Displaying asterisks vs. displaying characters with a function
I wrote a function (asterisksDisplay) that displays a solid rectangle of asterisks whose sides are specified in the integer parameters as row and column, which are taken from the user. The program below works perfectly.
#include <stdio.h>
void asterisksDisplay (int row, int column);
int main (void)
{
int a=0;
int b=0;
printf("Please enter sides of your shape: ");
scanf("%d%d", &a, &b);
printf("nYour shape is: n");
asterisksDisplay(a, b);
}
void asterisksDisplay (int row, int column)
{
for (int i = 1; i <= row; i++) {
for (int p = 1; p <= column; p++) {
printf("*");
}
printf("n");
}
}
When I try to modify this function of asterisks to a function of a user given character display, somehow compiler skips displaying the character.
#include <stdio.h>
void asterisksDisplay (int row, int column, char character);
int main (void)
{
int a=0;
int b=0;
char c;
printf("Please enter sides of your shape: ");
scanf("%d%d", &a, &b);
printf("nplease enter the character to be filled: ");
scanf("%s", &c);
printf("n");
asterisksDisplay(a, b, c);
}
void asterisksDisplay (int row, int column, char character)
{
for (int i = 1; i <= row; i++) {
for (int p = 1; p <= column; p++) {
printf("%c", character);
}
printf("n");
}
}
what is the solution for fixing this?
c scanf
edited Nov 13 '18 at 14:26
Sourav Ghosh
109k14130188
asked Nov 13 '18 at 14:15
BelverusBelverus
22027
add a comment |
I wrote a function (asterisksDisplay) that displays a solid rectangle of asterisks whose sides are specified in the integer parameters as row and column, which are taken from the user. The program below works perfectly.
#include <stdio.h>
void asterisksDisplay (int row, int column);
int main (void)
{
int a=0;
int b=0;
printf("Please enter sides of your shape: ");
scanf("%d%d", &a, &b);
printf("nYour shape is: n");
asterisksDisplay(a, b);
}
void asterisksDisplay (int row, int column)
{
for (int i = 1; i <= row; i++) {
for (int p = 1; p <= column; p++) {
printf("*");
}
printf("n");
}
}
When I try to modify this function of asterisks to a function of a user given character display, somehow compiler skips displaying the character.
#include <stdio.h>
void asterisksDisplay (int row, int column, char character);
int main (void)
{
int a=0;
int b=0;
char c;
printf("Please enter sides of your shape: ");
scanf("%d%d", &a, &b);
printf("nplease enter the character to be filled: ");
scanf("%s", &c);
printf("n");
asterisksDisplay(a, b, c);
}
void asterisksDisplay (int row, int column, char character)
{
for (int i = 1; i <= row; i++) {
for (int p = 1; p <= column; p++) {
printf("%c", character);
}
printf("n");
}
}
what is the solution for fixing this?
c scanf
edited Nov 13 '18 at 14:26
Sourav Ghosh
109k14130188
asked Nov 13 '18 at 14:15
BelverusBelverus
22027
add a comment |
I wrote a function (asterisksDisplay) that displays a solid rectangle of asterisks whose sides are specified in the integer parameters as row and column, which are taken from the user. The program below works perfectly.
#include <stdio.h>
void asterisksDisplay (int row, int column);
int main (void)
{
int a=0;
int b=0;
printf("Please enter sides of your shape: ");
scanf("%d%d", &a, &b);
printf("nYour shape is: n");
asterisksDisplay(a, b);
}
void asterisksDisplay (int row, int column)
{
for (int i = 1; i <= row; i++) {
for (int p = 1; p <= column; p++) {
printf("*");
}
printf("n");
}
}
When I try to modify this function of asterisks to a function of a user given character display, somehow compiler skips displaying the character.
#include <stdio.h>
void asterisksDisplay (int row, int column, char character);
int main (void)
{
int a=0;
int b=0;
char c;
printf("Please enter sides of your shape: ");
scanf("%d%d", &a, &b);
printf("nplease enter the character to be filled: ");
scanf("%s", &c);
printf("n");
asterisksDisplay(a, b, c);
}
void asterisksDisplay (int row, int column, char character)
{
for (int i = 1; i <= row; i++) {
for (int p = 1; p <= column; p++) {
printf("%c", character);
}
printf("n");
}
}
what is the solution for fixing this?
c scanf
edited Nov 13 '18 at 14:26
Sourav Ghosh
109k14130188
asked Nov 13 '18 at 14:15
BelverusBelverus
22027
I wrote a function (asterisksDisplay) that displays a solid rectangle of asterisks whose sides are specified in the integer parameters as row and column, which are taken from the user. The program below works perfectly.
