Is there a way to find the probability of different values in matrices
up vote
1
down vote
favorite
I thought there would be a library that would help me to do this task instead of writing many lines of codes. I tried finding some solutions from books related to my problem, but I could not find any.
One of the recent books I did read related to probability:
Python for Probability, Statistics, and Machine Learning for José
Unpingco
The task is that I have a matrix like this one below
0 1
213 vha
342 gha
523 xha
121 gha
812 gha
612 vha
123 gha
and I want the program to calculate the steps of moving from, say, vha
to gha
in the second row. and from gha
to xha
in the third row. If any step is repeated, it will be added to the previous step. For example vha
to gha
in the first and second rows is repeated at the end of the matrix.
The desired output is will be the similar steps added together
/ total number of rows-1
. In the first case it is vha
to gha
prob = 2/7-1
Desired output
vha to gha prob = 0.3
gha to xha prob = 0.16
xha to gha prob = 0.16
gha to gha prob = 0.16
gha to vha prob = 0.16
Total probs = 1
python python-3.x probability
add a comment |
up vote
1
down vote
favorite
I thought there would be a library that would help me to do this task instead of writing many lines of codes. I tried finding some solutions from books related to my problem, but I could not find any.
One of the recent books I did read related to probability:
Python for Probability, Statistics, and Machine Learning for José
Unpingco
The task is that I have a matrix like this one below
0 1
213 vha
342 gha
523 xha
121 gha
812 gha
612 vha
123 gha
and I want the program to calculate the steps of moving from, say, vha
to gha
in the second row. and from gha
to xha
in the third row. If any step is repeated, it will be added to the previous step. For example vha
to gha
in the first and second rows is repeated at the end of the matrix.
The desired output is will be the similar steps added together
/ total number of rows-1
. In the first case it is vha
to gha
prob = 2/7-1
Desired output
vha to gha prob = 0.3
gha to xha prob = 0.16
xha to gha prob = 0.16
gha to gha prob = 0.16
gha to vha prob = 0.16
Total probs = 1
python python-3.x probability
1
What datatype is this "matrix"?
– timgeb
Nov 11 at 20:59
it is<class 'list'>
– Abdulaziz Al Jumaia
Nov 11 at 21:04
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I thought there would be a library that would help me to do this task instead of writing many lines of codes. I tried finding some solutions from books related to my problem, but I could not find any.
One of the recent books I did read related to probability:
Python for Probability, Statistics, and Machine Learning for José
Unpingco
The task is that I have a matrix like this one below
0 1
213 vha
342 gha
523 xha
121 gha
812 gha
612 vha
123 gha
and I want the program to calculate the steps of moving from, say, vha
to gha
in the second row. and from gha
to xha
in the third row. If any step is repeated, it will be added to the previous step. For example vha
to gha
in the first and second rows is repeated at the end of the matrix.
The desired output is will be the similar steps added together
/ total number of rows-1
. In the first case it is vha
to gha
prob = 2/7-1
Desired output
vha to gha prob = 0.3
gha to xha prob = 0.16
xha to gha prob = 0.16
gha to gha prob = 0.16
gha to vha prob = 0.16
Total probs = 1
python python-3.x probability
I thought there would be a library that would help me to do this task instead of writing many lines of codes. I tried finding some solutions from books related to my problem, but I could not find any.
One of the recent books I did read related to probability:
Python for Probability, Statistics, and Machine Learning for José
Unpingco
The task is that I have a matrix like this one below
0 1
213 vha
342 gha
523 xha
121 gha
812 gha
612 vha
123 gha
and I want the program to calculate the steps of moving from, say, vha
to gha
in the second row. and from gha
to xha
in the third row. If any step is repeated, it will be added to the previous step. For example vha
to gha
in the first and second rows is repeated at the end of the matrix.
The desired output is will be the similar steps added together
/ total number of rows-1
. In the first case it is vha
to gha
prob = 2/7-1
Desired output
vha to gha prob = 0.3
gha to xha prob = 0.16
xha to gha prob = 0.16
gha to gha prob = 0.16
gha to vha prob = 0.16
Total probs = 1
python python-3.x probability
python python-3.x probability
asked Nov 11 at 20:58
Abdulaziz Al Jumaia
117113
117113
1
What datatype is this "matrix"?
– timgeb
Nov 11 at 20:59
it is<class 'list'>
– Abdulaziz Al Jumaia
Nov 11 at 21:04
add a comment |
1
What datatype is this "matrix"?
