Python sorting html table












0















I am looping through a list of servers and connecting with OpenSSL, to retrieve the SSL cert, and grabbing the server name, the date the cert expires, and calculating the number of days until cert expires. I am then building an html table with the data. The columns are Host, Hostname, Expiration Date, and Remaining Days. What is the best way to sort the table by the "Remaining Days" column?



# Update the hosts entry
ssl_results[str(ip)][0] = host
ssl_results[str(ip)][1] = server_name
ssl_results[str(ip)][2] = exp_date
ssl_results[str(ip)][3] = days_to_expire

# Loop through the ssl_results entries and generate a email + results file
try:

# variable to hold html for email
SSLCertificates = """<html>
<head>
<style>
table{width: 1024px;}

table, th, td {
border: 1px solid black;
border-collapse: collapse;
}

th, td {
padding: 5px;
text-align: left;
}

ul:before{
content:attr(data-header);
font-size:120%;
font-weight:bold;
margin-left:-15px;
}
</style>
</head>
<body>
<p><h2>Blah, </h2>
<h3>SSL Expiration Summary:</h3>
<span style="color:red;"><b>Blah Blah Blah.<b></span><br><br>
<table id="exp_ssls"><tr><th>Host</th><th>Hostname</th><th>Expiration Date</th><th>Remaining Days</th></tr>
"""

for entries in ssl_results:
SSLCertificates += "<tr><td>" + str(entries) + "</td><td>" + str(ssl_results[entries][1]) + "</td><td>" + str(
ssl_results[entries][2]) + "</td><td>" + str(ssl_results[entries][3]) + "</td></tr>"

SSLCertificates += """</body>
</html>"""

f = open('SSLCertificates.html', 'w')
f.write(SSLCertificates)
f.close()
filename = 'SSLCertificates.html'
attachment = open(filename, 'rb')









share|improve this question




















  • 1





    Put everything into a multi-dimensional list, then sort, then put it into the html table

    – SPYBUG96
    Nov 14 '18 at 19:52
















0















I am looping through a list of servers and connecting with OpenSSL, to retrieve the SSL cert, and grabbing the server name, the date the cert expires, and calculating the number of days until cert expires. I am then building an html table with the data. The columns are Host, Hostname, Expiration Date, and Remaining Days. What is the best way to sort the table by the "Remaining Days" column?



# Update the hosts entry
ssl_results[str(ip)][0] = host
ssl_results[str(ip)][1] = server_name
ssl_results[str(ip)][2] = exp_date
ssl_results[str(ip)][3] = days_to_expire

# Loop through the ssl_results entries and generate a email + results file
try:

# variable to hold html for email
SSLCertificates = """<html>
<head>
<style>
table{width: 1024px;}

table, th, td {
border: 1px solid black;
border-collapse: collapse;
}

th, td {
padding: 5px;
text-align: left;
}

ul:before{
content:attr(data-header);
font-size:120%;
font-weight:bold;
margin-left:-15px;
}
</style>
</head>
<body>
<p><h2>Blah, </h2>
<h3>SSL Expiration Summary:</h3>
<span style="color:red;"><b>Blah Blah Blah.<b></span><br><br>
<table id="exp_ssls"><tr><th>Host</th><th>Hostname</th><th>Expiration Date</th><th>Remaining Days</th></tr>
"""

for entries in ssl_results:
SSLCertificates += "<tr><td>" + str(entries) + "</td><td>" + str(ssl_results[entries][1]) + "</td><td>" + str(
ssl_results[entries][2]) + "</td><td>" + str(ssl_results[entries][3]) + "</td></tr>"

SSLCertificates += """</body>
</html>"""

f = open('SSLCertificates.html', 'w')
f.write(SSLCertificates)
f.close()
filename = 'SSLCertificates.html'
attachment = open(filename, 'rb')









share|improve this question




















  • 1





    Put everything into a multi-dimensional list, then sort, then put it into the html table

    – SPYBUG96
    Nov 14 '18 at 19:52














0












0








0








I am looping through a list of servers and connecting with OpenSSL, to retrieve the SSL cert, and grabbing the server name, the date the cert expires, and calculating the number of days until cert expires. I am then building an html table with the data. The columns are Host, Hostname, Expiration Date, and Remaining Days. What is the best way to sort the table by the "Remaining Days" column?