#include <stdio.h>
void asterisksDisplay (int row, int column);
int main (void)
{
int a=0;
int b=0;
printf("Please enter sides of your shape: ");
scanf("%d%d", &a, &b);
printf("nYour shape is: n");
asterisksDisplay(a, b);
}
void asterisksDisplay (int row, int column)
{
for (int i = 1; i <= row; i++) {
for (int p = 1; p <= column; p++) {
printf("*");
}
printf("n");
}
}
When I try to modify this function of asterisks to a function of a user given character display, somehow compiler skips displaying the character.
#include <stdio.h>
void asterisksDisplay (int row, int column, char character);
int main (void)
{
int a=0;
int b=0;
char c;
printf("Please enter sides of your shape: ");
scanf("%d%d", &a, &b);
printf("nplease enter the character to be filled: ");
scanf("%s", &c);
printf("n");
asterisksDisplay(a, b, c);
}
void asterisksDisplay (int row, int column, char character)
{
for (int i = 1; i <= row; i++) {
for (int p = 1; p <= column; p++) {
printf("%c", character);
}
printf("n");
}
}
what is the solution for fixing this?
c scanf
c scanf
edited Nov 13 '18 at 14:26
Sourav Ghosh
109k14130188
asked Nov 13 '18 at 14:15
BelverusBelverus
22027
edited Nov 13 '18 at 14:26
Sourav Ghosh
109k14130188
asked Nov 13 '18 at 14:15
BelverusBelverus
22027
edited Nov 13 '18 at 14:26
Sourav Ghosh
109k14130188
edited Nov 13 '18 at 14:26
Sourav Ghosh
109k14130188
edited Nov 13 '18 at 14:26
Sourav Ghosh
109k14130188
109k14130188
asked Nov 13 '18 at 14:15
BelverusBelverus
22027
asked Nov 13 '18 at 14:15
BelverusBelverus
22027
asked Nov 13 '18 at 14:15
BelverusBelverus
22027
22027
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Change
scanf("%s", &c);
to
scanf(" %c", &c);
^^-----------------------(i)
^^------------------------- (ii)
Change of the conversion specifier from
%sto%c, as (i): becausecis achartype.We need to escape the previously entered newline, so the extra whitespace before the conversion specifier, which matches and discards any leading whitespace input present in the buffer.
answered Nov 13 '18 at 14:17
Sourav GhoshSourav Ghosh
109k14130188
I've tried it but unfortunately, this is not the solution. Also, Xcode insists that I should change the %c to %s on scanf. I will try the code on visual studio and post the result.
– Belverus
Nov 13 '18 at 17:27
@Belverus any updates?
– Sourav Ghosh
Nov 14 '18 at 4:40
I tried the code with Visual Studio. If I change the %s with %c as you suggested, It still skips the output. Program gets 2 integers as size of our shape, and displays "Please enter character" and exits the program. If I keep %s it gives an error: Not enough arguments passed for format string.
– Belverus
Nov 15 '18 at 8:20
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Change
scanf("%s", &c);
to
scanf(" %c", &c);
^^-----------------------(i)
^^------------------------- (ii)
Change of the conversion specifier from
%sto%c, as (i): becausecis achartype.We need to escape the previously entered newline, so the extra whitespace before the conversion specifier, which matches and discards any leading whitespace input present in the buffer.
answered Nov 13 '18 at 14:17
Sourav GhoshSourav Ghosh
109k14130188
I've tried it but unfortunately, this is not the solution. Also, Xcode insists that I should change the %c to %s on scanf. I will try the code on visual studio and post the result.
– Belverus
Nov 13 '18 at 17:27
@Belverus any updates?
– Sourav Ghosh
Nov 14 '18 at 4:40
I tried the code with Visual Studio. If I change the %s with %c as you suggested, It still skips the output. Program gets 2 integers as size of our shape, and displays "Please enter character" and exits the program. If I keep %s it gives an error: Not enough arguments passed for format string.
