Jul 22 '16 at 2:14

s952163

5,07331840

asked Jul 22 '16 at 0:36

Bethany Hible

2536

add a comment |

The challenge is here: https://www.freecodecamp.com/challenges/escape-sequences-in-strings, below is my code.

var myStr =

FirstLinen

\SecondLine\

rThirdLine;

Thanks in advance!

Edit: 1st line error: unexpected '' and missing semicolon; 2nd line error: unexpected ''; 3rd line error: unexpected ''

edited Jul 22 '16 at 2:14

s952163

5,07331840

asked Jul 22 '16 at 0:36

Bethany Hible

2536

The challenge is here: https://www.freecodecamp.com/challenges/escape-sequences-in-strings, below is my code.

var myStr =

FirstLinen

\SecondLine\

rThirdLine;

Thanks in advance!

Edit: 1st line error: unexpected '' and missing semicolon; 2nd line error: unexpected ''; 3rd line error: unexpected ''

javascript escaping

edited Jul 22 '16 at 2:14

s952163

5,07331840

asked Jul 22 '16 at 0:36

Bethany Hible

2536

edited Jul 22 '16 at 2:14

s952163

5,07331840

asked Jul 22 '16 at 0:36

Bethany Hible

2536

edited Jul 22 '16 at 2:14

s952163

5,07331840

edited Jul 22 '16 at 2:14

s952163

5,07331840

edited Jul 22 '16 at 2:14

s952163

5,07331840

asked Jul 22 '16 at 0:36

Bethany Hible

2536

asked Jul 22 '16 at 0:36

Bethany Hible

2536

asked Jul 22 '16 at 0:36

Bethany Hible

2536

add a comment |

4 Answers
4

active

oldest

votes

In order to make the challenge work, you're going to need your whole string in quotes and on one line.

So change

var myStr =

FirstLinen

\SecondLine\

rThirdLine;

var myStr = "FirstLinen\SecondLine\rThirdLine";

answered Jul 22 '16 at 1:03

Davis

1,14658

i knew it was simple. thanks so much!
– Bethany Hible
Jul 22 '16 at 1:57

add a comment |

Here is the way I was able to answer the challenge and have the test cases pass:

var myStr = "FirstLinent\SecondLinenThirdLine"

edited May 31 '18 at 15:52

Subhrajyoti Das

9111023

answered May 31 '18 at 14:46

Lisa Mae

add a comment |

var myStr = "FirstLinentSecondLinenThirdLine";

This will work

answered Nov 12 '18 at 12:07

Aarav Mahajan

1

Maybe you can explain it a little more?
– Lithilion
Nov 12 '18 at 12:12

add a comment |

-1

var myStr = "FirstLinentSecondLinenThirdLine";

works also!

answered Sep 2 '18 at 10:15

Isaac

Hi, you might want to expand your answer. The OP asked "what is the error". If you're wondering why you're getting negative votes, have a read here stackoverflow.com/help/how-to-answer
– Michal
Sep 2 '18 at 10:43

add a comment |

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4 Answers
4

active

oldest

votes

4 Answers
4

active

oldest

votes

In order to make the challenge work, you're going to need your whole string in quotes and on one line.

So change

var myStr =

FirstLinen

\SecondLine\

rThirdLine;

var myStr = "FirstLinen\SecondLine\rThirdLine";

answered Jul 22 '16 at 1:03

Davis

1,14658

i knew it was simple. thanks so much!
– Bethany Hible
Jul 22 '16 at 1:57

add a comment |

In order to make the challenge work, you're going to need your whole string in quotes and on one line.

So change

var myStr =

FirstLinen

\SecondLine\

rThirdLine;

var myStr = "FirstLinen\SecondLine\rThirdLine";

answered Jul 22 '16 at 1:03

Davis

1,14658

i knew it was simple. thanks so much!
– Bethany Hible
Jul 22 '16 at 1:57

add a comment |

In order to make the challenge work, you're going to need your whole string in quotes and on one line.

So change

var myStr =

FirstLinen

\SecondLine\

rThirdLine;

var myStr = "FirstLinen\SecondLine\rThirdLine";

answered Jul 22 '16 at 1:03

Davis

1,14658

In order to make the challenge work, you're going to need your whole string in quotes and on one line.

