Conditionally select fields from an array in MongoDB document











up vote
1
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I am relatively new to mongodb. I have a document like:



{
"_id" : ObjectId("5bcf50938847292ecbadc3c1"),
"obsrvblKy" : "ABCDEFGHIJ",
"obsrvblKnd" : "PRICE",
"pblshrNm" : "BT",
"pblshrSrc" : "BT",
"dstrbtr" : "BT",
"crtdOn" : ISODate("2018-10-23T12:47:15.544Z"),
"qut" : [
{
"qlfr" : "BID",
"vl" : 100,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
},
{
"qlfr" : "ASK",
"vl" : 101,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
},
{
"qlfr" : "MID",
"vl" : 100.50,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
}
],
"mrkCurrncy" : "USD",
"sttlmntDt" : "2018-10-30"
}


I want this document to be transformed to a more simpler version enabling it to be downloaded into a CSV format.



{
"obsrvblKy" : "ABCDEFGHIJ",
"obsrvblKnd" : "PRICE",
"pblshrNm" : "BT",
"pblshrSrc" : "BT",
"dstrbtr" : "BT",
"Bid": 100,
"Bid-Timestamp": ISODate("2018-10-23T12:47:05.524Z"),
"Ask": 101,
"Ask-Timestamp": ISODate("2018-10-23T12:47:05.524Z"),
"Mid": 100.50,
"Mid-Timestamp": ISODate("2018-10-23T12:47:05.524Z")
}


Can someone point me to how this can be done.










share|improve this question






















  • what hve you tried so far ?
    – 0.sh
    Nov 11 at 15:28















up vote
1
down vote

favorite












I am relatively new to mongodb. I have a document like:



{
"_id" : ObjectId("5bcf50938847292ecbadc3c1"),
"obsrvblKy" : "ABCDEFGHIJ",
"obsrvblKnd" : "PRICE",
"pblshrNm" : "BT",
"pblshrSrc" : "BT",
"dstrbtr" : "BT",
"crtdOn" : ISODate("2018-10-23T12:47:15.544Z"),
"qut" : [
{
"qlfr" : "BID",
"vl" : 100,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
},
{
"qlfr" : "ASK",
"vl" : 101,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
},
{
"qlfr" : "MID",
"vl" : 100.50,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
}
],
"mrkCurrncy" : "USD",
"sttlmntDt" : "2018-10-30"
}


I want this document to be transformed to a more simpler version enabling it to be downloaded into a CSV format.



{
"obsrvblKy" : "ABCDEFGHIJ",
"obsrvblKnd" : "PRICE",
"pblshrNm" : "BT",
"pblshrSrc" : "BT",
"dstrbtr" : "BT",
"Bid": 100,
"Bid-Timestamp": ISODate("2018-10-23T12:47:05.524Z"),
"Ask": 101,
"Ask-Timestamp": ISODate("2018-10-23T12:47:05.524Z"),
"Mid": 100.50,
"Mid-Timestamp": ISODate("2018-10-23T12:47:05.524Z")
}


Can someone point me to how this can be done.










share|improve this question






















  • what hve you tried so far ?
    – 0.sh
    Nov 11 at 15:28













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I am relatively new to mongodb. I have a document like:



{
"_id" : ObjectId("5bcf50938847292ecbadc3c1"),
"obsrvblKy" : "ABCDEFGHIJ",
"obsrvblKnd" : "PRICE",
"pblshrNm" : "BT",
"pblshrSrc" : "BT",
"dstrbtr" : "BT",
"crtdOn" : ISODate("2018-10-23T12:47:15.544Z"),
"qut" : [
{
"qlfr" : "BID",
"vl" : 100,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
},
{
"qlfr" : "ASK",
"vl" : 101,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
},
{
"qlfr" : "MID",
"vl" : 100.50,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
}
],
"mrkCurrncy" : "USD",
"sttlmntDt" : "2018-10-30"
}


I want this document to be transformed to a more simpler version enabling it to be downloaded into a CSV format.