– Belverus
Nov 15 '18 at 8:20
add a comment |
Change
scanf("%s", &c);
to
scanf(" %c", &c);
^^-----------------------(i)
^^------------------------- (ii)
Change of the conversion specifier from
%sto%c, as (i): becausecis achartype.We need to escape the previously entered newline, so the extra whitespace before the conversion specifier, which matches and discards any leading whitespace input present in the buffer.
answered Nov 13 '18 at 14:17
Sourav GhoshSourav Ghosh
109k14130188
I've tried it but unfortunately, this is not the solution. Also, Xcode insists that I should change the %c to %s on scanf. I will try the code on visual studio and post the result.
– Belverus
Nov 13 '18 at 17:27
@Belverus any updates?
– Sourav Ghosh
Nov 14 '18 at 4:40
I tried the code with Visual Studio. If I change the %s with %c as you suggested, It still skips the output. Program gets 2 integers as size of our shape, and displays "Please enter character" and exits the program. If I keep %s it gives an error: Not enough arguments passed for format string.
– Belverus
Nov 15 '18 at 8:20
add a comment |
Change
scanf("%s", &c);
to
scanf(" %c", &c);
^^-----------------------(i)
^^------------------------- (ii)
Change of the conversion specifier from
%sto%c, as (i): becausecis achartype.We need to escape the previously entered newline, so the extra whitespace before the conversion specifier, which matches and discards any leading whitespace input present in the buffer.
answered Nov 13 '18 at 14:17
Sourav GhoshSourav Ghosh
109k14130188
Change
scanf("%s", &c);
to
scanf(" %c", &c);
^^-----------------------(i)
^^------------------------- (ii)
Change of the conversion specifier from
%sto%c, as (i): becausecis achartype.We need to escape the previously entered newline, so the extra whitespace before the conversion specifier, which matches and discards any leading whitespace input present in the buffer.
answered Nov 13 '18 at 14:17
Sourav GhoshSourav Ghosh
109k14130188
answered Nov 13 '18 at 14:17
Sourav GhoshSourav Ghosh
109k14130188
answered Nov 13 '18 at 14:17
Sourav GhoshSourav Ghosh
109k14130188
answered Nov 13 '18 at 14:17
Sourav GhoshSourav Ghosh
109k14130188
109k14130188
I've tried it but unfortunately, this is not the solution. Also, Xcode insists that I should change the %c to %s on scanf. I will try the code on visual studio and post the result.
– Belverus
Nov 13 '18 at 17:27
@Belverus any updates?
– Sourav Ghosh
Nov 14 '18 at 4:40
I tried the code with Visual Studio. If I change the %s with %c as you suggested, It still skips the output. Program gets 2 integers as size of our shape, and displays "Please enter character" and exits the program. If I keep %s it gives an error: Not enough arguments passed for format string.
– Belverus
Nov 15 '18 at 8:20
add a comment |
I've tried it but unfortunately, this is not the solution. Also, Xcode insists that I should change the %c to %s on scanf. I will try the code on visual studio and post the result.
– Belverus
Nov 13 '18 at 17:27
@Belverus any updates?
– Sourav Ghosh
Nov 14 '18 at 4:40
I tried the code with Visual Studio. If I change the %s with %c as you suggested, It still skips the output. Program gets 2 integers as size of our shape, and displays "Please enter character" and exits the program. If I keep %s it gives an error: Not enough arguments passed for format string.
– Belverus
Nov 15 '18 at 8:20
I've tried it but unfortunately, this is not the solution. Also, Xcode insists that I should change the %c to %s on scanf. I will try the code on visual studio and post the result.
– Belverus
Nov 13 '18 at 17:27
I've tried it but unfortunately, this is not the solution. Also, Xcode insists that I should change the %c to %s on scanf. I will try the code on visual studio and post the result.
– Belverus
Nov 13 '18 at 17:27
@Belverus any updates?
– Sourav Ghosh
Nov 14 '18 at 4:40
@Belverus any updates?
– Sourav Ghosh
Nov 14 '18 at 4:40
I tried the code with Visual Studio. If I change the %s with %c as you suggested, It still skips the output. Program gets 2 integers as size of our shape, and displays "Please enter character" and exits the program. If I keep %s it gives an error: Not enough arguments passed for format string.
– Belverus
Nov 15 '18 at 8:20
I tried the code with Visual Studio. If I change the %s with %c as you suggested, It still skips the output. Program gets 2 integers as size of our shape, and displays "Please enter character" and exits the program. If I keep %s it gives an error: Not enough arguments passed for format string.
– Belverus
Nov 15 '18 at 8:20
add a comment |
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