Python Separate list to be line by line











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I'm writing a program to do some statistics on some times. I want the output to look like



11: 4
22: 3
33: 1


instead of



11:4, 22:3, 33:1


because I find it hard to read.



Here is the code I have



#Copy solves here, in seconds, seperated by a comma for each solve
times = [11.9, 14.2, 17.3, 11.2 , 123.4]
#Blank list to copy modified solves into
newtimes =
for time in times:
#Rounds down every time
time = int(time)
#Adds time to new list
newtimes.append(time)
#Sorts list lowest to highest
newtimes.sort()
#Gets length of new list, which is amount of solves
solves = len(newtimes)
#Set longest and shortest solve times
longestSolve = max(newtimes)
shortestSolve = min(newtimes)

timesfreq = {i:newtimes.count(i) for i in newtimes}

print(newtimes)
print(timesfreq)
print(solves)
print("Your longest solve was " + str(longestSolve) + " seconds and your shortest solve was " + str(shortestSolve) + " seconds")









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    up vote
    0
    down vote

    favorite












    I'm writing a program to do some statistics on some times. I want the output to look like



    11: 4
    22: 3
    33: 1


    instead of



    11:4, 22:3, 33:1


    because I find it hard to read.



    Here is the code I have



    #Copy solves here, in seconds, seperated by a comma for each solve
    times = [11.9, 14.2, 17.3, 11.2 , 123.4]
    #Blank list to copy modified solves into
    newtimes =
    for time in times:
    #Rounds down every time
    time = int(time)
    #Adds time to new list
    newtimes.append(time)
    #Sorts list lowest to highest
    newtimes.sort()
    #Gets length of new list, which is amount of solves
    solves = len(newtimes)
    #Set longest and shortest solve times
    longestSolve = max(newtimes)
    shortestSolve = min(newtimes)

    timesfreq = {i:newtimes.count(i) for i in newtimes}

    print(newtimes)
    print(timesfreq)
    print(solves)
    print("Your longest solve was " + str(longestSolve) + " seconds and your shortest solve was " + str(shortestSolve) + " seconds")









    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm writing a program to do some statistics on some times. I want the output to look like



      11: 4
      22: 3
      33: 1


      instead of



      11:4, 22:3, 33:1


      because I find it hard to read.



      Here is the code I have



      #Copy solves here, in seconds, seperated by a comma for each solve
      times = [11.9, 14.2, 17.3, 11.2 , 123.4]
      #Blank list to copy modified solves into
      newtimes =
      for time in times:
      #Rounds down every time
      time = int(time)
      #Adds time to new list
      newtimes.append(time)
      #Sorts list lowest to highest
      newtimes.sort()
      #Gets length of new list, which is amount of solves
      solves = len(newtimes)
      #Set longest and shortest solve times
      longestSolve = max(newtimes)
      shortestSolve = min(newtimes)

      timesfreq = {i:newtimes.count(i) for i in newtimes}

      print(newtimes)
      print(timesfreq)
      print(solves)
      print("Your longest solve was " + str(longestSolve) + " seconds and your shortest solve was " + str(shortestSolve) + " seconds")









      share|improve this question













      I'm writing a program to do some statistics on some times. I want the output to look like



      11: 4
      22: 3
      33: 1


      instead of



      11:4, 22:3, 33:1


      because I find it hard to read.



      Here is the code I have



      #Copy solves here, in seconds, seperated by a comma for each solve
      times = [11.9, 14.2, 17.3, 11.2 , 123.4]
      #Blank list to copy modified solves into
      newtimes =
      for time in times:
      #Rounds down every time
      time = int(time)
      #Adds time to new list
      newtimes.append(time)
      #Sorts list lowest to highest
      newtimes.sort()
      #Gets length of new list, which is amount of solves
      solves = len(newtimes)
      #Set longest and shortest solve times
      longestSolve = max(newtimes)
      shortestSolve = min(newtimes)

      timesfreq = {i:newtimes.count(i) for i in newtimes}

      print(newtimes)
      print(timesfreq)
      print(solves)
      print("Your longest solve was " + str(longestSolve) + " seconds and your shortest solve was " + str(shortestSolve) + " seconds")






      python python-3.x list






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 10 at 22:25









      Joel Banks

      395




      395
























          2 Answers
          2






          active

          oldest

          votes

















          up vote
          0
          down vote



          accepted










          just go like this:



          for i in timesfreq.items():
          print(i)


          This gives



          (11, 2)
          (14, 1)
          (17, 1)
          (123, 1)