{
"obsrvblKy" : "ABCDEFGHIJ",
"obsrvblKnd" : "PRICE",
"pblshrNm" : "BT",
"pblshrSrc" : "BT",
"dstrbtr" : "BT",
"Bid": 100,
"Bid-Timestamp": ISODate("2018-10-23T12:47:05.524Z"),
"Ask": 101,
"Ask-Timestamp": ISODate("2018-10-23T12:47:05.524Z"),
"Mid": 100.50,
"Mid-Timestamp": ISODate("2018-10-23T12:47:05.524Z")
}


Can someone point me to how this can be done.










share|improve this question













I am relatively new to mongodb. I have a document like:



{
"_id" : ObjectId("5bcf50938847292ecbadc3c1"),
"obsrvblKy" : "ABCDEFGHIJ",
"obsrvblKnd" : "PRICE",
"pblshrNm" : "BT",
"pblshrSrc" : "BT",
"dstrbtr" : "BT",
"crtdOn" : ISODate("2018-10-23T12:47:15.544Z"),
"qut" : [
{
"qlfr" : "BID",
"vl" : 100,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
},
{
"qlfr" : "ASK",
"vl" : 101,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
},
{
"qlfr" : "MID",
"vl" : 100.50,
"mrkTmstmp" : ISODate("2018-10-23T12:47:05.524Z"),
"mrkDt" : ISODate("2018-10-23T00:00:00Z")
}
],
"mrkCurrncy" : "USD",
"sttlmntDt" : "2018-10-30"
}


I want this document to be transformed to a more simpler version enabling it to be downloaded into a CSV format.



{
"obsrvblKy" : "ABCDEFGHIJ",
"obsrvblKnd" : "PRICE",
"pblshrNm" : "BT",
"pblshrSrc" : "BT",
"dstrbtr" : "BT",
"Bid": 100,
"Bid-Timestamp": ISODate("2018-10-23T12:47:05.524Z"),
"Ask": 101,
"Ask-Timestamp": ISODate("2018-10-23T12:47:05.524Z"),
"Mid": 100.50,
"Mid-Timestamp": ISODate("2018-10-23T12:47:05.524Z")
}


Can someone point me to how this can be done.







mongodb mongodb-query aggregation-framework






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share|improve this question




share|improve this question










asked Nov 11 at 14:56









Senthil Vaithilingam

91




91












  • what hve you tried so far ?
    – 0.sh
    Nov 11 at 15:28


















  • what hve you tried so far ?
    – 0.sh
    Nov 11 at 15:28
















what hve you tried so far ?
– 0.sh
Nov 11 at 15:28




what hve you tried so far ?
– 0.sh
Nov 11 at 15:28












2 Answers
2






active

oldest

votes

















up vote
0
down vote













You can use below aggregation



db.collection.aggregate([
{ "$replaceRoot": {
"newRoot": {
"$mergeObjects": [
"$$ROOT",
{ "$arrayToObject": {
"$reduce": {
"input": "$qut",
"initialValue": ,
"in": {
"$concatArrays": [
[
{ "k": "$$this.qlfr", "v": "$$this.vl" },
{ "k": { "$concat": ["$$this.qlfr", "-", "TimeStamp"] }, "v": "$$this.mrkTmstmp" }
],
"$$value"
]
}
}
}}
]
}
}},
{ "$project": { "qut": 0 }}
])


Output



[
{
"ASK": 101,
"ASK-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
"BID": 100,
"BID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
"MID": 100.5,
"MID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
"_id": ObjectId("5bcf50938847292ecbadc3c1"),
"crtdOn": ISODate("2018-10-23T12:47:15.544Z"),
"dstrbtr": "BT",
"mrkCurrncy": "USD",
"obsrvblKnd": "PRICE",
"obsrvblKy": "ABCDEFGHIJ",
"pblshrNm": "BT",
"pblshrSrc": "BT",
"sttlmntDt": "2018-10-30"
}
]





share|improve this answer






























    up vote
    0
    down vote













    You can below aggregation in 3.6 version.



    db.colname.aggregate([
    {"$replaceRoot":{
    "newRoot":{
    "$reduce":{
    "input":"$qut",
    "initialValue":"$$ROOT",
    "in":{
    "$mergeObjects":[
    {"$arrayToObject":[[
    ["$$this.qlfr","$$this.vl"],
    [{"$concat":["$$this.qlfr","-","TimeStamp"]},"$$this.mrkTmstmp"]
    ]]},
    "$$value"
    ]
    }
    }
    }
    }},
    {"$project":{"crtdOn":0,"qut":0,"mrkCurrncy":0,"sttlmntDt":0}}
    ])





    share|improve this answer























    • Did the answer work for you ?
      – Veeram
      Nov 13 at 12:28











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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    You can use below aggregation



    db.collection.aggregate([
    { "$replaceRoot": {
    "newRoot": {
    "$mergeObjects": [
    "$$ROOT",
    { "$arrayToObject": {
    "$reduce": {
    "input": "$qut",
    "initialValue": ,
    "in": {
    "$concatArrays": [
    [
    { "k": "$$this.qlfr", "v": "$$this.vl" },
    { "k": { "$concat": ["$$this.qlfr", "-", "TimeStamp"] }, "v": "$$this.mrkTmstmp" }
    ],
    "$$value"
    ]
    }
    }
    }}
    ]
    }
    }},
    { "$project": { "qut": 0 }}
    ])


