How do I UPDATE from a SELECT in SQL Server - if the select returns multiple items (Follow up question...
This is a follow up of the question.
How do I UPDATE from a SELECT in SQL Server?
If I use the query in question 2334712, How would I insert 'ABC', 'BCD' or 'DEF' in the Table_A?
I tried but I can't use the ORDER BY clause in query.
Query result should be ABC (If ascending order), or DEF (If descending order), or based on a key on another column, say B3.
UPDATE
Table_A
SET
Table_A.A2 = Table_B.B2
FROM
Table_A
INNER JOIN Table_B
ON Table_A.A1 = Table_B.B1
WHERE
Table_A.A1 < 10
Table_A:
A1 A2
1 (desired result: can insert 'ABC' or 'DEF' based on my choice)
2
Table_B:
B1 B2 B3
1 ABC 1
1 BCD 2
1 DEF 3
2 GHI 4
sql
sql-server tsql edited Nov 12 at 10:17
Rahul Neekhra
6021627
asked Nov 12 at 9:55
Tony Chan
389
add a comment |
This is a follow up of the question.
How do I UPDATE from a SELECT in SQL Server?
If I use the query in question 2334712, How would I insert 'ABC', 'BCD' or 'DEF' in the Table_A?
I tried but I can't use the ORDER BY clause in query.
Query result should be ABC (If ascending order), or DEF (If descending order), or based on a key on another column, say B3.
UPDATE
Table_A
SET
Table_A.A2 = Table_B.B2
FROM
Table_A
INNER JOIN Table_B
ON Table_A.A1 = Table_B.B1
WHERE
Table_A.A1 < 10
Table_A:
A1 A2
1 (desired result: can insert 'ABC' or 'DEF' based on my choice)
2
Table_B:
B1 B2 B3
1 ABC 1
1 BCD 2
1 DEF 3
2 GHI 4
sql
sql-server tsql edited Nov 12 at 10:17
Rahul Neekhra
6021627
asked Nov 12 at 9:55
Tony Chan
389
there are three values in tableB for B1=1. In your question you said "based on my choice" - could you please explain what is your choice
– fa06
Nov 12 at 9:59
The choice can be highest value in B3, lowest value in B3 or specific value in B3 (e.g. B3 = 2)
– Tony Chan
Nov 12 at 10:06
add a comment |
This is a follow up of the question.
How do I UPDATE from a SELECT in SQL Server?
If I use the query in question 2334712, How would I insert 'ABC', 'BCD' or 'DEF' in the Table_A?
I tried but I can't use the ORDER BY clause in query.
Query result should be ABC (If ascending order), or DEF (If descending order), or based on a key on another column, say B3.
UPDATE
Table_A
SET
Table_A.A2 = Table_B.B2
FROM
Table_A
INNER JOIN Table_B
ON Table_A.A1 = Table_B.B1
WHERE
Table_A.A1 < 10
Table_A:
A1 A2
1 (desired result: can insert 'ABC' or 'DEF' based on my choice)
2
Table_B:
B1 B2 B3
1 ABC 1
1 BCD 2
1 DEF 3
2 GHI 4
sql
sql-server tsql edited Nov 12 at 10:17
Rahul Neekhra
6021627
asked Nov 12 at 9:55
Tony Chan
389
This is a follow up of the question.
How do I UPDATE from a SELECT in SQL Server?
If I use the query in question 2334712, How would I insert 'ABC', 'BCD' or 'DEF' in the Table_A?
I tried but I can't use the ORDER BY clause in query.
Query result should be ABC (If ascending order), or DEF (If descending order), or based on a key on another column, say B3.