# Update the hosts entry
ssl_results[str(ip)][0] = host
ssl_results[str(ip)][1] = server_name
ssl_results[str(ip)][2] = exp_date
ssl_results[str(ip)][3] = days_to_expire

# Loop through the ssl_results entries and generate a email + results file
try:

# variable to hold html for email
SSLCertificates = """<html>
<head>
<style>
table{width: 1024px;}

table, th, td {
border: 1px solid black;
border-collapse: collapse;
}

th, td {
padding: 5px;
text-align: left;
}

ul:before{
content:attr(data-header);
font-size:120%;
font-weight:bold;
margin-left:-15px;
}
</style>
</head>
<body>
<p><h2>Blah, </h2>
<h3>SSL Expiration Summary:</h3>
<span style="color:red;"><b>Blah Blah Blah.<b></span><br><br>
<table id="exp_ssls"><tr><th>Host</th><th>Hostname</th><th>Expiration Date</th><th>Remaining Days</th></tr>
"""

for entries in ssl_results:
SSLCertificates += "<tr><td>" + str(entries) + "</td><td>" + str(ssl_results[entries][1]) + "</td><td>" + str(
ssl_results[entries][2]) + "</td><td>" + str(ssl_results[entries][3]) + "</td></tr>"

SSLCertificates += """</body>
</html>"""

f = open('SSLCertificates.html', 'w')
f.write(SSLCertificates)
f.close()
filename = 'SSLCertificates.html'
attachment = open(filename, 'rb')









share|improve this question
















I am looping through a list of servers and connecting with OpenSSL, to retrieve the SSL cert, and grabbing the server name, the date the cert expires, and calculating the number of days until cert expires. I am then building an html table with the data. The columns are Host, Hostname, Expiration Date, and Remaining Days. What is the best way to sort the table by the "Remaining Days" column?



# Update the hosts entry
ssl_results[str(ip)][0] = host
ssl_results[str(ip)][1] = server_name
ssl_results[str(ip)][2] = exp_date
ssl_results[str(ip)][3] = days_to_expire

# Loop through the ssl_results entries and generate a email + results file
try:

# variable to hold html for email
SSLCertificates = """<html>
<head>
<style>
table{width: 1024px;}

table, th, td {
border: 1px solid black;
border-collapse: collapse;
}

th, td {
padding: 5px;
text-align: left;
}

ul:before{
content:attr(data-header);
font-size:120%;
font-weight:bold;
margin-left:-15px;
}
</style>
</head>
<body>
<p><h2>Blah, </h2>
<h3>SSL Expiration Summary:</h3>
<span style="color:red;"><b>Blah Blah Blah.<b></span><br><br>
<table id="exp_ssls"><tr><th>Host</th><th>Hostname</th><th>Expiration Date</th><th>Remaining Days</th></tr>
"""

for entries in ssl_results:
SSLCertificates += "<tr><td>" + str(entries) + "</td><td>" + str(ssl_results[entries][1]) + "</td><td>" + str(
ssl_results[entries][2]) + "</td><td>" + str(ssl_results[entries][3]) + "</td></tr>"

SSLCertificates += """</body>
</html>"""

f = open('SSLCertificates.html', 'w')
f.write(SSLCertificates)
f.close()
filename = 'SSLCertificates.html'
attachment = open(filename, 'rb')






python sorting html-table






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 13:38









Brian Tompsett - 汤莱恩

4,2231338101




4,2231338101










asked Nov 14 '18 at 19:48









Kevin RobersonKevin Roberson

272




272








  • 1





    Put everything into a multi-dimensional list, then sort, then put it into the html table

    – SPYBUG96
    Nov 14 '18 at 19:52














  • 1





    Put everything into a multi-dimensional list, then sort, then put it into the html table

    – SPYBUG96
    Nov 14 '18 at 19:52








1




1





Put everything into a multi-dimensional list, then sort, then put it into the html table