– timgeb
Nov 11 at 20:59
it is<class 'list'>
– Abdulaziz Al Jumaia
Nov 11 at 21:04
1
1
What datatype is this "matrix"?
– timgeb
Nov 11 at 20:59
What datatype is this "matrix"?
– timgeb
Nov 11 at 20:59
it is
<class 'list'>
– Abdulaziz Al Jumaia
Nov 11 at 21:04
it is
<class 'list'>
– Abdulaziz Al Jumaia
Nov 11 at 21:04
add a comment |
1 Answer
1
active
oldest
votes
up vote
2
down vote
accepted
You can use a Counter
to count how many times a transition occurs and then calculate probabilities for each transition.
You can use zip
to combine two slices of the list m
- one with the last element removed and another with the first element removed - to get tuples for adjacent elements. zip(m[:-1], m[1:])
does that. Then can you can count similar tuples - which represent transitions - with a Counter
:
from collections import Counter
m = [[213, 'vha'],
[342, 'gha'],
[523, 'xha'],
[121, 'gha'],
[812, 'gha'],
[612, 'vha'],
[123, 'gha']]
c = Counter([(x[1], y[1]) for x, y in zip(m[:-1], m[1:])])
probs = [(e, v / (len(m) - 1)) for e, v in c.items()]
for p in probs:
print(p)
Output
(('vha', 'gha'), 0.3333333333333333)
(('gha', 'xha'), 0.16666666666666666)
(('xha', 'gha'), 0.16666666666666666)
(('gha', 'gha'), 0.16666666666666666)
(('gha', 'vha'), 0.16666666666666666)
Amazing! the code is working. I have accepted your answer. I am just wondering if you can explain how the program works or refer me to a link with an explanation. Regards
– Abdulaziz Al Jumaia
Nov 12 at 22:44
@AbdulazizAlJumaia I've added links to documentation an a more detailed explanation. Hope that helps!
– slider
Nov 12 at 23:06
It does :). Thanks
– Abdulaziz Al Jumaia
Nov 13 at 8:31
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
You can use a Counter
to count how many times a transition occurs and then calculate probabilities for each transition.
You can use zip
to combine two slices of the list m
- one with the last element removed and another with the first element removed - to get tuples for adjacent elements. zip(m[:-1], m[1:])
does that. Then can you can count similar tuples - which represent transitions - with a Counter
:
from collections import Counter
m = [[213, 'vha'],
[342, 'gha'],
[523, 'xha'],
[121, 'gha'],
[812, 'gha'],
[612, 'vha'],
[123, 'gha']]
c = Counter([(x[1], y[1]) for x, y in zip(m[:-1], m[1:])])
probs = [(e, v / (len(m) - 1)) for e, v in c.items()]
for p in probs:
print(p)
Output
(('vha', 'gha'), 0.3333333333333333)
(('gha', 'xha'), 0.16666666666666666)
(('xha', 'gha'), 0.16666666666666666)
(('gha', 'gha'), 0.16666666666666666)
(('gha', 'vha'), 0.16666666666666666)
Amazing! the code is working. I have accepted your answer. I am just wondering if you can explain how the program works or refer me to a link with an explanation. Regards
– Abdulaziz Al Jumaia
Nov 12 at 22:44
@AbdulazizAlJumaia I've added links to documentation an a more detailed explanation. Hope that helps!
– slider
Nov 12 at 23:06
It does :). Thanks
– Abdulaziz Al Jumaia
Nov 13 at 8:31
add a comment |
up vote
2
down vote
accepted
You can use a Counter
to count how many times a transition occurs and then calculate probabilities for each transition.
You can use zip
to combine two slices of the list m
- one with the last element removed and another with the first element removed - to get tuples for adjacent elements. zip(m[:-1], m[1:])
does that. Then can you can count similar tuples - which represent transitions - with a Counter
:
from collections import Counter
m = [[213, 'vha'],
[342, 'gha'],
[523, 'xha'],
[121, 'gha'],
[812, 'gha'],
[612, 'vha'],
[123, 'gha']]
c = Counter([(x[1], y[1]) for x, y in zip(m[:-1], m[1:])])
probs = [(e, v / (len(m) - 1)) for e, v in c.items()]
for p in probs:
print(p)
Output
(('vha', 'gha'), 0.3333333333333333)
(('gha', 'xha'), 0.16666666666666666)
(('xha', 'gha'), 0.16666666666666666)
(('gha', 'gha'), 0.16666666666666666)
(('gha', 'vha'), 0.16666666666666666)
Amazing! the code is working. I have accepted your answer. I am just wondering if you can explain how the program works or refer me to a link with an explanation. Regards
– Abdulaziz Al Jumaia
Nov 12 at 22:44
@AbdulazizAlJumaia I've added links to documentation an a more detailed explanation. Hope that helps!