UPDATE
Table_A
SET
Table_A.A2 = Table_B.B2
FROM
Table_A
INNER JOIN Table_B
ON Table_A.A1 = Table_B.B1
WHERE
Table_A.A1 < 10
Table_A:
A1 A2
1 (desired result: can insert 'ABC' or 'DEF' based on my choice)
2
Table_B:
B1 B2 B3
1 ABC 1
1 BCD 2
1 DEF 3
2 GHI 4
sql
sql-server tsql sql
sql-server tsql edited Nov 12 at 10:17
Rahul Neekhra
6021627
asked Nov 12 at 9:55
Tony Chan
389
edited Nov 12 at 10:17
Rahul Neekhra
6021627
asked Nov 12 at 9:55
Tony Chan
389
edited Nov 12 at 10:17
Rahul Neekhra
6021627
edited Nov 12 at 10:17
Rahul Neekhra
6021627
edited Nov 12 at 10:17
Rahul Neekhra
6021627
6021627
asked Nov 12 at 9:55
Tony Chan
389
asked Nov 12 at 9:55
Tony Chan
389
asked Nov 12 at 9:55
Tony Chan
389
389
there are three values in tableB for B1=1. In your question you said "based on my choice" - could you please explain what is your choice
– fa06
Nov 12 at 9:59
The choice can be highest value in B3, lowest value in B3 or specific value in B3 (e.g. B3 = 2)
– Tony Chan
Nov 12 at 10:06
add a comment |
there are three values in tableB for B1=1. In your question you said "based on my choice" - could you please explain what is your choice
– fa06
Nov 12 at 9:59
The choice can be highest value in B3, lowest value in B3 or specific value in B3 (e.g. B3 = 2)
– Tony Chan
Nov 12 at 10:06
there are three values in tableB for B1=1. In your question you said "based on my choice" - could you please explain what is your choice
– fa06
Nov 12 at 9:59
there are three values in tableB for B1=1. In your question you said "based on my choice" - could you please explain what is your choice
– fa06
Nov 12 at 9:59
The choice can be highest value in B3, lowest value in B3 or specific value in B3 (e.g. B3 = 2)
– Tony Chan
Nov 12 at 10:06
The choice can be highest value in B3, lowest value in B3 or specific value in B3 (e.g. B3 = 2)
– Tony Chan
Nov 12 at 10:06
add a comment |
3 Answers
3
active
oldest
votes
Join to a subquery which identifies a single record for each value of B1:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B2) rn
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN cte b
ON a.A1 = b.B1 AND b.rn = 1
WHERE
a.A1 < 10;
This example assumes you want the record having the lowest B2 value for each value of B1. But, you may alter the call to ROW_NUMBER however you want to use a different ordering.
answered Nov 12 at 10:00
Tim Biegeleisen
217k1386139
add a comment |
You can try below using row_number()
WITH t1 AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B3 desc) rownum
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN t1 b
ON a.A1 = b.B1 AND rn=1
WHERE
a.A1 < 10;
OR you can use correlated subquery
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN Table_B b
ON a.A1 = b.B1 AND exists (select max(B3) from Table_B c on b.B1 and c.B1)
WHERE
a.A1 < 10;
answered Nov 12 at 10:15
fa06
11k2917
add a comment |
You'll can use 'with' table,
Something like that:
WITH AAA (T_B, ID)
AS
(
SELECT TOP (SELECT COUNT(*) FROM Table_A) Table_B.B2 AS RR ,Table_A.A1
FROM Table_A INNER JOIN Table_B
ON Table_A.A1 = Table_B.B1
WHERE Table_A.A1 < 10
ORDER BY 1 DESC-- OR ASC
)
UPDATE Table_A
SET Table_A.A2 = T_B
FROM AAA
answered Nov 12 at 10:34
Tamir alon
102
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Join to a subquery which identifies a single record for each value of B1:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B2) rn
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN cte b
ON a.A1 = b.B1 AND b.rn = 1
WHERE
a.A1 < 10;
This example assumes you want the record having the lowest B2 value for each value of B1. But, you may alter the call to ROW_NUMBER however you want to use a different ordering.
answered Nov 12 at 10:00
Tim Biegeleisen
217k1386139
add a comment |
Join to a subquery which identifies a single record for each value of B1:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B2) rn
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN cte b
ON a.A1 = b.B1 AND b.rn = 1
WHERE
a.A1 < 10;
This example assumes you want the record having the lowest B2 value for each value of B1. But, you may alter the call to ROW_NUMBER however you want to use a different ordering.
answered Nov 12 at 10:00
Tim Biegeleisen
217k1386139
add a comment |
Join to a subquery which identifies a single record for each value of B1:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B2) rn
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN cte b
ON a.A1 = b.B1 AND b.rn = 1
WHERE
a.A1 < 10;
This example assumes you want the record having the lowest B2 value for each value of B1. But, you may alter the call to ROW_NUMBER however you want to use a different ordering.
answered Nov 12 at 10:00
Tim Biegeleisen
217k1386139
Join to a subquery which identifies a single record for each value of B1:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B2) rn
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN cte b
ON a.A1 = b.B1 AND b.rn = 1
WHERE
a.A1 < 10;
This example assumes you want the record having the lowest B2 value for each value of B1. But, you may alter the call to ROW_NUMBER however you want to use a different ordering.