    Output



    [
    {
    "ASK": 101,
    "ASK-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
    "BID": 100,
    "BID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
    "MID": 100.5,
    "MID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
    "_id": ObjectId("5bcf50938847292ecbadc3c1"),
    "crtdOn": ISODate("2018-10-23T12:47:15.544Z"),
    "dstrbtr": "BT",
    "mrkCurrncy": "USD",
    "obsrvblKnd": "PRICE",
    "obsrvblKy": "ABCDEFGHIJ",
    "pblshrNm": "BT",
    "pblshrSrc": "BT",
    "sttlmntDt": "2018-10-30"
    }
    ]





    share|improve this answer



























      up vote
      0
      down vote













      You can use below aggregation



      db.collection.aggregate([
      { "$replaceRoot": {
      "newRoot": {
      "$mergeObjects": [
      "$$ROOT",
      { "$arrayToObject": {
      "$reduce": {
      "input": "$qut",
      "initialValue": ,
      "in": {
      "$concatArrays": [
      [
      { "k": "$$this.qlfr", "v": "$$this.vl" },
      { "k": { "$concat": ["$$this.qlfr", "-", "TimeStamp"] }, "v": "$$this.mrkTmstmp" }
      ],
      "$$value"
      ]
      }
      }
      }}
      ]
      }
      }},
      { "$project": { "qut": 0 }}
      ])


      Output



      [
      {
      "ASK": 101,
      "ASK-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
      "BID": 100,
      "BID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
      "MID": 100.5,
      "MID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
      "_id": ObjectId("5bcf50938847292ecbadc3c1"),
      "crtdOn": ISODate("2018-10-23T12:47:15.544Z"),
      "dstrbtr": "BT",
      "mrkCurrncy": "USD",
      "obsrvblKnd": "PRICE",
      "obsrvblKy": "ABCDEFGHIJ",
      "pblshrNm": "BT",
      "pblshrSrc": "BT",
      "sttlmntDt": "2018-10-30"
      }
      ]





      share|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        You can use below aggregation



        db.collection.aggregate([
        { "$replaceRoot": {
        "newRoot": {
        "$mergeObjects": [
        "$$ROOT",
        { "$arrayToObject": {
        "$reduce": {
        "input": "$qut",
        "initialValue": ,
        "in": {
        "$concatArrays": [
        [
        { "k": "$$this.qlfr", "v": "$$this.vl" },
        { "k": { "$concat": ["$$this.qlfr", "-", "TimeStamp"] }, "v": "$$this.mrkTmstmp" }
        ],
        "$$value"
        ]
        }
        }
        }}
        ]
        }
        }},
        { "$project": { "qut": 0 }}
        ])


        Output



        [
        {
        "ASK": 101,
        "ASK-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
        "BID": 100,
        "BID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
        "MID": 100.5,
        "MID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
        "_id": ObjectId("5bcf50938847292ecbadc3c1"),
        "crtdOn": ISODate("2018-10-23T12:47:15.544Z"),
        "dstrbtr": "BT",
        "mrkCurrncy": "USD",
        "obsrvblKnd": "PRICE",
        "obsrvblKy": "ABCDEFGHIJ",
        "pblshrNm": "BT",
        "pblshrSrc": "BT",
        "sttlmntDt": "2018-10-30"
        }
        ]





        share|improve this answer














        You can use below aggregation



        db.collection.aggregate([
        { "$replaceRoot": {
        "newRoot": {
        "$mergeObjects": [
        "$$ROOT",
        { "$arrayToObject": {
        "$reduce": {
        "input": "$qut",
        "initialValue": ,
        "in": {
        "$concatArrays": [
        [
        { "k": "$$this.qlfr", "v": "$$this.vl" },
        { "k": { "$concat": ["$$this.qlfr", "-", "TimeStamp"] }, "v": "$$this.mrkTmstmp" }
        ],
        "$$value"
        ]
        }
        }
        }}
        ]
        }
        }},
        { "$project": { "qut": 0 }}
        ])