– slider
Nov 12 at 23:06
It does :). Thanks
– Abdulaziz Al Jumaia
Nov 13 at 8:31
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
You can use a Counter
to count how many times a transition occurs and then calculate probabilities for each transition.
You can use zip
to combine two slices of the list m
- one with the last element removed and another with the first element removed - to get tuples for adjacent elements. zip(m[:-1], m[1:])
does that. Then can you can count similar tuples - which represent transitions - with a Counter
:
from collections import Counter
m = [[213, 'vha'],
[342, 'gha'],
[523, 'xha'],
[121, 'gha'],
[812, 'gha'],
[612, 'vha'],
[123, 'gha']]
c = Counter([(x[1], y[1]) for x, y in zip(m[:-1], m[1:])])
probs = [(e, v / (len(m) - 1)) for e, v in c.items()]
for p in probs:
print(p)
Output
(('vha', 'gha'), 0.3333333333333333)
(('gha', 'xha'), 0.16666666666666666)
(('xha', 'gha'), 0.16666666666666666)
(('gha', 'gha'), 0.16666666666666666)
(('gha', 'vha'), 0.16666666666666666)
You can use a Counter
to count how many times a transition occurs and then calculate probabilities for each transition.
You can use zip
to combine two slices of the list m
- one with the last element removed and another with the first element removed - to get tuples for adjacent elements. zip(m[:-1], m[1:])
does that. Then can you can count similar tuples - which represent transitions - with a Counter
:
from collections import Counter
m = [[213, 'vha'],
[342, 'gha'],
[523, 'xha'],
[121, 'gha'],
[812, 'gha'],
[612, 'vha'],
[123, 'gha']]
c = Counter([(x[1], y[1]) for x, y in zip(m[:-1], m[1:])])
probs = [(e, v / (len(m) - 1)) for e, v in c.items()]
for p in probs:
print(p)
Output
(('vha', 'gha'), 0.3333333333333333)
(('gha', 'xha'), 0.16666666666666666)
(('xha', 'gha'), 0.16666666666666666)
(('gha', 'gha'), 0.16666666666666666)
(('gha', 'vha'), 0.16666666666666666)
edited Nov 12 at 23:05
answered Nov 11 at 21:12
slider
7,9601129
7,9601129
Amazing! the code is working. I have accepted your answer. I am just wondering if you can explain how the program works or refer me to a link with an explanation. Regards
– Abdulaziz Al Jumaia
Nov 12 at 22:44
@AbdulazizAlJumaia I've added links to documentation an a more detailed explanation. Hope that helps!
– slider
Nov 12 at 23:06
It does :). Thanks
– Abdulaziz Al Jumaia
Nov 13 at 8:31
add a comment |
Amazing! the code is working. I have accepted your answer. I am just wondering if you can explain how the program works or refer me to a link with an explanation. Regards
– Abdulaziz Al Jumaia
Nov 12 at 22:44
@AbdulazizAlJumaia I've added links to documentation an a more detailed explanation. Hope that helps!
– slider
Nov 12 at 23:06
It does :). Thanks
– Abdulaziz Al Jumaia
Nov 13 at 8:31
Amazing! the code is working. I have accepted your answer. I am just wondering if you can explain how the program works or refer me to a link with an explanation. Regards
– Abdulaziz Al Jumaia
Nov 12 at 22:44
Amazing! the code is working. I have accepted your answer. I am just wondering if you can explain how the program works or refer me to a link with an explanation. Regards
– Abdulaziz Al Jumaia
Nov 12 at 22:44
@AbdulazizAlJumaia I've added links to documentation an a more detailed explanation. Hope that helps!
– slider
Nov 12 at 23:06
@AbdulazizAlJumaia I've added links to documentation an a more detailed explanation. Hope that helps!
– slider
Nov 12 at 23:06
It does :). Thanks
– Abdulaziz Al Jumaia
Nov 13 at 8:31
It does :). Thanks
– Abdulaziz Al Jumaia
Nov 13 at 8:31
add a comment |
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1
What datatype is this "matrix"?
– timgeb
Nov 11 at 20:59
it is
<class 'list'>
– Abdulaziz Al Jumaia
Nov 11 at 21:04