Filtering a Material Table with numbers ranges [Angular 7]
I am using Material Table on my Angular 7 project.
I have a table that displays several objects.
Each object has a property 'number of promotions' and i would like to filter this table using numbers ranges (under 5, from 6 to 10, from 11 to 20, more than 20).
Here is an example of the dataSource.filterPredicate I used to have custom filters on my table but i don't get how to manage the one i explained earlier...
this.dataSource.filterPredicate = (data: Store, filter: string) => {
switch (this.filterCriteria) {
case 'approval':
if (filter === 'null' || filter === '') {
return (data);
} else {
return (data.approval.trim().toLowerCase().indexOf(filter) !== -1
);
}
add a comment |
I am using Material Table on my Angular 7 project.
I have a table that displays several objects.
Each object has a property 'number of promotions' and i would like to filter this table using numbers ranges (under 5, from 6 to 10, from 11 to 20, more than 20).
Here is an example of the dataSource.filterPredicate I used to have custom filters on my table but i don't get how to manage the one i explained earlier...
this.dataSource.filterPredicate = (data: Store, filter: string) => {
switch (this.filterCriteria) {
case 'approval':
if (filter === 'null' || filter === '') {
return (data);
} else {
return (data.approval.trim().toLowerCase().indexOf(filter) !== -1
);
}
1
you can add your original datasource and expected output, it will be easy for us to understand
– Just code
Nov 15 '18 at 13:00
add a comment |
I am using Material Table on my Angular 7 project.
I have a table that displays several objects.
Each object has a property 'number of promotions' and i would like to filter this table using numbers ranges (under 5, from 6 to 10, from 11 to 20, more than 20).
Here is an example of the dataSource.filterPredicate I used to have custom filters on my table but i don't get how to manage the one i explained earlier...
this.dataSource.filterPredicate = (data: Store, filter: string) => {
switch (this.filterCriteria) {
case 'approval':
if (filter === 'null' || filter === '') {
return (data);
} else {
return (data.approval.trim().toLowerCase().indexOf(filter) !== -1
);
}
I am using Material Table on my Angular 7 project.
I have a table that displays several objects.
Each object has a property 'number of promotions' and i would like to filter this table using numbers ranges (under 5, from 6 to 10, from 11 to 20, more than 20).
Here is an example of the dataSource.filterPredicate I used to have custom filters on my table but i don't get how to manage the one i explained earlier...
this.dataSource.filterPredicate = (data: Store, filter: string) => {
switch (this.filterCriteria) {
case 'approval':
if (filter === 'null' || filter === '') {
return (data);
} else {
return (data.approval.trim().toLowerCase().indexOf(filter) !== -1
);
}
edited Nov 24 '18 at 15:22
Goncalo Peres
1,4791619
1,4791619
asked Nov 15 '18 at 12:15
A. GuyotA. Guyot
168
168
1
you can add your original datasource and expected output, it will be easy for us to understand
– Just code
Nov 15 '18 at 13:00
add a comment |
1
you can add your original datasource and expected output, it will be easy for us to understand
– Just code
Nov 15 '18 at 13:00
1
1
you can add your original datasource and expected output, it will be easy for us to understand
– Just code
Nov 15 '18 at 13:00
you can add your original datasource and expected output, it will be easy for us to understand
– Just code
Nov 15 '18 at 13:00
add a comment |
1 Answer
1
active
oldest
votes
I did manage to solve my problem, and i was very very very simple. -_-'
I just had a case to my switch with the correct filter on my dataSource.filterPredicate.
case 'promotion':
if (filter === 'null' || filter === '') {
return (data);
} else {
switch(filter){
case '5':
return (data.total_promotions <= 5);
case '10':
return (data.total_promotions > 5 && data.total_promotions <= 10);
}
}
}
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I did manage to solve my problem, and i was very very very simple. -_-'
I just had a case to my switch with the correct filter on my dataSource.filterPredicate.
case 'promotion':
if (filter === 'null' || filter === '') {
return (data);
} else {
switch(filter){
case '5':
return (data.total_promotions <= 5);
case '10':
return (data.total_promotions > 5 && data.total_promotions <= 10);
}
}
}
add a comment |
I did manage to solve my problem, and i was very very very simple. -_-'
I just had a case to my switch with the correct filter on my dataSource.filterPredicate.
case 'promotion':
if (filter === 'null' || filter === '') {
return (data);
} else {
switch(filter){
case '5':
return (data.total_promotions <= 5);
case '10':
return (data.total_promotions > 5 && data.total_promotions <= 10);
}
}
}
add a comment |
I did manage to solve my problem, and i was very very very simple. -_-'
I just had a case to my switch with the correct filter on my dataSource.filterPredicate.
case 'promotion':
if (filter === 'null' || filter === '') {
return (data);
} else {
switch(filter){
case '5':
return (data.total_promotions <= 5);
case '10':
return (data.total_promotions > 5 && data.total_promotions <= 10);
}
}
}
I did manage to solve my problem, and i was very very very simple. -_-'
I just had a case to my switch with the correct filter on my dataSource.filterPredicate.
case 'promotion':
if (filter === 'null' || filter === '') {
return (data);
} else {
switch(filter){
case '5':
return (data.total_promotions <= 5);
case '10':
return (data.total_promotions > 5 && data.total_promotions <= 10);
}
}
}
answered Nov 15 '18 at 13:03
A. GuyotA. Guyot
168
168
add a comment |
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1
you can add your original datasource and expected output, it will be easy for us to understand
– Just code
Nov 15 '18 at 13:00