How can I test a spring-cloud-contract containing a java.time.Instant field
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I want to test a contract where one field is of type java.time.Instant. But not all instances of an Instant are handled as I expect by spring-cloud-contract. Given the following simple contract:
Contract.make {
description("Get a version")
request {
method 'GET'
url '/config/version'
headers {
contentType(applicationJson())
}
}
response {
status 200
body(
nr: 42,
creationDate: producer(anyIso8601WithOffset())
)
headers {
contentType(applicationJson())
}
}
}
And this service implementation:
@RestController
public class VersionController {
@GetMapping(path = "/version")
public ResponseEntity<Version> getCurrentVersion() {
return ResponseEntity.ok(new Version(42, Instant.ofEpochMilli(0)));
}
}
Executing gradle test works fine. But if I replace the Instant with Instant.now(), my provider test fails with
java.lang.IllegalStateException: Parsed JSON [{"nr":42,"creationDate":"2018-11-11T15:28:26.958284Z"}] doesn't match the JSON path [$[?(@.['creationDate'] =~ /([0-9]{4})-(1[0-2]|0[1-9])-(3[01]|0[1-9]|[12][0-9])T(2[0-3]|[01][0-9]):([0-5][0-9]):([0-5][0-9])(.d{3})?(Z|[+-][01]d:[0-5]d)/)]]
which is understandable because Instant.now() produces an Instant whose string representation does indeed not match the anyIso8601WithOffset() pattern. But why is this? Why are Instants represented differently and how can I describe a contract that validates for any instant?
json testing spring-cloud-contract java.time.instant
edited Nov 12 at 12:54
Ole V.V.
26.4k62651
asked Nov 11 at 15:33
Tobias Neubert
114
add a comment |
up vote
0
down vote
favorite
I want to test a contract where one field is of type java.time.Instant. But not all instances of an Instant are handled as I expect by spring-cloud-contract. Given the following simple contract:
Contract.make {
description("Get a version")
request {
method 'GET'
url '/config/version'
headers {
contentType(applicationJson())
}
}
response {
status 200
body(
nr: 42,
creationDate: producer(anyIso8601WithOffset())
)
headers {
contentType(applicationJson())
}
}
}
And this service implementation:
@RestController
public class VersionController {
@GetMapping(path = "/version")
public ResponseEntity<Version> getCurrentVersion() {
return ResponseEntity.ok(new Version(42, Instant.ofEpochMilli(0)));
}
}
Executing gradle test works fine. But if I replace the Instant with Instant.now(), my provider test fails with
java.lang.IllegalStateException: Parsed JSON [{"nr":42,"creationDate":"2018-11-11T15:28:26.958284Z"}] doesn't match the JSON path [$[?(@.['creationDate'] =~ /([0-9]{4})-(1[0-2]|0[1-9])-(3[01]|0[1-9]|[12][0-9])T(2[0-3]|[01][0-9]):([0-5][0-9]):([0-5][0-9])(.d{3})?(Z|[+-][01]d:[0-5]d)/)]]
which is understandable because Instant.now() produces an Instant whose string representation does indeed not match the anyIso8601WithOffset() pattern. But why is this? Why are Instants represented differently and how can I describe a contract that validates for any instant?
json testing spring-cloud-contract java.time.instant
edited Nov 12 at 12:54
Ole V.V.
26.4k62651
asked Nov 11 at 15:33
Tobias Neubert
114
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I want to test a contract where one field is of type java.time.Instant. But not all instances of an Instant are handled as I expect by spring-cloud-contract. Given the following simple contract:
Contract.make {
description("Get a version")
request {
method 'GET'
url '/config/version'
headers {
contentType(applicationJson())
}
}
response {
status 200
body(
nr: 42,
creationDate: producer(anyIso8601WithOffset())
)
headers {
contentType(applicationJson())
}
}
}
And this service implementation:
@RestController
public class VersionController {
@GetMapping(path = "/version")
public ResponseEntity<Version> getCurrentVersion() {
return ResponseEntity.ok(new Version(42, Instant.ofEpochMilli(0)));
}
}
Executing gradle test works fine. But if I replace the Instant with Instant.now(), my provider test fails with
java.lang.IllegalStateException: Parsed JSON [{"nr":42,"creationDate":"2018-11-11T15:28:26.958284Z"}] doesn't match the JSON path [$[?(@.['creationDate'] =~ /([0-9]{4})-(1[0-2]|0[1-9])-(3[01]|0[1-9]|[12][0-9])T(2[0-3]|[01][0-9]):([0-5][0-9]):([0-5][0-9])(.d{3})?(Z|[+-][01]d:[0-5]d)/)]]
which is understandable because Instant.now() produces an Instant whose string representation does indeed not match the anyIso8601WithOffset() pattern. But why is this? Why are Instants represented differently and how can I describe a contract that validates for any instant?
json testing spring-cloud-contract java.time.instant
edited Nov 12 at 12:54
Ole V.V.