So change

var myStr =

FirstLinen

\SecondLine\

rThirdLine;

var myStr = "FirstLinen\SecondLine\rThirdLine";

answered Jul 22 '16 at 1:03

Davis

1,14658

answered Jul 22 '16 at 1:03

Davis

1,14658

answered Jul 22 '16 at 1:03

Davis

1,14658

answered Jul 22 '16 at 1:03

Davis

1,14658

i knew it was simple. thanks so much!
– Bethany Hible
Jul 22 '16 at 1:57

add a comment |

i knew it was simple. thanks so much!
– Bethany Hible
Jul 22 '16 at 1:57

i knew it was simple. thanks so much!
– Bethany Hible
Jul 22 '16 at 1:57

add a comment |

Here is the way I was able to answer the challenge and have the test cases pass:

var myStr = "FirstLinent\SecondLinenThirdLine"

edited May 31 '18 at 15:52

Subhrajyoti Das

9111023

answered May 31 '18 at 14:46

Lisa Mae

add a comment |

Here is the way I was able to answer the challenge and have the test cases pass:

var myStr = "FirstLinent\SecondLinenThirdLine"

edited May 31 '18 at 15:52

Subhrajyoti Das

9111023

answered May 31 '18 at 14:46

Lisa Mae

add a comment |

Here is the way I was able to answer the challenge and have the test cases pass:

var myStr = "FirstLinent\SecondLinenThirdLine"

edited May 31 '18 at 15:52

Subhrajyoti Das

9111023

answered May 31 '18 at 14:46

Lisa Mae

Here is the way I was able to answer the challenge and have the test cases pass:

var myStr = "FirstLinent\SecondLinenThirdLine"

edited May 31 '18 at 15:52

Subhrajyoti Das

9111023

answered May 31 '18 at 14:46

Lisa Mae

edited May 31 '18 at 15:52

Subhrajyoti Das

9111023

edited May 31 '18 at 15:52

Subhrajyoti Das

9111023

edited May 31 '18 at 15:52

Subhrajyoti Das

9111023

answered May 31 '18 at 14:46

Lisa Mae

answered May 31 '18 at 14:46

Lisa Mae

answered May 31 '18 at 14:46

Lisa Mae

add a comment |

var myStr = "FirstLinentSecondLinenThirdLine";

This will work

answered Nov 12 '18 at 12:07

Aarav Mahajan

1

Maybe you can explain it a little more?
– Lithilion
Nov 12 '18 at 12:12

add a comment |

var myStr = "FirstLinentSecondLinenThirdLine";

This will work

answered Nov 12 '18 at 12:07

Aarav Mahajan

1

Maybe you can explain it a little more?
– Lithilion
Nov 12 '18 at 12:12

add a comment |

var myStr = "FirstLinentSecondLinenThirdLine";

This will work

answered Nov 12 '18 at 12:07

Aarav Mahajan

var myStr = "FirstLinentSecondLinenThirdLine";

This will work

answered Nov 12 '18 at 12:07

Aarav Mahajan

answered Nov 12 '18 at 12:07

Aarav Mahajan

answered Nov 12 '18 at 12:07

Aarav Mahajan

answered Nov 12 '18 at 12:07

Aarav Mahajan

1

Maybe you can explain it a little more?
– Lithilion
Nov 12 '18 at 12:12

add a comment |

1

Maybe you can explain it a little more?
– Lithilion
Nov 12 '18 at 12:12

Maybe you can explain it a little more?
– Lithilion
Nov 12 '18 at 12:12

add a comment |

-1

var myStr = "FirstLinentSecondLinenThirdLine";

works also!

answered Sep 2 '18 at 10:15

Isaac

Hi, you might want to expand your answer. The OP asked "what is the error". If you're wondering why you're getting negative votes, have a read here stackoverflow.com/help/how-to-answer
– Michal
Sep 2 '18 at 10:43

add a comment |

-1

var myStr = "FirstLinentSecondLinenThirdLine";

works also!

answered Sep 2 '18 at 10:15

Isaac

Hi, you might want to expand your answer. The OP asked "what is the error". If you're wondering why you're getting negative votes, have a read here stackoverflow.com/help/how-to-answer
– Michal
Sep 2 '18 at 10:43

add a comment |

-1

var myStr = "FirstLinentSecondLinenThirdLine";

works also!

answered Sep 2 '18 at 10:15

Isaac

var myStr = "FirstLinentSecondLinenThirdLine";

works also!

answered Sep 2 '18 at 10:15

Isaac

answered Sep 2 '18 at 10:15

Isaac

answered Sep 2 '18 at 10:15

Isaac

answered Sep 2 '18 at 10:15

Isaac

Hi, you might want to expand your answer. The OP asked "what is the error". If you're wondering why you're getting negative votes, have a read here stackoverflow.com/help/how-to-answer
– Michal
Sep 2 '18 at 10:43

add a comment |

Hi, you might want to expand your answer. The OP asked "what is the error". If you're wondering why you're getting negative votes, have a read here stackoverflow.com/help/how-to-answer
– Michal
Sep 2 '18 at 10:43

Hi, you might want to expand your answer. The OP asked "what is the error". If you're wondering why you're getting negative votes, have a read here stackoverflow.com/help/how-to-answer
– Michal
Sep 2 '18 at 10:43

add a comment |

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