Ndtyjky

Hi so for homework I have to type up a program where it will accept two numbers. If one of the numbers on the left is smaller than the one on the right, it will increase. If the second number is smaller than the first number than it will decrease. If both numbers are the same then it should stay the same. Here the program I had written so far:

def range_of_numbers (number1, number2):

    if (number2 > number1):

        for num1 in range (1):

            print (2, 3, 4, 5, 6, 7 )

    elif (number1 > number2):

        for num2 in range (1):

            print (19, 18, 17, 16, 15, 14, 13, 12, 11)

    else:

        print (42)

The sample calls are:
range_of _numbers (2, 8)
range_of_numbers (18, 11)
range_of_numbers (42, 42)
I got two of them right, but the last one keeps getting the wrong output and i dont know what wrong or where the mistake to fix it.

Firstly, what you're doing with your first two cases is kind of "cheating" and is what's known as "hardcoding" results. You're not writing a function to perform the task but instead you're just printing the answers you know you should be seeing.

Ironically though, you're pretty close here.

This should do what you want:

def range_of_numbers (num1, num2):

    if(num1 < num2):

        for i in range(num2-num1 +1):

            print(num1+i)

    elif(num1 > num2):

        for i in range(num1-num2 +1):

            print(num1-i)

    else:

        print(num1)

if either num1 or num 2 is greater, we find the difference and make a for loop of that size (+1 since we're 0 indexed and we want to include both ends here). Then we either count up or count down, depending on which is higher.

Use 1 or -1 as steps in your range:

def range_of_numbers(a, b):

  if (a == b):

    print("same") 

  else:

    print(*list(range(a, b, (1 if a<b else -1))))

Test it:

range_of_numbers(2, 8)

range_of_numbers(18, 11)

range_of_numbers(42, 42)

Sure enough you get the desired output:

2 3 4 5 6 7

18 17 16 15 14 13 12

same