26.4k62651
asked Nov 11 at 15:33
Tobias Neubert
114
I want to test a contract where one field is of type java.time.Instant. But not all instances of an Instant are handled as I expect by spring-cloud-contract. Given the following simple contract:
Contract.make {
description("Get a version")
request {
method 'GET'
url '/config/version'
headers {
contentType(applicationJson())
}
}
response {
status 200
body(
nr: 42,
creationDate: producer(anyIso8601WithOffset())
)
headers {
contentType(applicationJson())
}
}
}
And this service implementation:
@RestController
public class VersionController {
@GetMapping(path = "/version")
public ResponseEntity<Version> getCurrentVersion() {
return ResponseEntity.ok(new Version(42, Instant.ofEpochMilli(0)));
}
}
Executing gradle test works fine. But if I replace the Instant with Instant.now(), my provider test fails with
java.lang.IllegalStateException: Parsed JSON [{"nr":42,"creationDate":"2018-11-11T15:28:26.958284Z"}] doesn't match the JSON path [$[?(@.['creationDate'] =~ /([0-9]{4})-(1[0-2]|0[1-9])-(3[01]|0[1-9]|[12][0-9])T(2[0-3]|[01][0-9]):([0-5][0-9]):([0-5][0-9])(.d{3})?(Z|[+-][01]d:[0-5]d)/)]]
which is understandable because Instant.now() produces an Instant whose string representation does indeed not match the anyIso8601WithOffset() pattern. But why is this? Why are Instants represented differently and how can I describe a contract that validates for any instant?
json testing spring-cloud-contract java.time.instant
json testing spring-cloud-contract java.time.instant
edited Nov 12 at 12:54
Ole V.V.
26.4k62651
asked Nov 11 at 15:33
Tobias Neubert
114
edited Nov 12 at 12:54
Ole V.V.
26.4k62651
asked Nov 11 at 15:33
Tobias Neubert
114
edited Nov 12 at 12:54
Ole V.V.
26.4k62651
edited Nov 12 at 12:54
Ole V.V.
26.4k62651
edited Nov 12 at 12:54
Ole V.V.
26.4k62651
26.4k62651
asked Nov 11 at 15:33
Tobias Neubert
114
asked Nov 11 at 15:33
Tobias Neubert
114
asked Nov 11 at 15:33
Tobias Neubert
114
114
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
Ok, I found a solution that works for me. Although I do not know if this is the way to go.
In order to always get the exact same format of the serialized instant, I define the format of the corresponding property of my version bean as follows:
public class Version {
private final int nr;
private final Instant creationDate;
@JsonCreator
public Version(
@JsonProperty("nr") int nr,
@JsonProperty("creationDate") Instant creationDate)
{
this.nr = nr;
this.creationDate = creationDate;
}
public int getNr() {
return nr;
}
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX", timezone = "UTC")
public Instant getCreationDate() {
return creationDate;
}
}
answered Nov 11 at 19:46
Tobias Neubert
114
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Ok, I found a solution that works for me. Although I do not know if this is the way to go.
In order to always get the exact same format of the serialized instant, I define the format of the corresponding property of my version bean as follows:
public class Version {
private final int nr;
private final Instant creationDate;
@JsonCreator
public Version(
@JsonProperty("nr") int nr,
@JsonProperty("creationDate") Instant creationDate)
{
this.nr = nr;
this.creationDate = creationDate;
}
public int getNr() {
return nr;
}
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX", timezone = "UTC")
public Instant getCreationDate() {
return creationDate;
}
}
answered Nov 11 at 19:46
Tobias Neubert
114
add a comment |
up vote
1
down vote
accepted
Ok, I found a solution that works for me. Although I do not know if this is the way to go.
In order to always get the exact same format of the serialized instant, I define the format of the corresponding property of my version bean as follows:
public class Version {
private final int nr;
private final Instant creationDate;
@JsonCreator
public Version(
@JsonProperty("nr") int nr,
@JsonProperty("creationDate") Instant creationDate)
{
this.nr = nr;
this.creationDate = creationDate;
}
public int getNr() {
return nr;
}
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX", timezone = "UTC")
public Instant getCreationDate() {
return creationDate;
}
}
answered Nov 11 at 19:46
Tobias Neubert
114
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Ok, I found a solution that works for me. Although I do not know if this is the way to go.
In order to always get the exact same format of the serialized instant, I define the format of the corresponding property of my version bean as follows:
public class Version {
private final int nr;
private final Instant creationDate;
@JsonCreator
public Version(
@JsonProperty("nr") int nr,
@JsonProperty("creationDate") Instant creationDate)
{
this.nr = nr;
this.creationDate = creationDate;
}
public int getNr() {
return nr;
}
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX", timezone = "UTC")
public Instant getCreationDate() {
return creationDate;
}
}
answered Nov 11 at 19:46
Tobias Neubert
114
Ok, I found a solution that works for me. Although I do not know if this is the way to go.
In order to always get the exact same format of the serialized instant, I define the format of the corresponding property of my version bean as follows:
public class Version {
private final int nr;
private final Instant creationDate;
@JsonCreator
public Version(
@JsonProperty("nr") int nr,
@JsonProperty("creationDate") Instant creationDate)
{
this.nr = nr;
this.creationDate = creationDate;
}
public int getNr() {
return nr;
}
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX", timezone = "UTC")
public Instant getCreationDate() {
return creationDate;
}
}
answered Nov 11 at 19:46
Tobias Neubert
114
answered Nov 11 at 19:46
Tobias Neubert
114
answered Nov 11 at 19:46
Tobias Neubert
114
answered Nov 11 at 19:46
Tobias Neubert
114
114
add a comment |
add a comment |
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