how to pass variable to http post API in Perl?
My snippet as below, I googled and cannot find a solution to pass variable to
the post request in my quoted string.
Most of the google result are just pass plain Json key value string pairs to the
post content. But I need to pass the parameter to the inner Json value part and call the related REST api. any suggestions? Thanks!
#!/usr/bin/perl -w
use strict;
use warnings;
# Create a user agent object
use LWP::UserAgent;
my $ua = LWP::UserAgent->new;
$ua->agent("MyApp/0.1");
# Create a request
my $req = HTTP::Request->new(POST => 'https://oapi.dingtalk.com/robot/send?access_token=foofb73f');
$req->content_type('application/json');
my $var1="value from var";
# works fine
my $message = '{"msgtype": "text","text":{"content":"plain string ok"}}';
# failed to compile
# my $message = '{"msgtype": "text","text":{"content":$var1}}';
$req->content($message);
# Pass request to the user agent and get a response back
my $res = $ua->request($req);
# Check the outcome of the response
if ($res->is_success) {
print $res->content;
} else {
print $res->status_line, "n";
}
perl http post lwp
add a comment |
My snippet as below, I googled and cannot find a solution to pass variable to
the post request in my quoted string.
Most of the google result are just pass plain Json key value string pairs to the
post content. But I need to pass the parameter to the inner Json value part and call the related REST api. any suggestions? Thanks!
#!/usr/bin/perl -w
use strict;
use warnings;
# Create a user agent object
use LWP::UserAgent;
my $ua = LWP::UserAgent->new;
$ua->agent("MyApp/0.1");
# Create a request
my $req = HTTP::Request->new(POST => 'https://oapi.dingtalk.com/robot/send?access_token=foofb73f');
$req->content_type('application/json');
my $var1="value from var";
# works fine
my $message = '{"msgtype": "text","text":{"content":"plain string ok"}}';
# failed to compile
# my $message = '{"msgtype": "text","text":{"content":$var1}}';
$req->content($message);
# Pass request to the user agent and get a response back
my $res = $ua->request($req);
# Check the outcome of the response
if ($res->is_success) {
print $res->content;
} else {
print $res->status_line, "n";
}
perl http post lwp
add a comment |
My snippet as below, I googled and cannot find a solution to pass variable to
the post request in my quoted string.
Most of the google result are just pass plain Json key value string pairs to the
post content. But I need to pass the parameter to the inner Json value part and call the related REST api. any suggestions? Thanks!
#!/usr/bin/perl -w
use strict;
use warnings;
# Create a user agent object
use LWP::UserAgent;
my $ua = LWP::UserAgent->new;
$ua->agent("MyApp/0.1");
# Create a request
my $req = HTTP::Request->new(POST => 'https://oapi.dingtalk.com/robot/send?access_token=foofb73f');
$req->content_type('application/json');
my $var1="value from var";
# works fine
my $message = '{"msgtype": "text","text":{"content":"plain string ok"}}';
# failed to compile
# my $message = '{"msgtype": "text","text":{"content":$var1}}';
$req->content($message);
# Pass request to the user agent and get a response back
my $res = $ua->request($req);
# Check the outcome of the response
if ($res->is_success) {
print $res->content;
} else {
print $res->status_line, "n";
}
perl http post lwp
My snippet as below, I googled and cannot find a solution to pass variable to
the post request in my quoted string.
Most of the google result are just pass plain Json key value string pairs to the
post content. But I need to pass the parameter to the inner Json value part and call the related REST api. any suggestions? Thanks!
#!/usr/bin/perl -w
use strict;
use warnings;
# Create a user agent object
use LWP::UserAgent;
my $ua = LWP::UserAgent->new;
$ua->agent("MyApp/0.1");
# Create a request
my $req = HTTP::Request->new(POST => 'https://oapi.dingtalk.com/robot/send?access_token=foofb73f');
$req->content_type('application/json');
my $var1="value from var";
# works fine
my $message = '{"msgtype": "text","text":{"content":"plain string ok"}}';
# failed to compile
# my $message = '{"msgtype": "text","text":{"content":$var1}}';
$req->content($message);
# Pass request to the user agent and get a response back
my $res = $ua->request($req);
# Check the outcome of the response
if ($res->is_success) {
print $res->content;
} else {
print $res->status_line, "n";
}
perl http post lwp
perl http post lwp
asked Nov 12 at 1:42
codebyte
52
52
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You didn't properly convert the value into a JSON string.
use Cpanel::JSON::XS qw( encode_json );
my $message = encode_json({ msgtype => "text", text => { content => $var1 } });
Your suggestion works fine. Thanks!
– codebyte
Nov 12 at 3:42
add a comment |
Your Answer
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You didn't properly convert the value into a JSON string.
use Cpanel::JSON::XS qw( encode_json );
my $message = encode_json({ msgtype => "text", text => { content => $var1 } });
Your suggestion works fine. Thanks!
– codebyte
Nov 12 at 3:42
add a comment |
You didn't properly convert the value into a JSON string.
use Cpanel::JSON::XS qw( encode_json );
my $message = encode_json({ msgtype => "text", text => { content => $var1 } });
Your suggestion works fine. Thanks!
– codebyte
Nov 12 at 3:42
add a comment |
You didn't properly convert the value into a JSON string.
use Cpanel::JSON::XS qw( encode_json );
my $message = encode_json({ msgtype => "text", text => { content => $var1 } });
You didn't properly convert the value into a JSON string.
use Cpanel::JSON::XS qw( encode_json );
my $message = encode_json({ msgtype => "text", text => { content => $var1 } });
answered Nov 12 at 1:59
ikegami
261k11176396
261k11176396
Your suggestion works fine. Thanks!
– codebyte
Nov 12 at 3:42
add a comment |
Your suggestion works fine. Thanks!
– codebyte
Nov 12 at 3:42
Your suggestion works fine. Thanks!
– codebyte
Nov 12 at 3:42
Your suggestion works fine. Thanks!
– codebyte
Nov 12 at 3:42
add a comment |
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