          If you want it exactly as you stated:



          for a,b in timesfreq.items():
          print("{}: {}".format(a,b))





          share|improve this answer

















          • 1




            Perfect solution! I'm still a beginner so sorry if this was an easy question, but this is exactly what I wanted!
            – Joel Banks
            Nov 10 at 22:51


















          up vote
          0
          down vote













          One way you can do this as a one-liner:



          >>> print('n'.join([str(key) + ': ' + str(val) for key, val in timesfreq.items()]))
          123: 1
          17: 1
          11: 2
          14: 1


          Here's a good reference for iterating over key/value pairs in a dictionary: Iterating over dictionaries using 'for' loops






          share|improve this answer





















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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            0
            down vote



            accepted










            just go like this:



            for i in timesfreq.items():
            print(i)


            This gives



            (11, 2)
            (14, 1)
            (17, 1)
            (123, 1)


            If you want it exactly as you stated:



            for a,b in timesfreq.items():
            print("{}: {}".format(a,b))





            share|improve this answer

















            • 1




              Perfect solution! I'm still a beginner so sorry if this was an easy question, but this is exactly what I wanted!
              – Joel Banks
              Nov 10 at 22:51















            up vote
            0
            down vote



            accepted










            just go like this:



            for i in timesfreq.items():
            print(i)


            This gives



            (11, 2)
            (14, 1)
            (17, 1)
            (123, 1)


            If you want it exactly as you stated:



            for a,b in timesfreq.items():
            print("{}: {}".format(a,b))





            share|improve this answer

















            • 1




              Perfect solution! I'm still a beginner so sorry if this was an easy question, but this is exactly what I wanted!
              – Joel Banks
              Nov 10 at 22:51













            up vote
            0
            down vote



            accepted







            up vote
            0
            down vote



            accepted






            just go like this:



            for i in timesfreq.items():
            print(i)


            This gives



            (11, 2)
            (14, 1)
            (17, 1)
            (123, 1)


            If you want it exactly as you stated:



            for a,b in timesfreq.items():
            print("{}: {}".format(a,b))





            share|improve this answer












            just go like this:



            for i in timesfreq.items():
            print(i)


            This gives



            (11, 2)
            (14, 1)
            (17, 1)
            (123, 1)


            If you want it exactly as you stated:



            for a,b in timesfreq.items():
            print("{}: {}".format(a,b))






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 10 at 22:39









            Christian Sloper

            1,024213




            1,024213








            • 1




              Perfect solution! I'm still a beginner so sorry if this was an easy question, but this is exactly what I wanted!
              – Joel Banks
              Nov 10 at 22:51














            • 1




              Perfect solution! I'm still a beginner so sorry if this was an easy question, but this is exactly what I wanted!
              – Joel Banks
              Nov 10 at 22:51








            1




            1




            Perfect solution! I'm still a beginner so sorry if this was an easy question, but this is exactly what I wanted!
            – Joel Banks
            Nov 10 at 22:51




            Perfect solution! I'm still a beginner so sorry if this was an easy question, but this is exactly what I wanted!
            – Joel Banks
            Nov 10 at 22:51












            up vote
            0
            down vote













            One way you can do this as a one-liner:



            >>> print('n'.join([str(key) + ': ' + str(val) for key, val in timesfreq.items()]))
            123: 1
            17: 1
            11: 2
            14: 1


            Here's a good reference for iterating over key/value pairs in a dictionary: Iterating over dictionaries using 'for' loops






            share|improve this answer

























              up vote
              0
              down vote













              One way you can do this as a one-liner:



              >>> print('n'.join([str(key) + ': ' + str(val) for key, val in timesfreq.items()]))
              123: 1
              17: 1
              11: 2
              14: 1


              Here's a good reference for iterating over key/value pairs in a dictionary: Iterating over dictionaries using 'for' loops






              share|improve this answer























                up vote
                0
                down vote










                up vote
                0
                down vote









                One way you can do this as a one-liner:



                >>> print('n'.join([str(key) + ': ' + str(val) for key, val in timesfreq.items()]))
                123: 1
                17: 1
                11: 2
                14: 1


                Here's a good reference for iterating over key/value pairs in a dictionary: Iterating over dictionaries using 'for' loops






                share|improve this answer












                One way you can do this as a one-liner:



                >>> print('n'.join([str(key) + ': ' + str(val) for key, val in timesfreq.items()]))
                123: 1
                17: 1
                11: 2
                14: 1


                Here's a good reference for iterating over key/value pairs in a dictionary: Iterating over dictionaries using 'for' loops







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 10 at 22:40









                Mixolydian

                613




                613






























                     

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