why is my code running through my while loop, when the conditions are not met? [duplicate]
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How to test multiple variables against a value?
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When I run this code, even if enter '1' or '2' or '3', my code still runs through the while loop. How do I change my code so that it will only run through the while loop if the user DOESN'T enter '1', '2' or '3'? Thank you very much!
column=input("What column is your card in? Please enter either '1', '2' or '3':")
while column != "1" or "2" or "3":
print("That is an invalid choice. You must enter either '1' or '2' or '3'")
column=input("What column is your card in? Please enter either '1', '2' or '3':")
print(column)
python-3.x loops while-loop
asked Nov 10 at 22:18
Atara Klein
84
marked as duplicate by Martijn Pieters♦ python-3.x
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Nov 10 at 22:25
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
up vote
-1
down vote
favorite
This question already has an answer here:
How to test multiple variables against a value?
18 answers
When I run this code, even if enter '1' or '2' or '3', my code still runs through the while loop. How do I change my code so that it will only run through the while loop if the user DOESN'T enter '1', '2' or '3'? Thank you very much!
column=input("What column is your card in? Please enter either '1', '2' or '3':")
while column != "1" or "2" or "3":
print("That is an invalid choice. You must enter either '1' or '2' or '3'")
column=input("What column is your card in? Please enter either '1', '2' or '3':")
print(column)
python-3.x loops while-loop
asked Nov 10 at 22:18
Atara Klein
84
marked as duplicate by Martijn Pieters♦ python-3.x
Users with the python-3.x badge can single-handedly close python-3.x questions as duplicates and reopen them as needed.
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Nov 10 at 22:25
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
Usecolumn not in {'1', '2', '3'}; computers are not human and English grammar is hard for computers.
– Martijn Pieters♦
Nov 10 at 22:26
The issue is that the condition IS actually true, because it is not what you expect. the "condition != 1" part evaluates, and then gets combined with or "2". Now, booleans accept and work with strings, non empty strings are considered Truthy. Combine this with the following functionality of "or" internally: For ‘or’ operator if left value is true, then it is returned, otherwise if left value is false, then right value is returned. And there you go. Hope that helps. Because of "or" 2, the overall condition will always evaluate to True.
– Paritosh Singh
Nov 10 at 22:32
Thank you so much! My code now works @MartijnPieters
– Atara Klein
Nov 11 at 14:36
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
This question already has an answer here:
How to test multiple variables against a value?
18 answers
When I run this code, even if enter '1' or '2' or '3', my code still runs through the while loop. How do I change my code so that it will only run through the while loop if the user DOESN'T enter '1', '2' or '3'? Thank you very much!
column=input("What column is your card in? Please enter either '1', '2' or '3':")
while column != "1" or "2" or "3":
print("That is an invalid choice. You must enter either '1' or '2' or '3'")
column=input("What column is your card in? Please enter either '1', '2' or '3':")
print(column)
python-3.x loops while-loop
asked Nov 10 at 22:18
Atara Klein
84
This question already has an answer here:
How to test multiple variables against a value?
18 answers
When I run this code, even if enter '1' or '2' or '3', my code still runs through the while loop. How do I change my code so that it will only run through the while loop if the user DOESN'T enter '1', '2' or '3'? Thank you very much!
column=input("What column is your card in? Please enter either '1', '2' or '3':")
while column != "1" or "2" or "3":
print("That is an invalid choice. You must enter either '1' or '2' or '3'")
column=input("What column is your card in? Please enter either '1', '2' or '3':")
print(column)
This question already has an answer here:
How to test multiple variables against a value?
18 answers
python-3.x loops while-loop
python-3.x loops while-loop
asked Nov 10 at 22:18
Atara Klein
84
asked Nov 10 at 22:18
Atara Klein
84
asked Nov 10 at 22:18
Atara Klein
84
asked Nov 10 at 22:18
Atara Klein
84
asked Nov 10 at 22:18
Atara Klein
84
84
marked as duplicate by Martijn Pieters♦ python-3.x
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Nov 10 at 22:25
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Martijn Pieters♦ python-3.x
Users with the python-3.x badge can single-handedly close python-3.x questions as duplicates and reopen them as needed.
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Nov 10 at 22:25
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
Usecolumn not in {'1', '2', '3'}; computers are not human and English grammar is hard for computers.
– Martijn Pieters♦
Nov 10 at 22:26
The issue is that the condition IS actually true, because it is not what you expect. the "condition != 1" part evaluates, and then gets combined with or "2". Now, booleans accept and work with strings, non empty strings are considered Truthy. Combine this with the following functionality of "or" internally: For ‘or’ operator if left value is true, then it is returned, otherwise if left value is false, then right value is returned. And there you go. Hope that helps. Because of "or" 2, the overall condition will always evaluate to True.