– SPYBUG96
Nov 14 '18 at 19:52





Put everything into a multi-dimensional list, then sort, then put it into the html table

– SPYBUG96
Nov 14 '18 at 19:52












1 Answer
1






active

oldest

votes


















0














Sort the dict before you form the html tags. then Iterate thru the dict and print it using html tags. Use sorted() to sort your dict before you iterate thru it.



import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


sorted_x will be a list of tuples sorted by the second element in each tuple. dict(sorted_x) == x.






share|improve this answer
























  • Thanks Sekar. That worked. The code I used: sorted_results = sorted(ssl_results.items(), key=lambda k: k[1]['days_to_expire'], reverse=False)

    – Kevin Roberson
    Nov 16 '18 at 19:35













  • Thanks for letting us know the results:)

    – Sekar Ramu
    Nov 16 '18 at 19:39











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53307754%2fpython-sorting-html-table%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Sort the dict before you form the html tags. then Iterate thru the dict and print it using html tags. Use sorted() to sort your dict before you iterate thru it.



import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


sorted_x will be a list of tuples sorted by the second element in each tuple. dict(sorted_x) == x.






share|improve this answer
























  • Thanks Sekar. That worked. The code I used: sorted_results = sorted(ssl_results.items(), key=lambda k: k[1]['days_to_expire'], reverse=False)

    – Kevin Roberson
    Nov 16 '18 at 19:35













  • Thanks for letting us know the results:)

    – Sekar Ramu
    Nov 16 '18 at 19:39
















0














Sort the dict before you form the html tags. then Iterate thru the dict and print it using html tags. Use sorted() to sort your dict before you iterate thru it.



import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


sorted_x will be a list of tuples sorted by the second element in each tuple. dict(sorted_x) == x.






share|improve this answer
























  • Thanks Sekar. That worked. The code I used: sorted_results = sorted(ssl_results.items(), key=lambda k: k[1]['days_to_expire'], reverse=False)

    – Kevin Roberson
    Nov 16 '18 at 19:35













  • Thanks for letting us know the results:)

    – Sekar Ramu
    Nov 16 '18 at 19:39














0












0








0







Sort the dict before you form the html tags. then Iterate thru the dict and print it using html tags. Use sorted() to sort your dict before you iterate thru it.



import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


sorted_x will be a list of tuples sorted by the second element in each tuple. dict(sorted_x) == x.






share|improve this answer













Sort the dict before you form the html tags. then Iterate thru the dict and print it using html tags. Use sorted() to sort your dict before you iterate thru it.



import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


sorted_x will be a list of tuples sorted by the second element in each tuple. dict(sorted_x) == x.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 13:51









Sekar RamuSekar Ramu

164110




164110













  • Thanks Sekar. That worked. The code I used: sorted_results = sorted(ssl_results.items(), key=lambda k: k[1]['days_to_expire'], reverse=False)

    – Kevin Roberson
    Nov 16 '18 at 19:35













  • Thanks for letting us know the results:)

    – Sekar Ramu
    Nov 16 '18 at 19:39



















  • Thanks Sekar. That worked. The code I used: sorted_results = sorted(ssl_results.items(), key=lambda k: k[1]['days_to_expire'], reverse=False)

    – Kevin Roberson
    Nov 16 '18 at 19:35













  • Thanks for letting us know the results:)

    – Sekar Ramu
    Nov 16 '18 at 19:39

















Thanks Sekar. That worked. The code I used: sorted_results = sorted(ssl_results.items(), key=lambda k: k[1]['days_to_expire'], reverse=False)

– Kevin Roberson
Nov 16 '18 at 19:35







Thanks Sekar. That worked. The code I used: sorted_results = sorted(ssl_results.items(), key=lambda k: k[1]['days_to_expire'], reverse=False)

– Kevin Roberson
Nov 16 '18 at 19:35















Thanks for letting us know the results:)

– Sekar Ramu
Nov 16 '18 at 19:39





Thanks for letting us know the results:)

– Sekar Ramu
Nov 16 '18 at 19:39




















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53307754%2fpython-sorting-html-table%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

The Sandy Post

Danny Elfman

Pages that link to "Head v. Amoskeag Manufacturing Co."