answered Nov 12 at 10:00
Tim Biegeleisen
217k1386139
answered Nov 12 at 10:00
Tim Biegeleisen
217k1386139
answered Nov 12 at 10:00
Tim Biegeleisen
217k1386139
answered Nov 12 at 10:00
Tim Biegeleisen
217k1386139
217k1386139
add a comment |
add a comment |
You can try below using row_number()
WITH t1 AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B3 desc) rownum
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN t1 b
ON a.A1 = b.B1 AND rn=1
WHERE
a.A1 < 10;
OR you can use correlated subquery
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN Table_B b
ON a.A1 = b.B1 AND exists (select max(B3) from Table_B c on b.B1 and c.B1)
WHERE
a.A1 < 10;
answered Nov 12 at 10:15
fa06
11k2917
add a comment |
You can try below using row_number()
WITH t1 AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B3 desc) rownum
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN t1 b
ON a.A1 = b.B1 AND rn=1
WHERE
a.A1 < 10;
OR you can use correlated subquery
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN Table_B b
ON a.A1 = b.B1 AND exists (select max(B3) from Table_B c on b.B1 and c.B1)
WHERE
a.A1 < 10;
answered Nov 12 at 10:15
fa06
11k2917
add a comment |
You can try below using row_number()
WITH t1 AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B3 desc) rownum
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN t1 b
ON a.A1 = b.B1 AND rn=1
WHERE
a.A1 < 10;
OR you can use correlated subquery
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN Table_B b
ON a.A1 = b.B1 AND exists (select max(B3) from Table_B c on b.B1 and c.B1)
WHERE
a.A1 < 10;
answered Nov 12 at 10:15
fa06
11k2917
You can try below using row_number()
WITH t1 AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY B1 ORDER BY B3 desc) rownum
FROM Table_B
)
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN t1 b
ON a.A1 = b.B1 AND rn=1
WHERE
a.A1 < 10;
OR you can use correlated subquery
UPDATE a
SET A2 = b.B2
FROM Table_A a
INNER JOIN Table_B b
ON a.A1 = b.B1 AND exists (select max(B3) from Table_B c on b.B1 and c.B1)
WHERE
a.A1 < 10;
answered Nov 12 at 10:15
fa06
11k2917
answered Nov 12 at 10:15
fa06
11k2917
answered Nov 12 at 10:15
fa06
11k2917
answered Nov 12 at 10:15
fa06
11k2917
11k2917
add a comment |
add a comment |
You'll can use 'with' table,
Something like that:
WITH AAA (T_B, ID)
AS
(
SELECT TOP (SELECT COUNT(*) FROM Table_A) Table_B.B2 AS RR ,Table_A.A1
FROM Table_A INNER JOIN Table_B
ON Table_A.A1 = Table_B.B1
WHERE Table_A.A1 < 10
ORDER BY 1 DESC-- OR ASC
)
UPDATE Table_A
SET Table_A.A2 = T_B
FROM AAA
answered Nov 12 at 10:34
Tamir alon
102
add a comment |
You'll can use 'with' table,
Something like that:
WITH AAA (T_B, ID)
AS
(
SELECT TOP (SELECT COUNT(*) FROM Table_A) Table_B.B2 AS RR ,Table_A.A1
FROM Table_A INNER JOIN Table_B
ON Table_A.A1 = Table_B.B1
WHERE Table_A.A1 < 10
ORDER BY 1 DESC-- OR ASC
)
UPDATE Table_A
SET Table_A.A2 = T_B
FROM AAA
answered Nov 12 at 10:34
Tamir alon
102
add a comment |
You'll can use 'with' table,
Something like that:
WITH AAA (T_B, ID)
AS
(
SELECT TOP (SELECT COUNT(*) FROM Table_A) Table_B.B2 AS RR ,Table_A.A1
FROM Table_A INNER JOIN Table_B
ON Table_A.A1 = Table_B.B1
WHERE Table_A.A1 < 10
ORDER BY 1 DESC-- OR ASC
)
UPDATE Table_A
SET Table_A.A2 = T_B
FROM AAA
answered Nov 12 at 10:34
Tamir alon
102
You'll can use 'with' table,
Something like that:
WITH AAA (T_B, ID)
AS
(
SELECT TOP (SELECT COUNT(*) FROM Table_A) Table_B.B2 AS RR ,Table_A.A1
FROM Table_A INNER JOIN Table_B
ON Table_A.A1 = Table_B.B1
WHERE Table_A.A1 < 10
ORDER BY 1 DESC-- OR ASC
)
UPDATE Table_A
SET Table_A.A2 = T_B
FROM AAA
answered Nov 12 at 10:34
Tamir alon
102
answered Nov 12 at 10:34
Tamir alon
102
answered Nov 12 at 10:34
Tamir alon
102
answered Nov 12 at 10:34
Tamir alon
102
102
add a comment |
add a comment |
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there are three values in tableB for B1=1. In your question you said "based on my choice" - could you please explain what is your choice
– fa06
Nov 12 at 9:59
The choice can be highest value in B3, lowest value in B3 or specific value in B3 (e.g. B3 = 2)
– Tony Chan
Nov 12 at 10:06