– Paritosh Singh
Nov 10 at 22:32
Thank you so much! My code now works @MartijnPieters
– Atara Klein
Nov 11 at 14:36
add a comment |
1
Usecolumn not in {'1', '2', '3'}; computers are not human and English grammar is hard for computers.
– Martijn Pieters♦
Nov 10 at 22:26
The issue is that the condition IS actually true, because it is not what you expect. the "condition != 1" part evaluates, and then gets combined with or "2". Now, booleans accept and work with strings, non empty strings are considered Truthy. Combine this with the following functionality of "or" internally: For ‘or’ operator if left value is true, then it is returned, otherwise if left value is false, then right value is returned. And there you go. Hope that helps. Because of "or" 2, the overall condition will always evaluate to True.
– Paritosh Singh
Nov 10 at 22:32
Thank you so much! My code now works @MartijnPieters
– Atara Klein
Nov 11 at 14:36
1
1
Use
column not in {'1', '2', '3'}; computers are not human and English grammar is hard for computers.– Martijn Pieters♦
Nov 10 at 22:26
Use
column not in {'1', '2', '3'}; computers are not human and English grammar is hard for computers.– Martijn Pieters♦
Nov 10 at 22:26
The issue is that the condition IS actually true, because it is not what you expect. the "condition != 1" part evaluates, and then gets combined with or "2". Now, booleans accept and work with strings, non empty strings are considered Truthy. Combine this with the following functionality of "or" internally: For ‘or’ operator if left value is true, then it is returned, otherwise if left value is false, then right value is returned. And there you go. Hope that helps. Because of "or" 2, the overall condition will always evaluate to True.
– Paritosh Singh
Nov 10 at 22:32
The issue is that the condition IS actually true, because it is not what you expect. the "condition != 1" part evaluates, and then gets combined with or "2". Now, booleans accept and work with strings, non empty strings are considered Truthy. Combine this with the following functionality of "or" internally: For ‘or’ operator if left value is true, then it is returned, otherwise if left value is false, then right value is returned. And there you go. Hope that helps. Because of "or" 2, the overall condition will always evaluate to True.
– Paritosh Singh
Nov 10 at 22:32
Thank you so much! My code now works @MartijnPieters
– Atara Klein
Nov 11 at 14:36
Thank you so much! My code now works @MartijnPieters
– Atara Klein
Nov 11 at 14:36
add a comment |
1 Answer
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Your condition should be for each check
while (column != "1") or (column != "2") or (column != "3"):
Without this check you say that it is non zero and hence True, the condition is satisfied for the while loop. Hence the conditions are met. 2 or 3 is not compared with column.
answered Nov 10 at 22:22
Ashok KS
203214
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Your condition should be for each check
while (column != "1") or (column != "2") or (column != "3"):
Without this check you say that it is non zero and hence True, the condition is satisfied for the while loop. Hence the conditions are met. 2 or 3 is not compared with column.
answered Nov 10 at 22:22
Ashok KS
203214
add a comment |
up vote
0
down vote
accepted
Your condition should be for each check
while (column != "1") or (column != "2") or (column != "3"):
Without this check you say that it is non zero and hence True, the condition is satisfied for the while loop. Hence the conditions are met. 2 or 3 is not compared with column.
answered Nov 10 at 22:22
Ashok KS
203214
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Your condition should be for each check
while (column != "1") or (column != "2") or (column != "3"):
Without this check you say that it is non zero and hence True, the condition is satisfied for the while loop. Hence the conditions are met. 2 or 3 is not compared with column.
answered Nov 10 at 22:22
Ashok KS
203214
Your condition should be for each check
while (column != "1") or (column != "2") or (column != "3"):
Without this check you say that it is non zero and hence True, the condition is satisfied for the while loop. Hence the conditions are met. 2 or 3 is not compared with column.
answered Nov 10 at 22:22
Ashok KS
203214
answered Nov 10 at 22:22
Ashok KS
203214
answered Nov 10 at 22:22
Ashok KS
203214
answered Nov 10 at 22:22
Ashok KS
203214
203214
add a comment |
add a comment |
1
Use
column not in {'1', '2', '3'}; computers are not human and English grammar is hard for computers.– Martijn Pieters♦
Nov 10 at 22:26
The issue is that the condition IS actually true, because it is not what you expect. the "condition != 1" part evaluates, and then gets combined with or "2". Now, booleans accept and work with strings, non empty strings are considered Truthy. Combine this with the following functionality of "or" internally: For ‘or’ operator if left value is true, then it is returned, otherwise if left value is false, then right value is returned. And there you go. Hope that helps. Because of "or" 2, the overall condition will always evaluate to True.
– Paritosh Singh
Nov 10 at 22:32
Thank you so much! My code now works @MartijnPieters
– Atara Klein
Nov 11 at 14:36