JQuery Datepicker is not working when appending new row - JQuery UI
0
I have a datepicker in a table. the <tr> appends when button clicked.
It's work fine when populate 1st <tr> but when 2nd <tr> created on button click, datepicker is not working.
Check My Fiddle
jquery jquery-ui jquery-ui-datepicker
asked Nov 15 '18 at 12:13
HuzaifaHuzaifa
347
add a comment |
0
I have a datepicker in a table. the <tr> appends when button clicked.
It's work fine when populate 1st <tr> but when 2nd <tr> created on button click, datepicker is not working.
Check My Fiddle
jquery jquery-ui jquery-ui-datepicker
asked Nov 15 '18 at 12:13
HuzaifaHuzaifa
347
add a comment |
0
0
0
I have a datepicker in a table. the <tr> appends when button clicked.
It's work fine when populate 1st <tr> but when 2nd <tr> created on button click, datepicker is not working.
Check My Fiddle
jquery jquery-ui jquery-ui-datepicker
asked Nov 15 '18 at 12:13
HuzaifaHuzaifa
347
I have a datepicker in a table. the <tr> appends when button clicked.
It's work fine when populate 1st <tr> but when 2nd <tr> created on button click, datepicker is not working.
Check My Fiddle
jquery jquery-ui jquery-ui-datepicker
jquery jquery-ui jquery-ui-datepicker
asked Nov 15 '18 at 12:13
HuzaifaHuzaifa
347
asked Nov 15 '18 at 12:13
HuzaifaHuzaifa
347
asked Nov 15 '18 at 12:13
HuzaifaHuzaifa
347
asked Nov 15 '18 at 12:13
HuzaifaHuzaifa
347
asked Nov 15 '18 at 12:13
HuzaifaHuzaifa
347
347
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
2
This code should do the trick. You need to remove the id from the date input. Since, datepicker uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function () {
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker({
autoclose: true
});
counter++;
});
Hope it works.
answered Nov 15 '18 at 12:22
Alain CruzAlain Cruz
2,0983918
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
This code should do the trick. You need to remove the id from the date input. Since, datepicker uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function () {
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker({
autoclose: true
});
counter++;
});
Hope it works.
answered Nov 15 '18 at 12:22
Alain CruzAlain Cruz
2,0983918
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
2
This code should do the trick. You need to remove the id from the date input. Since, datepicker uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function () {
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker({
autoclose: true
});
counter++;
});
Hope it works.
answered Nov 15 '18 at 12:22
Alain CruzAlain Cruz
2,0983918
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
2
2
2
This code should do the trick. You need to remove the id from the date input. Since, datepicker uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function () {
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker({
autoclose: true
});
counter++;
});
Hope it works.
answered Nov 15 '18 at 12:22
Alain CruzAlain Cruz
2,0983918
This code should do the trick. You need to remove the id from the date input. Since, datepicker uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function () {
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker({
autoclose: true
});
counter++;
});
Hope it works.
answered Nov 15 '18 at 12:22
Alain CruzAlain Cruz
2,0983918
edited Nov 15 '18 at 12:33
answered Nov 15 '18 at 12:22
Alain CruzAlain Cruz
2,0983918
answered Nov 15 '18 at 12:22
Alain CruzAlain Cruz
2,0983918
answered Nov 15 '18 at 12:22
Alain CruzAlain Cruz
2,0983918
2,0983918
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
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