        Output



        [
        {
        "ASK": 101,
        "ASK-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
        "BID": 100,
        "BID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
        "MID": 100.5,
        "MID-TimeStamp": ISODate("2018-10-23T12:47:05.524Z"),
        "_id": ObjectId("5bcf50938847292ecbadc3c1"),
        "crtdOn": ISODate("2018-10-23T12:47:15.544Z"),
        "dstrbtr": "BT",
        "mrkCurrncy": "USD",
        "obsrvblKnd": "PRICE",
        "obsrvblKy": "ABCDEFGHIJ",
        "pblshrNm": "BT",
        "pblshrSrc": "BT",
        "sttlmntDt": "2018-10-30"
        }
        ]






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 11 at 16:46

























        answered Nov 11 at 16:40









        Anthony Winzlet

        12.7k41038




        12.7k41038
























            up vote
            0
            down vote













            You can below aggregation in 3.6 version.



            db.colname.aggregate([
            {"$replaceRoot":{
            "newRoot":{
            "$reduce":{
            "input":"$qut",
            "initialValue":"$$ROOT",
            "in":{
            "$mergeObjects":[
            {"$arrayToObject":[[
            ["$$this.qlfr","$$this.vl"],
            [{"$concat":["$$this.qlfr","-","TimeStamp"]},"$$this.mrkTmstmp"]
            ]]},
            "$$value"
            ]
            }
            }
            }
            }},
            {"$project":{"crtdOn":0,"qut":0,"mrkCurrncy":0,"sttlmntDt":0}}
            ])





            share|improve this answer























            • Did the answer work for you ?
              – Veeram
              Nov 13 at 12:28















            up vote
            0
            down vote













            You can below aggregation in 3.6 version.



            db.colname.aggregate([
            {"$replaceRoot":{
            "newRoot":{
            "$reduce":{
            "input":"$qut",
            "initialValue":"$$ROOT",
            "in":{
            "$mergeObjects":[
            {"$arrayToObject":[[
            ["$$this.qlfr","$$this.vl"],
            [{"$concat":["$$this.qlfr","-","TimeStamp"]},"$$this.mrkTmstmp"]
            ]]},
            "$$value"
            ]
            }
            }
            }
            }},
            {"$project":{"crtdOn":0,"qut":0,"mrkCurrncy":0,"sttlmntDt":0}}
            ])





            share|improve this answer























            • Did the answer work for you ?
              – Veeram
              Nov 13 at 12:28













            up vote
            0
            down vote










            up vote
            0
            down vote









            You can below aggregation in 3.6 version.



            db.colname.aggregate([
            {"$replaceRoot":{
            "newRoot":{
            "$reduce":{
            "input":"$qut",
            "initialValue":"$$ROOT",
            "in":{
            "$mergeObjects":[
            {"$arrayToObject":[[
            ["$$this.qlfr","$$this.vl"],
            [{"$concat":["$$this.qlfr","-","TimeStamp"]},"$$this.mrkTmstmp"]
            ]]},
            "$$value"
            ]
            }
            }
            }
            }},
            {"$project":{"crtdOn":0,"qut":0,"mrkCurrncy":0,"sttlmntDt":0}}
            ])





            share|improve this answer














            You can below aggregation in 3.6 version.



            db.colname.aggregate([
            {"$replaceRoot":{
            "newRoot":{
            "$reduce":{
            "input":"$qut",
            "initialValue":"$$ROOT",
            "in":{
            "$mergeObjects":[
            {"$arrayToObject":[[
            ["$$this.qlfr","$$this.vl"],
            [{"$concat":["$$this.qlfr","-","TimeStamp"]},"$$this.mrkTmstmp"]
            ]]},
            "$$value"
            ]
            }
            }
            }
            }},
            {"$project":{"crtdOn":0,"qut":0,"mrkCurrncy":0,"sttlmntDt":0}}
            ])






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 11 at 17:25

























            answered Nov 11 at 15:44









            Veeram

            37.6k33157




            37.6k33157












            • Did the answer work for you ?
              – Veeram
              Nov 13 at 12:28


















            • Did the answer work for you ?
              – Veeram
              Nov 13 at 12:28
















            Did the answer work for you ?
            – Veeram
            Nov 13 at 12:28




            Did the answer work for you ?
            – Veeram
            Nov 13 at 12:28


















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